Re: [Qemu-discuss] How do -icount flags work in QEMU TCG

I see I see. So instead of creating a bigger TB that starts from the start of the TB to the particular I/O instruction, only a single TB would be created that contains only one instruction, which is the I/O instruction. Many thanks for letting me know. Best Regards, Arnab On Sat, Mar 24, 2018 at

Re: [Qemu-discuss] How do -icount flags work in QEMU TCG

On 23 March 2018 at 19:47, Arnabjyoti Kalita wrote: > Hi Peter, > > Yes only I could see that. Sorry for dumping out incomplete logs :) > > Well I think I figured out the source of this representation of repeating TB > blocks. Your 3rd point in your previous answer was

Re: [Qemu-discuss] How do -icount flags work in QEMU TCG

Hi Peter, Yes only I could see that. Sorry for dumping out incomplete logs :) Well I think I figured out the source of this representation of repeating TB blocks. Your 3rd point in your previous answer was the solution. The fact that QEMU in TCG mode executes I/O instructions at the end of the

Re: [Qemu-discuss] How do -icount flags work in QEMU TCG

On 22 March 2018 at 22:34, Arnabjyoti Kalita wrote: > From what I can see from the logs, it is quite hard to tell why this occurs. > I am afraid I might have to disagree with your point 2. If it was an MMU > page fault, one of the TCG blocks would have started executing

Re: [Qemu-discuss] How do -icount flags work in QEMU TCG

>From what I can see from the logs, it is quite hard to tell why this occurs. I am afraid I might have to disagree with your point 2. If it was an MMU page fault, one of the TCG blocks would have started executing the page fault handlers already - which I do not see in the TCG execution flow yet

Re: [Qemu-discuss] How do -icount flags work in QEMU TCG

On 21 March 2018 at 20:22, Arnabjyoti Kalita wrote: > I see that in the trace file, some of the TCG blocks seem to be translated > more than once - > > ( NOTE: I am not using the TB Cache/Hash Table and have managed to disable > it in the QEMU code ) > > IN: >

[Qemu-discuss] How do -icount flags work in QEMU TCG

Hi all, I have been trying to understand how the -icount shift=N | auto flags work in QEMU. There are small descriptions as to how it works already, but I just wanted a clearer perspective. I obtained a trace of the target instructions using "-d in_asm" switch while having the icount flags in