Just out of curiosity, what system do you have?
These are the results in my machine:
system.time(exp(m), gcFirst=TRUE)
user system elapsed
0.520.040.56
library(pnmath)
system.time(exp(m), gcFirst=TRUE)
user system elapsed
0.660 0.016 0.175
Juan Pablo
Hi,
Is there a way to do it?
For example I have the following vector:
print(myvector)
[1] -295.8045 -295.8045 -295.8045 -295.8045 -325.4754 -295.8045 -295.8045
[8] -295.8045 -413.2099 -295.8045
I want it to return -295.8045, which occur most often.
- Gundala Viswanath
Jakarta - Indonesia
Hi Gundala,
This would be a way to do it:
names(which.max(table(myvector)))
For example:
set.seed(99)
y - sample(letters[1:3], 40, replace=TRUE)
[1] b a c c b c c a b a b b a b c b
[17] b a a a a a c b c b a c a a b a
[33] b b a b c c b c
table(y)
y
a b c
14 15 11
If you just want the value which is the most frequent try
as.numeric(names(which.max(table(c( -295.8045 ,-295.8045, -295.8045,
-295.8045 ,-325.4754 ,-295.8045, -295.8045, -295.8045, -413.2099,
-295.8045)
[1] -295.8045
There may be easier ways
Regards
Duncan Mackay
Department of
Hi Paul,
Can someone explain why the childNames below
gives
character(0)
instead of the (canonical) names of the children grobs
of the xaxis gTree ?
[1] major ticks labels
The problem is that you xaxis has an 'at' component of NULL, which means
that the axis calculates its tick marks
leeznar wrote:
Dear all:
I ‘m a newer. I have some problem when I check my package.
The error messages were as follows. It shows that the problem is about Rd
file. How can I find where the error is? How can I do??
Inside your log directory, you should have bear-manual.tex and
Thank you Martin! This code is amazing! SO fast! Exactly what i was
looking for!
Parsing ~8M lines (~ 600M file size) took about 45s on a Xeon 3,4 Ghz (8
Gb).
Thank you so much!
Sincerely,
Paolo
Martin Morgan ha scritto:
Paolo Sonego [EMAIL PROTECTED] writes:
I apologize for giving
Sorry, my original message used the term 'shingle' where I meant to
use the term 'strip'. That is, I'm looking to merge the strip of text
naming the shingles.
Mike
On 10-Jul-08, at 1:47 AM, Mike Lawrence wrote:
Hi all,
By default a call to xyplot from the Lattice package when using 2
Hello,
I have to merge several serie by date. I used:
cb-merge(cbds,cbbond,by=c(date),all=T).
I have the daily and the high frequency data.
Unfortunately, the programm did not sort by sort
my data in a chronological manner.
Is there any possibility to do this in R?.
Thanks in advance,
Silke
Hello,
I have the data whcih are not balanced (several missing observations),
and one possibility is t use interpolation method
to get the information missing in this series from other series.
Does anybody know how I can program interpolation of
series1 (which ahs missing observations) and series
Hi, where did you find the Peter Rossi test.zip file??
Xiaohui Wang wrote:
I followed the instruction of building R package on PC by Peter Rossi. I
got
problem when I tried to build a R package from his example, test.zip. The
problem occurs when I tried to
R CMD check test
the
Dear all,
I am running a quantile estimation with Sparse matrix and when I run
the procedure rq.fit.sfn I receive the following warning: tiny
diagonals replaced with Inf when calling blkfct.
Does anyone knows exactly what does it mean? What's this kind of
error? Should I get worried about this
Tine wrote:
Hi!
I was just wondering is there anyway to overload operator for custom
class.
For example:
I have two matrices A and B with same dimensions. I want to overload
operator '+' with my own function.
Or even better can I create my own (new) operator.
Example:
A+-B where '+-'
did you remark you obtain the half of rows (636615*2=1273230) ; maybe the
columns aren't good sliced
phoebe kong wrote:
Dear all,
I have problem when reading a table into R. The total row of read in table
has is much less than the original saved table.
I built a 1,273,230 by 6 data set
Hi,
I have a problem sorting a table;
When I read a table into R by x - read.table() I get something like
this:
V1 V2 V3
yes 1 3
no 2 6
yes 3 9
no 4 12
Now I want to generate a vector of V2.
But R should only put in the numbers of V2 into
Hi
You can try the intro book by Peter Dalgaard and I found useful also
R-tips (statsRus), You can find it through google.
Regards
Petr
[EMAIL PROTECTED] napsal dne 10.07.2008 06:25:36:
Thanks! I'll use the which.min function. I've been learning R from the
pdfs
on the CRAN website, but
Jörg Groß wrote:
Hi,
I have a problem sorting a table;
When I read a table into R by x - read.table() I get something like
this:
V1V2V3
yes13
no26
yes39
no412
Now I want to generate a vector of V2.
But R should only put in the numbers of V2
Jörg Groß wrote:
I have a problem sorting a table;
When I read a table into R by x - read.table() I get something like this:
V1V2V3
yes13
no26
yes39
no412
Now I want to generate a vector of V2.
But R should only put in the numbers of V2 into the new
Type
?ifelse
in the R prompt and hit enter
you will have to put the yes (or the no) in in your ifelse command.
Best,
Daniel
Jörg Groß wrote:
Hi,
I have a problem sorting a table;
When I read a table into R by x - read.table() I get something like
this:
V1V2 V3
yes
http://www.ats.ucla.edu/stat/r/faq/sort.htm
Best,
daniel
sprohl wrote:
Hello,
I have to merge several serie by date. I used:
cb-merge(cbds,cbbond,by=c(date),all=T).
I have the daily and the high frequency data.
Unfortunately, the programm did not sort by sort
my data in a
Please do read the posting guide. Please provide self-contained code (calls
to randomly generated data) and illustrate (e.g. in a small table) what you
want to do and also illustrate (with the self-contained code) where your
current approach (if any) fails. After reading your message, I have only
[EMAIL PROTECTED] napsal dne 10.07.2008 08:10:36:
Hello,
I have to merge several serie by date. I used:
cb-merge(cbds,cbbond,by=c(date),all=T).
I have the daily and the high frequency data.
Unfortunately, the programm did not sort by sort
Maybe ?sort or ?order can help you. I presume
On Thu, Jul 10, 2008 at 6:26 AM, Vincent Goulet
[EMAIL PROTECTED] wrote:
Le mer. 09 juil. à 06:20, Rainer M Krug a écrit :
Hi
I tried to install rkward under ubuntu hardy heron, but it tried to
use the one from the cran repository which was newer, but it did not
install. To be able to
Dear all,
I am running a quantile estimation with Sparse matrix and when I run
the procedure rq.fit.sfn I receive the following warning: tiny
diagonals replaced with Inf when calling blkfct.
Does anyone knows exactly what does it mean? What's this kind of
error? Should I get worried about this
Hi list,
I have an database (30.000 entrys) that my R is not modelling into betareg()
so I decided to do an sample and uses an bootstrap to give me the correct
estimates to the variance. Anybody knows what library can I use in this
case?
Regards,
Atenciosamente,
Leandro Lins Marino
Centro de
Dear R-users,
I'd like to turn a vector so it starts with it's end. For better
understanding, this set of commands will do what I need:
i - seq(1:10)
i_turned - i
for (j in 1:length(i)) i_turned[j] - i[length(i)-j+1]
now, i_turned is what I call turned. Is there a function which would make a
See ?rev
On Thu, Jul 10, 2008 at 8:56 AM, Zroutik Zroutik [EMAIL PROTECTED] wrote:
Dear R-users,
I'd like to turn a vector so it starts with it's end. For better
understanding, this set of commands will do what I need:
i - seq(1:10)
i_turned - i
for (j in 1:length(i)) i_turned[j] -
It is called 'rev', see ?rev.
rev(1:10)
[1] 10 9 8 7 6 5 4 3 2 1
G.
On Thu, Jul 10, 2008 at 01:56:58PM +0200, Zroutik Zroutik wrote:
Dear R-users,
I'd like to turn a vector so it starts with it's end. For better
understanding, this set of commands will do what I need:
i -
rev(1:10)
[1] 10 9 8 7 6 5 4 3 2 1
Javier
Dear R-users,
I'd like to turn a vector so it starts with it's end. For better
understanding, this set of commands will do what I need:
i - seq(1:10)
i_turned - i
for (j in 1:length(i)) i_turned[j] - i[length(i)-j+1]
now,
Thanks all of you. It's really catchy name for the wanted function
(reverse), somehow I could not find it unfortunately :( Z
On Thu, Jul 10, 2008 at 2:04 PM, Gabor Csardi [EMAIL PROTECTED] wrote:
It is called 'rev', see ?rev.
rev(1:10)
[1] 10 9 8 7 6 5 4 3 2 1
G.
On Thu, Jul
On Thu, Jul 10, 2008 at 5:09 AM, Peter Dalgaard
[EMAIL PROTECTED] wrote:
Tine wrote:
Hi!
I was just wondering is there anyway to overload operator for custom
class.
For example:
I have two matrices A and B with same dimensions. I want to overload
operator '+' with my own function.
Or even
hadley wickham wrote:
On Thu, Jul 10, 2008 at 5:09 AM, Peter Dalgaard
[EMAIL PROTECTED] wrote:
Tine wrote:
Hi!
I was just wondering is there anyway to overload operator for custom
class.
For example:
I have two matrices A and B with same dimensions. I want to overload
operator
Yeah,
It is a IF-THEN-ELSE.
Possible combinations are c4...c7. I know how to combine them in a plot.
But what I don't know is to build a function which return a plot depending
on those conditions !!!
Any help?
Thanks,
Adel Tekari
jholtman wrote:
It sounds like an IF-THEN-ELSE should do the
The canonical answer is: It is R, so everything is possible.
Sounds like you need to read what is produced by
?summary.rq
carefully.
url:www.econ.uiuc.edu/~rogerRoger Koenker
email [EMAIL PROTECTED] Department of Economics
vox:
So the solution is : tapply(content, list(factor1, factor2), mean)
An example of what it does :
my.data
name item vote
1 Ricardo Coke 20
2 Ricardo Fanta 60
3 Ricardo Pepsi 100
4 Marie Pepsi 40
5 Marie Coke 60
6 Julia
This shouldn't be hard, but it's just not
coming to me:
Given a vector, e.g.,
v - c(20, 134, 45, 20, 24, 500, 20, 20, 20)
how can I get the index of the last value in
the vector having a value greater than n, in
this case, greater than 20? I'm looking for
an efficient function I can use on very
Try this:
v[max(which(v 20))]
On Thu, Jul 10, 2008 at 9:41 AM, Thaden, John J [EMAIL PROTECTED] wrote:
This shouldn't be hard, but it's just not
coming to me:
Given a vector, e.g.,
v - c(20, 134, 45, 20, 24, 500, 20, 20, 20)
how can I get the index of the last value in
the vector having a
I think the problem is that you are trying to plot non-numeric values
on your x. I built some test code around your example; I don't think
you can plot non-numeric characters. If the plot is working on your
end, it's likely because it's recognizing your X variable as a factor
and it's plotting the
Hi,
Just so this doesn't end up being a dead-end post, here's what I figured out:
It's a GSview issue- for whatever reason, the version of GSview (4.9)
that I am using doesn't recognize WinAnsi encoding. I imagine there is
a way to fix this, but I don't care, because specifying an alternative
if it is a time series the interpolation methods in zoo are an option.
On Thu, Jul 10, 2008 at 6:41 AM, Daniel Malter [EMAIL PROTECTED] wrote:
Please do read the posting guide. Please provide self-contained code (e.g.
to
randomly generate data) and illustrate (e.g. in a small table) what you
Try this:
Lines - Q1-60 26.528 1.268
Q2-60 27.535 1.087
Q3-60 27.737 1.346
Q4-60 28.243 3
Q1-61 26.462 3.272
Q2-61 27.769 3.863
Q3-61 27.903 4.606
Q4-61 31.673 4.1
Q1-62 28.211 5.395
Q2-62 29.469 5.554
Q3-62 30.249 4.903
library(zoo)
# z - read.zoo(myfile.dat, FUN = as.yearqtr, format = Q%q-%y)
ACroske Audy3272 at yahoo.com writes:
Ben:
Thanks for the reply. One further question, and this is where my novice
status at R shows through. The code makes sense, but what would I put it for
m? Is it the same number for all three (that was my first thought since it
was the same
Try
help.search('interpolate')
and
help.search('impute')
(most of the responses to the latter come from packages that you may
not have installed, such as Hmisc)
-Don
At 8:15 AM +0200 7/10/08, [EMAIL PROTECTED] wrote:
Hello,
I have the data whcih are not balanced (several missing
Does this thread solve your problem? -
https://stat.ethz.ch/pipermail/r-help/2007-July/136814.html
On 10-Jul-08, at 3:15 AM, [EMAIL PROTECTED] wrote:
Hello,
I have the data whcih are not balanced (several missing observations),
and one possibility is t use interpolation method
to get the
Dear list,
using the packages Hmisc and lattice i produced some nice xYplots. However,
since the data range of the conditioning variable is very big, i need to
define more than one y-scale for the plot (in some panels you just see a
flat line of data points very close to the x-axis), e.g.
Dear All,
It is not a typical R question (though I use R for this) but I thought someone
will help me. For the list of P values, I have calculated FDR using p.adjust()
in R (bioconductor). But my FDR values are same for all the P values. When do
we get same FDR values? Does the smallest P
Hi
Are all your input p values the same? If so your output FDR values would
be the same.
Or are all your p-values relatively large? Then (nearly) all your FDR
values might be 1.
Why don't you put a small example up of what you did? Then we could see
what method you used etc.
Regards
JS
Creating variables for small dataset is very mundane, but lately I am dealing
with 10^7 by 10^3 datasets which eats up alot of memory. How can I monitor how
much has been used or reserved ?
_
[[alternative HTML version
As I understand it, Duncan MacKay's solution involves simply pasting
the factors together, as in:
|_AX_|_AY_|_BX_|_BY_|
Which isn't quite as aesthetically pleasing as what I I'm looking for:
|___A___|___B___|
|_X_|_Y_|_X_|_Y_|
Any further suggestions?
Mike
On 10-Jul-08, at 2:43 AM,
Hi All,
This is a rather general post to begin with. This is because I need to
provide you some important context. There are very R specific elements to
this further along in this rather long posting so I thank you in advance
for your patients.
I will do my best to clearly explain my experiment,
Hi, I'd like to create a S4 class contains only one type of data.
However, the number of slots varies.
For example, I want to create a class a, each slots in a contains
numeric value only.
setClass(a, contains = numeric)
If I want to create an object a with only one slot
I hope you don't really want our patients :)
It looks that you have an experiment with two groups. You have several
trials for each group. And within each trial you observe your units a
distinct points in time.
The first advice for you is to graphically display your data. Before you
start
Juan Pablo Romero Méndez [EMAIL PROTECTED] writes:
Just out of curiosity, what system do you have?
These are the results in my machine:
system.time(exp(m), gcFirst=TRUE)
user system elapsed
0.520.040.56
library(pnmath)
system.time(exp(m), gcFirst=TRUE)
user system
I have a longitudinal data set in long format and I want to run
individual regressions. I do this by using the by() function as
follows:
temp - by(tolerance.pp, tolerance.pp$id, function(x)
summary(lm(tolerance ~ time, data=x)))
This works fine. Coefficients for the first two subjects
Li, Xuejun [EMAIL PROTECTED] writes:
Hi, I'd like to create a S4 class contains only one type of data.
However, the number of slots varies.
For example, I want to create a class a, each slots in a contains
numeric value only.
setClass(a, contains = numeric)
If I want to create an
On Thu, Jul 10, 2008 at 5:15 PM, Andrew Jackson [EMAIL PROTECTED] wrote:
Hi All,
Hi Andrew,
The main questions here are not R-related, but statistical modelling
questions, and much too broad for the R list. They are things you'd
ask a (paid) statistical consultant. I would suggest taking
On Thu, Jul 10, 2008 at 11:06 AM, Daniel Malter [EMAIL PROTECTED] wrote:
I hope you don't really want our patients :)
It looks that you have an experiment with two groups. You have several
trials for each group. And within each trial you observe your units a
distinct points in time.
The
Hi All,
Title: Non-normal data issues in PhD software engineering experiment
I hope I am not breeching any terms of this forum by this rather general
post. There are very R specific elements to this rather long posting.
I will do my best to clearly explain my experiment, goals and problems
I do not understand how to interpret this to find the T Value for the data.
Is there a way to figure this out, or another function that will provide
this for me using Fisher's Exact Test?
The outcome of my data is listed below.
data: DATA
p-value = 0.1698
alternative hypothesis: true odds
I have just installed Rmpi on a Suse 9.1 linux cluster with
openmpi-1.0.1. I am trying the example included below from the tutorial
website. However, I keep getting the following error:
# Load the R MPI package if it is not already loaded.
if (!is.loaded(mpi_initialize)) {
+
Hi Dave,
As I know there is no T value for Fisher's exact test (no matter you
use SAS, R or other packages)
Fisher's exact test is for the categorical data analysis.
Fisher's exact test for testing the null of independence of rows and
columns in a contingency table with fixed marginals
so
Hi Henning,
have a look at the scales argument in the xyplot documentation.
You could try adding the following to your code:
scales=list(y=list(relation=free))
Cheers,
Christoph
Thursday, July 10, 2008, 4:35:28 PM, you wrote:
Dear list,
using the packages Hmisc and lattice i produced
pnmath currently uses up to 8 threads (i.e. 1, 2, 4, or 8).
getNumPnmathThreads() should tell you the maximum number used on your
system, which should be 8 if the number of processors is being
identified correctly. With the size of m this calculation should be
using 8 threads, but the exp
I did a search on my system and it seems like R.h and the other files are not
on the system. Also, CRAN or a google search does not seem to have any relevant
info about these files.
Here's the most relevant one in regards to Rversion.h:
[Rd] Rversion.h [EMAIL PROTECTED] [EMAIL PROTECTED]
Henning Wildhagen HWildhagen at gmx.de writes:
Dear list,
using the packages Hmisc and lattice i produced some nice xYplots. However,
since the data range of the conditioning variable is very big, i need to
define more than one y-scale for the plot (in some panels you just see a
flat
Christoph Meyer christoph.meyer at uni-ulm.de writes:
Hi Henning,
have a look at the scales argument in the xyplot documentation.
You could try adding the following to your code:
scales=list(y=list(relation=free))
Cheers,
Christoph
Yes, but this apparently doesn't work for
Do you really want to sort a *matrix*, or do you mean a data.frame? See
?order.
Angelo Scozzarella wrote:
Hi,
I want to sort a matrix by a specific variable without changing the row
binding between variables.
Ex.
NameSexAge
FredM24
JohnM18
MaryF
Has anyone successfully compiled pnmath (http://www.stat.uiowa.edu/~luke/R/experimental
) for an intel processor running mac OS 10.5? When I attempt to do so
via the R package installer (choosing Local Source Package and
pointing to the pnmath_0.0-2.tar.gz file), I get the following errors:
Dear Angelo,
What about this?
mydata=read.table(textConnection(NameSex Age
FredM 24
JohnM 18
MaryF 21), header=TRUE,sep=)
mydata[order(mydata$Age),]
HTH,
Jorge
On Thu, Jul 10, 2008 at 2:21 PM, Angelo Scozzarella
[EMAIL
On 10-Jul-08 16:49:57, DaveFrisch wrote:
I do not understand how to interpret this to find the T Value
for the data.
Is there a way to figure this out, or another function that will
provide this for me using Fisher's Exact Test?
If I interpret your query correctly, you are expecting to find
Search is not working after starting the help facility using the
help.start function. The firefox browser says the applet has started,
but nothing happens What to do to get it working? Versions of R, java,
and firefox are shown below.
Thanks,
Carlisle
version
_
platform
1. This is a data frame, not a matrix ! -- ?data.frame
2. help.search(sort) is the first thing you should have done. You probably
wouldn't have needed to post if you had.
3. The canonical answer is ?order and indexing -- as in:
yourdf[order(yourdf$Age),]
Note that order() can be used to sort
Hi:
I have a function as follows:
my.plot- function( x, y = NULL, ... )
{
plot( x, y, cex.axis=0.5, ...)
}
Set up the variables:
x - 1:10; y - x; tdf - data.frame( x, y ); main.str - test
I will exercise the function in two ways:
my.plot( y ~ x, tdf, main = test )
This works fine
The 'polynom' package provides one example of how to do this.
However, getAnywhere(+.polynomial) just told me no object named
‘+.polynomial’ was found; I don't know why. The documentation says it
uses S3 classes. The 'Matrix' package should provide other examples,
using S4 classes.
You need a gcc version that supports OpenMP; I believe that means gcc
4.2 or later.
pnmath0 should work with older gcc versions.
luke
On Thu, 10 Jul 2008, Mike Lawrence wrote:
Has anyone successfully compiled pnmath
(http://www.stat.uiowa.edu/~luke/R/experimental) for an intel processor
Hi everyone,
Thanks very much for all your replies.
I'm interested in hearing more about the lag function. I remember coming
across this in the R intro manual, but I couldn't figure out how to apply it
to my case. Does anyone know how it is applied, assuming a time series data
frame?
Thanks,
Hi,
Round(0.55,1)=0.5
Round(2.55,1)=2.6
Can this be right?
Thanks,
Ed
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
Hi, everybody.
I have visited the revolution computing web page, but its not clear when or
what will be the new release be. Does anybody have information about that.
Thank you
Mariana
John Maindonald wrote:
Does anyone know any more than is in the following press release
about REvolution
Okay, so I'm fairly retarded, and asked a question about finding the T-Value
in the Fisher Exact method. I suppose what I'm truly after can best be
explained by the Biddle Consulting site that has a program setup to deal
with this kind of thing. Unfortunately, it is not currently functioning,
Playing with ggplot, something I'd promised myself I'd get around to. I've
the following scenario:
library(lattice)
library(ggplot2)
myData - data.frame(
x = rnorm(100),
y = rnorm(100),
group = 1:4
)
xyplot(y ~ x | factor(group), data = myData, layout = c(2, 2))
Hi,
I'm trying to run a garch model. and I want to use the predict
function to predict ahead the conditional standard deviation.
but when I run the predict function I get the same number of return as my data.
How should I define the number of days looking ahead in garch predict?
I really
On 11/07/2008, at 8:07 AM, Korn, Ed (NIH/NCI) [E] wrote:
Hi,
Round(0.55,1)=0.5
Round(2.55,1)=2.6
Can this be right?
Yes.
Rolf Turner
##
Attention:\ This e-mail message is privileged and
See ?lag and in zoo ?lag.zoo. Both pages have
examples. Using lag.zoo here it is with your data:
Lines - Date Apples Oranges Pears
1/7 2 35
2/7 1 47
3/7 3 810
4/7 5 72
5/7 6 3
On 10-Jul-08 20:43:12, DaveFrisch wrote:
Okay, so I'm fairly retarded, and asked a question about finding
the T-Value in the Fisher Exact method. I suppose what I'm truly
after can best be explained by the Biddle Consulting site that has
a program setup to deal with this kind of thing.
Max Friends,
I've run into a problem with odfWeave 0.7.5 running under R 2.7.1
(Windows XP, SP2) doing some monthly production reports.
Under 2.7.1 I'm getting various parsing errors after Sweaving starts, e.g.:
Sweaving content.Rnw
Writing to file content_1.xml
Processing code chunks
Actually my last reply will drop one row since its pushed off
to beyond the data range. You can avoid that with zooreg:
# from before for comparison
lag(z, -1, na.pad = TRUE)
# pure shift - note use of zooreg here
# Unlike lag.zoo, lag.zooreg can shift beyond data range
zr - as.zooreg(z)
I just noticed that CRAN Package check Error for Windows Mac:
http://www.r-project.org/nosvn/R.check/r-patched-windows-x86_64/odfWeave-00check.html
-Jim
On Thu, Jul 10, 2008 at 3:03 PM, Jim Porzak [EMAIL PROTECTED] wrote:
Max Friends,
I've run into a problem with odfWeave 0.7.5 running
On Thu, Jul 10, 2008 at 3:28 PM, Jim Price [EMAIL PROTECTED] wrote:
Playing with ggplot, something I'd promised myself I'd get around to. I've
the following scenario:
library(lattice)
library(ggplot2)
myData - data.frame(
x = rnorm(100),
y = rnorm(100),
group = 1:4
I think it's rather presumptuous of you to ask whether a fundamental
behavior that you don't understand in a mature software product that has
been used by literally thousands of people for around 10 years (20 for S)
is a bug, don't you?
So the answer is, no, this is how R's evaluation mechanism
Dear all,
When I print out princomp's loading outputs, there is alwasy a section for SS
loading, Proportional Var and Cumulative Var. Anybody can tell what they
are for? Or anyone can direct me to some reference to read about?
Any help will be highly appricated.
Hongsheng
Please provide a self-contained example with a post like this. I guess you
mean the output of the last line below? It looks those are just the
theoretical proportions if your data is perfectly orthogonal. I found those
values invariant to changing the distributional parameters of the variables,
u... ?princomp ** does give you references **. Did you not first check
this before posting?
-- Bert Gunter
Genentech, Inc.
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On
Behalf Of Wu, Hong-Sheng
Sent: Thursday, July 10, 2008 4:01 PM
To: r-help@r-project.org
I got
round(0.55,1)
[1] 0.6
round(2.55,1)
[1] 2.5
Your answers are also correct. Please check ?round
Quoting Korn, Ed (NIH/NCI) [E] [EMAIL PROTECTED]:
Hi,
Round(0.55,1)=0.5
Round(2.55,1)=2.6
Can this be right?
Thanks,
Ed
[[alternative HTML version deleted]]
on 07/10/2008 01:39 PM Carlisle Thacker wrote:
Search is not working after starting the help facility using the
help.start function. The firefox browser says the applet has started,
but nothing happens What to do to get it working? Versions of R, java,
and firefox are shown below.
Thanks,
The problem is that neither 0.55 nor 2.55 are exact machine numbers (the
computer uses binary representation), so it may happen that the machine
representation of 0.55 is slightly less than 0.55 while the machine
representation of 2.55 is slightly above 2.55.
--- On Fri, 11/7/08, Korn, Ed
I am having difficulty installing packages. For example, here I have tried to
install gplots but to no avail. I have tried multiple mirrors and
different packages (errbar) but after installation I seem to be unable to
access any of the commands or help pages. I am a little concerned about the
Actually, your result is strange, since if x = 0.55 then a hexadecimal
representation of x*100 is 404B8000 0001 which is above 55, meaning that x
is above 0.55 and should have been rounded to 0.6, while if x = 2.55 then the
hexadecimal representation of x*100 is 406FDFFF which is
You must load the package with the library function after installing it.
so:
library(gplots)
and then
?plotCI
hippie dream wrote:
I am having difficulty installing packages. For example, here I have tried to
install gplots but to no avail. I have tried multiple mirrors and
different
On 11/07/2008, at 12:47 PM, hippie dream wrote:
I am having difficulty installing packages. For example, here I
have tried to
install gplots but to no avail.
snip
install.packages()
snip
** building package indices ...
* DONE (gplots)
The downloaded packages are
Dear R community,
I am using 6 variables to test for an effect (by linear regression).
These 6 variables are strongly correlated among each other and I would like
to find out the number of independent test that I perform in this
calcuation. For this I calculated a matrix of correlation
1 - 100 of 108 matches
Mail list logo
