From: "Justin Terry (VM) via Qemu-devel" <qemu-devel@nongnu.org>
The code already is holding the qemu_mutex for the IO thread. We do not need
to additionally take the lock again in this case.
Signed-off-by: Justin Terry (VM) <jute...@microsoft.com>
Message-Id: <1519665216-1078-5-git-send-email-jute...@microsoft.com>
Signed-off-by: Paolo Bonzini <pbonz...@redhat.com>
Signed-off-by: Justin Terry (VM) via Qemu-devel <qemu-devel@nongnu.org>
---
target/i386/whpx-all.c | 2 --
1 file changed, 2 deletions(-)
diff --git a/target/i386/whpx-all.c b/target/i386/whpx-all.c
index 14ea732..74a8f4d 100644
--- a/target/i386/whpx-all.c
+++ b/target/i386/whpx-all.c
@@ -705,9 +705,7 @@ static void whpx_vcpu_pre_run(CPUState *cpu)
new_int.InterruptionVector = 2;
}
if (cpu->interrupt_request & CPU_INTERRUPT_SMI) {
- qemu_mutex_lock_iothread();
cpu->interrupt_request &= ~CPU_INTERRUPT_SMI;
- qemu_mutex_unlock_iothread();
}
}
--
1.8.3.1
