DISCCRS wrote:
Hi,
I have a dataset of historical monthly temperature data that is grouped by
weather station. I want to create z-scores of the monthly data using a base
period of a subset of years. I subset the dataset first to include only data
from the years (V2) that make up the base period
Hi I don't want to ignore the date row.
See basically my first row is the date column and the 1st column is the
stocks name.
Now using the if loop I have to find prices of stocks corresponding to a
date.
I hope the problem is clear to you now
For example
Stocks 30-Jan-08 28-Feb-08
Hi
What if I need to take dates and stock names from these table...i mean I need
to read in this table and then use if function and extratc the data from FOO
Identifier weight Start_Date End_Date
a 6.7631Jan06 31Jan07
g 2.8628Feb06 28Feb07
e 22.94 31Mar06
Dear All,
I have two questions regarding distribution fitting.
I have several datasets, all left-truncated at x=1, that I am attempting
to fit distributions to (lognormal, weibull and exponential). I had
been using fitdistr in the MASS package as follows:
fitdistr-(x,weibull)
However, this
Ben Bryant wrote:
Greetings -
Is anyone aware of an automatic code diagrammer/flow chart creator that
works for the R language (either a contributed package, or external
software)? I need to explain some code structure of a package I'm working
on to non-R users, and would find it extremely
He everybody,
Well I have a biplot CCA-like origined from plot.cca (vegan package). I need to
rotate on y axis the lines and symbols of constrained and sites representation.
If I do that on an image editor, I rotate everything, including titles, axes
labels and positions. I just need to rotate
For example
Stocks 30-Jan-08 28-Feb-08 31-Mar-08 30-Apr-08
a 1.003.007.003.00
b 2.004.004.007.00
c 3.008.00655.00 3.00
d 4.0023.00 4.005.00
e 5.0078.00 6.005.00
OK
I have several datasets, all left-truncated at x=1, that I am
attempting
to fit distributions to (lognormal, weibull and exponential). I had
been using fitdistr in the MASS package as follows:
A possible solution is to use the survreg() in the survival package
without specifying the
Perhaps it would be easier to try something like this:
df1 - read.table(filename, ... ) # All columns read as characters
df1 - t(df1) # Transpose df1
write.table - (df1, newfile, ...) # Write the transposed data
# to a new file
df2 -
hi folks,
I believe that the construction
y ~ A + (A|B)
(where A is a categorical variable for a fixed effect and
B is a categorical variable for a random effect) will generate random
effects for all of the fixed effect coefficients. That is, in addition
fitted a systematic fixed effect
Hi Rodrigo,
I need to rotate on y axis the lines and symbols of constrained and sites
representation.
Easiest is to multiply the axis you want to invert by -1. Something like the
following, where my.cca is the orginal object and yax = obj[, 2] (xax being
obj[, 1]). Obviously, copying isn't
Hi Rodrigo,
Sorry, that will not return a result (I use several different ordination
packages, in most of which this is possible). What you need to do with vegan
is the following:
scores(mynew.cca)$species[, 2] - scores(mynew.cca)$species[, 2] * -1
You will be able to do the rest.
Regards,
Quotes
I probably have an unhealthy attraction to the powers of Excel. I taught my
daughter how to use it when she was 7. When I teach corporate finance, I try to
make sure that my law students come away from the course knowing how to crunch
in Excel.
And R is probably not kept up to speed on
Hi,
I noticed the temperature of my laptop rises sharply during execution of a
long R script that generates several hundred plots, all of them saved to
files. No screen output. Temps reached above 90 Celsius degrees in the box
and above 80 C deg in the processor. The machine turns on cooler at
Hi!
I am working on scorecard model and I have arrived at the regression equation.
I have used logistic regression using R.
My question is how do I validate this model? I do have hold out sample of 5000
customers.
Please guide me. Problem is I had never used Logistic regression earlier
What if I need to take dates and stock names from these table...i mean I
need to read in this table and then use if function and extratc the
data from FOO
Not sure what exactly the problem is. Can you give an example? Of course
the first thing would be to make sure that dates are in the same
mbr wrote:
I have found lots of good advice on this forum about stacked area charts but
I’ve run into problems with the 2 recommended options: stackploy in plotrix
or qplot in ggplot2. I have a many page report that will be in a 2x2 page
format “par(mfrow=c(2,2))”” and need one of the page
On Tue, Oct 7, 2008 at 10:36 AM, [EMAIL PROTECTED] wrote:
Hi,
I have a data in which the first row is in date format and the first
column is in text format and rest all the entries are numeric. Whenever
I am trying to read the data using read.table, the whole of my data is
converted in to
Why don't you hack a little script that looks at system load,
temperature and date/time and writes it somewhere. Then
you can load it into R and plot it nicely :-))-O
Even compare it witht he desktop :-)-O
el
on 10/7/08 12:21 PM Alexandre Aguiar said the following:
Hi,
I noticed the
A follow-up to Need to calculate within- and between-run CV
I have a dataset of 210 Samples, of which each was run several times in
several consecutive days. A dataset for one sample is below:
qu.s -
structure(list(Sample = c(44L, 44L, 44L, 44L, 44L, 44L, 44L,
44L, 44L, 44L), Run = c(1L, 1L,
Thanks a lot for your help (again) Mark.
I adapted your suggestion to my analysis.
But I'm getting and error when trying to apply the new values.
The error is:
Erro em scores(CAPpotiFTI)$species[, 2] - scores(CAPpotiFTI)$species[, :
não foi posssível encontrar a função scores-
Translating:
Hi
I have a data frame containing numeric and factor data.
I want to extract the numeric data only. How can this be done?
Thanks
Meir
Meir Preiszler - Research Engineer
I t a m a r M e d i c a l Ltd.
Caesarea, Israel:
Tel: +(972) 4 617 7000 ext
Maithili Shiva wrote:
Hi!
I am working on scorecard model and I have arrived at the regression equation.
I have used logistic regression using R.
My question is how do I validate this model? I do have hold out sample of 5000
customers.
Please guide me. Problem is I had never used Logistic
Meir Preiszler wrote:
Hi
I have a data frame containing numeric and factor data.
I want to extract the numeric data only. How can this be done?
Thanks
Meir
d[sapply(d,is.numeric)]
--
O__ Peter Dalgaard Øster Farimagsgade 5, Entr.B
c/ /'_ --- Dept. of
Alexandre Aguiar wrote:
Hi,
I noticed the temperature of my laptop rises sharply during execution of a
long R script that generates several hundred plots, all of them saved to
files. No screen output. Temps reached above 90 Celsius degrees in the box
and above 80 C deg in the processor. The
carlos.grohmann at gmail.com writes:
Hello all. This is likely to be a silly question, but I have a set of
data points and I want to fit a curve to it, like this:
http://www.igc.usp.br/pessoais/guano/temp/curve.png
While you could use a loess-curve, interpreting the rising branch a the
end
A simple example:
temp - as.Date('2001-10-5')
class(temp)
Date
How do I tell if Date is implemented as an S3 or an S4 class type?
I tried ?class, but didn't see anything obvious. Functions like inherit() work
equally well with both types (which is a good thing).
Thanks Hadley, for some reason I didn't see your email until now. It
works fine with the development version,
library(plyr)
df - data.frame(a=1:10 , b=1:10)
foo1 - function(a, b, cc=0, d=0){
a + b + cc + d
}
mdply(data. = df, foo1, cc=1, d=2)
I think using . prefixes is a safer option
On 07/10/2008 10:41 AM, Terry Therneau wrote:
A simple example:
temp - as.Date('2001-10-5')
class(temp)
Date
How do I tell if Date is implemented as an S3 or an S4 class type?
I tried ?class, but didn't see anything obvious. Functions like inherit() work
Bang on!!
Thanks for the help
Rahul Agarwal
Analyst
Equities Quantitative Research
UBS_ISC, Hyderabad
On Net: 19 533 6363
-Original Message-
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of Philipp Pagel
Sent: Tuesday, October 07, 2008 2:52 PM
To:
I am performing many permutations on a data-set with each permutation
producing a variable number of results. I thought that the best way to keep
track of all this in one object would be with a list ('res.lst'). To address
these variable results for each permutation I attempted to construct this
Julia S. julia.schroeder at gmail.com writes:
Now, I did that in my article and I got a response from a reviewer that I
additionally should give the degrees of freedom, and the F-statistics. From
what I read here, that would be incorrect to do, and I sort of intuitively
also understand why
Hi,
how can I attach variable labels originally read by read.spss() to the
resulting variables?
pre
X - read.spss('data.sav', use.value.labels = TRUE, to.data.frame =
TRUE, trim.factor.names = TRUE, trim_values = TRUE, reencode = UTF-8)
names(X) - tolower(names(X))
attach(X)
/pre
Thank
Alexandre Aguiar asaguiar at spsconsultoria.com writes:
I noticed the temperature of my laptop rises sharply during execution of a
long R script that generates several hundred plots, all of them saved to
files. No screen output. Temps reached above 90 Celsius degrees in the box
and above
Hi Frank,
Thanks for your feedback! But I think we are talking about two different
things.
1) Validation: The generalization performance of the classifier. See,
for example, Studies on the Validation of Internal Rating Systems by
BIS.
2) Calibration: Correct calibration of a PD rating system
Hi Rodrigo,
Sorry again: the structure vegan uses is quite complex. Technically you
should use the extractor function scores() to extract what you want from the
object, e.g. scores(my.cca, display=species) or scores(my.cca,
display=cn) [centroids]. I did work out a quicker way of reversing axes,
Why m I getting this message
data=read.table(H:/Rahul/london/david/rexcel/price1.txt,header=T,check.names=F,row.names=1)
Error in read.table(H:/Rahul/london/david/rexcel/price1.txt, header = T, :
duplicate 'row.names' are not allowed
Rahul Agarwal
Analyst
Equities Quantitative Research
On Tue, 7 Oct 2008, [EMAIL PROTECTED] wrote:
I have several datasets, all left-truncated at x=1, that I am
attempting
to fit distributions to (lognormal, weibull and exponential). I had
been using fitdistr in the MASS package as follows:
A possible solution is to use the survreg() in the
Dear all,
I am running a code using bootstraps for estimating standard errors but the
mac crashes. When I use small number of bootstraps (100) it works fine but
if I increase that number it crashes.
Thanks in advance
dimitris
The code, the error and my mac characteristics are the following:
Dear list,
I've been trying this for a few hours and I just don't understand how
lattice works with groups and subscripts.
Consider the following example,
xx - seq(1, 10, length=100)
x - rep(xx, 4)
y - c(cos(xx), sin(xx), xx, xx^2/10)
fact - factor(rep(c(cos, sin, id, square),
Antje niederlein-rstat at yahoo.de writes:
I get a strange behaviour of a boxplot with the following code. There seems
to
be a problem with the xlim-parameter. Did I do anything wrong? What else can
I
do to force the boxplot to have a defined x-range?
x - rnorm(100)
boxplot(x,
Here is something to try:
result - list()
for (i in 1:2){
+ for (j in 1:2){
+ result[[paste(i, j, sep=|)]] - rep(i,j)
+ }
+ }
result
$`1|1`
[1] 1
$`1|2`
[1] 1 1
$`2|1`
[1] 2
$`2|2`
[1] 2 2
On Tue, Oct 7, 2008 at 11:01 AM, Mark Kimpel [EMAIL PROTECTED] wrote:
I am
Hi Tony --
Tony Breyal [EMAIL PROTECTED] writes:
Dear R-help,
I want to download the text from a web page, however what i end up
with is the html code. Is there some option that i am missing in the
RCurl package? Or is there another way to achieve this? This is the
code i am using:
Thanks a lot for the suggestion!
Unfortunately R --no-save prog.R does not work well with my
situation because prog.R
contain lines such as readline() and () that require user response in
the middle of the
execution. I also tried other options such as R -f prog.R and R
--interactive prog.R,
I am trying to sort a list and the data is obiously not in the right format. I
am trying:
x - list()
x[[A]] - 1
x[[B]] - 2
order(x)
But am getting:
Error in order(x) : unimplemented type 'list' in 'orderVector1'
How should I change the list so that it can be sorted? What kinds of objects
Does anyone know how to retrieve the R squared value for a line on a graph?
Thanks
Georgina
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
Dear all,
We have a data frame x with n people as rows and k variables as columns.
Now, for each person (i.e., each row) we want to calculate a distance
between him/her and EACH other person in x. In other words, we want to
create a n x n matrix with distances (with zeros in the diagonal).
Hello all,
I am fitting a Gamma distribution to some data I have using nls(). The
function obviously runs into issues when using a 0 as a parameter value. I
understand the line alg = port can be used to set the lower bounds to
prevent this from happening. When I run the code I get the following:
I will preface this message by saying that I am not an R developer and no
very little about R...but here is my situation:
One of my users has developed a model for analysing commodity prices. At the
moment when he runs this model on his daily data set it takes roughly 5
hours to complete. He is
Something like
env R_PROFILE=prog.R R
may work for you. You may need to call .First.sys at the beginning of
prog.R to get default packages loaded.
luke
On Tue, 7 Oct 2008, Gang Chen wrote:
Thanks a lot for the suggestion!
Unfortunately R --no-save prog.R does not work well with my
distance() from the ecodist package will calculate Mahalanobis distances.
Sarah
--
Sarah Goslee
http://www.functionaldiversity.org
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
I gather you are using Windows and in that case you could
use RDCOMClient or rcom to get it via Internet Explorer, e.g.
library(RDCOMClient)
ie - COMCreate(InternetExplorer.Application)
URL - https://stat.ethz.ch/mailman/listinfo/r-help;
ie$Navigate(URL)
while(ie[[Busy]]) Sys.sleep(1)
txt -
Try this:
x[order(unlist(x), decreasing = TRUE)]
On Tue, Oct 7, 2008 at 1:28 PM, [EMAIL PROTECTED] wrote:
I am trying to sort a list and the data is obiously not in the right format.
I am trying:
x - list()
x[[A]] - 1
x[[B]] - 2
order(x)
But am getting:
Error in order(x) :
Exactly what were your expections from sorting the list? What did you
expect the answer to look like? You can 'unlist' the list and then
sort the elements:
x[[A]] - 1:10
x[[B]] - 4:12
sort(unlist(x))
A1 A2 A3 A4 B1 A5 B2 A6 B3 A7 B4 A8 B5 A9 B6 A10 B7 B8 B9
1 2 3 4
Hi all,
I have looked around for help on creating GUIs for R, but haven't found
anything. I would be interested in any advice or webpages that have
information on the best language, tutorials etc. for creating simple GUIs.
Mainly I want to do this as a heuristic exercise.
Thanks for any help.
Since objects of class list in R can be made up of heterogeneous
objects, sorting them does not make much sense. For example, does A,
come before or after 1000, does a linear model summary come before or
after pi?
If your data are all numeric, store them as a numeric vector, where sort
Georgina Sarah Humphreys g.humphreys.1 at research.gla.ac.uk writes:
Does anyone know how to retrieve the R squared value for a line on a graph?
Thanks
Georgina
We need a LOT more information to answer your question ...
please read the posting guide and tell us in a bit more
detail
Hi Frank,
If the way distance() calculates the Mahalanobis distance meets your
needs other than the covariance specification, you can tweak that
_very_ easily. If you use fix(distance) at the command line, you can
edit the source.
change the first line to:
function (x, method = euclidean, icov)
Wade,
What type of GUI do you want?
Do you want a full GUI that the user runs to do everything (that uses R as the
computational engine)? Look at R commander, JGR, and the R plugin for Excel as
possible examples.
Are you more interested in a simple GUI for one specific plot or function to
Georgina Sarah Humphreys g.humphreys.1 at research.gla.ac.uk writes:
Does anyone know how to retrieve the R squared value for a line on a graph?
The balloon rule
http://www.jstor.org/pss/2683562
Dieter
__
R-help@r-project.org mailing list
Seek and ye shall find ... Check the RGUI's link on the other web page on
CRAN.
If you are on Windows, there is some simple built-in GUI functionality.
?winMenuAdd, ?select.list and the links therein will get you started there.
Cheers,
Bert Gunter
-Original Message-
From: [EMAIL
Not exactly sure what you want to do, but ...
In your example, you do not need groups, since the color doesn't change
within the levels of the conditioning variable (fact). Hence you can use the
panel.number() function to choose the plotting color of each panel, like
this:
## .. continuing with
Sorry that my post wasn't very clear.
What I am wanting to do is learn to build some simple GUIs for a limited
number of functions. Basically, I am envisioning a screen with check boxes,
a drop down menu etc. that users could select to run analyses on imported
data.
I have worked with VB before,
Dear all,we just realized something. Sarah's distance function - indeed -
calculates mahalanobis distance very well. However, it uses the
observed variance-covariance matrix by default.
What we actually need (sorry for not stating it clearly in to be able to
specify which variance-covariance
Ok Mark, it worked for the species.
I still get an error if I try with biplot (cn,sp), but it's not a problem,
repositioning the species is enough.
Thanks once again.
Just for future consults the error that still remains:
CAPpotiFTI-scores(CAPpotiFT, display=c('bp','species','cn','sites')
Hi,
I have a question to ask. if in a linear regression model, the independent
variables are not statistically significant, is it necessary to test these
variables in a non-linear model? Since most of non-linear form of a variable
can be represented to a linear combination using Taylor's
THank you. I just didn't know the rules. In other languages it is possible to
pass in a 'compare' function so the sort is defined by the function. I guess I
was a) wondering why it failed, and b) if there was a similar work around to
sort generic lists. Also I was specifically addressing the
Hello R users
My goal is to use R to write functions for and automate a series of analyses
i would like to do on a large data set. The calculations are not very
difficult in themselves, however they will be very time consuming (Plus I
think R will be extremely useful and this is another excuse
Thanks for the suggestion, Luke!
Your approach would load prog.R whenever invoking R, but that is not
exactly what I want. Basically I can run prog.R through
source(~/someDir/prog.R) inside R. Also since prog.R involves many
lines of readline() and tclvalue() in tcltk package, the program
Well here is one example where x is not significant in a linear regression:
x - seq( -1,1, 0.1 )
y - x^2 + rnorm(21,0,.1)
summary(lm(y~x))
Would you really want to dismiss any relationship (non-linear) between x and y
based on the above p-value?
--
Gregory (Greg) L. Snow Ph.D.
Statistical
I think prior posters addressed that or maybe what you really want is
a command that accepts your function and automatically constructs
a GUI front end for it. In that case see ggenericwidget in the gWidgets
package and the fgui package. You don't need VB at all for this.
On Tue, Oct 7, 2008 at
On 07-Oct-08 17:46:52, Hsiao-nan Cheung wrote:
Hi,
I have a question to ask. if in a linear regression model, the
independent variables are not statistically significant, is it
necessary to test these variables in a non-linear model?
Since most of non-linear form of a variable can be
Hi, and thanks for your email,
I realise my example was not very good. The actual dataset I'm trying
to plot is rather big and this oversimplified example did not make
much sense.
I actually do need to color different subsets of the data differently
in each panel, that's why I thought of
I have a set of values and their corresponding weights. I can use the
function weighted.mean to calculate the weighted mean, I would like to be
able to similarly calculate the weighted median and quantiles? Is there a
function in R that can do this?
thanks,
Spencer
[[alternative HTML
Here is one way that might work for you:
x - c(20,18, 45, 16, 47, 47, 15, 26, 14,14,12,16,35,27,18,94,16,26,26,30)
# create a matrix of pairs
matrix(sample(x), ncol=2)
[,1] [,2]
[1,] 14 16
[2,] 27 20
[3,] 26 16
[4,] 47 15
[5,] 35 47
[6,] 16 18
[7,] 14
Hi Rodrigo,
I looked through my scripts and found my old hack. __WARNING__: Be very
careful to check that
the mirror isn't broken and that all is in order! Make sure that you are
reversing the axes you want. In your original post you mention axis 2, i.e.
y-axis. Below you have used axis 1.
##
Hi Rodrigo,
Again an error, as that doesn't touch one of the data structures. You need
to extend the range to include #15, as below:
## This does axis 2
mynew.cca - my.cca
for (i in c(2:8,15)) mynew.cca$CCA[[i]][, 2] - mynew,cca$CCA[[i]][, 2] * -1
Cheers, Mark.
Mark Difford wrote:
Hi
sj wrote:
I have a set of values and their corresponding weights. I can use the
function weighted.mean to calculate the weighted mean, I would like to be
able to similarly calculate the weighted median and quantiles? Is there a
function in R that can do this?
thanks,
Spencer
library(Hmisc)
[EMAIL PROTECTED] wrote:
Hi,
how can I attach variable labels originally read by read.spss() to the
resulting variables?
pre
X - read.spss('data.sav', use.value.labels = TRUE, to.data.frame =
TRUE, trim.factor.names = TRUE, trim_values = TRUE, reencode = UTF-8)
names(X) - tolower(names(X))
Try the linear quantile regression function rq() in the quantreg package.
For 1 sample estimates, your model would have just an intercept term.
There is a weight argument.
quantiles.out - rq(y ~ 1, data=mydata, tau=1:9/10, weight=myweights)
would yield the 0.10, 0.20, ..., 0.80, 0.90 weighted
Sorry for the mistake, I'm trying to rotate the CAP 1 axis not 2!
Ah well, I tried the this other way, but it gave me an error.
Something in the syntax, I tried to change something but didn't fix the
error.
CAPpotiFTI-CAPpotiFT
for(i in c(2:8,15))
To all:
I'm using RBloomberg to pull historical equity prices across a range of
international markets. Bloomberg defaults to returning stock prices to
R in local currency, for example,
blpGetData(conn, ALUA AR Equity, PX_LAST,start=09/30/08,
end=09/30/08)
returns a stock price in Argentine
[EMAIL PROTECTED] wrote:
Hi Frank,
Thanks for your feedback! But I think we are talking about two different
things.
1) Validation: The generalization performance of the classifier. See,
for example, Studies on the Validation of Internal Rating Systems by
BIS.
I didn't think the desire was
Hi Rodrigo,
Yes it does, but this will work. You have erroneously used a , in your
call, it should be a ., if anything. You have also inserted cca... And
the axes being switched must be conformant:
CAPpotiFTI-CAPpotiFT
for(i in c(2:8,15))
that is a pretty big question. And I am not qualified to answer it,
but my suggestion- from figuring out how to use other things- is to
find out how other people have modeled ecological niches- not
necessarily with R, and then try and find out functions that preform
the pieces or the whole
On Tue, Oct 7, 2008 at 8:54 AM, baptiste auguie [EMAIL PROTECTED] wrote:
Dear list,
I've been trying this for a few hours and I just don't understand how
lattice works with groups and subscripts.
Consider the following example,
xx - seq(1, 10, length=100)
x - rep(xx, 4)
y - c(cos(xx),
not reproducible.
On Tue, Oct 7, 2008 at 11:35 AM, dimitris kapetanakis [EMAIL PROTECTED] wrote:
Dear all,
I am running a code using bootstraps for estimating standard errors but the
mac crashes. When I use small number of bootstraps (100) it works fine but
if I increase that number it
Many thanks, I think I got the spirit of 'capturing and overriding'
the arguments which was the bit i was missing. It's much clearer now
with a working example.
Thanks again,
baptiste
On 7 Oct 2008, at 21:19, Deepayan Sarkar wrote:
On Tue, Oct 7, 2008 at 8:54 AM, baptiste auguie [EMAIL
You may find this site useful:
http://lme4.r-forge.r-project.org/bib/lme4bib.html
On Tue, Oct 7, 2008 at 9:08 AM, Dieter Menne
[EMAIL PROTECTED] wrote:
Julia S. julia.schroeder at gmail.com writes:
Now, I did that in my article and I got a response from a reviewer that I
additionally should
R pattern-matching and replacement functions are
vectorized: they can operate on vectors of targets.
However, they can only use one pattern and replacement.
Here is code to apply a different pattern and replacement
for every target. My question: can it be done better?
sub2 - function(pattern,
Well this time I have to assume, I'm not understanding what is wrong now.
And I have to say: 'Thank You for your patience', cause I'm going crazy
here! :-)
Mark, I tried this:
CAPpotiFTI-CAPpotiFT
for(i in c(2:8,15)) CAPpotiFTI$CCA[[i]][, 1]-CAPpotiFTI$CCA[[i]][, 1] * -1
and got this:
Erro
Hi John,
Wouldn't you get the same with just mapply(sub, patt, repl, X) ?
Nael
On Tue, Oct 7, 2008 at 9:58 PM, Thaden, John J [EMAIL PROTECTED] wrote:
R pattern-matching and replacement functions are
vectorized: they can operate on vectors of targets.
However, they can only use one pattern
John,
Try the following:
mapply(function(p, r, x) sub(p, r, x, fixed = TRUE), p=patt, r=repl, x=X)
b cda
aB CD ef
-Christos
-Original Message-
From: [EMAIL PROTECTED]
[mailto:[EMAIL PROTECTED] On Behalf Of Thaden, John J
Sent: Tuesday, October 07, 2008 3:59 PM
To:
Deepayan,
Thanks for the advice.
-Micahel
On Fri, Oct 3, 2008 at 1:24 AM, Deepayan Sarkar
[EMAIL PROTECTED]wrote:
On 10/2/08, Michael Just [EMAIL PROTECTED] wrote:
Dieter and Thierry:
Per you suggestions I have tried:
ggplot2 from Thierry:
p - ggplot(dat, aes(x=bbContag,
Thierry,
Thanks. This worked.
Cheers,
Michael
On Fri, Oct 3, 2008 at 2:46 AM, ONKELINX, Thierry
[EMAIL PROTECTED]wrote:
Michael,
You get this error because you make the subset at the wrong place. Try
p - ggplot(dat[dat$sc_recov %in% c(21,31,41), ], aes(x=bbContag,
y=..density..)) +
This is probably a very basic question. I want to understand factors but I am
not sure where to turn. Looking up factor in the Chambers book doesn't even
show up in the index. Maybe I am just slow but ?factor doesn't help either.
Would someone please point me to a very basic tutorial where I
stephen sefick ssefick at gmail.com writes:
that is a pretty big question. And I am not qualified to answer it,
but my suggestion- from figuring out how to use other things- is to
find out how other people have modeled ecological niches- not
necessarily with R, and then try and find out
Hi Rodrigo,
This is because [I now see] you are working on a capscale object, not a cca
object, which is what I thought you were using. It still works, though, even
with c(2:8,15), though DF #15 doesn't exist in capscale objects. To show you
that this is so, run the example below, which uses a
Well, writing on my rebuttal, I find myself being unable to explain in a
few, easy to understand (and, at the same time, correct) sentences
stating
that it is not a good idea to report (most likely wrong) dfs and F
statistics.
Without pretending to be able to discuss the details, may I
Exactly. It's solved. Just remove #15.
CAPpotiFTI-CAPpotiFT
for(i in c(2:8))CAPpotiFTI$CCA[[i]][,1]-CAPpotiFTI$CCA[[i]][,1]*-1
It seems that I've to pay more attention and study more about R language.
Thanks a lot once more.
Rodrigo.
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