I am trying to figure out how to show a specified file in explorer. I
know I can call os.startfile(directory) to show the containing
directory, but I would like the file to be selected also. Is there an
API call that windows makes to do this?
For example, right click on a shortcut and go to
:[EMAIL PROTECTED] On Behalf Of Tim Roberts
Sent: Thursday, April 03, 2008 11:42 AM
To: Python-Win32 List
Subject: Re: [python-win32] Find Target
Rickey, Kyle W wrote:
I am trying to figure out how to show a specified file in explorer. I
know I can call os.startfile(directory) to show
Rickey, Kyle W wrote:
Tim, let me rephrase. I'm not trying to display the shortcut dialog,
only reproduce the behavior that happens when you click 'Find Target'.
For instance, I've generated a file and I want show the user that file
in explorer.
Find Target just follows a shortcut and
Kyle,
If I understand you correctly, and if your not stuck on using os.startfile(),
you can use explorer.exe's command line options to do this (and more).
os.system('%SystemRoot%\explorer.exe/e,/select=C:\MyFolder\subfolder\MyFile.
txt')
See thisfor more info:
Rickey, Kyle W wrote:
Tim, thanks for your patience :). I think I'm still miscommunicating to
you what I need to do. Let's throw the whole shortcut idea out the
window and start from scratch.
My code generates a file, I want to open the directory (which is known)
containing that file and
