On Wed, Feb 3, 2010 at 10:40 AM, Johannes Graumann
johannes_graum...@web.de wrote:
Hello,
I would like to organize the R directory in my home-grown package into
sub-directories, but R CMD --build doesn't seem to find *.R files below
the actual source directory. Is there any way around that?
Hi all,
Is there are reason that there is no c.factor method? Analogous to
c.Date, I'd expect something like the following to be useful:
c.factor - function(...) {
factors - list(...)
levels - unique(unlist(lapply(factors, levels)))
char - unlist(lapply(factors, as.character))
On Thu, 4 Feb 2010, Barry Rowlingson wrote:
On Wed, Feb 3, 2010 at 10:40 AM, Johannes Graumann
johannes_graum...@web.de wrote:
Hello,
I would like to organize the R directory in my home-grown package into
sub-directories, but R CMD --build doesn't seem to find *.R files below
the actual
On Thu, 4 Feb 2010, Hadley Wickham wrote:
Hi all,
Is there are reason that there is no c.factor method? Analogous to
c.Date, I'd expect something like the following to be useful:
c.factor - function(...) {
factors - list(...)
levels - unique(unlist(lapply(factors, levels)))
char -
Dear Thomas and Hadley,
I'd propose the following: If the sets of levels of all arguments are the
same, then c.factor() would return a factor with the common set of levels;
if the sets of levels differ, then, as Hadley suggests, the level-set of the
result would be the union of sets of levels of
The argument I have in 'The R Inferno'
is that how you want to combine factors
may differ from someone else's desires.
There are lots of tricky questions:
What about ordered factors?
What if the ordered levels are different in
different objects?
...
Pat
On 04/02/2010 15:53, Hadley Wickham
I'd propose the following: If the sets of levels of all arguments are the
same, then c.factor() would return a factor with the common set of levels;
if the sets of levels differ, then, as Hadley suggests, the level-set of the
result would be the union of sets of levels of the arguments, but a
On Thu, Feb 4, 2010 at 10:45 AM, Patrick Burns pbu...@pburns.seanet.com wrote:
The argument I have in 'The R Inferno'
is that how you want to combine factors
may differ from someone else's desires.
There are lots of tricky questions:
What about ordered factors?
What if the ordered levels
A search for c.factor returns tons of hits on this topic.
Heres just one of the hits from 2006, when I asked the same question :
http://tolstoy.newcastle.edu.au/R/e2/devel/06/11/1137.html
So it appears to be complicated and there are good reasons.
Since I needed it, I created c.factor in
On 2/3/2010 7:48 AM, Brian Diggs wrote:
On 2/1/2010 3:57 PM, Brian Diggs wrote:
The following code:
cut(as.POSIXct(2009-11-01 04:00:00, tz=America/Los_Angeles), 1 day)
gives the error:
Error in seq.int(0, to - from, by) : 'to' must be finite
[details deleted...]
Is there a
10 matches
Mail list logo