Zitat von Peter Alspach [EMAIL PROTECTED]:
Udo
Seems you might want merge()
HTH ...
Peter Alspach
Thank you Peter and Jorge,
but as I had written in my last sentence,
Merge doesn´t do the job, because it makes
all possible matches, but maybe there is a sophisticated
solution with
I would like to do looping for this process below to estimate alpha
beta from gamma distribution:
Here are my data:
day_data1 -
123456 789 10 11 12
13 14 15 16 17 18 19 20 21 22 23
1943 48.3 18.5 0.0 0.0 18.3 0.0 0.0
On 4/14/2008 6:21 AM, Louisa Hay wrote:
Hi,
I am trying to create a power curve to show how the power of a t-test varies
depending on the mean. Any ideas how I should go about this?
Louisa
Something like this maybe?
mydiffs - seq(.05,1,.05)
mypower - vector(numeric, 20)
for(i in
On 4/14/2008 6:35 AM, Chuck Cleland wrote:
On 4/14/2008 6:21 AM, Louisa Hay wrote:
Hi,
I am trying to create a power curve to show how the power of a t-test varies
depending on the mean. Any ideas how I should go about this?
Louisa
Something like this maybe?
mydiffs -
Dear R-help group,
I have a dataset with daily closing prices from a stock exchange (consecutive 5
trading days) from a firm trading a specific commodity. The date variable looks
like:
quote_date
20080411
With the format; mmdd.
Moreover, I have another data set with a (average) weekly
Here is one way to get the 'week':
x - as.character(seq(20080401, 20080430))
# get the week
cbind(x, format(as.Date(x, %Y%m%d), %W))
x
[1,] 20080401 13
[2,] 20080402 13
[3,] 20080403 13
[4,] 20080404 13
[5,] 20080405 13
[6,] 20080406 13
[7,] 20080407 14
[8,] 20080408 14
[9,]
Louisa Hay wrote:
Hi,
I am trying to create a power curve to show how the power of a t-test varies
depending on the mean. Any ideas how I should go about this?
Louisa
The pt() function supports a non-centrality parameter, so you can do
this calculation directly.
For other situations
)
library(xts)
Lines.daily - quote_date value
+ 200804071
+ 200804082
+ 200804093
+ 200804104
+ 200804116
+ 200804127
+ 200804138
+ 200804149
+ 20080415 10
+
daily - read.zoo(textConnection(Lines.daily),
+ header = TRUE
Dear all,
I used which to obtain a subset of values from my data.frame.
however, I find that there is a trace of the values I have removed.
Any suggestions would be greatly appreciate.
Below is my data:
d - data.frame( val = 1:10,
group = sample(LETTERS[1:5], 10,
Thiemo Fetzer wrote:
As a general rule and practical in many contexts uses the following
steps: (a) Use the R2HTML library to write the results from the summary
to the clipboard (b) Open a spreadsheet and paste the results there.
(c) Edit and shove things around until everything are where you
Thanks all. I will try to use both tapply and by, and have no idea how I
missed the by function. Thanks again.
--
View this message in context:
http://www.nabble.com/Equivalent-to-a-BY-command-in-SAS-tp16670452p16676280.html
Sent from the R help mailing list archive at Nabble.com.
Tania Oh wrote:
Dear all,
I used which to obtain a subset of values from my data.frame.
however, I find that there is a trace of the values I have removed.
Any suggestions would be greatly appreciate.
Below is my data:
d - data.frame( val = 1:10,
group =
On Thu, 10 Apr 2008, Peter Muhlberger wrote:
Hi Bill: Thanks for the reply! As you've no doubt guessed, I'm not a
statistician (I'm a social scientist). I hadn't given thought to
modeling the cluster-based covariance explicitly--interesting
possibility. My responses are drawn from some
Dear Uwe,
thank you very much for this.
After reading your solution below, I searched the help pages for
data.frame, which, factor but I didn't see the option for drop in
them.
I googled and found drop associated with the function subset. is
this the help page you were alluding to?
Sorry
On 4/14/2008 7:30 AM, zerfetzen wrote:
Thanks all. I will try to use both tapply and by, and have no idea how I
missed the by function. Thanks again.
One problem with both of those arises if you are subsetting on several
columns. They will do the calculations for all combinations of all
Hi,
Two questions:
A) Assuming OB is an object, how do I store 20 of OB in a vector or list ?
B) Does R has something similar associative array to Perl ? For example,
%our_friends = ('best', 'Don', 'good', 'Robert', 'worst', 'Joe');
$our_friends{'cool'} = Karen;
Thanks
Stanley
On Mon, Apr 14, 2008 at 08:32:55PM +0800, Ng Stanley wrote:
Hi,
Two questions:
A) Assuming OB is an object, how do I store 20 of OB in a vector or list ?
replicate(20, OB, simplify=FALSE)
B) Does R has something similar associative array to Perl ? For example,
%our_friends = ('best',
Hi,
Didn't make myself clear on A). The twenty OBs are all different, how to
store them in a vector or list ?
Your solution to B) is nice and clear. Will read up on the Introduction
also.
On Mon, Apr 14, 2008 at 8:39 PM, Gabor Csardi [EMAIL PROTECTED] wrote:
On Mon, Apr 14, 2008 at 08:32:55PM
[EMAIL PROTECTED] wrote:
I used which to obtain a subset of values from my data.frame.
however, I find that there is a trace of the values I have removed.
Any suggestions would be greatly appreciate.
Below is my data:
d - data.frame( val = 1:10,
group =
Hi,
I am trying to write R code to produce a power curve to show how the power of a
Wilcoxon-test varies depending on the mean, with data generated from a uniform
distribution. Any ideas how I should go about this?Louisa
_
Amazing
Louisa Hay louisahay at msn.com writes:
Hi,
I am trying to write R code to produce a power curve to show
how the power of a
Wilcoxon-test varies depending on the mean, with data
generated from a uniform
distribution. Any ideas
how I should go about this?Louisa
Here's a
Dear Spencer.
Thank you for your kind reply.
I have n data points observed on the surface of a
torus. I am trying to fit the geodesic line equation
to these points on the surface:
the equation is
âu=h*integrate(((5+cos(v))*sqrt((5+cos(v))^2-h^2))^{-1})
from 0 to vâ.
I wrote the following R
Bill,
We already have erf() and erfc() as examples, and help.search() will find
them. I've added erfinv() and erfcinv() to the examples and concept
index.
I don't see a good reason to add them to e.g. the 'stats' namespace: it is
not as if we wish to encourage people to use them instead of
You might also take a look at the doBy package.
On Apr 14, 2008, at 7:30 AM, zerfetzen wrote:
Thanks all. I will try to use both tapply and by, and have no idea
how I
missed the by function. Thanks again.
_
Professor Michael Kubovy
University of Virginia
Hi all,
When I use the function envelope(???,pcf,i=???,j=???), there are some errors
as followings:
Error: cannot allocate vector of size 5.3 Mb
In addition: Warning messages:
1: In vector(double, length) :
Reached total allocation of 502Mb: see help(memory.size)
2: In vector(double, length) :
Dear all,
Wouldn't it be helpful if the
install.views
install.packages
update.packages
had a downloadonly=TRUE flag which would allow us to download the
packages and install them later (or put them in a USB stick and take
them for installation on anothe PC).
I am behind a firewall (Bank)
Hello,
I am trying to test for non-linearity in a set of non-parametric data.
Furthermore, I would like to do so in a multi-variate model. Frankly, I
don't even know if this is possible, and if it is possible, I don't know if
it is implemented in an R package. Any advice would greatly
Hi,
Two questions:
A) I need to initialize many variables to NULL. So I created variable_names
- c(a1, a2). What can I do to variable_names so that variable a1 is
NULL and a2 is NULL ?
B) How can I check whether an object exist ?
Thanks
Stanley
[[alternative HTML version deleted]]
On Mon, Apr 14, 2008 at 09:47:49PM +0800, Ng Stanley wrote:
Hi,
Two questions:
A) I need to initialize many variables to NULL. So I created variable_names
- c(a1, a2). What can I do to variable_names so that variable a1 is
NULL and a2 is NULL ?
for (n in variable_names) assign(n, NULL)
On 4/14/2008 8:59 AM, Louisa Hay wrote:
Hi,
I am trying to write R code to produce a power curve to show how the power of
a
Wilcoxon-test varies depending on the mean, with data generated from a
uniform distribution. Any ideas how I should go about this?Louisa
I think I gave you enough of
I would like to ensure that all the text in my plot is in the arial font, like
in excel and word. I have been saving my graphics to a file using the png()
function, and have tried the postscript() function. In the documentation I
have not been able to find a way of changing the family
The (imho) unintuitive behaviour is to do with the subsetting function
[.factor, not which. There are a couple of workarounds:
In that case, your intuition needs readjustment
There are other systems which (de facto) drop unused levels by default,
and it is a real pain to work
Have you tried plotting it, e.g., like the following:
npts = 51 # or some number
h = seq(0, ???, length=npts)
funh - rep(NA, npts)
for(i in 1:npts)funh[i] - fun(h[i])
plot(h, funh)
Hope this helps.
Spencer
Sungsu wrote:
Dear
Hi Achim: Thanks for the reply! I did notice that robcov() requires
the X Y and also a scores vector and that these are not readily
available under fixed names or at all in output from such functions as
systemfit and optim. I wonder if it would make sense to have a
stop-gap function that would
CT YU wrote:
Hi all,
When I use the function envelope(???,pcf,i=???,j=???), there are some errors
as followings:
Error: cannot allocate vector of size 5.3 Mb
In addition: Warning messages:
1: In vector(double, length) :
Reached total allocation of 502Mb: see help(memory.size)
2: In
Duncan Murdoch murdoch at stats.uwo.ca writes:
On 4/14/2008 8:59 AM, Louisa Hay wrote:
Hi,
I am trying to write R code to produce a
power curve to show how the power of a
Wilcoxon-test varies depending on the mean, with data
generated from a
uniform distribution. Any ideas
how I
I think that the problem is with the dev.off commands.
The first time running b there are not a device 2 and device 3 so
dev.off does nothing (or if they did exist then they are turned off).
Then you set the graphics event callback which attaches to the current
graph window (number 3 in general).
Tania Oh wrote:
Dear Uwe,
thank you very much for this.
After reading your solution below, I searched the help pages for
data.frame, which, factor but I didn't see the option for drop in them.
In fact, ?factor links to ?[.factor whcih explains it.
Uwe
I googled and found drop
Hi,
How can I force the assignment ?
RG[[ABC]] - c(a, b)
Error in RG[[ABC]] - c(a, b) :
more elements supplied than there are to replace
On Mon, Apr 14, 2008 at 9:53 PM, Gabor Csardi [EMAIL PROTECTED] wrote:
On Mon, Apr 14, 2008 at 09:47:49PM +0800, Ng Stanley wrote:
Hi,
Two
What is RG? I suspect it is not a list but a vector and
you operation you wrote does not make sense. Convert it
to a list if you want to store c(a,b) is RG[[AB]].
G.
On Tue, Apr 15, 2008 at 12:06:14AM +0800, Ng Stanley wrote:
Hi,
How can I force the assignment ?
RG[[ABC]] - c(a, b)
Hi,
Is there a way to write a table to pdf ? I have checked write.table, it only
writes to text file.
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the
See textplot function in gplots package
On Mon, Apr 14, 2008 at 1:09 PM, Ng Stanley [EMAIL PROTECTED] wrote:
Hi,
Is there a way to write a table to pdf ? I have checked write.table, it
only
writes to text file.
[[alternative HTML version deleted]]
Dear all,
Max, first of all, many thanks for providing the odfWeave package.
My problem: Whenever I have multiple plots in one single chunk of my
ODF file, only the last plot gets shown. The problem can be reproduced
with this toy example (to be used in an ODF file together with
odfWeave -- I'm
I am using the function metaMDS with jaccard distances to ordinate a
set of constituent by site matrix. I can post this data if it would
be helpful, but it is large to include in an email. I can also
provide reproducable code if necessary. I would like to get an R^2
value for the axes of the
If you ran that code outside ODFWeave, you'd only get one plot,
so why would you expect to get more within ODFWeave?
for (i in 1:3) {
plot(1,1, main=paste('Plot',i))
}
You need to add some sort of par() command, or use layout(), to create
a single plot that contains all three of the plots
Another option, if you want them in separate figures, is to write a loop
that generates the image file, saves it to the file system, and use
odfInsertPlot to put the file into the document.
This might work better if you have an unknown number of images that you
want to insert.
Max
Sarah, thanks for your reply.
On Mon, Apr 14, 2008 at 8:32 PM, Sarah Goslee [EMAIL PROTECTED] wrote:
If you ran that code outside ODFWeave, you'd only get one plot,
so why would you expect to get more within ODFWeave?
No, it depends on the device that is used. If I use PDF or postscript
they
the below is a three dimensional solution
On Mon, Apr 14, 2008 at 3:09 PM, stephen sefick [EMAIL PROTECTED] wrote:
cor(x, dist(mds))^2
Error in dist(mds) : (list) object cannot be coerced to 'double'
On Mon, Apr 14, 2008 at 2:40 PM, Sarah Goslee [EMAIL PROTECTED] wrote:
The nmds()
Hi
i have a list of many files and want to load them into a list of tables, that
can be adressed with a variable 'i'.
something like
files = c(0125um,2000um,2200um,2500um,2700um)
for (i in 1:5)
{
fp[i] - read.table( files[i] )
}
but this does not work of course.
Has anyone a good hint?
Hi!
I'm having a trouble changing font size of histogram label.
I have tried help(hist), but I couldn't find anything explain how to fix
label's font size.
Could you help me please?
Thank you.
_
Going green? See the top 12 foods
Dimensionality doesn't matter. 2, 3, 14 will all work.
What matters is that apparently vegan returns the results in some
format other than a straight sites x ordination coordinates matrix,
which is what dist expects. You'll need to convert it to one, possibly
with as.matrix, or extract the
Try this:
fp - lapply(files, read.table, header = T)
On Mon, Apr 14, 2008 at 4:21 PM, Jonas Stein [EMAIL PROTECTED] wrote:
Hi
i have a list of many files and want to load them into a list of tables,
that
can be adressed with a variable 'i'.
something like
files =
Dear
I try to add three different lines (solid, short dash, long dash) in to
current barplot. I saw there are types of lines (p,b, ect). However, they
are not what I request. Has nayone have this experience?
Many Thanks!
Xin
[[alternative HTML version deleted]]
I think that you can edit the source code of histogram for this:
myhist - getS3method(plot, histogram)
body(myhist)[9] -
parse(text = c(capture.output(body(myhist)[9])[-6],
} else labels, adj = c(0.5, -0.5), ...)))
r - hist(islands, plot = F)
myhist(r, labels = T, cex =
On Mon, 14 Apr 2008, Vorlow Constantinos wrote:
Dear all,
Wouldn't it be helpful if the
install.views
install.packages
update.packages
had a downloadonly=TRUE flag which would allow us to download the
packages and install them later (or put them in a USB stick and take
them for
Guillaume Brutel guillaume.brutel at yahoo.fr writes:
I am trying to fit a non linear regression model to time series data.
If I do this:
reg.logis = nls(myVar~SSlogis(myTime,Asym,xmid,scal))
I get this error message (translated to English from French):
Erreur in nls(y ~ 1/(1 + exp((xmid -
Here's an example to make the text 18 point. You can set ps=6 to make small
text.
x=rnorm(100)
opar=par(ps=18) # Make text 18 point
hist(x)
opar
Rob Baer
- Original Message -
From: Sue Lee [EMAIL PROTECTED]
To: r-help@r-project.org
Sent: Monday, April 14, 2008 2:35 PM
Subject: [R]
Dear
I try to make lines smoothly which are added on current barplot. I tried to
use smo and it does not work. Has nayone have this experience?
Many Thanks!
Xin
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
Hi All
I have matrix Like:-
10 20 40 60 100
Glucose UP Down UP No UP
Fructose UP UP Down UP No
Sucrose UP Down UP No Down
Taurine No No No No UP
Cellobiose Up
On Mon, 14-Apr-2008 at 08:37AM +0200, Udo wrote:
| Zitat von Peter Alspach [EMAIL PROTECTED]:
|
| Udo
|
| Seems you might want merge()
|
| HTH ...
|
| Peter Alspach
|
| Thank you Peter and Jorge,
|
| but as I had written in my last sentence,
| Merge doesn´t do the job, because it
On Mon, 2008-04-14 at 15:38 -0400, Sarah Goslee wrote:
Dimensionality doesn't matter. 2, 3, 14 will all work.
What matters is that apparently vegan returns the results in some
format other than a straight sites x ordination coordinates matrix,
which is what dist expects. You'll need to
The type argument to plotting functions determines the type of plot
(plot lines or points or both or ...). To specify the type of line you
need to use the lty argument. See the help page for par (?par) for
details on the types of line you can use (also lwd is the width of the
lines).
But you
On Mon, Apr 14, 2008 at 4:47 PM, Gavin Simpson [EMAIL PROTECTED] wrote:
Note that the default is to produce a bray-curtis dissimilarity matrix
from the input species data. As such, I reproduce this dissimilarity
matrix as arg 1 to cor and then take the Euclidean distances of the
I try to add three different lines (solid, short dash, long dash)
in to current barplot.
Have a look at the lty parameter. It's documented in ?par. If I
understand your question correctly, you may also be interested in
segments() to actually draw the lines (or maybe abline()).
cu
i have a list of many files and want to load them into a list of tables,
that
can be adressed with a variable 'i'.
fp - lapply(files, read.table, header = T)
Thank you that works fine.
But how can i access the data in column fp$foo now?
fp[1]$foo does not work.
ps: thank you all for the
hi all-
i am creating a boxplot and would like to shift the x-axis tick marks
(named 1:23) so that the ticks are in between the boxes and not centered
in the middle of the boxes. i have searched the help files and google
and have not found what i am looking for.
does anyone know how to do
I'm trying to analyze a model with two variables, one is Group with
two levels (male and female), and other is Time with four levels (T1,
T2, T3 and T4). And for the convenience of post-hoc testing I wanted
to consider a model with no intercept for factor Time, so I tried
formula
Group*(Time-1)
Sherri
Is this what you want?
sherri - data.frame(grp=rep(letters[1:6], 20), value=rnorm(6*20)+6)
temp - with(sherri, boxplot(value~grp, xaxt='n'))
axis(1, 1:5+0.5, rep('', 5))
Peter Alspach
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of Sherri
---
merca duria desea mantener el contacto contigo a través de algunos de
los mejores productos que Google ha lanzado recientemente.
Si ya utilizas Gmail o Google Talk, visita:
I have a matrix with N x N points, that I would like to represent on a map.
The points are an estimation of the bidimensional density of certain
quantity observed on a geographical region.
I am interested in a map with several colours displaying several values of
the density
Can you help me
try
?image
Xiaohui
merca duria wrote:
I have a matrix with N x N points, that I would like to represent on a map.
The points are an estimation of the bidimensional density of certain
quantity observed on a geographical region.
I am interested in a map with several colours displaying
Peter:
Hi Achim: Thanks for the reply! I did notice that robcov() requires
the X Y and also a scores vector and that these are not readily
available under fixed names or at all in output from such functions as
systemfit and optim. I wonder if it would make sense to have a
stop-gap
Hello,
If I make a plot, say something simple like
plot( runif(100) )
then the origin (0,0) is not at the bottom-left corner of the box
surrounding the plot. The axis limits are padded slightly. This is
ordinarily a good feature, because it makes plots look better. But now I
would like to make
On 14/04/2008 6:56 PM, Enrico Rossi wrote:
Hello,
If I make a plot, say something simple like
plot( runif(100) )
then the origin (0,0) is not at the bottom-left corner of the box
surrounding the plot. The axis limits are padded slightly. This is
ordinarily a good feature, because it
Hi all,
I have not been able to find an answer to what is a simple question:
conaguaMexicoSub - subset(conagua, unidad == Jalapa, select =
c(equipo,X101:X309))
This subset gives me all the rows from conagua where unidad is Jalapa.
But, please, how do I get all the rows where unidad contents
Hi,
type ?plot [Enter]and click the par link in the first line. This takes you
to all the parameters you can set for plot commands. The one you are looking
for is:
xaxs
The style of axis interval calculation to be used for the x-axis. Possible
values are r, i, e, s, d. The styles are generally
On Tue, 15 Apr 2008, [Ricardo Rodriguez] Your XEN ICT Team wrote:
Hi all,
I have not been able to find an answer to what is a simple question:
conaguaMexicoSub - subset(conagua, unidad == Jalapa, select =
c(equipo,X101:X309))
This subset gives me all the rows from conagua where unidad is
Try something like this:
x[grep(Jalapa, x$unidad),, drop = F]
On Mon, Apr 14, 2008 at 9:10 PM, [Ricardo Rodriguez] Your XEN ICT Team
[EMAIL PROTECTED] wrote:
Hi all,
I have not been able to find an answer to what is a simple question:
conaguaMexicoSub - subset(conagua, unidad == Jalapa,
Thanks! Here what I get:
Henrique Dallazuanna wrote:
Try something like this:
x[grep(Jalapa, x$unidad),, drop = F]
conaguaMexicoSub - subset(conagua, unidad == x[grep(Jalapa,
x$unidad),, drop = F], select = c(equipo,X101:X309))
Error en x$unidad : $ operator is invalid for atomic vectors
Charles C. Berry wrote:
You want
?regexpr
Something like
regexpr(Jalapa, as.character( unidad ) ) != -1
HTH,
Chuck
Please, look at this...
substringJalapa - regexpr(Jalapa, as.character(conagua$unidad ) )
!= -1
Hubo 50 o más avisos (use warnings() para ver los primeros
That's exactly what I needed! Many thanks to Mark, Daniel and Duncan for
your help!
Enrico
On Mon, Apr 14, 2008 at 8:14 PM, Daniel Malter [EMAIL PROTECTED] wrote:
Hi,
type ?plot [Enter]and click the par link in the first line. This takes
you
to all the parameters you can set for plot
Quick question about the usage of glht. I'm working with a data set
from an experiment where the response is bounded at 0 whose variance
increases with the mean, and is continuous. A Gamma error
distribution with a log link seemed like the logical choice, and so
I've modeled it as such.
Thank you.
Does the spatstat or R need bigger memory?
Paul Hiemstra wrote:
CT YU wrote:
Hi all,
When I use the function envelope(???,pcf,i=???,j=???), there are some
errors
as followings:
Error: cannot allocate vector of size 5.3 Mb
In addition: Warning messages:
1: In vector(double,
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