subject:"Re\: why this code loop forever after a draw a rectangle"

Re: why this code loop forever after a draw a rectangle

2016-09-16 Thread meInvent bbird

after succeed to draw lines in graph,

however,

https://drive.google.com/file/d/0Bxs_ao6uuBDUWVBFZzVIVGotRlk/view?usp=sharing

expected the blue line connect the bottom of red line graph

https://drive.google.com/file/d/0Bxs_ao6uuBDUNGZFS2F3WnJERzA/view?usp=sharing

how can convex hull be adjusted to do like second graph of sky blue line


On Saturday, September 17, 2016 at 7:48:46 AM UTC+8, meInvent bbird wrote:
> img is the image
> 
> im is a new memory of image using  img.copy()
> 
> 
> On Saturday, September 17, 2016 at 7:46:42 AM UTC+8, meInvent bbird wrote:
> > thank you very much,
> > it out of the loop now.
> > because drawLine function return things
> > 
> > i just change drawLine to rectangle,
> > have not thought that rectangle not return thing, just edit the parameter
> > 
> > 
> > 
> > On Saturday, September 17, 2016 at 5:26:53 AM UTC+8, MRAB wrote:
> > > On 2016-09-16 20:14, Gary Herron wrote:
> > > > On 09/16/2016 04:24 AM, meInvent bbird wrote:
> > > >> im = img.copy()
> > > >> cntcounter = 0
> > > >> for cnt in contours:
> > > >>  epsilon = 0.1*cv2.arcLength(cnt,True)
> > > >>  approx = cv2.approxPolyDP(cnt,epsilon,True)   
> > > >>  #peri = cv2.arcLength(cnt, True)
> > > >>  #approx = cv2.approxPolyDP(c, 0.5 * peri, True)
> > > >>  #print("len(approx)="+str(len(approx)))
> > > >>  if len(approx) == 4:
> > > >>  print("approx=" + str(approx))
> > > >>  cntcounter = cntcounter + 1
> > > >>  print("here1")
> > > >>  x,y,w,h = cv2.boundingRect(cnt)
> > > >>  print("here2")
> > > >>  while im is None:
> > > >>  time.sleep(1)
> > > >>  if im is not None:
> > > >>  print("here3")
> > > >>  im = cv2.rectangle(im.copy(), (x,y), (x+w, y+h), 
> > > >> (0,255,0), 2)
> > > >>  #im = cv2.line(im,(x,y),(x+w,y),(0,255,0),2)
> > > >>  #im = cv2.line(im,(x+w,y),(x+w,y+h),(0,255,0),2)
> > > >>  #im = cv2.line(im,(x,y+h),(x+w,y+h),(0,255,0),2)
> > > >>  #im = cv2.line(im,(x,y),(x,y+h),(0,255,0),2)
> > > >>
> > > >>
> > > >> cv2.imwrite(r'C:\Users\tester\Documents\masda.png',im)
> > > >
> > > >
> > > > These two lines:
> > > >
> > > >while im is None:
> > > >  time.sleep(1)
> > > >
> > > > are an infinite loop if im is None;
> > > >
> > > >
> > > > Since you haven't told us what im (or img, contours, cv2) are, I can't
> > > > tell how im might become None, but it does look like you (confusingly)
> > > > use im for two different things:  an img.copy() and a cv2.rectangle,
> > > > whatever those may be.
> > > >
> > > > Pure guesswork:  if cv2.rectangle draws a rectangle, what does it
> > > > return?  If it doesn't return anything, the line
> > > >  im = cv2.rectangle(...)
> > > > is how im gets the value of None.
> > > >
> > > It looks like the OP is using OpenCV.
> > > 
> > > You're right about cv2.rectangle; it does return None.
> > > 
> > > The line:
> > > 
> > >  im = cv2.rectangle(im.copy(), (x,y), (x+w, y+h), (0,255,0), 2)
> > > 
> > > makes a copy of the image im, draws a rectangle on it, and then binds 
> > > None to im.
> > > 
> > > The copied rectangle is discarded because there's no reference to it, so 
> > > the entire line in pointless.
> > > 
> > > It basically does the same thing as:
> > > 
> > >  im = None
> > > 
> > > only slower!

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Re: why this code loop forever after a draw a rectangle

2016-09-16 Thread meInvent bbird

img is the image

im is a new memory of image using  img.copy()


On Saturday, September 17, 2016 at 7:46:42 AM UTC+8, meInvent bbird wrote:
> thank you very much,
> it out of the loop now.
> because drawLine function return things
> 
> i just change drawLine to rectangle,
> have not thought that rectangle not return thing, just edit the parameter
> 
> 
> 
> On Saturday, September 17, 2016 at 5:26:53 AM UTC+8, MRAB wrote:
> > On 2016-09-16 20:14, Gary Herron wrote:
> > > On 09/16/2016 04:24 AM, meInvent bbird wrote:
> > >> im = img.copy()
> > >> cntcounter = 0
> > >> for cnt in contours:
> > >>  epsilon = 0.1*cv2.arcLength(cnt,True)
> > >>  approx = cv2.approxPolyDP(cnt,epsilon,True) 
> > >>  #peri = cv2.arcLength(cnt, True)
> > >>  #approx = cv2.approxPolyDP(c, 0.5 * peri, True)
> > >>  #print("len(approx)="+str(len(approx)))
> > >>  if len(approx) == 4:
> > >>  print("approx=" + str(approx))
> > >>  cntcounter = cntcounter + 1
> > >>  print("here1")
> > >>  x,y,w,h = cv2.boundingRect(cnt)
> > >>  print("here2")
> > >>  while im is None:
> > >>  time.sleep(1)
> > >>  if im is not None:
> > >>  print("here3")
> > >>  im = cv2.rectangle(im.copy(), (x,y), (x+w, y+h), 
> > >> (0,255,0), 2)
> > >>  #im = cv2.line(im,(x,y),(x+w,y),(0,255,0),2)
> > >>  #im = cv2.line(im,(x+w,y),(x+w,y+h),(0,255,0),2)
> > >>  #im = cv2.line(im,(x,y+h),(x+w,y+h),(0,255,0),2)
> > >>  #im = cv2.line(im,(x,y),(x,y+h),(0,255,0),2)
> > >>
> > >>
> > >> cv2.imwrite(r'C:\Users\tester\Documents\masda.png',im)
> > >
> > >
> > > These two lines:
> > >
> > >while im is None:
> > >  time.sleep(1)
> > >
> > > are an infinite loop if im is None;
> > >
> > >
> > > Since you haven't told us what im (or img, contours, cv2) are, I can't
> > > tell how im might become None, but it does look like you (confusingly)
> > > use im for two different things:  an img.copy() and a cv2.rectangle,
> > > whatever those may be.
> > >
> > > Pure guesswork:  if cv2.rectangle draws a rectangle, what does it
> > > return?  If it doesn't return anything, the line
> > >  im = cv2.rectangle(...)
> > > is how im gets the value of None.
> > >
> > It looks like the OP is using OpenCV.
> > 
> > You're right about cv2.rectangle; it does return None.
> > 
> > The line:
> > 
> >  im = cv2.rectangle(im.copy(), (x,y), (x+w, y+h), (0,255,0), 2)
> > 
> > makes a copy of the image im, draws a rectangle on it, and then binds 
> > None to im.
> > 
> > The copied rectangle is discarded because there's no reference to it, so 
> > the entire line in pointless.
> > 
> > It basically does the same thing as:
> > 
> >  im = None
> > 
> > only slower!

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Re: why this code loop forever after a draw a rectangle

2016-09-16 Thread meInvent bbird

thank you very much,
it out of the loop now.
because drawLine function return things

i just change drawLine to rectangle,
have not thought that rectangle not return thing, just edit the parameter



On Saturday, September 17, 2016 at 5:26:53 AM UTC+8, MRAB wrote:
> On 2016-09-16 20:14, Gary Herron wrote:
> > On 09/16/2016 04:24 AM, meInvent bbird wrote:
> >> im = img.copy()
> >> cntcounter = 0
> >> for cnt in contours:
> >>  epsilon = 0.1*cv2.arcLength(cnt,True)
> >>  approx = cv2.approxPolyDP(cnt,epsilon,True)   
> >>  #peri = cv2.arcLength(cnt, True)
> >>  #approx = cv2.approxPolyDP(c, 0.5 * peri, True)
> >>  #print("len(approx)="+str(len(approx)))
> >>  if len(approx) == 4:
> >>  print("approx=" + str(approx))
> >>  cntcounter = cntcounter + 1
> >>  print("here1")
> >>  x,y,w,h = cv2.boundingRect(cnt)
> >>  print("here2")
> >>  while im is None:
> >>  time.sleep(1)
> >>  if im is not None:
> >>  print("here3")
> >>  im = cv2.rectangle(im.copy(), (x,y), (x+w, y+h), 
> >> (0,255,0), 2)
> >>  #im = cv2.line(im,(x,y),(x+w,y),(0,255,0),2)
> >>  #im = cv2.line(im,(x+w,y),(x+w,y+h),(0,255,0),2)
> >>  #im = cv2.line(im,(x,y+h),(x+w,y+h),(0,255,0),2)
> >>  #im = cv2.line(im,(x,y),(x,y+h),(0,255,0),2)
> >>
> >>
> >> cv2.imwrite(r'C:\Users\tester\Documents\masda.png',im)
> >
> >
> > These two lines:
> >
> >while im is None:
> >  time.sleep(1)
> >
> > are an infinite loop if im is None;
> >
> >
> > Since you haven't told us what im (or img, contours, cv2) are, I can't
> > tell how im might become None, but it does look like you (confusingly)
> > use im for two different things:  an img.copy() and a cv2.rectangle,
> > whatever those may be.
> >
> > Pure guesswork:  if cv2.rectangle draws a rectangle, what does it
> > return?  If it doesn't return anything, the line
> >  im = cv2.rectangle(...)
> > is how im gets the value of None.
> >
> It looks like the OP is using OpenCV.
> 
> You're right about cv2.rectangle; it does return None.
> 
> The line:
> 
>  im = cv2.rectangle(im.copy(), (x,y), (x+w, y+h), (0,255,0), 2)
> 
> makes a copy of the image im, draws a rectangle on it, and then binds 
> None to im.
> 
> The copied rectangle is discarded because there's no reference to it, so 
> the entire line in pointless.
> 
> It basically does the same thing as:
> 
>  im = None
> 
> only slower!

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Re: why this code loop forever after a draw a rectangle

2016-09-16 Thread MRAB


On 2016-09-16 20:14, Gary Herron wrote:

On 09/16/2016 04:24 AM, meInvent bbird wrote:

im = img.copy()
cntcounter = 0
for cnt in contours:
 epsilon = 0.1*cv2.arcLength(cnt,True)
 approx = cv2.approxPolyDP(cnt,epsilon,True)
 #peri = cv2.arcLength(cnt, True)
 #approx = cv2.approxPolyDP(c, 0.5 * peri, True)
 #print("len(approx)="+str(len(approx)))
 if len(approx) == 4:
 print("approx=" + str(approx))
 cntcounter = cntcounter + 1
 print("here1")
 x,y,w,h = cv2.boundingRect(cnt)
 print("here2")
 while im is None:
 time.sleep(1)
 if im is not None:
 print("here3")
 im = cv2.rectangle(im.copy(), (x,y), (x+w, y+h), (0,255,0), 2)
 #im = cv2.line(im,(x,y),(x+w,y),(0,255,0),2)
 #im = cv2.line(im,(x+w,y),(x+w,y+h),(0,255,0),2)
 #im = cv2.line(im,(x,y+h),(x+w,y+h),(0,255,0),2)
 #im = cv2.line(im,(x,y),(x,y+h),(0,255,0),2)


cv2.imwrite(r'C:\Users\tester\Documents\masda.png',im)



These two lines:

   while im is None:
 time.sleep(1)

are an infinite loop if im is None;


Since you haven't told us what im (or img, contours, cv2) are, I can't
tell how im might become None, but it does look like you (confusingly)
use im for two different things:  an img.copy() and a cv2.rectangle,
whatever those may be.

Pure guesswork:  if cv2.rectangle draws a rectangle, what does it
return?  If it doesn't return anything, the line
 im = cv2.rectangle(...)
is how im gets the value of None.


It looks like the OP is using OpenCV.

You're right about cv2.rectangle; it does return None.

The line:

im = cv2.rectangle(im.copy(), (x,y), (x+w, y+h), (0,255,0), 2)

makes a copy of the image im, draws a rectangle on it, and then binds 
None to im.


The copied rectangle is discarded because there's no reference to it, so 
the entire line in pointless.


It basically does the same thing as:

im = None

only slower!

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https://mail.python.org/mailman/listinfo/python-list

Re: why this code loop forever after a draw a rectangle

2016-09-16 Thread Gary Herron


On 09/16/2016 05:18 AM, meInvent bbird wrote:

i follow this post to give some time it to operate,
wait a long time still looping

http://answers.opencv.org/question/60094/libpng-warning-image-width-is-zero-in-ihdr/


i can not stand this Ninja coding life any more,
i have to open my code for ask this error


import cv2
import numpy as np
#from matplotlib import pyplot as plt
import time

#print("1=" + str(int(sys.argv[1])))
#print("2=" + str(int(sys.argv[2])))
#print("3=" + str(int(sys.argv[3])))

img_rgb = cv2.imread(r'C:\Users\martin\Documents\scree2.png')
img_gray = cv2.cvtColor(img_rgb, cv2.COLOR_BGR2GRAY)
template = cv2.imread(r'C:\Users\martin\Documents\dragob.png',0)
w, h = template.shape[::-1]

res = cv2.matchTemplate(img_gray,template,cv2.TM_CCOEFF_NORMED)
threshold = 0.64
 
loc = np.where( res >= threshold)

pt = [(0,0)]
 
while not zip(*loc[::-1]):

 threshold = threshold - 0.02
 loc = np.where( res >= threshold)

counter = 1
print("threshold="+str(threshold))
for pt2 in zip(*loc[::-1]):
 cv2.rectangle(img_rgb, pt2, (pt2[0] + w, pt2[1] + h), (0,0,255), 2)
 pt = pt2
 crop_img = img_rgb[pt[1]:(pt[1]+h), pt[0]:(pt[0]+w)]
 counter = counter + 1

cv2.imwrite("C:\\Users\\tester\\Documents\\res.png",crop_img)


#import cv2
#winName = "Movement Indicator"
#cv2.namedWindow(winName, cv2.WINDOW_NORMAL)
img = cv2.imread(r'C:\Users\tester\Documents\res.png',1)
gray = cv2.cvtColor(img,cv2.COLOR_BGR2GRAY)
height, width = gray.shape
edges = cv2.Canny(gray,height,width,apertureSize = 3)
#edges = cv2.Canny(gray,30,200)

#gray = cv2.cvtColor(img, cv2.COLOR_RGB2GRAY)
#ret,thresh = 
cv2.threshold(edges.copy(),cv2.RETR_TREE,cv2.CHAIN_APPROX_SIMPLE,0)
ret,thresh = cv2.threshold(edges,250,150,0)
contours,hierarchy = cv2.findContours(thresh, 1, 2)
#contours = sorted(contours, key = cv2.contourArea, reverse = True)[:10]

im = img.copy()
cntcounter = 0
for cnt in contours:
 epsilon = 0.1*cv2.arcLength(cnt,True)
 approx = cv2.approxPolyDP(cnt,epsilon,True)
 #peri = cv2.arcLength(cnt, True)
 #approx = cv2.approxPolyDP(c, 0.5 * peri, True)
 #print("len(approx)="+str(len(approx)))
 if len(approx) == 4:
 print("approx=" + str(approx))
 cntcounter = cntcounter + 1
 print("here1")
 x,y,w,h = cv2.boundingRect(cnt)
 print("here2")
 #im = img.copy()
 while im is None:
 time.sleep(1)
 if im is not None:
 print("here3")
 im = cv2.rectangle(im.copy(), (x,y), (x+w, y+h), (0,255,0), 2)
 
#cv2.imwrite("C:\\Users\\martin\\Documents\\masda"+str(cntcounter)+".png",imi)
 #im = cv2.line(im,(x,y),(x+w,y),(0,255,0),2)
 #im = cv2.line(im,(x+w,y),(x+w,y+h),(0,255,0),2)
 #im = cv2.line(im,(x,y+h),(x+w,y+h),(0,255,0),2)
 #im = cv2.line(im,(x,y),(x,y+h),(0,255,0),2)








On Friday, September 16, 2016 at 7:34:04 PM UTC+8, Waffle wrote:

On 16 September 2016 at 14:24, meInvent bbird  wrote:

im = img.copy()
cntcounter = 0
for cnt in contours:
 epsilon = 0.1*cv2.arcLength(cnt,True)
 approx = cv2.approxPolyDP(cnt,epsilon,True)
 #peri = cv2.arcLength(cnt, True)
 #approx = cv2.approxPolyDP(c, 0.5 * peri, True)
 #print("len(approx)="+str(len(approx)))
 if len(approx) == 4:
 print("approx=" + str(approx))
 cntcounter = cntcounter + 1
 print("here1")
 x,y,w,h = cv2.boundingRect(cnt)
 print("here2")
 while im is None:
 time.sleep(1)
 if im is not None:
 print("here3")
 im = cv2.rectangle(im.copy(), (x,y), (x+w, y+h), (0,255,0), 2)
 #im = cv2.line(im,(x,y),(x+w,y),(0,255,0),2)
 #im = cv2.line(im,(x+w,y),(x+w,y+h),(0,255,0),2)
 #im = cv2.line(im,(x,y+h),(x+w,y+h),(0,255,0),2)
 #im = cv2.line(im,(x,y),(x,y+h),(0,255,0),2)


cv2.imwrite(r'C:\Users\tester\Documents\masda.png',im)
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not sure but..  this bit reads really suspicious:

 while im is None:
 time.sleep(1)

if im is ever None then how will it ever become not None? unless there
is some other thread at work i can't really see this happening.
and if there is some other thread at work then there is probably some
better solution than sleep()


Reading the manual for opencv, we see that cv2.rectangle does indeed 
return None:
  Python: cv.Rectangle(img, pt1, pt2, color, thickness=1, 
lineType=8, shift=0) → None


So the first pass through your loop does indeed set im to None with the line
im = cv2.rectangle(im.copy(), (x,y), (x+w, y+h), (0,255,0), 2)
and the next pass through the loop hits the infinite loop:
while im is None:
time.sleep(1)

Re: why this code loop forever after a draw a rectangle

2016-09-16 Thread Gary Herron


On 09/16/2016 04:24 AM, meInvent bbird wrote:

im = img.copy()
cntcounter = 0
for cnt in contours:
 epsilon = 0.1*cv2.arcLength(cnt,True)
 approx = cv2.approxPolyDP(cnt,epsilon,True)
 #peri = cv2.arcLength(cnt, True)
 #approx = cv2.approxPolyDP(c, 0.5 * peri, True)
 #print("len(approx)="+str(len(approx)))
 if len(approx) == 4:
 print("approx=" + str(approx))
 cntcounter = cntcounter + 1
 print("here1")
 x,y,w,h = cv2.boundingRect(cnt)
 print("here2")
 while im is None:
 time.sleep(1)
 if im is not None:
 print("here3")
 im = cv2.rectangle(im.copy(), (x,y), (x+w, y+h), (0,255,0), 2)
 #im = cv2.line(im,(x,y),(x+w,y),(0,255,0),2)
 #im = cv2.line(im,(x+w,y),(x+w,y+h),(0,255,0),2)
 #im = cv2.line(im,(x,y+h),(x+w,y+h),(0,255,0),2)
 #im = cv2.line(im,(x,y),(x,y+h),(0,255,0),2)


cv2.imwrite(r'C:\Users\tester\Documents\masda.png',im)



These two lines:

  while im is None:
time.sleep(1)

are an infinite loop if im is None;


Since you haven't told us what im (or img, contours, cv2) are, I can't 
tell how im might become None, but it does look like you (confusingly) 
use im for two different things:  an img.copy() and a cv2.rectangle, 
whatever those may be.


Pure guesswork:  if cv2.rectangle draws a rectangle, what does it 
return?  If it doesn't return anything, the line

im = cv2.rectangle(...)
is how im gets the value of None.

--
Dr. Gary Herron
Professor of Computer Science
DigiPen Institute of Technology
(425) 895-4418

--
https://mail.python.org/mailman/listinfo/python-list

Re: why this code loop forever after a draw a rectangle

2016-09-16 Thread meInvent bbird

i follow this post to give some time it to operate,
wait a long time still looping

http://answers.opencv.org/question/60094/libpng-warning-image-width-is-zero-in-ihdr/


i can not stand this Ninja coding life any more,
i have to open my code for ask this error


import cv2
import numpy as np
#from matplotlib import pyplot as plt
import time

#print("1=" + str(int(sys.argv[1])))
#print("2=" + str(int(sys.argv[2])))
#print("3=" + str(int(sys.argv[3])))

img_rgb = cv2.imread(r'C:\Users\martin\Documents\scree2.png')
img_gray = cv2.cvtColor(img_rgb, cv2.COLOR_BGR2GRAY)
template = cv2.imread(r'C:\Users\martin\Documents\dragob.png',0)
w, h = template.shape[::-1]

res = cv2.matchTemplate(img_gray,template,cv2.TM_CCOEFF_NORMED)
threshold = 0.64

loc = np.where( res >= threshold)
pt = [(0,0)]

while not zip(*loc[::-1]):
threshold = threshold - 0.02
loc = np.where( res >= threshold)

counter = 1
print("threshold="+str(threshold))   
for pt2 in zip(*loc[::-1]):
cv2.rectangle(img_rgb, pt2, (pt2[0] + w, pt2[1] + h), (0,0,255), 2)
pt = pt2
crop_img = img_rgb[pt[1]:(pt[1]+h), pt[0]:(pt[0]+w)]
counter = counter + 1

cv2.imwrite("C:\\Users\\tester\\Documents\\res.png",crop_img)


#import cv2
#winName = "Movement Indicator"
#cv2.namedWindow(winName, cv2.WINDOW_NORMAL)
img = cv2.imread(r'C:\Users\tester\Documents\res.png',1)
gray = cv2.cvtColor(img,cv2.COLOR_BGR2GRAY)
height, width = gray.shape
edges = cv2.Canny(gray,height,width,apertureSize = 3)
#edges = cv2.Canny(gray,30,200)

#gray = cv2.cvtColor(img, cv2.COLOR_RGB2GRAY)
#ret,thresh = 
cv2.threshold(edges.copy(),cv2.RETR_TREE,cv2.CHAIN_APPROX_SIMPLE,0)
ret,thresh = cv2.threshold(edges,250,150,0)
contours,hierarchy = cv2.findContours(thresh, 1, 2)
#contours = sorted(contours, key = cv2.contourArea, reverse = True)[:10]

im = img.copy()
cntcounter = 0
for cnt in contours:
epsilon = 0.1*cv2.arcLength(cnt,True)
approx = cv2.approxPolyDP(cnt,epsilon,True) 
#peri = cv2.arcLength(cnt, True)
#approx = cv2.approxPolyDP(c, 0.5 * peri, True)
#print("len(approx)="+str(len(approx)))
if len(approx) == 4:
print("approx=" + str(approx))
cntcounter = cntcounter + 1
print("here1")
x,y,w,h = cv2.boundingRect(cnt)
print("here2")
#im = img.copy()
while im is None:
time.sleep(1)
if im is not None:
print("here3")
im = cv2.rectangle(im.copy(), (x,y), (x+w, y+h), (0,255,0), 2) 

#cv2.imwrite("C:\\Users\\martin\\Documents\\masda"+str(cntcounter)+".png",imi)  
  
#im = cv2.line(im,(x,y),(x+w,y),(0,255,0),2)
#im = cv2.line(im,(x+w,y),(x+w,y+h),(0,255,0),2)
#im = cv2.line(im,(x,y+h),(x+w,y+h),(0,255,0),2)
#im = cv2.line(im,(x,y),(x,y+h),(0,255,0),2)








On Friday, September 16, 2016 at 7:34:04 PM UTC+8, Waffle wrote:
> On 16 September 2016 at 14:24, meInvent bbird  wrote:
> > im = img.copy()
> > cntcounter = 0
> > for cnt in contours:
> > epsilon = 0.1*cv2.arcLength(cnt,True)
> > approx = cv2.approxPolyDP(cnt,epsilon,True)
> > #peri = cv2.arcLength(cnt, True)
> > #approx = cv2.approxPolyDP(c, 0.5 * peri, True)
> > #print("len(approx)="+str(len(approx)))
> > if len(approx) == 4:
> > print("approx=" + str(approx))
> > cntcounter = cntcounter + 1
> > print("here1")
> > x,y,w,h = cv2.boundingRect(cnt)
> > print("here2")
> > while im is None:
> > time.sleep(1)
> > if im is not None:
> > print("here3")
> > im = cv2.rectangle(im.copy(), (x,y), (x+w, y+h), (0,255,0), 
> > 2)
> > #im = cv2.line(im,(x,y),(x+w,y),(0,255,0),2)
> > #im = cv2.line(im,(x+w,y),(x+w,y+h),(0,255,0),2)
> > #im = cv2.line(im,(x,y+h),(x+w,y+h),(0,255,0),2)
> > #im = cv2.line(im,(x,y),(x,y+h),(0,255,0),2)
> >
> >
> > cv2.imwrite(r'C:\Users\tester\Documents\masda.png',im)
> > --
> > https://mail.python.org/mailman/listinfo/python-list
> 
> not sure but..  this bit reads really suspicious:
> 
> while im is None:
> time.sleep(1)
> 
> if im is ever None then how will it ever become not None? unless there
> is some other thread at work i can't really see this happening.
> and if there is some other thread at work then there is probably some
> better solution than sleep()





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Re: why this code loop forever after a draw a rectangle

2016-09-16 Thread Joonas Liik

On 16 September 2016 at 14:24, meInvent bbird  wrote:
> im = img.copy()
> cntcounter = 0
> for cnt in contours:
> epsilon = 0.1*cv2.arcLength(cnt,True)
> approx = cv2.approxPolyDP(cnt,epsilon,True)
> #peri = cv2.arcLength(cnt, True)
> #approx = cv2.approxPolyDP(c, 0.5 * peri, True)
> #print("len(approx)="+str(len(approx)))
> if len(approx) == 4:
> print("approx=" + str(approx))
> cntcounter = cntcounter + 1
> print("here1")
> x,y,w,h = cv2.boundingRect(cnt)
> print("here2")
> while im is None:
> time.sleep(1)
> if im is not None:
> print("here3")
> im = cv2.rectangle(im.copy(), (x,y), (x+w, y+h), (0,255,0), 2)
> #im = cv2.line(im,(x,y),(x+w,y),(0,255,0),2)
> #im = cv2.line(im,(x+w,y),(x+w,y+h),(0,255,0),2)
> #im = cv2.line(im,(x,y+h),(x+w,y+h),(0,255,0),2)
> #im = cv2.line(im,(x,y),(x,y+h),(0,255,0),2)
>
>
> cv2.imwrite(r'C:\Users\tester\Documents\masda.png',im)
> --
> https://mail.python.org/mailman/listinfo/python-list

not sure but..  this bit reads really suspicious:

while im is None:
time.sleep(1)

if im is ever None then how will it ever become not None? unless there
is some other thread at work i can't really see this happening.
and if there is some other thread at work then there is probably some
better solution than sleep()
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Re: why this code loop forever after a draw a rectangle

Re: why this code loop forever after a draw a rectangle

Re: why this code loop forever after a draw a rectangle

Re: why this code loop forever after a draw a rectangle

Re: why this code loop forever after a draw a rectangle

Re: why this code loop forever after a draw a rectangle

Re: why this code loop forever after a draw a rectangle

Re: why this code loop forever after a draw a rectangle

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