Gabor Grothendieck wrote:
Try:
http://news.gmane.org/gmane.comp.lang.r.general
Fantastic - perfect. Saves my inbox filling up!
Thanks
Martin
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R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the
Greetings,
I have a large dendrogram that I would like to use to extract groups. But any
group with 2 or fewer members is not useful to me, so I would like to remove
all of the nodes with less than 3 members from the dendrogram.
1) Is there a good way to iterate through a dendrogram list to
It worked. But this student of R is left wondering why or how. In
particular the construction foo[.][.] was puzzling. I doubt that
matters greatly, but I am using R in both a Mac (OSX 10.2 v 2.0.1) and
WinXP (v 2.4.1.)
I have broken it into what I think are its pieces:
table(my.mat)[-1]
On Nov 8, 2007 11:22 AM, Van Campenhout Bjorn
[EMAIL PROTECTED] wrote:
On 11/6/07, Van Campenhout Bjorn [EMAIL PROTECTED] wrote:
Hi all,
I made a dotplot() with lattice, which comes out nice on the graphics
device. I can save this as a eps using postscript() and include this in
On 11/11/2007 11:49 AM, Alex Park wrote:
R Help
Feel sure there is a simple answer to this but answer has eluded me so far.
NB. Using R 2.6.0.
I am plotting a simple chart using plot():
plot(df, ylim=c(as.numeric(min(df)), as.numeric(max(df))), col=OliveDrab,
xlab=, ylab=)
What I
You may want to have a look at the vars package
Frank
Giusy schrieb:
Hello to everyone!
I have a question for you..I need to predict multivariate time series, for
example sales of 2 products related one to the other, having the 2 prices
like inputs..
Is there in R a function to do it? I saw
On Nov 11, 2007 11:23 AM, David Winsemius [EMAIL PROTECTED] wrote:
It worked. But this student of R is left wondering why or how. In
particular the construction foo[.][.] was puzzling. I doubt that
matters greatly, but I am using R in both a Mac (OSX 10.2 v 2.0.1) and
WinXP (v 2.4.1.)
I have
Hi - I follow some references and now implement my own state-space model
estimation. I have a question. In case, my equations are like this:
y(t) = Ax(t)+Bu(t)+eps(t) # observation eq
x(t) = Cx(t-1)+Du(t)+eta(t) # state eq
Using EM, after backward recursion, you will use the smoothed state
Hi Gabor,
I replaced multiple spaces with a single one and tried
the code you suggested. I got:
library(sqldf)
Loading required package: RSQLite
Loading required package: DBI
Loading required package: gsubfn
Loading required package: proto
I've been looking for ways to calculate a large number (100) of non-crossing
Nonparametric quantile regressions on large populations (1000+).
Can the quantreg package in R ensure the non-crossing property?
If not, do you know any alternative?
Thank you,
Paulbegc
--
View this message in
On 11/11/2007, at 1:43 AM, Uwe Ligges wrote:
Paul Smith wrote:
Dear All,
Can R perform multivariate integration with infinite limits of
integration?
No, R does numerical (not symbolical) calculations, hence it can never
perform integration (not even univariate) with infinite limits.
On 10/11/2007, at 3:48 AM, Irene Mantzouni wrote:
Dear all,
probably this is quite clear for most of you but for me it is a
headache...
I am regressing response A against the continuous covariate B and
the relationship is clearly quadratic.
When I add a second covariate B, the
Hello,
I am trying to use the tree package in R with RSperl.
I have generated a regression tree using the tree package in R and saved it
in a file say RegTree_2.Rdata
If I use the predict function from R command line, it works fine. However, I
want to use it from within perl using RSperl. To
Hello,
I am trying to use the tree package in R with RSperl.
I have generated a regression tree using the tree package in R and saved it
in a file say RegTree_2.Rdata
If I use the predict function from R command line, it works fine. However, I
want to use it from within perl using RSperl. To
Dear list,
I am new to R and very inexperienced. Sorry for the trouble.
I have two txt files and want to merge them by taking the average.
More specifically, for example, the txt file1, with row names and column names,
consists of 238000 rows and 196 columns. Each column corresponds
to a sample.
On Nov 11, 2007 2:28 PM, affy snp [EMAIL PROTECTED] wrote:
Hi Gabor,
I replaced multiple spaces with a single one and tried
the code you suggested. I got:
library(sqldf)
Loading required package: RSQLite
Loading required package: DBI
Loading required package: gsubfn
Loading required
-BEGIN PGP SIGNED MESSAGE-
Hash: SHA1
Rachana Jain wrote:
Hello,
I am trying to use the tree package in R with RSperl.
I have generated a regression tree using the tree package in R and saved it
in a file say RegTree_2.Rdata
If I use the predict function from R command line,
You can apply 1:n to order(x) so you don't wind up
subscripting x by every element in order(x).
o - head(order(x), n) # positions
x[o]
A completely different approach, if X is a data frame with d as a data
column is this where the row names give the positions (don't know
about speed):
Is it possible to run a linux syntax (i.e. like i was at a linux
terminal) from an R code?
Just one example:
Let say that I have an R code with
hist(rnorm(100))
dev.copy2eps(file=Dnormal.eps)
and then within the same R code, i want to convert the file
'Dnormal.eps' to 'Dnormal.pdf'. This can
?system
On 12/11/2007, at 2:28 PM, Christian Salas wrote:
Is it possible to run a linux syntax (i.e. like i was at a linux
terminal) from an R code?
Just one example:
Let say that I have an R code with
hist(rnorm(100))
dev.copy2eps(file=Dnormal.eps)
and then within the same R code, i
Hi,Jim. I created two txt files as:
x.txt
id b1 b2 b3
a1 246
a2 12 NA
a3 46 NA
y.txt
idb1 b2 b3
a1 NA44
a2 22 NA
a3 122
I tried it one more time but got different z:
x-read.table(file=x.txt,header=TRUE,row.names=1,na.strings = NA)
Here is the way to read the data and convert it. Your data was a
dataframe with the first column being the id:
x - read.table(textConnection(id b1 b2 b3
+ a1 246
+ a2 12 NA
+ a3 46 NA), header=TRUE)
y - read.table(textConnection(idb1 b2 b3
+ a1 NA44
+ a2
Try this:
par(mfrow = 1:2)
acf(cbind( = 1:10))
acf(cbind( = 1:10))
par(mfrow=c(1,1))
par(mfrow=c(1,1), oma=c(0,0,1,0))
mtext(My Title, 3, outer = TRUE, cex = par(cex.main))
Please provide reproducible code next time as requested in
last line of every message to r-help.
On Nov 11, 2007 10:32
Hi Jim,
However, the real file has 238000 row ids and 196 column ids.
How could I read the file first and then convert it to a matrix?
Allen
On Nov 11, 2007 11:02 PM, jim holtman [EMAIL PROTECTED] wrote:
Here is the way to read the data and convert it. Your data was a
dataframe with the
I have a vector whose length is nearly 70 thousand.
I need randomize it for 1000 times .
for randomizing , I mean ,the elements of the vector remain intact while
their order in the vector get changed randomly.
I have written a function which seems to be able to solve short vectors ,
but waste a
What is 'x' here? What type? Does it contain NAs? Are there ties? R's
ordering functions are rather general, and you can gain efficiency by
ruling some of these out.
See ?sort, look at the 'partial' argument, including the comments in the
Details. And also look at ?sort.list.
sort.int(x)
I don't know what you mean by 'the latest release', but R does not behave
this way in a vanilla session in 2.6.0 or R-patched. Had you given the
'at a minimum' information asked for in the posting guide, we might have
been able to deduce what the problem is. I get
x1 - c(1:4,4,4,4)
f -
On my system
system.time(x1 - sort(x,decreasing=TRUE)[1:1000])
user system elapsed
0.030.000.03
whereas
system.time(x1 - x[order(x)][1:1000])
user system elapsed
0.110.000.11
I.e. using sort is about 30 times faster.
Best regards
Frede Aakmann Tøgersen
oh, thank you ,
I used the samplefunction to generate new subordinates
but never think that it can directly act on the vector .
thank you very much.
Frede Aakmann Tøgersen wrote:
Why didn't you do this in R?
help.search(random sample)
Help files with alias or concept or title
Dear all,
I'm using the ape package in R and want to draw a
phylogenetic tree with not only the tip labels but
also some labels for the edges. e.g. Mark the edge AB
as m in the tree ABC.
Couldn't find a way to do that. Can someone help?
Thanks,
Hua
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