> Martin Maechler
> on Fri, 29 Apr 2011 16:25:09 +0200 writes:
> Paul Johnson
> on Thu, 28 Apr 2011 00:20:27 -0500 writes:
>> On Wed, Apr 27, 2011 at 12:44 PM, Patrick Burns
>> wrote:
>>> Here are some data frames:
>>>
>>> df3.2 <- data.frame(1:3, 7
On Fri, Apr 29, 2011 at 9:25 AM, Martin Maechler
wrote:
>> Paul Johnson
>> on Thu, 28 Apr 2011 00:20:27 -0500 writes:
>
> > On Wed, Apr 27, 2011 at 12:44 PM, Patrick Burns
> > wrote:
> >> Here are some data frames:
> >>
> >> df3.2 <- data.frame(1:3, 7:9)
> >> df4.2
I also favor deprecating mean.data.frame.
One possible exception would be for a single-column data frame.
But even here I'd say no, lest people expect the same behavior for
median, var, ...
Pat's suggestion of using stop() would work nicely for mean.
(but omit paste - stop handles that).
Tim Hes
If Martin's proposal is accepted, does
that mean that the median method for
data frames would be something like:
function (x, ...)
{
stop(paste("you probably mean to use the command: sapply(",
deparse(substitute(x)), ", median)", sep=""))
}
Pat
On 29/04/2011 15:25, Mart
> My personal oppinion is that mean.data.frame() should never have
> been written.
> People should know, or learn, to use apply functions for such a
> task.
>
> The unfortunate fact that mean.data.frame() exists makes people
> think that median.data.frame() should too,
> and then
>
> var.data.fra
> From: r-devel-boun...@r-project.org
> [mailto:r-devel-boun...@r-project.org] On Behalf Of Martin Maechler
> Sent: Friday, April 29, 2011 7:25 AM
> To: Paul Johnson
> Cc: r-devel
> Subject: Re: [Rd] median and data frames
> [ ... lots of lines elided ... ]
> My
> Paul Johnson
> on Thu, 28 Apr 2011 00:20:27 -0500 writes:
> On Wed, Apr 27, 2011 at 12:44 PM, Patrick Burns
> wrote:
>> Here are some data frames:
>>
>> df3.2 <- data.frame(1:3, 7:9)
>> df4.2 <- data.frame(1:4, 7:10)
>> df3.3 <- data.frame(1:3, 7:9, 10:
This seems trivially fixable using something like
median.data.frame <- function(x, na.rm=FALSE) {
sapply(x, function(y, na.rm=FALSE) if(is.factor(y)) NA else
median(y, na.rm=na.rm), na.rm=na.rm)
}
>>> Paul Johnson 28/04/2011 06:20 >>>
On Wed, Apr 27, 2011 at 12:44 PM, Patrick Burns
wrote:
>
On Wed, Apr 27, 2011 at 12:44 PM, Patrick Burns
wrote:
> Here are some data frames:
>
> df3.2 <- data.frame(1:3, 7:9)
> df4.2 <- data.frame(1:4, 7:10)
> df3.3 <- data.frame(1:3, 7:9, 10:12)
> df4.3 <- data.frame(1:4, 7:10, 10:13)
> df3.4 <- data.frame(1:3, 7:9, 10:12, 15:17)
> df4.4 <- data.frame(
On Apr 27, 2011, at 19:44 , Patrick Burns wrote:
> I would think a method in analogy to
> 'mean.data.frame' would be a logical choice.
> But I'm presuming there might be an argument
> against that or 'median.data.frame' would already
> exist.
Only if someone had a better plan. As you are probabl
Here are some data frames:
df3.2 <- data.frame(1:3, 7:9)
df4.2 <- data.frame(1:4, 7:10)
df3.3 <- data.frame(1:3, 7:9, 10:12)
df4.3 <- data.frame(1:4, 7:10, 10:13)
df3.4 <- data.frame(1:3, 7:9, 10:12, 15:17)
df4.4 <- data.frame(1:4, 7:10, 10:13, 15:18)
Now here are some commands and their answers
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