Perhaps you should try http://www.rforge.net/pgfSweave/
On Mon, Jun 8, 2009 at 5:38 PM, maiya maja.zaloz...@gmail.com wrote:
Wow! Thank you for that Ted, a wonderfully comprehensive explanation and
now
everything makes perfect sense!!
Regarding your last point, I would love to hear other
Diego,
Start with Bob Muenchen's site: http://www.rforsasandspssusers.com/
HTH,
Jim Porzak
TGN.com
San Francisco, CA
www.linkedin.com/in/jimporzak
use R! Group SF: www.meetup.com/R-Users/
On Mon, Jun 8, 2009 at 5:47 PM, DIEGO CHAVEZ diego.cha...@andinanet.netwrote:
Sent: Sunday, June 07,
Gabor Grothendieck wrote:
On Mon, Jun 8, 2009 at 7:18 PM, Wacek
Kusnierczykwaclaw.marcin.kusnierc...@idi.ntnu.no wrote:
Gabor Grothendieck wrote:
Try this. See ?regex for more.
x - 'This happened in the 21. century. (the dot behind 21 is'
regexpr((?![0-9]+)[.], x, perl =
On Tue, 09-Jun-2009 at 11:50AM +0800, Daofeng Li wrote:
| Dear list members,
|
| i am currently want to install Rpy2 in a linux box which has R 2.4.0
| installed
| RPy requries R 2.7.0 or above
| but i have no root previlleges
| so my question is how to install R 2.7.0 on my own directory?
You
Date: Fri, 5 Jun 2009 16:09:42 -0700 (PDT)
From: Thomas Lumley tlum...@u.washington.edu
To: dylan.beaude...@gmail.com
Cc: 'r-h...@stat.math.ethz.ch' r-h...@stat.math.ethz.ch
Subject: Re: [R] OT: a weighted rank-based, non-paired test statistic ?
On Fri, 5 Jun 2009, Dylan Beaudette wrote:
Is
On Tue, Jun 9, 2009 at 2:47 AM, DIEGO CHAVEZdiego.cha...@andinanet.net wrote:
I am reading about the functional features of R statistical software,
because I want to compare these progarm with the basic module of SPSS
software.
I would like to know if the R version 2.9.0 application
Marc Schwartz wrote:
On Jun 8, 2009, at 5:27 PM, Barry Rowlingson wrote:
On Mon, Jun 8, 2009 at 10:40 PM, Tan, Richardr...@panagora.com wrote:
Hi,
This is not exactly an R question but I am trying to use gsub to
replace
a string that contains 5-9 alpha-numeric characters, at least one of
Hi,
I always use source for this kinds of things. If you have a lot of code,
you could consider wrapping it into an R-package. This would allow you
to load all the code by using the library(myPackage) command. But this
might be unnecessary for your situation.
cheers,
Paul
Jason Rupert
Wacek Kusnierczyk wrote:
Marc Schwartz wrote:
On Jun 8, 2009, at 5:27 PM, Barry Rowlingson wrote:
On Mon, Jun 8, 2009 at 10:40 PM, Tan, Richardr...@panagora.com wrote:
Hi,
This is not exactly an R question but I am trying to use gsub to
replace
a string that contains 5-9
Hi,
In addition. You can also install everything just in your home drive.
Using the configure script you can change the installation path of all R
related stuff:
./configure --prefix=/home/bla/progsandlibs
The binaries end up in ~/progsandlibs/bin, and the libraries in
~/progsandlibs/bin.
is there a simple way of altering wgplot() such that binwidth is sufficient
to prevent overlap in symbols?
i've noticed postings regarding specific plotting functions but not
specifically wgplot().
Thanks!
--
View this message in context:
Hi list!
An operation that I often need is splicing two vectors:
splice(1:3, 4:6)
[1] 1 4 2 5 3 6
For numeric vectors I use this hack:
splice - function(x, y) {
xy - cbind(x, y)
xy - t(xy)
dim(xy) - length(x) * 2
return(xy)
}
So far, so good (?). But I also need
thanks Duncan, i've updated it and it works now. since it did not
complain about version numbers, i did not think that was the problem.
i'll take care about it next time.
robert.
On Fri, 2009-06-05 at 13:35 -0700, Duncan Temple Lang wrote:
Hi Robert
As Brian Ripley wrote in a message to
Other then the reengineering of the approach, one thing that helps is don't
index rows of data frames via loops... ever. It is actually faster to convert
to a matrix, do the operations, and then convert back to a data frame if you
have too.
As an example I have your code in a function:
Dear Titus,
Your first function can be simplified to
splice - function(x, y) {
as.vector(rbind(x, y))
}
For factors, you better convert them first back to character strings.
splice - function(x, y) {
x - levels(x)[x]
y - levels(y)[y]
factor(as.vector(rbind(x,
Titus von der Malsburg malsburg at gmail.com writes:
An operation that I often need is splicing two vectors:
splice(1:3, 4:6)
[1] 1 4 2 5 3 6
For numeric vectors I use this hack:
splice - function(x, y) {
xy - cbind(x, y)
xy - t(xy)
dim(xy) - length(x) * 2
Graves, Gregory wrote:
My x axis is a series of daily dates (e.g., 01/01/2000, 01/02/2000,
etc.) from 2000 to end of 2008. The default only gives me 4 ticks. I
want more. Why doesn't this work?
sdate-as.POSIXct(strptime(date,format=%m/%d/%Y))
On Tue, Jun 09, 2009 at 11:23:36AM +0200, ONKELINX, Thierry wrote:
For factors, you better convert them first back to character strings.
splice - function(x, y) {
x - levels(x)[x]
y - levels(y)[y]
factor(as.vector(rbind(x, y)))
}
Thank you very much, Thierry!
I
On Tue, Jun 9, 2009 at 3:04 AM, Wacek
Kusnierczykwaclaw.marcin.kusnierc...@idi.ntnu.no wrote:
Gabor Grothendieck wrote:
On Mon, Jun 8, 2009 at 7:18 PM, Wacek
Kusnierczykwaclaw.marcin.kusnierc...@idi.ntnu.no wrote:
Gabor Grothendieck wrote:
Try this. See ?regex for more.
x - 'This
Gabor Grothendieck wrote:
On Tue, Jun 9, 2009 at 3:04 AM, Wacek
Kusnierczykwaclaw.marcin.kusnierc...@idi.ntnu.no wrote:
Gabor Grothendieck wrote:
On Mon, Jun 8, 2009 at 7:18 PM, Wacek
Kusnierczykwaclaw.marcin.kusnierc...@idi.ntnu.no wrote:
Gabor Grothendieck wrote:
On Jun 9, 2009, at 6:44 AM, Mark Heckmann wrote:
Hey all,
Thanks for your help. Your answers solved the problem I posted and
that is
just when I noticed that I misspecified the problem ;)
My problem is to separate a German texts by sentences. Unfortunately I
haven't found an R package doing
I've got two data.frames and, when certain keys match, I would like to add
the column values from one data frame to the other data.frame.
Below I list the two data.frames, i.e. neighborhoodInfo_df, and schoolZone_df.
Based on the address key I would like to add the schoolZone key to the
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
Have a look at the merge function.
Merge two data frames by common columns or row names, or do other
versions of database _join_ operations.
Titus
On Tue, Jun 09, 2009 at 05:48:05AM -0700, Jason Rupert wrote:
I've got two data.frames and, when certain keys match, I would like to
Dear list,
I'm quite surprised by this,
unit(1:5,char)[-c(1:2)]
#4char 3char # what's going on??
while I expected something like,
c(1:5)[-c(1:2)]
# 3 4 5
Note that,
unit(1:5,char)[c(1:2)]
# 1char 2char # fine
?unit warns about unit.c for concatenating, but also says,
It is possible to
An example:
schoolZone1_df - data.frame(address=101, schoolZone=Sherman)
schoolZone2_df - data.frame(address=108, schoolZone=Baker)
schoolZone_df - rbind(schoolZone1_df, schoolZone2_df)
schoolZone_df
address schoolZone
1 101Sherman
2 108 Baker
neighborhoodInfo1_df -
Dear R users,
I'm working with the rpart package and want to evaluate the performance of
user defined split functions.
I have some problems in understanding the meaning of the xval argument in
the two functions rpart.control and xpred.rpart. In the former it is defined
as the number of
On 6/9/2009 9:02 AM, baptiste auguie wrote:
Dear list,
I'm quite surprised by this,
unit(1:5,char)[-c(1:2)]
#4char 3char # what's going on??
while I expected something like,
c(1:5)[-c(1:2)]
# 3 4 5
Note that,
unit(1:5,char)[c(1:2)]
# 1char 2char # fine
?unit warns about unit.c for
I have some problems in understanding the meaning of the xval argument in
the two functions rpart.control and xpred.rpart. In the former it is defined
as the number of cross-validations while in the latter it is defined as the
number of cross-validation groups.
It is the same thing. If
Usually 10-fold cross validation is performed more than once to get an
estimate of the misclassification rate thus I thought number of
cross-validations was different from the number of cross-validation
groups. So, if I want to perform 10-fold cross-validation more than once
(say 5) in order
Marc Schwartz wrote:
On Jun 9, 2009, at 6:44 AM, Mark Heckmann wrote:
Hey all,
Thanks for your help. Your answers solved the problem I posted and
that is
just when I noticed that I misspecified the problem ;)
My problem is to separate a German texts by sentences. Unfortunately I
haven't
Dear all,
has someone implemented functionality for writing reports from R in
Office Open XML format (*), similar to what odfWeave does for the ODF
format of OpenOffice? It would be great to have a kind of
ooxmlWeave at least for those of us who are forced to work in an
MS ecosystem.
(*)
Hi the list,
I build a package. They was a mistake in it, but R CMD check did not
find it. Is that normal ?
Here is what Kurt gets (which is right, I did this mistake):
--- 8
* checking for code/documentation mismatches ... WARNING
S4 class codoc mismatches from
Yes. We will release a version in the next few weeks
when I have time to wrap it all up.
There is also a Docbook-based version that uses
R extensions to Docbook for authoring structured
documents.
D.
Tobias Sing wrote:
Dear all,
has someone implemented functionality for writing reports from
i am working with two sets of likert scale type (4 distinct values) data:
dataA - rep(1:4, c(3,2,2,4))
dataB - rep(1:4, c(5,4,3,2))
i can now (bar)plot both of these separately and compare the distributions.
plot(table(dataA), type='h')
plot(table(dataB), type='h')
is there a way to plot both
Dear R-Help,
I am using the 'mfp' package. It produces three plots (as I am using
the Cox model) simultaneously which can be viewed together using the
following code:
fit -
mfp(Surv(rem.Remtime,rem.Rcens)~fp(age)+strata(rpa),family=cox,data=nearma,select=0.05,verbose=TRUE)
par(mfrow=c(2,2))
You can use barchart in package lattice. Here's a rough sketch:
library(lattice)
dataA - rep(1:4, c(3,2,2,4))
dataB - rep(1:4, c(5,4,3,2))
da - data.frame(table(dataA))
db - data.frame(table(dataB))
da$cond - a
db$cond - b
colnames(da)[1] - data
On Tue, Jun 09, 2009 at 04:39:29PM +0200, Titus von der Malsburg wrote:
is there a way to plot both of them in one plot, so that the bars for
value 1 (dataA: 3, dataB: 5) would appear side by side, followed by
the bars for value 2 etc.?
Oh, I see you want something different. I should've
using R version 2.9.0 beta (2009-04-04 r48290)
As a start, Kurt et al. are for sure using a much more recent version
(probably also the very latest patched version).
/H
On Tue, Jun 9, 2009 at 7:17 AM, Christophe
Genolinicgeno...@u-paris10.fr wrote:
Hi the list,
I build a package. They was a
I am trying to install the Cairo package on a linux machine, the Cairo
package did not install correctly (could not find cairo.h), I am new to
R and linux any help on the installation would be great. Below are
output from trying to install the Cairo package, thought this might help.
try issueing this before calling R CMD check
export _R_CHECK_CODOC_S4_METHODS_=true
hth, Ingmar
On 9 Jun 2009, at 16:17, Christophe Genolini wrote:
Hi the list,
I build a package. They was a mistake in it, but R CMD check did not
find it. Is that normal ?
Here is what Kurt gets (which
Henrik Bengtsson wrote:
using R version 2.9.0 beta (2009-04-04 r48290)
As a start, Kurt et al. are for sure using a much more recent version
(probably also the very latest patched version).
and if not only then at least also R-devel.
Uwe
/H
On Tue, Jun 9, 2009 at 7:17 AM,
Install the cairo headers? Probably in some cairo or cairo-devel package
for your OS.
Uwe Ligges
Douglas M. Hultstrand wrote:
I am trying to install the Cairo package on a linux machine, the Cairo
package did not install correctly (could not find cairo.h), I am new to
R and linux any help
Hi,
I'm relatively new to R and need to do a quantile regression. Linear
quantile regression works, but for my data I need some quadratic function.
So I guess, I have to use a nonlinear quantile regression. I tried the
example on the help page for nlrq with my data and it worked. But the
example
Wow, It sounds great. Looking forward to it.
2009/6/9 Duncan Temple Lang dun...@wald.ucdavis.edu:
Yes. We will release a version in the next few weeks
when I have time to wrap it all up.
There is also a Docbook-based version that uses
R extensions to Docbook for authoring structured
Hello,
I have a pretty large data set of insect community data from a tree
plantation. There are 14 subraces (fixed) of tree, each with 10
families fixed within subrace. There are then 10 reps (random) of
each family, which are in specific part of the plantation. I am
trying to
Thanks,
Now it works great. I modified it a bit so the sentences will be split by
questionmarks (.?!:), etc. as well.
strsplit(gsub(([[:alpha:]][\\.\\?\\!\\:]), \\1*, txt), \\* *) [[1]]
e.g.
strsplit(gsub(([[:alpha:]][\\.\\?\\!\\:]), \\1*, txt), \\* *) [[1]]
[1] One January 1. I saw Rick?
Hi,
I am quite new to R and would appreciate some guidance, if possible.
I have imported a csv file: spread - read.csv(Spread.csv)
I get the following error when I try to run adf.test:
adf.test(spread,alternative = c(stationary, explosive),0)
Error in embed(y, k) : 'x' is not a vector or
Hey all,
Thanks for your help. Your answers solved the problem I posted and that is
just when I noticed that I misspecified the problem ;)
My problem is to separate a German texts by sentences. Unfortunately I
haven't found an R package doing this kind of text separation in German, so
I try it
Various people have provided technical solutions to your problem.
May I suggest, though, that 'splice' isn't quite the right word for this
operation? Splicing two pieces of rope / movie film / audio tape / wires /
etc. means connecting them at their ends, either at an extremity or in the
middle,
On Tue, Jun 09, 2009 at 11:04:03AM -0400, Stavros Macrakis wrote:
This may seem like a minor point, but I think it is worthwhile using
descriptive names for functions.
Makes sense. I thought I've seen this use somewhere else (probably in
Lisp?). What better name do you suggest for this
Those are linear in the coefficients so try these:
library(quantreg)
rq1 - rq(demand ~ Time + I(Time^2), data = BOD, tau= 1:3/4); rq1
# or
rq2 - rq(demand ~ poly(Time, 2), data = BOD, tau = 1:3/4); rq2
On Tue, Jun 9, 2009 at 10:55 AM, despairedmeyfa...@uni-potsdam.de wrote:
Hi,
I'm
This is almost certainly a device-dependent issue, which is the reason
the Posting Guide requests that you include such details.
On a Mac using the GUI interface, one can scroll backwards through the
graphics windows with cmd-left arrow. With the plot of interest as
the focus one can then
-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of Mark Heckmann
Sent: Tuesday, June 09, 2009 4:45 AM
To: r-help@r-project.org
Cc: waclaw.marcin.kusnierc...@idi.ntnu.no; marc_schwa...@me.com
Subject: Re: [R] using regular
On Tue, Jun 9, 2009 at 11:16 AM, Titus von der Malsburg
malsb...@gmail.comwrote:
On Tue, Jun 09, 2009 at 11:04:03AM -0400, Stavros Macrakis wrote:
This may seem like a minor point, but I think it is worthwhile using
descriptive names for functions.
Makes sense. I thought I've seen this
Hi,
thanks, it works :-)
But where is the difference between demand ~ Time + I(Time^2) and demand ~
poly(Time, 2) ?
Or: How do I have to interpret the results? (I get different results for the
two methods)
Thank you again!
Gabor Grothendieck wrote:
Those are linear in the coefficients so
Another way to handle is to match the contents rather than the
delimiters using strapply in gsubfn (http://gsubfn.googlecode.com).
Below a sentence is defined as starting with a non-space followed by
anything followed by an alpha followed by dot, question mark or
exclamation mark.
The (?U) means
Hello.
I want to write my notes in Sweave in my own language (spanish). But
my language has accents and when I run Sweave in R to translate my Snw
file into the tex file the accents are translated into unrecognizable
characters.
For example, the word camión (truck) is translated into
Hi R-users,
can anyone explain me how to play around with the options of the bootstrap
calibration curve obtained using the calibrate() function in Design package?
I am trying to colour the diagonal, i.e. the ideal curve, in red, and also hide
the bias-corrected curve.
Thanks,
Dave
Hi:
For those of you who are adept at both SAS and R, I have the following
questions:
a) What are some reasons / tasks for which you would use R over SAS and vice
versa?
b) What are some things for which R is a must have that SAS cannot fulfill the
requirements?
I am on the ramp up on both of
Hi,
Does anyone know how to compute the quantile of a mixture of four
bivariate normal distriutions?
Many thanks!
Hannah
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
Hi
I am trying to create a column in a data frame which gives a sigificane score
from 0-7. It should read values from 7 different colums and add 1 to the
counter if the value is =0.05. I get an error message saying
Error in if (ALLRESULTS[i, 16] = 0.05) significance_count =
On Tue, 9 Jun 2009, Laura Bonnett wrote:
I'd like to isolate the second plot produced (the estimated functional
form of the influence of age on the log relative hazard) so that I can
use the 'points' function to add the linear predictors for the
untransformed and the log-transformed models. In
Try `poly(Time, 2, raw=TRUE)'
Here is an example:
Time - runif(100)
demand - 1 + 0.5 * Time - 1.2 * Time^2 + rt(100, df=4)
rq1 - rq(demand ~ Time + I(Time^2), tau = 1:3/4)
rq2 - rq(demand ~ poly(Time, 2, raw=TRUE), tau = 1:3/4)
all.equal(c(rq1$coef), c(rq2$coef))
Ravi.
Here is one way using a single pattern (so can be used in a substitution), it
uses Perl's positive look ahead patters:
test -
c(SHRT,5HRT,M1TCH,M1TCH5,LONG3RS,NONUMBER,TOOLNGG,ooops.3)
sub( '(?=[a-zA-Z]{0,8}[0-9])[a-zA-Z0-9]{5,9}', 'xxx', test, perl=TRUE)
[1] SHRT5HRT
Try this:
for (i in 1:dim(ALLRESULTS)[1]) {
ALLRESULTS[i,23] - length(ALLRESULTS[i,][ALLRESULTS[i,16:22] = 0.05])
}
On Wed, Jun 10, 2009 at 12:17 AM, Amit Patelamitrh...@yahoo.co.uk wrote:
Hi
I am trying to create a column in a data frame which gives a sigificane score
from 0-7. It should
Dear Amit,
Try this:
significance_count - apply( ALLRESULTS[,16:22], 1, function(x) sum( x =
0.05 ) ) )
HTH,
Jorge
On Tue, Jun 9, 2009 at 12:17 PM, Amit Patel amitrh...@yahoo.co.uk wrote:
Hi
I am trying to create a column in a data frame which gives a sigificane
score from 0-7. It should
On 6/9/2009 12:17 PM, Amit Patel wrote:
Hi
I am trying to create a column in a data frame which gives a sigificane score
from 0-7. It should read values from 7 different colums and add 1 to the
counter if the value is =0.05. I get an error message saying
Error in if (ALLRESULTS[i, 16] =
You can sometimes fake variable width look behinds with Perl regexs using '\K':
gregexpr('\\b[0-9]+\\K[.]', 'a. 1. a1. 11.', perl=TRUE)
[[1]]
[1] 5 13
attr(,match.length)
[1] 1 1
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111
Hi,
I have already asked a similar question without response
(https://stat.ethz.ch/pipermail/r-help/2009-June/200300.html) so I am
here reformulating in the hope that someone is able to help. If
something is unclear, please ask.
I am working on the development of two packages, pkg1 and pkg2
On 6/9/2009 12:07 PM, Arnau Mir Torres wrote:
Hello.
I want to write my notes in Sweave in my own language (spanish). But
my language has accents and when I run Sweave in R to translate my Snw
file into the tex file the accents are translated into unrecognizable
characters.
For example,
poly by default uses orthogonal polynomials which work better mathematically
but are harder to interpret. See ?poly
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111
-Original Message-
From:
Greg Snow wrote:
Here is one way using a single pattern (so can be used in a substitution), it
uses Perl's positive look ahead patters:
test -
c(SHRT,5HRT,M1TCH,M1TCH5,LONG3RS,NONUMBER,TOOLNGG,ooops.3)
sub( '(?=[a-zA-Z]{0,8}[0-9])[a-zA-Z0-9]{5,9}', 'xxx', test, perl=TRUE)
On Tue, Jun 9, 2009 at 7:44 AM, Mark Heckmann mark.heckm...@gmx.de wrote:
Thanks for your help. Your answers solved the problem I posted and that is
just when I noticed that I misspecified the problem ;)
My problem is to separate a German texts by sentences. Unfortunately I
haven't found an R
Sorry I did not give some examples in my previous posting to make my
question clear. It's not exactly 1 digit, but at least one digit. Here
are some examples:
input = c(none='0foo f0oo foo0 foofoofoo0 0foofoofoo TOOL9NGG
NONUMBER',all='foob0 fo0o0b 0foob 0foobardo foob4rdoo foobardo0')
It's rather simple to get the code and add modifications. You wanted
the dashed line to be red? (To find out what the underlying function
name is, you use methods(plot):
The dashed ideal line plotting function is not set up to accept
parameters. so you need to alter the code. Use this as a
Wacek already mentioned that; however, its still
arguably more complex to specify delimiters
than to specify content. Aside from having
to specify perl = TRUE and ungreedy matching
the content-based regexp is entirely straight forward
but for lookbehind (including \K) one has the added
complexity
The coefficients are different but the predictions are the same.
On Tue, Jun 9, 2009 at 12:41 PM, Greg Snowgreg.s...@imail.org wrote:
poly by default uses orthogonal polynomials which work better mathematically
but are harder to interpret. See ?poly
--
Gregory (Greg) L. Snow Ph.D.
Yes, I already apologized to Wacek for missing that and pointing out what he
had already said.
Given everything in this thread (though it is hard to keep track of all of it,
my e-mail client does not keep all the parts of the thread together), this is
probably one of those few tasks that R is
David A.G wrote:
Hi R-users,
can anyone explain me how to play around with the options of the bootstrap
calibration curve obtained using the calibrate() function in Design package?
I am trying to colour the diagonal, i.e. the ideal curve, in red, and also hide
the bias-corrected curve.
1) Please send reproducible code. In this case possibly with a link to the
Snw file.
2) Try setting the charset in LaTeX: \usepackage[utf8]{inputenc}
On Tue, Jun 9, 2009 at 12:07 PM, Arnau Mir Torres arnau@uib.es wrote:
Hello.
I want to write my notes in Sweave in my own language
Tan, Richard wrote:
Sorry I did not give some examples in my previous posting to make my
question clear. It's not exactly 1 digit, but at least one digit. Here
are some examples:
input = c(none='0foo f0oo foo0 foofoofoo0 0foofoofoo TOOL9NGG
NONUMBER',all='foob0 fo0o0b 0foob
If there were significant advantage to that perl module
I would recommend interfacing R to it rather than
suffer with perl.
For example, see xls2csv (and read.xls) in the gdata package
for an example of interfacing to a perl program.
I don't want to turn this into an R vs. perl thread but there
This is just to you.
You might want to read r-help through gmane.org or one of the other
online readers or get a gmail or other online email account just
for reading newsgroups to circumvent your thread-challenged
email client.
Regards.
On Tue, Jun 9, 2009 at 1:42 PM, Greg
You could try:
do.call(rbind, lapply(list.files(path/to/files, full = TRUE), read.csv))
And add more arguments to lapply if the files are not csv, have no header, etc.
--sundar
On Tue, Jun 9, 2009 at 11:18 AM, Erin Hodgesserinm.hodg...@gmail.com wrote:
Dear R People:
I have about 6000 files
Dear R People:
I have about 6000 files to be read in that I'd like to go to one
matrix. There are two columns, 1 line in each file.
Is there a way to bring them in to produce one matrix or data frame, please?
Thanks,
Erin
--
Erin Hodgess
Associate Professor
Department of Computer and
On Tuesday 09 June 2009, Torsten Hothorn wrote:
Date: Fri, 5 Jun 2009 16:09:42 -0700 (PDT)
From: Thomas Lumley tlum...@u.washington.edu
To: dylan.beaude...@gmail.com
Cc: 'r-h...@stat.math.ethz.ch' r-h...@stat.math.ethz.ch
Subject: Re: [R] OT: a weighted rank-based, non-paired test
Dear Sir/Madam,
i am learning to use a statistical sampling-modle(arms in HI)
But i have a problem with the indFunc(bounds of the convex support).
I have found a good example of c code using arms function and try to
program the example in R.
If you are interested, you can find the c code from
Dear Sam,
It's not exactly clear to me what you're doing here, since you appear to be
specifying some of the arguments to scatterplot() (and to other functions)
in the command used to invoke R. I'm not sure why you would want to do that.
That said, you could suppress the legend that
Ben Bolker bolker at ufl.edu writes:
Sweave does something clever with warnings, which I have so far been
...
I thought I could get around this with last.warning , but apparently
that doesn't work -- this file doesn't produce the desired output of
reproducing the last warning ...
Anyone know where I can obtain an R implementation of the Black-
Litterman portfolio model?
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Not sure either where the warning gets trapped, but you could use
something like that:
\documentclass{article}
\begin{document}
Test {\tt last.warning}
=
withCallingHandlers( {
x - log(-1)
}, warning = function(w){
assign( last.warning, w, env = baseenv() )
})
@
=
last.warning
@
Hello everyone,
I am trying to import all of the csv files from a particular folder and then
run cross correlations on each of them. i.e In the end have a matrix like
structure with cross correlations.
So far I have been able to import all of the data and run the ccf's but I
need a way to
The surveillance package (see below) seems to be mainly designed for
weekly or monthly surveillance (although I am still learning about it.)
Can it be used for daily surveillance? I had hoped to try using it with
respect to daily visits to walk-in clinics in our area.
Package ‘surveillance’
JannaB schrieb:
Anyone know where I can obtain an R implementation of the Black-
Litterman portfolio model?
There is the BLCOP package.
hth
Stefan
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PLEASE do read
Hi Peter,
I hope you could help. I am stuck with this. The last problem I have is:
I have table like:
id rank color status ip
138 29746 yellow yes 162.131.58.1
138 29746 yellow yes 162.131.58.2
138 29746 yellow yes 162.131.58.3
138 29746 yellow yes 162.131.58.4
138 29746 yellow yes
I'm new at R ...
I've not done for loops in R - so this is very new to me.
One of our students has a data frame that contains two columns data
1. unixtime time of an event (in unix time - #of seconds)
2. duration of event in seconds.
We need to create new data - the unixtime (seconds) that
quote
Error in if (ALLRESULTS[i, 16] = 0.05) significance_count =
significance_count + :
missing value where TRUE/FALSE needed
The script is included below
it works if i convert the NA values to zero but this is not
appropriate as it includes the zero as significant.
ANY SUGGESTIONS
Try this:
x - data.frame(u=c(1:5), seconds=sample(5))
transform(x[rep(1:nrow(x),x$seconds),], seconds =
unlist(lapply(split(x$seconds, x$u), seq)))
On Tue, Jun 9, 2009 at 6:11 PM, Gordon J Holtslander
gordon.holtslan...@usask.ca wrote:
I'm new at R ...
I've not done for loops in R - so
Dear R-List!
Is there any function (apparently for BioStat there is!) to calculate
effect sizes with the p-values and sample sizes?
That would be really useful for meta-analysis!
Thanks for the help!
Jokel
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