On 2017-09-06 08:37, Thomas Devoogdt wrote:
> Is there a reason why multiple AND statements are converted like this.
>
>
> (stm1) & (stm2) & (stm3)
>
> ->
>
> (((stm1) AND (stm2)) AND (stm3))
>
> and not
>
> ((stm1) AND (stm2) AND (stm3))
>
This is because '&' which is __and__ operator in P
Is there a reason why multiple AND statements are converted like this.
(stm1) & (stm2) & (stm3)
->
(((stm1) AND (stm2)) AND (stm3))
and not
((stm1) AND (stm2) AND (stm3))
Thanks in advance.
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