On 27/11/10 17:53, Tobias Fröschle wrote:
>> Puts() needs #include or at least defining correctly!
> It should, for the sake of art, but doesn't need to.
Hmm. Not declaring a function, even one returning int (the default
return type) is listed in my book of common C mistakes.
>> Main() always re
Marcel Kilgus wrote, on 28/Nov/10 16:02 | Nov28:
Laurence Reeves wrote:
1PRINT CHR$(RND(TO 255)):GO TO 1
Great thought in the spirit of Tony's cheating :-)
But there's always room for optimizations:
1REP:BPUT RND(90)
Will probably also need a few thousand years less! :-)
He he - infinite
Laurence Reeves wrote:
> 1PRINT CHR$(RND(TO 255)):GO TO 1
Great thought in the spirit of Tony's cheating :-)
But there's always room for optimizations:
1REP:BPUT RND(90)
Will probably also need a few thousand years less! :-)
Marcel
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On 28 Nov 2010, at 14:51, Laurence Reeves wrote:
> Tony Firshman wrote:
>> Marcel Kilgus wrote, on 26/Nov/10 17:02 | Nov26:
>>> Marcel Kilgus wrote:
1for i=1to 100
2a$="":if i mod 3=0:a$="FIZZ"
3if i mod 5=0:a$=a$&"BUZZ"
4print i,a$:next i
(91 bytes including 4 LF)
Tony Firshman wrote:
Marcel Kilgus wrote, on 26/Nov/10 17:02 | Nov26:
Marcel Kilgus wrote:
1for i=1to 100
2a$="":if i mod 3=0:a$="FIZZ"
3if i mod 5=0:a$=a$&"BUZZ"
4print i,a$:next i
(91 bytes including 4 LF)
Damn, missed something:
1for i=1to 100
2a$="":if i mod 3=0:a$="FIZZ"
3if i mod 5=0:
gdgqler wrote:
> Another 1988 winning entry was as follows according to Peter van der Linden.
Though one must say that these programs are usually not written this
way, they're written more readable and obfuscated afterwards,
sometimes even using specialized obfuscation programs.
In any case, here
On 27 Nov 2010, at 18:16, Marcel Kilgus wrote:
> Norman Dunbar wrote:
>> Main() always returns int.
>
> True.
>
>> Main always takes two parameters int and char **.
>
> Not true, "int main(void)" is valid according to C99 spec (see chapter
> 5.1.2.2.1 ;-) )
>
> But in context of the IOCC con
Marcel Kilgus wrote, on 27/Nov/10 18:16 | Nov27:
Norman Dunbar wrote:
Main() always returns int.
True.
Main always takes two parameters int and char **.
Not true, "int main(void)" is valid according to C99 spec (see chapter
5.1.2.2.1 ;-) )
But in context of the IOCC contest Tobias referr
Norman Dunbar wrote:
> Main() always returns int.
True.
> Main always takes two parameters int and char **.
Not true, "int main(void)" is valid according to C99 spec (see chapter
5.1.2.2.1 ;-) )
But in context of the IOCC contest Tobias referred to, basically
everything that compiles is valid
Am 27.11.2010 15:48, schrieb Norman Dunbar:
On 26/11/10 21:48, Tobias Fröschle wrote:
main(){for(;;i++){puts(!i%3)?"FIZZ":(!(i%5)?"BUZZ":""));}}
Error!
Warning!
Puts() needs #include or at least defining correctly!
It should, for the sake of art, but doesn't need to.
Main() always returns
On 27 Nov 2010, at 13:25, Norman Dunbar wrote:
>> This meets all Rich's requirements:
>> --
>> The rules are simple -
>> write out the values 1 to 100 on screen
>> If the value is divisible by 3 write 'FIZZ' after the number
>> If the value is divisible by 5 write 'BUZZ' after the number
On 26/11/10 21:48, Tobias Fröschle wrote:
> main(){for(;;i++){puts(!i%3)?"FIZZ":(!(i%5)?"BUZZ":""));}}
Error!
Puts() needs #include or at least defining correctly!
Main() always returns int.
Main always takes two parameters int and char **.
Your main() function doesn't return a value.
The corre
> This meets all Rich's requirements:
> --
> The rules are simple -
> write out the values 1 to 100 on screen
> If the value is divisible by 3 write 'FIZZ' after the number
> If the value is divisible by 5 write 'BUZZ' after the number
> If the value is divisible by 3 and 5 write 'FIZZBUZZ'
En/Je/On 2010-11-27 02:32, Marcel Kilgus escribió / skribis / wrote :
> > 1for i=1to 100:print i!"FIZZ"(to 4*not i mod 3);"BUZZ"(to 4*not i mod 5)
> This is pure awesomeness, I wish I had thought of that!
It's "Forthness" :-) I'm used to "think in Forth" in any other programming
language.
> But
Marcos Cruz wrote:
> 1for i=1to 100:print i!"FIZZ"(to 4*not i mod 3);"BUZZ"(to 4*not i mod 5)
>
> (73 bytes including LF).
This is pure awesomeness, I wish I had thought of that!
But now that I've seen this trick, I hereby steal it and improve it to
1FOR i=1TO 100:PRINT i!"FIZZBUZZ"(1+4*(i MOD 3
Marcos Cruz wrote:
En/Je/On 2010-11-26 17:17, P Witte escribió / skribis / wrote :
The rules are simple -
write out the values 1 to 100 on screen
If the value is divisble by 3 write 'FIZZ' after the number
If the value is divisble by 5 write 'BUZZ' after the number
If the value is divisble by 3
En/Je/On 2010-11-26 17:17, P Witte escribió / skribis / wrote :
>> The rules are simple -
>> write out the values 1 to 100 on screen
>> If the value is divisble by 3 write 'FIZZ' after the number
>> If the value is divisble by 5 write 'BUZZ' after the number
>> If the value is divisble by 3 and 5
Am 26.11.2010 20:41, schrieb Tony Firshman:
P Witte wrote, on 26/Nov/10 19:34 | Nov26:
Marcel Kilgus wrote:
Tony Firshman wrote:
I obeyed the rules (8-)#
Maybe, but that is more creativity in applying the rules than
creativity in programming. You clearly have chosen the wrong career,
you sho
P Witte wrote, on 26/Nov/10 19:34 | Nov26:
Marcel Kilgus wrote:
Tony Firshman wrote:
I obeyed the rules (8-)#
Maybe, but that is more creativity in applying the rules than
creativity in programming. You clearly have chosen the wrong career,
you should have been a lawyer ;)
... and there is
Marcel Kilgus wrote:
Tony Firshman wrote:
I obeyed the rules (8-)#
Maybe, but that is more creativity in applying the rules than
creativity in programming. You clearly have chosen the wrong career,
you should have been a lawyer ;)
... and there is nothing to say the program has to
Cheater! ;-) Also, one can only run your program once.
This meets all Rich's requirements:
--
The rules are simple -
write out the values 1 to 100 on screen
If the value is divisible by 3 write 'FIZZ' after the number
If the value is divisible by 5 write 'BUZZ' after the number
If the va
Marcel Kilgus wrote, on 26/Nov/10 18:48 | Nov26:
Tony Firshman wrote:
I obeyed the rules (8-)#
Maybe, but that is more creativity in applying the rules than
creativity in programming. You clearly have chosen the wrong career,
you should have been a lawyer ;)
... and there is nothing to say t
Tony Firshman wrote:
> I obeyed the rules (8-)#
Maybe, but that is more creativity in applying the rules than
creativity in programming. You clearly have chosen the wrong career,
you should have been a lawyer ;)
> ... and there is nothing to say the program has to be run more than once.
> I did c
Marcel Kilgus wrote, on 26/Nov/10 18:09 | Nov26:
Tony Firshman wrote:
and CTRL SPACE after 100.
Cheater! ;-) Also, one can only run your program once.
This meets all Rich's requirements:
--
The rules are simple -
write out the values 1 to 100 on screen
If the value is divisible by 3
Tony Firshman wrote:
> and CTRL SPACE after 100.
Cheater! ;-) Also, one can only run your program once.
> This meets all Rich's requirements:
> --
> The rules are simple -
> write out the values 1 to 100 on screen
> If the value is divisible by 3 write 'FIZZ' after the number
> If the val
Marcel Kilgus wrote, on 26/Nov/10 17:02 | Nov26:
Marcel Kilgus wrote:
1for i=1to 100
2a$="":if i mod 3=0:a$="FIZZ"
3if i mod 5=0:a$=a$&"BUZZ"
4print i,a$:next i
(91 bytes including 4 LF)
Damn, missed something:
1for i=1to 100
2a$="":if i mod 3=0:a$="FIZZ"
3if i mod 5=0:a$=a$&"BUZZ"
4print i,
Marcel Kilgus wrote:
> 1for i=1to 100
> 2a$="":if i mod 3=0:a$="FIZZ"
> 3if i mod 5=0:a$=a$&"BUZZ"
> 4print i,a$:next i
>
> (91 bytes including 4 LF)
Damn, missed something:
1for i=1to 100
2a$="":if i mod 3=0:a$="FIZZ"
3if i mod 5=0:a$=a$&"BUZZ"
4print i,a$:next
(89 bytes including 4 LF)
Marcel
P Witte wrote:
> Just had another look: Is this the shortest possible version?
>
> 1defproc z:if i mod 3=0:print'FIZZ';:endif:if i mod
> 5=0:print'BUZZ';:endif:print:enddef:for i=1to 100:print i,:z:endfor i
>
> Thats all one line. It should result in a file of 122b including eol.
> Once LOADed it
Rich Mellor wrote:
I was just reading that 99/100 job applicants for programming jobs
apparently cannot write a short "fizzbuzz" program when given 10 minutes
to do so in an interview.
The rules are simple -
write out the values 1 to 100 on screen
If the value is divisble by 3 write 'FIZZ' a
gdgqler wrote:
On 4 Nov 2010, at 12:20, Dilwyn Jones wrote:
Norman Dunbar Does It In Assembler
George Gwilt Does It Turbo-Charged
Tony Firshman Does It In Pearl(s)
Now all I need is one for Rich Mellor, which I failed to provide, possibly
something like Rich Mellor Does It With Second User H
Dilwyn Jones wrote:
<>
Now, if you want something to puzzle with, try my little pointer driven
puzzle program at http://www.dilwyn.me.uk/games/djpuzzle.zip
Nice one, Dilwyn ;o)
Per
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http://www.q-v-d.demon.co.uk/smsqe.htm
On 4 Nov 2010, at 13:42, Dilwyn Jones wrote:
>>> Norman Dunbar Does It In Assembler
>>> George Gwilt Does It Turbo-Charged
>>> Tony Firshman Does It In Pearl(s)
>>>
>>> Now all I need is one for Rich Mellor, which I failed to provide, possibly
>>> something like Rich Mellor Does It With Second
Norman Dunbar Does It In Assembler
George Gwilt Does It Turbo-Charged
Tony Firshman Does It In Pearl(s)
Now all I need is one for Rich Mellor, which I failed to provide,
possibly something like Rich Mellor Does It With Second User
Hardware, but I thought that was too rude ;-)
Now, if you want
On 4 Nov 2010, at 12:20, Dilwyn Jones wrote:
>
> Norman Dunbar Does It In Assembler
> George Gwilt Does It Turbo-Charged
> Tony Firshman Does It In Pearl(s)
>
> Now all I need is one for Rich Mellor, which I failed to provide, possibly
> something like Rich Mellor Does It With Second User Hard
My S*BASIC program is:
10 CLS:FOR x=1 to 100:PRINT
x&isit$(3,"FIZZ")&isit$(5,"BUZZ"):PAUSE 5
20 DEFine FuNction isit$(m%,a$)
30 IF (x MOD m%):RETRurn "":ELSE:RETurn a$
40 END vDEFine
This will work better if you replace RETRurn by RETurn (which is
what I had in the QPC2 program).
(8-)#
V
On 4 Nov 2010, at 11:05, Tony Firshman wrote:
> gdgqler wrote, on 04/11/2010 10:52:
>>
>> On 4 Nov 2010, at 10:44, gdgqler wrote:
>>
>>> My S*BASIC program is:
>>>
>>> 10 CLS:FOR x=1 to 100:PRINT x&isit$(3,"FIZZ")&isit$(5,"BUZZ"):PAUSE 5
>>> 20 DEFine FuNction isit$(m%,a$)
>>> 30 IF (x MOD m%
gdgqler wrote, on 04/11/2010 10:52:
On 4 Nov 2010, at 10:44, gdgqler wrote:
My S*BASIC program is:
10 CLS:FOR x=1 to 100:PRINT x&isit$(3,"FIZZ")&isit$(5,"BUZZ"):PAUSE 5
20 DEFine FuNction isit$(m%,a$)
30 IF (x MOD m%):RETRurn "":ELSE:RETurn a$
40 END vDEFine
This will work better if you r
On 4 Nov 2010, at 10:44, gdgqler wrote:
> My S*BASIC program is:
>
> 10 CLS:FOR x=1 to 100:PRINT x&isit$(3,"FIZZ")&isit$(5,"BUZZ"):PAUSE 5
> 20 DEFine FuNction isit$(m%,a$)
> 30 IF (x MOD m%):RETRurn "":ELSE:RETurn a$
> 40 END vDEFine
>
This will work better if you replace RETRurn by RETurn (
On 2 Nov 2010, at 11:23, Tony Firshman wrote:
>
> sB is my limit (8-)# I would love to see Laurence Reeves' version. He was
> always looking for how to reduce code. He, for instance, did a *very* tiny
> Forth for the QL.
> There were loads of examples in Hermes and (especially) superHermes
On 3 Nov 2010, at 17:06, gdgqler wrote:
>
> This would take, I suppose, 3 minutes in S*BASIC.
>
My S*BASIC program is:
10 CLS:FOR x=1 to 100:PRINT x&isit$(3,"FIZZ")&isit$(5,"BUZZ"):PAUSE 5
20 DEFine FuNction isit$(m%,a$)
30 IF (x MOD m%):RETRurn "":ELSE:RETurn a$
40 END vDEFine
This must t
Rich Mellor wrote, on 03/11/2010 20:47:
By the way Tony,
Have you built a time machine in one of your sheds? Just your
messages seem to be sent a whole day before the message they are
responding to!
I am using a spare laptop that has a dead bios battery!
Tony
--
QBBS (QL fido BBS 2:25
On 02/11/2010 18:22, Tony Firshman wrote:
Rich Mellor wrote, on 03/11/2010 17:49:
On 02/11/2010 17:34, Tony Firshman wrote:
10 FOR j = 1 TO 100
15 sp$ = " ";
20 PRINT j;
20 if j/3 == int(j/3)
25 sp$="";
30 PRINT " FIZZ";
40 END IF
30 IF j/5 == int(j/5)
40 PRINT sp$&"BUZZ";
50 END IF
60 PRINT
7
Rich Mellor wrote, on 03/11/2010 17:49:
On 02/11/2010 17:34, Tony Firshman wrote:
10 FOR j = 1 TO 100
15 sp$ = " ";
20 PRINT j;
20 if j/3 == int(j/3)
25 sp$="";
30 PRINT " FIZZ";
40 END IF
30 IF j/5 == int(j/5)
40 PRINT sp$&"BUZZ";
50 END IF
60 PRINT
70 END FOR
Hi Tony,
Yes, you are going t
On 02/11/2010 17:34, Tony Firshman wrote:
10 FOR j = 1 TO 100
15 sp$ = " ";
20 PRINT j;
20 if j/3 == int(j/3)
25 sp$="";
30 PRINT " FIZZ";
40 END IF
30 IF j/5 == int(j/5)
40 PRINT sp$&"BUZZ";
50 END IF
60 PRINT
70 END FOR
Hi Tony,
Yes, you are going to confuse SB programmers with that one -
Rich Mellor wrote, on 02/11/2010 19:53:
I was just reading that 99/100 job applicants for programming jobs
apparently cannot write a short "fizzbuzz" program when given 10
minutes to do so in an interview.
The rules are simple -
write out the values 1 to 100 on screen
If the value is divisble
On 2 Nov 2010, at 19:53, Rich Mellor wrote:
> I was just reading that 99/100 job applicants for programming jobs apparently
> cannot write a short "fizzbuzz" program when given 10 minutes to do so in an
> interview.
>
> The rules are simple -
> write out the values 1 to 100 on screen
> If the
Rich Mellor wrote, on 02/11/2010 19:53:
I was just reading that 99/100 job applicants for programming jobs
apparently cannot write a short "fizzbuzz" program when given 10
minutes to do so in an interview.
The rules are simple -
write out the values 1 to 100 on screen
If the value is divisble
Evening Rich,
I would do something like the following, equally untested - assumes the
channel to the screen is open, etc.
Is it elegant? I don't know, probably not. Is it simple, yes. And no
messing with the arithmetic stack etc either, all done in integers.
begin equ 1
exitequ 101
io_sbyt
On 02/11/2010 20:45, P Witte wrote:
Rich Mellor wrote:
I was just reading that 99/100 job applicants for programming jobs
apparently cannot write a short "fizzbuzz" program when given 10
minutes to do so in an interview.
The rules are simple -
write out the values 1 to 100 on screen
If the
Rich Mellor wrote:
I was just reading that 99/100 job applicants for programming jobs
apparently cannot write a short "fizzbuzz" program when given 10 minutes
to do so in an interview.
The rules are simple -
write out the values 1 to 100 on screen
If the value is divisble by 3 write 'FIZZ' a
I was just reading that 99/100 job applicants for programming jobs
apparently cannot write a short "fizzbuzz" program when given 10 minutes
to do so in an interview.
The rules are simple -
write out the values 1 to 100 on screen
If the value is divisble by 3 write 'FIZZ' after the number
If the
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