Hi Jeff,
You could do this with [1], but if you are hoping to learn something
statistical by doing this you should probably reconsider, because the
regression line residuals are minimized along the dependent variable
axis,
It should be said that there are valid forms of linear regression
Dear John.
Thank you so much for the patience and time, you have just answered my question!
I was so used to the mean ss term from the aov table, that I didn't
stop to look and realize that the values you added in the Error SS
and den Df columns in the summary tables are actually the residuals
somewhereondearth wrote:
Hi,
i have a data with values against time and date. for plotting against date
i used axis.Date() option. but I need a 24hr time plot as well. i have
extracted and plotted, but not being able to put the time ticks ( eg. 6am, 7
am etc) on the x-axis. Im new to R, any
Dear Sir/Madam,
I was trying to upload my data in BRB array tools (R version 2.8.0). The
following errors occured:
Error: package/namespace load failed for 'affy'
Error occured while executing the following R command: try(library(affy)).
Could you please tell me what this means (and how
Hello dear R mailing list members.
I have recently became curious of the possibility applying model
selection algorithms (even as simple as AIC) to regressions of large
datasets. I searched as best as I could, but couldn't find any
reference or wrapper for using step or stepAIC to packages such
Dear R users,
I'd like to announce the RcmdrPlugin.survival package, which has just been
made available on CRAN. The package provides an R Commander plug-in for the
survival package, with dialogs for Cox models, parametric survival
regression models, estimation of survival curves, and testing for
WARNING!!!
Not a good idea to post code that deletes every object
in your workspace! Other people may blindly copy
and paste your code.
I've added some verbiage to Example 12 on the home
page:
http://sqldf.googlecode.com
that hopefully clarifies it a bit.
On Sat, Feb 21, 2009 at 2:36 AM,
I just wanted to post in conclusion to this thread that I have had success
running WinBUGS from R via R2WinBUGS, with the help of Gorjanc, Uwe, and Ben
by email outside of this thread.
I may have had a permissions problem, that was probably corrected by
entering this in the terminal:
Hi,
Both operators - and = can be used to make an assignment. My question
is: Is there a semantic difference between these two? Some time ago, I
remember I have read that because of some reason, one should be given
preference over the other - but I cannot remember the source, nor the
Hi,
I am trying to convince lattice to use bold face in an expression containing
Greek characters without any luck.
Example code (without Greek characters, renders the expression in bold)
library(lattice)
data(Cars93,package==MASS)
On 20 February 2009 at 22:40, stephen sefick wrote:
| I have the libx11-dev package installed through the aptitude
| application. This is on 5.0 power pc. What can I provide to help
| with this? I don't know where to begin.
Sorry, but what exactly is your question? Provide help with what?
If
Different methods of performing least squares calculations in R are discussed in
@Article{Rnews:Bates:2004,
author = {Douglas Bates},
title= {Least Squares Calculations in {R}},
journal = {R News},
year = 2004,
volume = 4,
number = 1,
pages
Patrick Burns wrote:
'The R Inferno' page 78 is one source you can
look at.
Patrick Burns
wow .. nice! .. thanks for posting this reference.
Esmail
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https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read
On Sat, 21 Feb 2009, Tal Galili wrote:
Hello dear R mailing list members.
I have recently became curious of the possibility applying model
selection algorithms (even as simple as AIC) to regressions of large
datasets.
Large in the sense of many observations, one assumes.
But how large in
Hi Chuck,
Thanks for the guidelines.
I was hoping someone in the group already experienced handling this
type of task and have some handy code to share.
I'll wait another day or two to see if someone responds with any more
ideas or experience, and if nothing will come up, I might try my hand
in
It turned out that the directory where I had installed contributed packages
(as defined by the environment variable R_LIB) was damaged, though it was
not revealed by the usual disk maintenance tools (chkdsk, etc). I deleted it
and created a new one, and everything looks fine now.
Renaud
On Fri, Feb 20, 2009 at 3:57 PM, Fredrik Karlsson dargo...@gmail.com wrote:
Dear list,
I am sorry for asking you this, but I am trying to do again what I
thought I have done before, although this time it does not work.
So, given the data set:
testdf -
Hi,
Which package would you recommend for an implementation of EM for density
estimation (eg. mixture of Gaussian)?
Thanks!
Lars.
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I would like to convert a list to matrix. This can be easily achieved via
do.call. The only problem is each element of the list has different length,
which causes the recycling of values. How can I have NA instead of recycled
values ?
m - list()
m[[A]] - 1
m[[B]] - 2:3
do.call(rbind, m)
[,1]
I tried cast and melt in reshape package, but still can't convert this data
frame m
m
[,1] [,2]
[1,] A 1
[2,] A 2
[3,] B 3
to this form.
m1
[,1] [,2]
[1,] A B
[2,] 1 3
[3,] 2 NA
Please help.
[[alternative HTML version deleted]]
This should do what you want:
m - list()
m[[A]] - 1
m[[B]] - 2:3
# get the maximum length
maxLen - max(sapply(m, length))
# create a new list with elements padded out with NAs
newM - lapply(m, function(.ele){
+ c(.ele, rep(NA, maxLen))[1:maxLen]
+ })
do.call(rbind, newM)
[,1] [,2]
A
G'day Darren,
On Sun, 22 Feb 2009 11:23:27 +0800
Daren Tan darenta...@gmail.com wrote:
I tried cast and melt in reshape package, but still can't convert
this data frame m
m
[,1] [,2]
[1,] A 1
[2,] A 2
[3,] B 3
from the output, this does not look like a data frame to me but like
I am experiencing some problems at working with lists at high level.
In the following coef contains the original DWT coefficients organized in a
list.
Thorugh applying the following two commands:
coef.abs - lapply(unlist(coef,recursive=FALSE,use.names =TRUE),abs)
coef.abs.sorted -
Not completely clear what you want (it does not appear to be a
conventional reshape) but try this:
m - matrix(c(A, A, B, 1, 2, 3), 3, 2)
structure(do.call(cbind, lapply(tapply(m[,2], m[,1], c), ts)), tsp = NULL,
class = NULL)
A B
[1,] 1 3
[2,] 2 NA
On Sat, Feb 21, 2009 at 10:23 PM,
Here is one way that might work.
x - list(a=runif(10), b=runif(30), c=runif(25))
# unlist and then construct a factor to put them back together
x.u - unlist(x)
x.f - unlist(mapply(rep, names(x), sapply(x, length)))
# find the lowest 5 values and set to -1
x.u[order(x.u)[1:5]] - -1
# put back
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