> Thanks, I was worried that it is some problem with my QGIS implementation
> at GIS.lab [1]. I will submit ticket with GDB traceback.
> Anyone else can confirm ?
>
Ticked created: http://hub.qgis.org/issues/9213
Ivan
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Thank you everyone for your various answers to this question, both on
and off list.
Best,
--Lee
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Hi Richard,
thanks for the hint.
do we have some prominent area at qgis.org, where we can announce those
community/devel/user events?
Regards
Otto
Am Sat, 14 Dec 2013 16:37:26 +0100
schrieb Richard Duivenvoorde :
> Hi Devs,
>
> after last PSC meeting we decided to go to Vienna for the next Q
Hi,
Sorry, I'm a beginner in pyqgis.
I found the signal "layerDeleted ()" in the QgsVectorLayer class,
however, I can't find it in the QgsRasterLayer class :
http://qgis.org/api/2.0/classQgsVectorLayer.html#acc3e594b1dac4815dc031a2236f66a96
Is there a reason ?
How can I detect that a raster laye
Hi Devs,
after last PSC meeting we decided to go to Vienna for the next QGIS
Hackfest.
This makes it possible for QGIS devs to spar a little with the Osgeo
C-tribe devs, because Stephan is organizing an Osgeo Code sprint there.
Because there is already an osgeo wiki page [0] we decided to not cr
What is map x/y? Do you mean projected coordinates or screen/print
coordinates?
Is this a question within the QGIS API context?
giovanni
Il 14/dic/2013 12:56 "SIVA RAMA KRISHNA" ha
scritto:
> Hello,
>
> I have a query related to conversion between lat long to map x map y
>
> I have a *lat ,lon
Dear Siva,
try proj.4 api
http://trac.osgeo.org/proj/wiki/ProjAPI
Regards,
Zoltan
On Sat, 14 Dec 2013, SIVA RAMA KRISHNA wrote:
Hello,
I have a query related to conversion between lat long to map x map y
I have a *lat ,lon *point with projection system and I wanted to know the*
map x map y
Hello,
I have a query related to conversion between lat long to map x map y
I have a *lat ,lon *point with projection system and I wanted to know the*
map x map y *so that i can map on the map
I am working in c++
Any help in this context will be highly appreciated
Thanks in advance to all
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