Jim Lemon wrote:
> Jan M. Wiener wrote:
>
>>hello,
>>I am trying to rescale a matrix according to one column in the matrix.
>>Imagine having two matrices with 2 columns each:
>>
>>mat1:
>>12.1
>>22.2
>>3 2.2
>>4 2.4
>>5 2.7
>>6 2.9
>>
>>mat2:
>>11.9
>>22.0
>>3 2.1
>
Thank you Bert, Marc, James
You have all pointed out that I can use xlim and ylim.
As Bert pointed out, the documentation is not as clear as it might be about
this. Perhaps the R development team would consider modifying the help page.
As Marc points out, the documentation does say that usr can
Jan M. Wiener wrote:
> hello,
> I am trying to rescale a matrix according to one column in the matrix.
> Imagine having two matrices with 2 columns each:
>
> mat1:
> 12.1
> 22.2
> 3 2.2
> 4 2.4
> 5 2.7
> 6 2.9
>
> mat2:
> 11.9
> 22.0
> 3 2.1
> 4 2.2
> 5 2.4
>
A little different solution, but it gives you the matches and the
columns in a more compact form. You can always take the data and use
it to put into your array.
> # creation of the data matrix
> c1<- c(1,4,3,2,4,1,3,2,4,3)
> c2<- c(2,4,3,4,4,3,4,1,3,2)
> c3<- c(1,3,2,4,4,3,4,4,2,2)
> c4<- c(2,3,
On 10/19/07, Allison Bailey <[EMAIL PROTECTED]> wrote:
> Thanks for the suggestions. The factor function on the RYEAR column worked
> well.
>
> I need to clarify my question about the order of the plot. as.table appears
> to be concerned with the order that each panel is plotted. Is that corr
Thanks for the suggestions. The factor function on the RYEAR column worked
well.
I need to clarify my question about the order of the plot. as.table appears
to be concerned with the order that each panel is plotted. Is that correct?
I'm interested in controlling the order of the elements on
On 10/19/07, HU,ZHENGJUN <[EMAIL PROTECTED]> wrote:
> Hi All,
>
> When I tried to catch a returned value from a R graphical
> function or command (e.g., plot, lines, points, abline, title,
> xyplot, etc.), I always get a NULL value if it is executed
> correctly. For example:
> x <- c(1,2,3,4,5,
Virus Folder Summary Digest for [EMAIL PROTECTED] sent on Friday, October 19,
2007
The emails listed below have been placed by MailMarshal in your Virus Folder.
They will be automatically deleted after 7 days.
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From:[E
What exactly are you trying to determine? You can look at the help
page for a function to see what, if any, value is returned.
If you are 'try'ing to catch an error, then the following might help:
> x <- plot(0)
> x
NULL
> x <- plot()
Error in plot() : argument "x" is missing, with no default
>
Hi All,
When I tried to catch a returned value from a R graphical
function or command (e.g., plot, lines, points, abline, title,
xyplot, etc.), I always get a NULL value if it is executed
correctly. For example:
x <- c(1,2,3,4,5,9,13,19,36)
plot.Comm <- plot(x) # plot.Comm <- try(eval(plo
You have this sequence of code in your script:
for (a in seq(1,(ncol(X)-3), by=2)){
for (b in seq(3,(ncol(X)-1), by=2)){
for (i in a){
j <- a+1
for (k in b){
l <- b+1
The 'for (i in a){' appears to meaningless since 'a' is just a single
value. What did you think this is supposed to do? S
Tom La Bone wrote:
> I understand that the hat matrix is a function of the predictor variable
> alone. So, in the following example why do the values on the diagonal of the
> hat matrix change when I go from an unweighted fit to a weighted fit? Is the
> function hatvalues giving me something other
Because it does. I should have looked ahead a few chapters in the book
before I asked the question. However, I can't seem to reproduce the values
of the hat matrix given by R for the weighted fit example I gave. Any
suggestions (other than looking ahead a few more chapters)?
Tom
[[
# Hello
# I have a question regarding pairwise calculations of a matrix using a
"for-loop."
# Below I have a matrix "X" with 8 columns. These are genotypic data so
Column1 & Column2 is
# a unit, Column3 & Column4 is a unit, Column5 & Column6 is a unit, and
Coulmn7 & 8 is a unit.
# I have a loop d
# Hello
# I have a question regarding pairwise calculations of a matrix using a
"for-loop."
# Below I have a matrix "X" with 8 columns. These are Genotypic data so
Column1 & Column2 is
# a unit, Column3 & Column4 is a unit, Column5 & Column6 is a unit, and
Coulmn7 & 8 is a unit.
# I have a loop d
I'd like to fit a linear model on a subset of a data frame with given weights.
I am curious how the lm() works when both subset and weights argument
is specified.
Let me give an example: filter is a boolean vector of length the same
as one column of df, my dataframe. What I want is the linear
reg
I understand that the hat matrix is a function of the predictor variable
alone. So, in the following example why do the values on the diagonal of the
hat matrix change when I go from an unweighted fit to a weighted fit? Is the
function hatvalues giving me something other than what I think it is?
John M. Chambers Statistical Software Award - 2008
Statistical Computing Section
American Statistical Association
The Statistical Computing Section of the American Statistical
Association announces the competition for the John M. Chambers
Statistical Software Award. In 1998 the Association for
I wrote: [note to self: I must stop this schizophrenic habit
of replying to self. note to self II: I must also stop making
notes to self]
> I am struck here. What magic inchantation is required with tkmenubutton?
> (...)
> # HERE!!! What is the magic inchantation that I must use here?
> #
> # $m
On 10/19/07, Allison Bailey <[EMAIL PROTECTED]> wrote:
> I'm just learning to work with R, and am having some difficulty controlling
> the output of my dotplot.
>
> The default order of the function dotchart seems to be the largest value on
> the bottom and the smallest on the top. I wanted it i
Hi,
I have a question regarding two way anova.
I have a data sheet as following:
ID -- representing the same sample gets several repeated measures at
the same time point
group -- treated vs untreated
time -- different time point (3, 9, 15 hours)
signal -- measurement signal
I use the aov function
Thanks Katharine,
for the moment I'm not on a PC on which VisIt is installed, but it should do
the trick.
By the way: to use 2 variables when creating the cdf file:
ncnew <- create.ncdf(filename="file.cdf", vars = list(x1,x2))
That was one of the things that was working within the 2 hours ;-).
Bert et al,
A point of clarification. If one reads ?par, one will note [emphasis
added]:
There are several parameters can **only** be set by a call to par():
* "ask",
* "fig", "fin",
* "lheight",
* "mai", "mar", "mex", "mfcol", "mfrow", "mfg",
* "new",
* "oma
Does this do what you want?
> x <- data.frame(subj=sample(1:3,20,TRUE), cond=sample(1:2,20,TRUE),
> time=runif(20,1,10))
> # add mean and sd
> x$mean <- ave(x$time, x$subj, x$cond)
> x$sd <- ave(x$time, x$subj, x$cond, FUN=sd)
> x
subj cond time mean sd
1 32 3.563114 5.63
John:
I agree: the Docs are not clear on this. V&R's MASS (p.84 in the 4th
edition) gives an explanation:
"Positions in the plot region may also be specified in absolute **user
coordinates**. Initially user coordinates and relative coordinates
[..relative to the unit square of the enclosing regi
Check out 'as.table' option in the help file.
On 10/19/07, Allison Bailey <[EMAIL PROTECTED]> wrote:
> I'm just learning to work with R, and am having some difficulty controlling
> the output of my dotplot.
>
> The default order of the function dotchart seems to be the largest value on
> the bot
Hi.
A colleague of mine figured out how to get the RMySQL 0.6 package to load
properly in our environment with MySQL 5.0.45. Every time I tried to load
the RMySQL library in R 2.5.1 I was getting an error message:
LoadLibrary failure: Invalid access to memory location.
We did the following:
On Oct 19, 2007, at 10:54 AM, John Sorkin wrote:
> Windows XP
> R 2.5.0
> I am trying to produce two plots that have the same range, i.e. x
> from 50 to 400 on both plots and y from 50 to 400 on both plots.
> (This will allow me to compare slopes). I have used the code below
> without succes
Windows XP
R 2.5.0
I am trying to produce two plots that have the same range, i.e. x from 50 to
400 on both plots and y from 50 to 400 on both plots. (This will allow me to
compare slopes). I have used the code below without success using usr (I have
also used xaxp and yaxp but I am not includi
I have been trying to figure out how Hadley Wickhams
"reshape" package works and I tried it on what may be
your problem. Here is my example. Does it do
something like what you want?
===
# Test Data
zz <- "subj cond t1 t2 t3
A1 4 5 7
A
Below is an example R -> netCDF -> R for rows of a dataframe that are
numeric vectors --note however that your dataframe includes character
vectors. I can't look into that case at the moment - maybe it's easy to
solve, or maybe you have to do some hashing.
## begin ex.
library(ncdf)
dat <- matri
I'm just learning to work with R, and am having some difficulty controlling the
output of my dotplot.
The default order of the function dotchart seems to be the largest value on the
bottom and the smallest on the top. I wanted it in the opposite order (which
is how my data frame is currently s
On Fri, 19 Oct 2007, Ralf Goertz wrote:
=
> Thanks to Thomas Lumley there is another convincing example. But still
> I've got a problem with it:
>
>> x<-c(2,3,4);y<-c(2,3,3)
>
>> 1-2*var(residuals(lm(y~x+1)))/sum((y-mean(y))^2)
>
> [1] 0.75
>
> That's okay, but neither
>
>> 1-3*var(residuals(lm(y~x
On Thu, 18 Oct 2007, Moshe Olshansky wrote:
> Please forgive me if my question is answered in Help
> FAQ no. 23481739...
If it were, we might well not forgive you -- the faq isn't *that* long. But it
isn't.
> In VBA one can use a special statement (Option
> Explicit) which does not allow using
Dear List,
I have a data frame containing reaction times of participants in some
experiment.
As usual each line is single trial in the experiment. Two factors denote the
conditions in the experiment. Each participant completes different trials for
each condition.
Now, the question:
I want to
Peter,
what a quick response!
But unfortunately, yes I tried the ncdf package, I looked at the examples,
but after 2 hours trying and many, many errors, I gave up.
Bart
- Original Message -
From: "Peter Dalgaard" <[EMAIL PROTECTED]>
To: "Bart Joosen" <[EMAIL PROTECTED]>
Cc: <[EMAI
Bart Joosen wrote:
> Hello,
>
> Is there anyone porting R data to VisIt (http://www.llnl.gov/visit/)?
> Altough VisIt accepts 5 dozen of data formats, I can't get my data into VisIt.
>
> I currently ran a simulation which gave me a data frame, which I wanted to
> import into VisIt to further explo
Hello,
Is there anyone porting R data to VisIt (http://www.llnl.gov/visit/)?
Altough VisIt accepts 5 dozen of data formats, I can't get my data into VisIt.
I currently ran a simulation which gave me a data frame, which I wanted to
import into VisIt to further explore the dataframe.
Let's say I
Petr PIKAL wrote:
> Hi
>
> [EMAIL PROTECTED] napsal dne 19.10.2007 15:58:43:
>
>
>> Sorry if this is already answered somewhere, but I could not find it.
>> I have two vectors, x,y, of different length, and I want to recycle
>> the smaller one (whichever one it is) until they have the same
>>
On Oct 19, 2007, at 10:25 AM, Petr PIKAL wrote:
> E.g.
>
> mat<-cbind(x,y)
>
Ah, that's an interesting idea, though it assumes they are of the
same mode (admittedly, in my example they are, I should have made up
an example where one of them is a character vector).
> gives you desired recyclin
frequent itemset, yeah.. I did not use that for a while
thanks.
On 10/19/07, Gad Abraham <[EMAIL PROTECTED]> wrote:
> Weiwei Shi wrote:
> > Hi,
> >
> > I am looking for an algorithm (better if it is implemented in R) which
> > can do the following:
> >
> > from the following list:
> > a,b,c,d
Hi
[EMAIL PROTECTED] napsal dne 19.10.2007 15:58:43:
> Sorry if this is already answered somewhere, but I could not find it.
> I have two vectors, x,y, of different length, and I want to recycle
> the smaller one (whichever one it is) until they have the same
> length. I was wondering if there
Hello,
I am looking for a way to extract fitted values of a 2-level generalized
linear mixed model using lme4-package.
As it is a Poisson-model, I have to use lmer(.), e.g.:
(y ~ x1 + x2 + (1|PtID), data = mydata, family = "poisson", method = "ML")
If it was a linear mixed model with normally
I am not sure if this is what you want but to re-direct the results to a
file
see ?sink
good luck
AA.
- Original Message -
From: "Ashish Jha" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>
Sent: Wednesday, October 17, 2007 2:46 AM
Subject: [R] How to save association rules generated by arule
Sorry if this is already answered somewhere, but I could not find it.
I have two vectors, x,y, of different length, and I want to recycle
the smaller one (whichever one it is) until they have the same
length. I was wondering if there is a anything better than something
like:
x<-1:3
y<-1:10
mydata[is.na(mydata)] <- NaN
should work
--- Samor Gandhi <[EMAIL PROTECTED]> wrote:
> Hi, Is it possible to do the following
>
> > mydata
>yx
> 1 0.3 1
> 2 0.8 NA
> 3 NA 0
> 4 0.2 1
>
> I would like to solve
>
> mydata <- replace(mydata, NA, NaN)
>
> Thanks!
I'm no expert in R but I think that read.table simply will not start a variable
with a numeric. If you really want
the names to be as listed below you can assign them after import by using :
names(mydata) <- c(name, "20_1_TT_Z_e4" "20_2_TT_Z_e4")
name is a factor as far as I can see because tha
Dear R-users:
I am trying to use the following code to reproduce the figures on page 140
of Prof. Frank Harrell's book 'Regression Modeling Strategies':
rm(list=ls())
options(width=128)
library(Hmisc)
library(Design)
getHdata(counties)
counties$older <- counties$age6574 + counties$age75
label(co
See ?make.names, specifically the Details section which notes:
A syntactically valid name consists of letters, numbers and the dot or
underline characters and starts with a letter or the dot not followed by
a number. Names such as ".2way" are not valid, and neither are the
reserved words.
The cha
What you have is a slightly more subtle variant of the following:
library(survival)
data(lung)
mydata <- cbind(lung, newvar =2)
coxph(Surv(time, status) ~ ph.karno + newvar, mydata)
coef exp(coef) se(coef) z p
ph.karno -0.0164 0.984 0.00585 -2.81
Maybe I had to write that the original data what I read are
name 20_1_TT_Z_e4 20_2_TT_Z_e4
A1 10222
A2 10321
A3 10720
Thatk you!
Neuer Arkadasch <[EMAIL PROTECTED]> schrieb:
Hi everyone, I read the following
Hello all
Simple question for the gurus. I'm trying to interactively label curves
on a single plot. The labcurve() function from Hmisc seems like the way
to do this (?). I just can't seem to get it to work. Toy example:
> x <- 1:10
> y1 <- x^2
> y2 <- 2*x
> plot(x,y1)
> lines(x,y2)
> labc
Berwin A Turlach, Freitag, 19. Oktober 2007:
> G'day Ralf,
Hi Berwin,
> On Fri, 19 Oct 2007 09:51:37 +0200 Ralf Goertz <[EMAIL PROTECTED]>
> wrote:
>
> Why should either of those formula yield the output of
> summary(lm(y~x+0)) ? The R-squared output of that command is
> documented in help(su
Hi everyone, I read the following data
> setwd("d:/")
> mydata <- read.table("mydata.txt", header=T)
> attach(mydata)
> mydata
name X20_1_TT_Z_e4 X20_2_TT_Z_e4
1 A1 10222
2 A2 10321
3 A3 10720
> name
[1] A1 A2 A3
Levels: A1
mydata[is.na(mydata)] <- NaN
Uwe Ligges
Samor Gandhi wrote:
> Hi, Is it possible to do the following
>
>> mydata
>yx
> 1 0.3 1
> 2 0.8 NA
> 3 NA 0
> 4 0.2 1
>
> I would like to solve
>
> mydata <- replace(mydata, NA, NaN)
>
> Thanks!
> ___
Hi, Is it possible to do the following
> mydata
yx
1 0.3 1
2 0.8 NA
3 NA 0
4 0.2 1
I would like to solve
mydata <- replace(mydata, NA, NaN)
Thanks!
__
[[alternative HTML version deleted]]
___
hello,
I am trying to rescale a matrix according to one column in the matrix.
Imagine having two matrices with 2 columns each:
mat1:
12.1
22.2
3 2.2
4 2.4
5 2.7
6 2.9
mat2:
11.9
22.0
3 2.1
4 2.2
5 2.4
6 3.0
7. 2.8
I now want to rescale mat2 such that the
>> I guess that explains why statisticians tell you not to use
>> R^2 as a goodness-of-fit indicator.
>IIRC, I have not been told so. Perhaps my teachers were not as good
they
>should have been.
I couldn't possibly comment ;-)
>So what is R^2 good if not to indicate the goodness of fit?.
Broad
Hi Deepayan!
For your info: I am using R 2.6.0 and lattice 0.17. Appended with this
email is a test case which aborts on my machine with the error message
Error in lattice.getStatus("current.cond.levels")[[current.row(),
current.column()]] :
subscript out of bounds
So, I hope to have helped y
I am struck here. What magic inchantation is required with tkmenubutton?
I am converting the examples of Perl/Tk from page...
http://gd.tuwien.ac.at/languages/perl/Hajji-Perlkurs/part4/tkperl.html
... to R's tcltk.
But I don't know how to convert one line in this example:
library(tcltk)
# crea
Perhaps:
z <- matrix(1:10, nrow=1)
image(z, col=rev(terrain.colors(10)))
On 19/10/2007, Dong-hyun Oh <[EMAIL PROTECTED]> wrote:
>
> Dear UserRs,
>
> I draw filled contour plot with filled.contour function.
> By default, colors of filled.contour is terrain.colors which alters
> from green (the l
2007/10/19, Frede Aakmann Tøgersen <[EMAIL PROTECTED]>:
>
> If you carefully read the man for boxplot (?boxplot) you can see in the
> examples that you can put in a ylim as an argument to the boxplot function:
>
> boxplot(3:5, 2:4,4:6, ylim = c(0, 8))
>
> See also ?bxp.
>
> best regards
>
> Frede
Thanks for the quick and nice reply.
I must apologise twice:
1-I should have reported I am using R 2.5.1 on Windows;
2- It was a spelling error on my part (rigth instead of right).
Pedro
At 11:27 2007/10/19, you wrote:
>Works for me with current R-2.6.0 (but you haven't told us about
>your R ver
Dear UserRs,
I draw filled contour plot with filled.contour function.
By default, colors of filled.contour is terrain.colors which alters
from green (the lowest level) to white (the highest level).
I want the colors to alter from white (the lowest level) to green
(the highest level).
How can
Hello Moshe,
Moshe Olshansky <[EMAIL PROTECTED]> writes:
> Try
> x <- as.integer(Membersind06$actual06)
> and then
> x/10
I think I tried that without success (but I tried so many things, that
one may have escaped me). In the meantime I changed the database
relation to a numeric type [numeric(
On 19-Oct-07 09:36:52, raymond chiruka wrote:
> sorry but how do i accsess r archives
If you mean the archive of postings to the R-help list,
then:
http://stat.ethz.ch/pipermail/r-help/
For a general search through R-related material (including
R-help):
http://finzi.psych.upenn.edu/nmz.ht
Works for me with current R-2.6.0 (but you haven't told us about your R
version!):
> cut(1:5, 1:5)
[1] (1,2] (2,3] (3,4] (4,5]
Levels: (1,2] (2,3] (3,4] (4,5]
> cut(1:5, 1:5, right=FALSE)
[1] [1,2) [2,3) [3,4) [4,5)
Levels: [1,2) [2,3) [3,4) [4,5)
Uwe Ligges
Pedro de Barros wrote:
> Dear
raymond chiruka wrote:
> sorry but how do i accsess r archives
Which archives, R version? Package versions? Mailing list archives
Uwe Ligges
> __
>
>
>
> [[alternative HTML version deleted]]
>
>
Aydemir, Zava (FID) wrote:
> Hi
>
> what does this mean when i get above error? When I call function foo(),
> specifying parameters a and b as below
>
> a<-5
> b<-6
>
>
>>y <- foo(a,b)
>>Error in foo(a, b) : unused argument(s) (6)
>
Hi Zava,
As the other Jim noted, it looks like foo() is de
If you carefully read the man for boxplot (?boxplot) you can see in the
examples that you can put in a ylim as an argument to the boxplot function:
boxplot(3:5, 2:4,4:6, ylim = c(0, 8))
See also ?bxp.
best regards
Frede
Fra: Klaus Friis Østergaard [mail
Hi
[EMAIL PROTECTED] napsal dne 19.10.2007 11:24:23:
> 2007/10/19, Frede Aakmann Tøgersen <[EMAIL PROTECTED]>:
> >
> > So where is the reproducable example?
> >
> > How can we know that you're not doing
> >
> > boxplot(1:10)
> > abline(h = 400, col = "red")?
> >
> > best regards
> >
> > Frede
>
Now my Windows machine is back online again, I have been able to do some
work on this.
You can download the latest ODBC drivers from download.microsoft.com
(select Office as the product, search for ODBC and you will get to
AccessDatabaseEngine.exe). You don't need any version of Office install
hie
Im trying to calculate the power of the logrank test for different values
of rho .I was just wandering whether the following programme would do it. any
suggestions are welcome
s=50
number=1
count1=0;count2=0;count3=0;count4=0;count5=0;count6=0;cou
2007/10/19, Frede Aakmann Tøgersen <[EMAIL PROTECTED]>:
>
> So where is the reproducable example?
>
> How can we know that you're not doing
>
> boxplot(1:10)
> abline(h = 400, col = "red")?
>
> best regards
>
> Frede
You are right, a reproducable example should have been there.
I don't know wh
sorry but how do i accsess r archives
__
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting gu
The Fondation De France(FDF) ( http://www.fdf.org), would
like to notify you that you have been chosen by the Board of Trustees as one of
the final recipients of a Cash Grant/Donation for your Personal, Educational,
and Business Development.
The Fondation De France(FDF) was conceived with the
Dear All,
I am trying to use cut() to produce intervals open on the right, but
it seems to ignore the argument right=F, contrary to what is
indicated on the help for cut.
Can anyone help?
Thanks,
Pedro
__
R-help@r-project.org mailing list
https://st
G'day Ralf,
On Fri, 19 Oct 2007 09:51:37 +0200
Ralf Goertz <[EMAIL PROTECTED]> wrote:
> Thanks to Thomas Lumley there is another convincing example. But still
> I've got a problem with it:
>
> > x<-c(2,3,4);y<-c(2,3,3)
>
> [...]
> That's okay, but neither [...] nor [...]
> give the result of su
Which marketers have used to hype the internet as a seamless part of everyday
life.
Already achieved universal access thanks to the 6000 UK Online centres that
have.
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEA
Hi all!
I would like to fit a simple regression model to a number of observations.
However, I have reasons to think that maybe the relationship I am testing is
significant only for a number of them.
Is there some automated method to test the model for all possible data
combinations?
Thank y
Hi all!
I would like to fit a simple regression model to a number of observations.
However, I have reasons to think that maybe the relationship I am testing is
significant only for a number of them.
Is there some automated method to test the model for all possible data
combinations?
Thank y
So where is the reproducable example?
How can we know that you're not doing
boxplot(1:10)
abline(h = 400, col = "red")?
best regards
Frede
Fra: [EMAIL PROTECTED] på vegne af Klaus Friis Østergaard
Sendt: fr 19-10-2007 09:55
Til: Gabor Grothendieck
C
It works for me. Perhaps you could make the line thicker.
abline(h = 4, col = "red", lwd = 3)
On 10/19/07, Klaus Friis Østergaard <[EMAIL PROTECTED]> wrote:
>
>
> 2007/10/19, Gabor Grothendieck <[EMAIL PROTECTED]>:
> > Try this:
> >
> > boxplot(1:10)
> > abline(h = 4, col = "red")
>
> Have trie
2007/10/19, Gabor Grothendieck <[EMAIL PROTECTED]>:
>
> Try this:
>
> boxplot(1:10)
> abline(h = 4, col = "red")
Have tried it, I only get the boxplot, no red line.
It works on the plotte images.
That is why I asked the question here on the list.
--
Klaus F. Østergaard,
[[alternat
The R graphics model is low-level, and the problem is CorelDraw's limited
capabilities (Adobe Illustrator seems to do rather better with postscript
generated by R). The XFig and SVG drivers may produce output that is more
easily editable, but ultimately the problem is that R graphics is done by
Berwin A Turlach, Donnerstag, 18. Oktober 2007:
> G'day all,
>
> I must admit that I have not read the previous e-mails in this thread,
> but why should that stop me to comment? ;-)
Your comments are very welcome.
> On Thu, 18 Oct 2007 16:17:38 +0200
> Ralf Goertz <[EMAIL PROTECTED]> wrote:
>
See findGlobals in the codetools package.
On 10/19/07, Moshe Olshansky <[EMAIL PROTECTED]> wrote:
> Please forgive me if my question is answered in Help
> FAQ no. 23481739...
>
> In language like C every variable must be declared
> before it can be used.
> In VBA, if a variable has not been declar
Try this:
boxplot(1:10)
abline(h = 4, col = "red")
On 10/18/07, Klaus Friis Østergaard <[EMAIL PROTECTED]> wrote:
> Hi,
>
> Is it possible to add horizontal lines to a boxplot.
>
> I want to add these lines in ordre to indicate where tolerance limits on the
> boxplot.
>
> --
> Klaus F. Østergaa
Please forgive me if my question is answered in Help
FAQ no. 23481739...
In language like C every variable must be declared
before it can be used.
In VBA, if a variable has not been declared it is
assumed to be of a special type (Variant).
In R (and Matlab) variables do not have to be
declared. Th
Hi,
Is it possible to add horizontal lines to a boxplot.
I want to add these lines in ordre to indicate where tolerance limits on the
boxplot.
--
Klaus F. Østergaard,
[[alternative HTML version deleted]]
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R-help@r-project.org mailing list
Good afternoon!
My question is more of a "is there a package for doing?"
If one has 2 independent studies which both independently measure a trait of
a population, but both of them are constructed from 2 separate frames (which
TOGETHER refer to the population of interest),
> I would like to do a fit of the form: y = a (x+c)**b, where a, b and c
> are unknown.
The popular method of fitting a linear model to log-log transformed data was
already mentioned. ALthough this works in many situations, it is
considered to be somewhat biased an not very robust. I suggest to
Hi there
Does anyone know if there is an rcode (or another program code) for estimating
time series with the MAR-ARCH model? An indication on where to obtain such a
code would be great.
Thanks
Nigel
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R-help@r-project.org mailing list
https://stat.et
On 10/19/07, Steffen Neumann (on the road) <[EMAIL PROTECTED]> wrote:
> Hi,
>
> I am trying to create a plot with pairs()
> using a gplot.hexbin() for each pair.
>
> For pairs I can provide a custom upperPanel function:
>
> pairs(iris[1:4], panel=mypanel)
>
> and mypanel() calls plot.hexbin():
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