Le 21/02/2018 à 18:23, bartc a écrit :
On 21/02/2018 15:54, ast wrote:
Le 21/02/2018 à 15:02, bartc a écrit :
On 21/02/2018 13:27, ast wrote:
Time efficient or space efficient?
space efficient
If the latter, how many floats are we talking about?
10^9
Although it might be better
On 21/02/2018 15:54, ast wrote:
Le 21/02/2018 à 15:02, bartc a écrit :
On 21/02/2018 13:27, ast wrote:
Time efficient or space efficient?
space efficient
If the latter, how many floats are we talking about?
10^9
OK. My experiment of writing the same 64-bit float a billion times to a
Le 21/02/2018 à 14:27, ast a écrit :
struct.pack() as advised works fine.
Exemple:
>>> import struct
>>> struct.pack(">d", -0.0)
b'\x80\x00\x00\x00\x00\x00\x00\x00'
before I read your answers I found a way
with pickle
>>> import pickle
>>> pickle.dumps(-0.0)[3:-1]
b'\x80\x00\x00\x00\x00\x00\x0
Le 21/02/2018 à 15:02, bartc a écrit :
On 21/02/2018 13:27, ast wrote:
Time efficient or space efficient?
space efficient
If the latter, how many floats are we talking about?
10^9
--
https://mail.python.org/mailman/listinfo/python-list
ast wrote:
>Hello
>I would like to write a huge file of double precision
>floats, 8 bytes each, using IEEE754 standard. Since
>the file is big, it has to be done in an efficient
>way.
>I tried pickle module but unfortunately it writes
>12 bytes per float instead of just 8.
>Is there a way to wr
ast wrote:
> Is there a way to write a float with only 8 bytes ?
If you want to write the values one-by-one convert them to bytes with
struct.pack() and then write the result.
To write many values at once use array.array.tofile() or
numpy.array.tofile().
--
https://mail.python.org/mailman/l
On 21/02/2018 13:27, ast wrote:
Hello
I would like to write a huge file of double precision
floats, 8 bytes each, using IEEE754 standard. Since
the file is big, it has to be done in an efficient
way.
Time efficient or space efficient?
If the latter, how many floats are we talking about?
I t
