Re: [Qgis-user] How to use a vat.dbf with tif in QGIS?

[Albin Blaschka]

Am 20.02.2015 um 09:13 schrieb Albin Blaschka:

Hello List,

I have a geotiff raster [1] with an associated vat.dbf - file containing
the legend for the unique values of the raster.  Now, I would like to
use this information to style the raster in QGIS, but did not find a way...

Has anyone experience with such a file (vat.dbf) in QGIS or better found
a way to use it? Other tools like grass or command-line tools are also ok.
I googled around, but I am stuck...

As anybody a hint or push in the right direction?

Thanks in advance,
Albin

[1] http://rmgsc.cr.usgs.gov/outgoing/ecosystems/Global/



Hello,

so, in the meantime after excessive googling and much trial and error, I 
found (hopefully) the solution by myself :-)


https://pvanb.wordpress.com/2014/02/05/creating-a-qgis-color-map-from-text-file/

Not tested yet...

Albin


--
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| Etrichstrasse 26, A-5020 Salzburg
| * www.albinblaschka.info *
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[Qgis-user] How evaluate a string as an expression in expression builder

[Alexandre Neto]

Hello all,

Does any one know how if it's possible to evaluate an all string as an
expression in expression builder.

What I'm aiming to be able to do is to dynamicly create expression based on
other fields. So Imagine I have attribute with a string like this:

'field_1 = 20'

Is there a way to evaluate this as an conditional expression?

Thanks,

Alexandre Neto
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[Qgis-user] Re : How evaluate a string as an expression in expression builder

[Junior]

Hi,
Can't this be done with the simple use of case when condition? Something like:
CASE WHEN field_1= 20 THEN 'something True' ELSE 'something false' END

Envoyé depuis mon HTC

- Reply message -
De : Enrico Ferreguti enrico...@gmail.com
Pour : Alexandre Neto senhor.n...@gmail.com
Cc : QGIS User qgis-user@lists.osgeo.org
Objet : [Qgis-user] How evaluate a string as an expression in expression builder
Date : jeu., févr. 26, 2015 15:52

I developed a plugin called refFunctions v1.0 that extends expressions with a 
new group of functions.
In Expression calculator, under the group 'Reference' you will find a function 
called dbquery(targetLayer,targetField,whereClause)


It was developed keeping in mind the reference to other layers, but I think you 
can use it with the same layer. 

You can pass the field containing conditional expression in whereClause 
parameter and retrieve the same field used in where clause. 
I you get NULL the test is false otherwise is true.


for example (with field condition containing 'testField = 1'):


CASE
WHEN dbquery('samelayer','testFiled',condition) = NULL THEN 0

ELSE 1

END



Pay attention to quotes!




Here is the description:

dbquery function

Retrieve first targetField value from targetLayer when whereClause is true 
Syntax 
dbquery(targetLayer,targetField,whereClause) 
Arguments 
targetLayer → the name of a currently loaded layer, for example 'myLayer'.
targetLayer → a field of targetLayer whom value is needed, for example 
'myField'. In case of multiple results only the first is retrieved. If 
targetLayer = '$geometry' geometry value is retrieved 
whereClause → a valid expression string without duoble quotes to identify 
fields, for example 'field1  1 and field2 = foo' 

Example 
dbquery('myLayer','myField','field1  1 and field2 = foo') 
dbquery('myLayer','$geometry','field1  1 and field2 = foo') 






2015-02-26 14:00 GMT+01:00 Alexandre Neto senhor.n...@gmail.com:
Hello all,
Does any one know how if it's possible to evaluate an all string as an 
expression in expression builder.

What I'm aiming to be able to do is to dynamicly create expression based on 
other fields. So Imagine I have attribute with a string like this:

'field_1 = 20'

Is there a way to evaluate this as an conditional expression?

Thanks,

Alexandre Neto


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[Qgis-user] No module namede zope.interface

[Ventura Bartolomeo]

Hi all,
I'm trying to install the GEarthView plugin but I got the error:

The plugin is broken. Python said:
No module named zope.interface

I tried to install different version of zope.interface lib and also the Twisted 
lib (as suggested in some posts  around the web) but without success.

Could you please tell me if there is any work around to this problem?

Thanks in advance

Regards,

Bart

_ _

Dr. Ventura Bartolomeo
Institute for Applied Remote Sensing
Technology for Environmental Monitoring

EURAC research
Viale Druso 1, I-39100 Bolzano, Italy
t +39 0471 055 374
f +39 0471 055 389
bartolomeo.vent...@eurac.edumailto:bartolomeo.vent...@eurac.edu
www.eurac.eduhttp://www.eurac.edu/

This transmission is intended only for the use of the addressee and may contain 
confidential or legally privileged information.
If you receive this transmission by error, please notify the author immediately 
by mail and delete all copies of this transmission and any attachments.
Any use or dissemination of this communication is strictly prohibited by the 
Privacy-Code, D.Lgs. 196/2003 and may lead to penal prosecution and liability 
for damages.
P Think before you print

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Re: [Qgis-user] How evaluate a string as an expression in expression builder

[Enrico Ferreguti]

I developed a plugin called refFunctions v1.0
http://geogear.wordpress.com/2014/11/13/reffunctions-v1-0/ that extends
expressions with a new group of functions.
In Expression calculator, under the group 'Reference' you will find a
function called dbquery(targetLayer,targetField,whereClause)
It was developed keeping in mind the reference to other layers, but I think
you can use it with the same layer.
You can pass the field containing conditional expression in whereClause
parameter and retrieve the same field used in where clause.
I you get NULL the test is false otherwise is true.

for example (with field condition containing 'testField = 1'):

CASE
WHEN dbquery('samelayer','testFiled',condition) = NULL THEN 0
ELSE 1
END

Pay attention to quotes!


Here is the description:

dbquery function


Retrieve first targetField value from targetLayer when whereClause is true

Syntax

dbquery(targetLayer,targetField,whereClause)

Arguments

targetLayer → the name of a currently loaded layer, for example 'myLayer'.
targetLayer → a field of targetLayer whom value is needed, for example
'myField'. In case of multiple results only the first is retrieved. If
targetLayer = '$geometry' geometry value is retrieved
whereClause → a valid expression string without duoble quotes to identify
fields, for example 'field1  1 and field2 = foo'

Example

dbquery('myLayer','myField','field1  1 and field2 = foo')
dbquery('myLayer','$geometry','field1  1 and field2 = foo')





2015-02-26 14:00 GMT+01:00 Alexandre Neto senhor.n...@gmail.com:

 Hello all,

 Does any one know how if it's possible to evaluate an all string as an
 expression in expression builder.

 What I'm aiming to be able to do is to dynamicly create expression based
 on other fields. So Imagine I have attribute with a string like this:

 'field_1 = 20'

 Is there a way to evaluate this as an conditional expression?

 Thanks,

 Alexandre Neto

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Re: [Qgis-user] print composer and atlas feature on large dataset

[Alexandre Neto]

Hello matteo,

Can you send me a sample you your dataset, so I can do some tests?

thanks,

Alexandre Neto,

PS: I will only be able to work on a proper solution tomorrow, I will leave
a partial answer on gis.stackexchange meanwhile.

On Thu, Feb 26, 2015 at 10:46 AM, Matteo Ghetta matteo.ghe...@gmail.com
wrote:

 Thanks! :)
 I hope you'll get an answer..

 please tell me if you need a subset of my data..

 Cheers

 Mattep

 2015-02-26 11:14 GMT+01:00 Alexandre Neto senhor.n...@gmail.com:

 Nice challenge!

 I will try to think of a good answer.

 Alexandre Neto

 On Thu, Feb 26, 2015 at 9:55 AM, Matteo Ghetta matteo.ghe...@gmail.com
 wrote:

 Hi guys,
 I raised up this question on stackoverflow some times ago, but no answer
 yet, maybe someone can help me..


 http://gis.stackexchange.com/questions/135834/print-composer-and-atlas-feature-on-large-dataset

 does somebody ever had a similar problem?

 Basically the question is if one can use the atlas in order to print
 several layout depending on different styles (categorization based on
 different attributes) of a layer..

 Thanks!

 Matteo

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[Qgis-user] print composer and atlas feature on large dataset

[Matteo Ghetta]

Hi guys,
I raised up this question on stackoverflow some times ago, but no answer
yet, maybe someone can help me..

http://gis.stackexchange.com/questions/135834/print-composer-and-atlas-feature-on-large-dataset

does somebody ever had a similar problem?

Basically the question is if one can use the atlas in order to print
several layout depending on different styles (categorization based on
different attributes) of a layer..

Thanks!

Matteo
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Re: [Qgis-user] print composer and atlas feature on large dataset

[Alexandre Neto]

Nice challenge!

I will try to think of a good answer.

Alexandre Neto

On Thu, Feb 26, 2015 at 9:55 AM, Matteo Ghetta matteo.ghe...@gmail.com
wrote:

 Hi guys,
 I raised up this question on stackoverflow some times ago, but no answer
 yet, maybe someone can help me..


 http://gis.stackexchange.com/questions/135834/print-composer-and-atlas-feature-on-large-dataset

 does somebody ever had a similar problem?

 Basically the question is if one can use the atlas in order to print
 several layout depending on different styles (categorization based on
 different attributes) of a layer..

 Thanks!

 Matteo

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[Qgis-user] QGIS 2.6.1 on Centos 6.5

[Paolo Corti]

Hi all

I would need to have QGIS 2.6.1 working in Centos 6.5, and I am trying
to build it, but I am struggling at the same point hit by other users
with Debian 6 [1]:

[clipped]
[  8%] Building CXX object
src/core/CMakeFiles/qgis_core.dir/qgsvectorlayerfeatureiterator.cpp.o
/home/test/software/qgis/QGIS/src/core/qgsvectorlayerfeatureiterator.cpp:
In constructor 
‘QgsVectorLayerFeatureIterator::QgsVectorLayerFeatureIterator(QgsVectorLayerFeatureSource*,
bool, const QgsFeatureRequest)’:
/home/test/software/qgis/QGIS/src/core/qgsvectorlayerfeatureiterator.cpp:87:
error: class ‘QgsVectorLayerFeatureIterator’ does not have any field
named ‘QgsAbstractFeatureIteratorFromSource’
/home/test/software/qgis/QGIS/src/core/qgsvectorlayerfeatureiterator.cpp:88:
error: no matching function for call to
‘QgsAbstractFeatureIteratorFromSourceQgsVectorLayerFeatureSource::QgsAbstractFeatureIteratorFromSource()’
/home/test/software/qgis/QGIS/src/core/qgsfeatureiterator.h:113: note:
candidates are: QgsAbstractFeatureIteratorFromSource
template-parameter-1-1 ::QgsAbstractFeatureIteratorFromSource(T*,
bool, const QgsFeatureRequest) [with T = QgsVectorLayerFeatureSource]
/home/test/software/qgis/QGIS/src/core/qgsfeatureiterator.h:111: note:

QgsAbstractFeatureIteratorFromSourceQgsVectorLayerFeatureSource::QgsAbstractFeatureIteratorFromSource(const
QgsAbstractFeatureIteratorFromSourceQgsVectorLayerFeatureSource)
/home/test/software/qgis/QGIS/src/core/qgsvectorlayerfeatureiterator.cpp:
At global scope:
/home/test/software/qgis/QGIS/src/core/qgsvectorlayerfeatureiterator.cpp:521:
warning: unused parameter ‘methodType’

I have upgraded gcc to 4.7.2 version, but still no joy here.

Some more information on the non standard Centos 6.5 dependencies 9
(compiled from sources) I am using:

QT 4.7.2
SIP 4.13.3
PyQT 4.9.4
QScintilla 2.8.4
GDAL 1.11.2

Anyone can give a good recommendation about what is the cleanest way
to build on Centos 6.5?
Are you aware of any package created for it even only for test?

thanks a lot
p

[1] 
http://osgeo-org.1560.x6.nabble.com/Compiling-QGIS-2-4-with-GCC-4-4-debian-squeeze-td5146777.html

-- 
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Geospatial software developer
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twitter: @capooti
skype: capooti
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Re: [Qgis-user] print composer and atlas feature on large dataset

[Matteo Ghetta]

Thanks! :)
I hope you'll get an answer..

please tell me if you need a subset of my data..

Cheers

Mattep

2015-02-26 11:14 GMT+01:00 Alexandre Neto senhor.n...@gmail.com:

 Nice challenge!

 I will try to think of a good answer.

 Alexandre Neto

 On Thu, Feb 26, 2015 at 9:55 AM, Matteo Ghetta matteo.ghe...@gmail.com
 wrote:

 Hi guys,
 I raised up this question on stackoverflow some times ago, but no answer
 yet, maybe someone can help me..


 http://gis.stackexchange.com/questions/135834/print-composer-and-atlas-feature-on-large-dataset

 does somebody ever had a similar problem?

 Basically the question is if one can use the atlas in order to print
 several layout depending on different styles (categorization based on
 different attributes) of a layer..

 Thanks!

 Matteo

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Re: [Qgis-user] How can I attach a label to precede an attribute value?

[Joey Wang]

Hi Goyo,Thank you VERY MUCH for the answer to my question.  I have used it and 
it worked.  I'm very new to QGIS, so I'm still in the learning process.  Part 
of the problem for me was that I was searching the user manual, but not 
searching in the right place!!
Thank you again
joey
  From: Goyo goyod...@gmail.com
 To: Joey Wang joey.wan...@yahoo.com 
Cc: qgis-user@lists.osgeo.org qgis-user@lists.osgeo.org 
 Sent: Wednesday, February 25, 2015 3:11 PM
 Subject: Re: [Qgis-user] How can I attach a label to precede an attribute 
value?
   
In the expression editor:

'System A: '||System A||' System B: '||System B

http://docs.qgis.org/testing/en/docs/user_manual/working_with_vector/vector_properties.html#labeling-with-expressions

Regards

Goyo



2015-02-24 21:27 GMT+01:00 Joey Wang joey.wan...@yahoo.com:
 Hello,
 I am currently running QGIS 2.6.1-Brighton on a Mac Air, and I am having a
 difficult time figuring out how to attach a label to an attribute value at a
 geographic point.  For example, for a geographic location I have a value for
 System A, and a value for System B.  How do I actually create the label for
 each geographic location so that at every location it shows (for example)
 System A: 15  System B: 7 rather than just the values themselves (for
 example) 15  7.

 Thanks very much!!
 joey wang

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Re: [Qgis-user] raster calculator - no file produced

[Pedro Venâncio]

This is already fixed (tested on master) and backported to 2.8.

https://github.com/qgis/QGIS/commit/0ccc07af0eacd56986fbf01418aa6d3a701e231e

Thanks Jurgen!

Pedro



2015-02-23 16:47 GMT+00:00 Pedro Venâncio pedrongvenan...@gmail.com:

 Same test on Windows produces a raster file with all pixel values zero,
 like Anita.


 - Metadata:

 Driver
 GDAL provider
 GTiff
 GeoTIFF
 Dataset Description
 D:\Testes\mdt.tif
 AREA_OR_POINT=Area
 Band 1
 STATISTICS_MAXIMUM=0
 STATISTICS_MEAN=0
 STATISTICS_MINIMUM=0
 STATISTICS_STDDEV=0
 Dimensions
 X: 2896 Y: 1870 Bands: 1
 Origin
 50410.2,147300
 Pixel Size
 24.9975,-24.9975
 No Data Value
 *NoDataValue not set*
 Data Type
 Float32 - Thirty two bit floating point
 Pyramid overviews
 Layer Spatial Reference System
 +proj=tmerc +lat_0=39.668258 +lon_0=-8.1331084 +k=1 +x_0=0
 +y_0=0 +ellps=GRS80 +towgs84=0,0,0,0,0,0,0 +units=m +no_defs
 Layer Extent (layer original source projection)
 50410.245009987287,100555.123890025751 :
 122802.919680063377,147300.393790018999
 Band
 Band 1
 Band No
 1
 No Stats
 No stats collected yet


 - gdalinfo:

 Algorithm Information starting...
 GDAL command:
 gdalinfo D:\Testes\mdt.tif
 GDAL command output:
 Driver: GTiff/GeoTIFF
 Files: D:\Testes\mdt.tif
 Size is 2896, 1870
 Coordinate System is:
 PROJCS[ETRS89 / Portugal TM06,
 GEOGCS[ETRS89,
 DATUM[European_Terrestrial_Reference_System_1989,
 SPHEROID[GRS 1980,6378137,298.2572221010002,
 AUTHORITY[EPSG,7019]],
 TOWGS84[0,0,0,0,0,0,0],
 AUTHORITY[EPSG,6258]],
 PRIMEM[Greenwich,0],
 UNIT[degree,0.0174532925199433],
 AUTHORITY[EPSG,4258]],
 PROJECTION[Transverse_Mercator],
 PARAMETER[latitude_of_origin,39.668258],
 PARAMETER[central_meridian,-8.1331084],
 PARAMETER[scale_factor,1],
 PARAMETER[false_easting,0],
 PARAMETER[false_northing,0],
 UNIT[metre,1,
 AUTHORITY[EPSG,9001]],
 AUTHORITY[EPSG,3763]]
 Origin = (50410.24500999000,147300.3937900)
 Pixel Size = (24.997470535220998,-24.997470534759358)
 Metadata:
 AREA_OR_POINT=Area
 Image Structure Metadata:
 INTERLEAVE=BAND
 Corner Coordinates:
 Upper Left ( 50410.245, 147300.394) ( 7d32' 2.45W, 40d59'35.67N)
 Lower Left ( 50410.245, 100555.124) ( 7d32'16.02W, 40d34'20.37N)
 Upper Right ( 122802.920, 147300.394) ( 6d40'25.89W, 40d59' 8.02N)
 Lower Right ( 122802.920, 100555.124) ( 6d40'58.94W, 40d33'53.13N)
 Center ( 86606.582, 123927.759) ( 7d 6'25.74W, 40d46'47.18N)
 Band 1 Block=2896x1 Type=Float32, ColorInterp=Gray



 Pedro

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Re: [Qgis-user] Trouble projecting on the fly

[Sharon Selvaggio]

Still struggling I am attaching the info from the prj file and the 
extent info from the metadata for each shapefile:


I noticed that the PROJCS is labeled as Custom...could that be 
confusing QGIS?


Or is it because one is a projected CRS and one is a geographic CRS?

*_or_state_boundary.prj_*
PROJCS[Custom,
GEOGCS[GCS_North_American_1983,
DATUM[D_North_American_1983,
SPHEROID[GRS_1980,6378137.0,298.257222101]],
PRIMEM[Greenwich,0.0],
UNIT[Degree,0.0174532925199433]],
PROJECTION[Lambert_Conformal_Conic],
PARAMETER[False_Easting,1312335.958],
PARAMETER[False_Northing,0.0],
PARAMETER[Central_Meridian,-120.5],
PARAMETER[Standard_Parallel_1,43.0],
PARAMETER[Standard_Parallel_2,45.5],
PARAMETER[Central_Parallel,41.75],
UNIT[Foot,0.3048]]

xMin,yMin 183871.74,88600.9 : xMax,yMax 2345213.24,1675042.97



*_CKUWR.prj_*
GEOGCS[GCS_North_American_1983,
DATUM[D_North_American_1983,
SPHEROID[GRS_1980,6378137.0,298.257222101]],
PRIMEM[Greenwich,0.0],
UNIT[Degree,0.0174532925199433]]

xMin,yMin -123.522,43.356 : xMax,yMax -121.714,45.4562


Help very much appreciated.



On 02/24/2015 07:26 AM, Andre Joost wrote:

Am 24.02.2015 um 07:55 schrieb Ramon Andiñach:


On 24 Feb 2015, at 14:06, Sharon Selvaggio

I start by setting my project CRS.


And make sure OTF is on.


You have no choice of setting a project CRS if OTF is off.




But when I do this with files that have originated from two
different sources with different native projections (or no
projection?) they still do not align.


Different sources or different layer CRS shouldn't matter.


Shapefiles without .prj file are still existing in the world.




There is an option mentioned previously so that you can set how QGIS
handles layers that it can't tell what the CRS is.


Settings - Options, CRS Tab, CRS foor new layers.



If you can point us at the files you're using - or excerpts from them
- then we might be able to understand where the problem is better.


Or tell us the extent of every layer, as reported by Rightclick - 
Properties, metadata tab.




1. On a side note. Do not use the Google maps/satellite images to
check if your layers are in the right place unless you understand the
gotchas in using that service.



I don't agree with that.
If some layers come up on the wrong part of the Earth, it is a good 
reference to see which layers are right and which are wrong.


Natural Earth shapefiles can be a reference as well.

Greetings,
André Joost


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