Hi Lei,
one way to do this is the following:
mat - matrix(rnorm(4*6), 4, 6)
ind - c(3, 2, 4, 5)
mat[rep(seq_along(ind), ind), ]
I hope it helps.
Best,
Dimitris
Lei Liu wrote:
Hi there,
I have a question on manipulating a matrix. Say I have a matrix A with 3
rows. I want to generate a
Try:
b- ifelse(is.na(a),1,2)
Grześ wrote:
2 - is.na(a) - it's superb! but I need call a function: wy[i]-
ifelse(((is.na(a))), call_fun1(x), call_fun2(x)
Gabor Grothendieck wrote:
Try:
2 - is.na(a)
On Tue, Jun 16, 2009 at 5:46 PM, Grześgregori...@gmail.com wrote:
Hi,
How about this:
mat - matrix(rep(1:4, each=4), nrow=4, byrow=TRUE)
mat[rep(1:4, times=c(3,2,4,5)),]
Cheers,
Simon.
On Wed, 2009-06-17 at 01:54 -0400, Lei Liu wrote:
Hi there,
I have a question on manipulating a matrix. Say I have a matrix A
with 3 rows. I want to generate a new matrix
On Tue, 16-Jun-2009 at 03:48PM -0700, J Dougherty wrote:
[...]
| You might simply ask your administrator to install R and the
| relevant libraries. Not infrequently admins can get cranky about
| users with executables in their user space.
I suspect that the OP is in a position similar to mine
Hi everyone
I have created a function that uses xtable to print table of frequencies and
percentages with a heading and some sample information (the sample size and
missing values). The function and example data is below.
I want a vertical line that separates the results from the sample
Hello,
I 've just re-installed R 2.9.0 on ubuntu 9.04.
I do not understand why I am unable to use simple device function such as
jpeg(), png()...
png()
Error in X11(paste(png::, filename, sep = ), width, height, pointsize, :
unable to start device PNG
In addition: Warning message:
In
Hi all,
Many thanks for your advice.
Lindsay
-Original Message-
From: Peter Flom [mailto:peterflomconsult...@mindspring.com]
Sent: 12 June 2009 11:18
To: Lindsay Banin; 'r-help@r-project.org'
Subject: Re: [R] Comparing model fits for NLME when models are not nested
Lindsay Banin
Hi there,
I'm a bit confused concerning the axis tck setting in the lattice
package as the ticks on left sided axis aren't
drawn at all with the following setting:
dados - data.frame(varsep = factor(rep(1:2,10)),
i = runif(20))
library(lattice)
my.theme - list(
Dear list,
I have been working on a report with around 60 images in it, and
everything has been fine, until now. I find that the image output that
is produced by odfWeave produces images that are NOT readable by
OpenOffice or NeoOffice. I get empty boxes with Read-Error written in
them. While
If you use lattice to produce the figures, you need to wrap them in print, say,
=
print(xyplot(y~x,data=dat))
@
Ronggui
2009/6/17 Fredrik Karlsson dargo...@gmail.com:
Dear list,
I have been working on a report with around 60 images in it, and
everything has been fine, until now. I find that
I have a large dataset grouped by a factor and I want to perform a regression
on each data subset based on this factor. There are many ways to do this,
posted here and elsewhere. I have tried several. However I found one method
posted on the R wiki which works exactly as I want, and I like the
-- Forwarded message --
From: Fredrik Karlsson dargo...@gmail.com
Date: Wed, Jun 17, 2009 at 11:10 AM
Subject: Re: [R] Urgent - odfWeave produces graphs /images with Read-Error
To: Ronggui Huang ronggui.hu...@gmail.com
Hi Ronggui,
Thank you for this! In some of the graphs, the
Mark Kimpel wrote:
I'm using R to do some file processing in Linux and am trying to read
in the output of find . -type f -print
~/Music_Archives_search_problem/ls.output.find.txt
This command yields a text file with each line representing the full
path name of all files in the directory
Hi
Threshold models with time series for ecology have been quite famous with
bookf from Tong (1990, nonlinear time series), who studied lynx population
and showed evidence of threshold (regime specific) effects, and built a
model called threshold autoregressive
Many of those functions are
I have a question about the function duleg in the
package labdsv.
How the p-value is calculated ?
Dufrene and Legendre (1997) have shown two calculation way
; one is the difference between the observed value and the
mean of those obtained from random permutations and
another is the rank of the
Dear All,
I decided to use an AR(1) model for the residual series and trying to find the
p-value for each parameter by using arima command in R, but i never find it
from the output. The output gives me the parameter and mean's value, its
standard error, estaimated variance, AIC and
Hi everyone (Pardon the incorrect terminology of my previous post: vertical
line...).
I have created a function that uses xtable to print table of frequencies and
percentages with a heading and some sample information (the sample size and
missing values). The function and example data is below.
I have resumed developing R code on SuSE/Linux version 11.1
I installed the latest 64-bit R version available for my platform.
Accidentally I figured out I still had an old R installation that,
surprisingly, was not wiped out
by the new SuSE installation from scratch.
I suspect the new and old
On Jun 16, 2009, at 6:13 PM, jproville wrote:
Thanks David! I had trouble understanding how to convert factors,
and was
playing around with as.numeric but it had never occurred to me to
use a
combination of both that and as.character.
There's a FAQ on the topic.
I am getting really
Hi there,
I don't have much experience with fitting at all and I'd like to get
some advice how to use the weights-argument with nls correctly.
I have created some data with a sigmoidal curve shape. Each y-Value was
generated by the mean of three values. A standard deviation was
calculated
2 - is.na(a) - it's superb! but I need call a function: wy[i]-
ifelse(((is.na(a))), call_fun1(x), call_fun2(x)
Gabor Grothendieck wrote:
Try:
2 - is.na(a)
On Tue, Jun 16, 2009 at 5:46 PM, Grześgregori...@gmail.com wrote:
Hi,
I have a vector a=c(NA, 3, 4, 4, NA, NA, 3) and I
-BEGIN PGP SIGNED MESSAGE-
Hash: SHA1
I have a rectangular matrix of size 920 by 85. I'd like to coerce it into a
square matrix such that all row/col names are present in the new matrix and the
additional values are zero.
As an example:
A B C D
A 1 2 3 4
E 5 6 7 8
F 9 10
Dear All,
I am having some problem in apply function.
I have some data like below. I want to get a range vector (which is max-min
value for each row , ignoring NA values.)
Species.all[1:10,]
V2 V3 V4 V5V6 V7V8 V9
1 57543 55938 47175 54922 36032 5785 29497
Hi All,
I am using glm function to build logistic regression. I noticed that glm
function glm function is computing many other statistics which are not
required for our analysis. As our dataset is very big and we have to run
logistic regression on several samples the run time drastically
Pharmacokinetic and pharmacodynamic modeling and simulation
By Dr. Jan Freijer
September 24, 2009
Amsterdam, The Netherlands
http://www.can.nl/events/details.php?id=57
This course is aimed at users of R or S-PLUS in the bio-pharmaceutical
sciences who would like to use R
Bonjour Monsieur, Madame,
Je vous écris pour vous demander une question concernant le logiciel R.
Je voudrais vous demander l'équivalent de lsmeans de SAS dans R pour les
échantillons d'éffectifs inégaux?
Merci d'avance.
Carlo.
[[alternative HTML version deleted]]
I am using R version 2.6.0 on Linux (CentOS 4.5) and have a problem with
executing nearZeroVar function in the package caret.
I am using the latest release of caret v4.17.
I have a matrix X with 266 rows and 4 columns and when implementing nearZeroVar
function from caret package I get
Dear All,
Just to add some more lines in my previous query I am writing this. I was
checking with several data. The cases where the apply function is working,
the part of result looks like :
apply(Species.all[1:10,],1,max,na.rm=TRUE)
1 2 3 4 5 6 7 8 910
Hi,
I have a problem with dynamic appending to a list. Here is the list
variable:
clusters - vector(list, 0)
I extended in the function below:
cluster - function (pair, clusters)
{
found - FALSE
for (i in length(clusters))
{
if (length(intersect(pair, clusters[i])) 0)
{
As a long time nonlinear modeller, I always compute a quantity
commonly referred to as R_squared or the coefficient of
determination. However, I agree with other commentators, including
those of several years ago, that one wants to be very careful about
interpretation. In fact, I would say DO NOT
Hello Maura,
Date: Wed, 17 Jun 2009 14:07:44 +0200
From: mau...@alice.it
To: r-h...@stat.math.ethz.ch
Subject: [R] shall I uninstall an old R installation in advance of
installing a new one ?
I have resumed developing R code on SuSE/Linux version 11.1
I installed the latest 64-bit R
Function parameters in R are passed by value, not by reference. In
order to resolve it, just remove clusters from the parameter list,
and use clusters[i] - ... to change the value of global variable.
On Wed, Jun 17, 2009 at 7:52 PM, Nick Angelounikola...@yahoo.com wrote:
Hi,
I have a problem
Hi
r-help-boun...@r-project.org napsal dne 17.06.2009 07:51:27:
2 - is.na(a) - it's superb! but I need call a function: wy[i]-
ifelse(((is.na(a))), call_fun1(x), call_fun2(x)
You did not grasp how to use ifelse. It goes not cycle through logical
vector is.na(a).
from help page
Could it be that the problematic data came from csv files with quotes?
What does str() on those data say? Recall that apply() will coerce the
object to a matrix (if it's not), which means everything needs to be the
same type, so if even just one column is read into R as non-numeric, the
entire
Do an 'str' of your object. It looks like one of the columns is probably
character/factor since there are quotes around the 'numbers'. You can also
explicity convert the offending columns to numeric is you want to. Also use
colClasses on the read.csv to define the class of the data in each
Look at this:
http://finzi.psych.upenn.edu/Rhelp08/2009-May/198540.html
Ravi.
---
Ravi Varadhan, Ph.D.
Assistant Professor, The Center on Aging and Health
Division of Geriatric Medicine and Gerontology
Johns
I will wait for the next version-2.9.1 and presently using Petr's
suggestion, i.e.,
(x[1]*length(x))==sum(x)
which significantly reduced the run time.
The problem is now there might be only small differences ,say, of the
order of 10^-10 which I want to ignore.
So I used:
On Jun 17, 2009, at 1:45 AM, ja...@cmi.ac.in wrote:
Hi All,
I am using glm function to build logistic regression. I noticed
that glm
function glm function is computing many other statistics which are not
required for our analysis. As our dataset is very big and we have to
run
logistic
This is my function:
zywnoscCalosc - function( zywnosc, sklepik, sklslodycze) {
b=as.vector(sklslodycze)
fun=function(a,b){
a=2+b
}
zywnosc=ifelse(is.na(sklepik),NA,fun(a,b))#Here I have a problem !
}
I always get: Error in 2 + b : non-numeric argument to binary operator
I think
The updated package has been submitted to CRAN and will propagate to
mirrors over the next day or so.
It is maintained on R-Forge at http://r-forge.r-project.org/projects/writexls
, where downloads are available as well.
Package: WriteXLS
Version: 1.8.0
Description: Cross-platform perl
On Jun 17, 2009, at 7:52 AM, Nick Angelou wrote:
I have a problem with dynamic appending to a list. Here is the list
variable:
clusters - vector(list, 0)
library(fortunes)
fortune(dog)
I would suggest that referring to a character vector as a list, and
then also calling an element in
David,
It turns out that the 'at' argument takes the values 1,70,by=5, while the
'label' spans -36,33,by=5
Just took a little trial and error, but the graph now looks great. Cheers!
Jeremy
jproville wrote:
Hi,
I'd really appreciate if someone could give me some help or advice about
Hi,
I am helping another R user (off list) and I would like to email her
an R script containing the data she needs and the code to solve her
problem. I have made a small dummy dataset, but instead of sending her
a CSV I would prefer to send the data embedded in the script, so there
would be a
See
?dump
?dput
On Wed, Jun 17, 2009 at 10:43 AM, Mark Namtb...@gmail.com wrote:
Hi,
I am helping another R user (off list) and I would like to email her
an R script containing the data she needs and the code to solve her
problem. I have made a small dummy dataset, but instead of sending
why not save it as an .Rd file, or use some R code to to create the
dataframe. This way the code will be totally self-contained.
Stephen
On Wed, Jun 17, 2009 at 10:43 AM, Mark Namtb...@gmail.com wrote:
Hi,
I am helping another R user (off list) and I would like to email her
an R script
You don't say why you think that computing these other statistics is responsible
for the run time.
If you just want to fit logistic regressions faster, glm.fit() is likely to be
helpful.
-thomas
On Wed, 17 Jun 2009 ja...@cmi.ac.in wrote:
Hi All,
I am using glm function to build
On Jun 17, 2009, at 9:27 AM, jim holtman wrote:
Do an 'str' of your object. It looks like one of the columns is
probably
character/factor since there are quotes around the 'numbers'. You
can also
explicity convert the offending columns to numeric is you want to.
Also use
colClasses on
Hi folks,
I'm trying to consolidate the outputs (of anova() and lrm()) from
multiple runs of single-variable logistic regression. Here's how the
output looks:
y ~ x1 y ~ x2 y ~ x3 y ~
x4
Dear all,
If I understood well with my broken french, Carlo are looking for some R
solution that do the same as lsmeans that SAS do.
Bests
milton
2009/6/17 Da MUNDA Carlo carlo_damu...@yahoo.fr
Bonjour Monsieur, Madame,
Je vous écris pour vous demander une question concernant le logiciel R.
May I recommend my new book on mathematical modeling to you, which is
based on R as a main software tool:
Kai Velten: Mathematical Modeling and Simulation, Wiley-VCH, 2009,
ISBN 978-3527407583.
See also:
http://www.wiley.com/WileyCDA/WileyTitle/productCd-3527407588.html
Does R support unicode normalization? For my application, I'd quite
like to test for canonical equivalence (e.g. n\u0303 is equivalent to
\u00F1 which is ñ) and ideally convert strings to NFD form. (\u0303
is the combining tilde character.) Is there a package for this?
The Unicode
Sorry for this trivial question. I have just installed R on SuSE/Linux and
cannot cope with the character terminal.
I am going to install JGR that will make my life easier at searching for
existing R functions/packages.
In the meantime (higher-priority things to do) I would appreciate your
Hello.
I am trying to invert a matrix, and I am finding that I can get different
answers depending on whether I set LAPACK true or false using qr. I had
understood that LAPACK is, in general more robust and faster than LINPACK,
so I am confused as to why I am getting what seems to be invalid
Hello R Users,
I have a question regarding fitting a model with GAM{mgcv}. I have
data from several predictor (X) variables I wish to use to develop a
model to predict one Y variable. I am working with ecological data, so
have data collected many times (about 20) over the course of two years.
I just put in a new version of that function contributed by a user.
I'll make that modification and send it to CRAN shortly.
caret depends on R = 2.5.1.
Thanks,
Max
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
Dear R-Help List,
I have a question about data manipulation. I tried to make code myself but too
much for me. I would greatly appreciate your help.
I have data set consisting of site (from 1 to N1) and distance and there are
several variables (1 to N2) collected from each sampling site. I am
Hello
I am trying to install the following package . I am logged in as SU of
course.
Below is my input and output.
Any ideas?
install.packages(kernlab)
--- Please select a CRAN mirror for use in this session ---
Loading Tcl/Tk interface ... done
Error in m[, 1] : incorrect number of dimensions
Your French is almost perfect Milton... This is what in fact Carlo is
looking for.
JP
Dear all,
If I understood well with my broken french, Carlo are looking for some R
solution that do the same as lsmeans that SAS do.
Bests
milton
2009/6/17 Da MUNDA Carlo carlo_damu...@yahoo.fr
read.xls in the gdata package works on Linux.
On Wed, Jun 17, 2009 at 11:37 AM, mau...@alice.it wrote:
Sorry for this trivial question. I have just installed R on SuSE/Linux and
cannot cope with the character terminal.
I am going to install JGR that will make my life easier at searching for
On Jun 17, 2009, at 10:06 AM, Girish A.R. wrote:
Hi folks,
I'm trying to consolidate the outputs (of anova() and lrm()) from
multiple runs of single-variable logistic regression. Here's how the
output looks:
Paul,
I think I would try something like
yoyoras~te(temp,date) ...
to incorportate a continuous interaction of temp and date. Otherwise with the
models you are using, if `datecode' is a factor you'll get a smooth for every
date, which may be over-flexible, and if datecode is numeric you'll
Thanks, Marc! This is what I was looking for.
best,
-Girish
PS: Also appreciate your concern about this being a part of a variable
selection process.
On Jun 17, 9:01 pm, Marc Schwartz marc_schwa...@me.com wrote:
On Jun 17, 2009, at 10:06 AM, Girish A.R. wrote:
Hi folks,
I'm trying to
Here is one way of doing it:
x - read.table(textConnection(sitedistancevar1var2
+ 1 10 1 0
+ 1 20 0 1
+ 1 30 1 2
+ 1 40 3 3
+ 1 50 1 4
+ 2 10 1
Dear Steve,
Using Jim Holtman's x data, you can also try the following for columns 3 and
4:
a - with(x, apply(x[,3:4], 2, tapply, site,function(x) cumsum(x)))
x[,c('cvar1','cvar2')] - do.call(cbind,lapply(a, function(x) do.call(c,x)))
x
HTH,
Jorge
On Wed, Jun 17, 2009 at 11:48 AM, SEUNG CHEON
Hello all,
a friend has a problem with tiff() which I was unable to help about. I
searched the error messages to no avail. When he tries:
tiff(filename = FedeWhyDoesntThisBloodyWork.tif, width = 5, height =
5, units = cm, bg = white, res = 1200)
Error in tiff(filename =
Hello,
I am using
mod1 - lrm(y~x1+x2,na.action=na.pass,method=lrm.fit)
summary(mod1)
and I've got the following error:
Error in summary.Design(mod1) : adjustment values not defined here or with
datadist for x1 x2
Many thank,
Amor
[[alternative HTML version deleted]]
Hi Avraham,
I think this is a bug in solve() and qr.solve().
The structure of the QR object produced by LINPACK and LAPACK are different.
In fact, the help page for qr says:
qr a matrix with the same dimensions as x. The upper triangle contains the
R of the decomposition and the lower
Hi,
I am a bit stuck on specifying ui and ci.
I have read Lange's book ((1999) Numerical Analysis for Statisticians) to
his approach and unfortunately his descriptions were not helpful for me.
Here is what I have:
ui - rbind(c(0, -1, 0), c(0, 0, -1))
ci - c(0, -1, -1))
amor Gandhi wrote:
Hello,
I am using
mod1 - lrm(y~x1+x2,na.action=na.pass,method=lrm.fit)
summary(mod1)
and I've got the following error:
Error in summary.Design(mod1) : adjustment values not defined here or with
datadist for x1 x2
Many thank,
Amor
Please read the documentation for the
Avraham,
You can make LAPACK work by doing the following:
Hinv[, 1] - solve(qr(PLLH, LAPACK=TRUE), c(1,0))
Hinv[, 2] - solve(qr(PLLH, LAPACK=TRUE), c(0,1))
Here is an example:
H - matrix(runif(4), 2, 2)
H - H + t(H)
Hinv - solve(qr(H)) # this is the correct inverse from LINPACK
Hinv1 -
Dear All,
I like to use nlmeode but so far having a trouble with setting up a function
part. It does not allow me to use Cliver etc in the DiffEq and it does not
allow me to have Vabs in the ObsEq. Would you kindly let me know what to do?
Best wishes,
In-Sun
FunODE - list(
DiffEq=list(
On Jun 17, 2009, at 12:35 PM, amor Gandhi wrote:
Hello,
I am using
mod1 - lrm(y~x1+x2,na.action=na.pass,method=lrm.fit)
summary(mod1)
and I've got the following error:
Error in summary.Design(mod1) : adjustment values not defined here
or with datadist for x1 x2
Several of the useful
Thank you VERY much, that was fantastic. I wish I understood WHY your
suggestion works.
To extend that to an n-by-n square matrix, the proper procedure would be
(example, n=5 - most I would usually use (mixture of lognormals)):
Hinv - matrix(NA, 5, 5)
Hinv[, 1] - solve(qr(PLLH, LAPACK=TRUE),
The situation is that I know there is a function and know approximately what
the name is, and want to find the exact name. Is there a way of searching
for near-matches (similar to unix apropos). For example, I know there is a
function called something like allequal (or allequals or AllEquals
My understanding is that optim(method=L-BFGS-B) does box constraints
and constrOptim linear constraints. You want box.
On 17/06/09 17:51, Stu @ AGS wrote:
Hi,
[...]
My goal is to feed these into constrOptim such that there is
no constraint on theta[1] and that theta[2]
I don't think that your questions are stupid, but they probably are the wrong
one(s).
There are 2 questions (or sets of questions) when thinking about your data for
doing statistical inference.
The first question is does this assumption hold exactly? e.g. are the
residuals exactly normal?.
Steve Jaffe wrote:
The situation is that I know there is a function and know approximately what
the name is, and want to find the exact name. Is there a way of searching
for near-matches (similar to unix apropos). For example, I know there is a
function called something like allequal (or
?help.search
help.search(allequal)
help.search(apropos=allequal)
??allequal
On 17/06/09 18:12, Steve Jaffe wrote:
The situation is that I know there is a function and know approximately what
the name is, and want to find the exact name. Is there a way of searching
for near-matches (similar to
On 17/06/09 18:20, baptiste auguie wrote:
??Allequal
gets me there, admittedly not as cleverly as google would do if I
failed to spell it correctly, for instance.
??Allepual
No help files found matching ‘Allepual’ using fuzzy matching
But it *almost* gets you there; try
help.search -- excellent
I'm a bit confused though -- doc seems to say that ??pattern is same as
help.search(pattern) but it doesn't work that way for me...I'd been trying
?? for some time without success.
For example,
??allequal #returns
No documentation for '?allequal' in specified packages
Avraham,
You can create a function to do the steps that I showed you, so that it is
easy to use:
solve.lapack - function(A) {
# A function to invert a matrix using LAPACK
qrA - qr(A, LAPACK=TRUE)
apply(diag(1, ncol(A)), 2, function(x) solve(qrA, x))
}
On Jun 17, 2009, at 1:31 PM, Steve Jaffe wrote:
help.search -- excellent
I'm a bit confused though -- doc seems to say that ??pattern is same
as
help.search(pattern) but it doesn't work that way for me...I'd been
trying
?? for some time without success.
I thought the docs on this
I am trying to plot 2 time series on the same graph.
For example, X1 is the vector of dates and times, its class is POSIXt. Y1
is an environmental parameter, e.g. salinity. X2 is a second vector of
dates and times, also of class POSIXt.X2 has a different length than
X1, but they have the
one way is the following:
mat - matrix(1:12, 3, 4, TRUE)
dimnames(mat) - list(c(A, E, F), LETTERS[1:4])
cnams - colnames(mat)
rnams - rownames(mat)
unq.nams - unique(c(cnams, rnams))
out - matrix(0, length(unq.nams), length(unq.nams),
dimnames = list(unq.nams, unq.nams))
p1 -
I recently use gbm for a binary classification problem. As expected, it gets
very good results, based on Area under ROC with 7-fold cross validation.
However, the application (malware detection) is cost-sensitive, getting a FP
(classify a clean sample as a dirty one) is much worse than getting
I found the problem. the date range was not exactly overlapping as i had
thought. If the range of the 2 time series exactly overlap, then the two
graphs overlay correctly. Unless there is another method or package that
fixes this, it seems that if the 2 time series have non-matching ranges
A colleague and I were trying to understand all the possible things one
can do with for loops in R, and found some surprises. I think we've
done sufficient detective work to have a good guess as to what's going
on underneath, but it would be nice to get some confirmation, and
better yet, perhaps
I'm trying to build up a list of data.frames by appending one by one.
If x,y,z are data.frames, I can do
somelist - list(x, y, z) (or even somelist - list(x=x, y=y, z=z) to get
names)
But if I start with
somelist - list(x,y) and now want to go from this to list(x,y,z) I'm stuck.
I've tried
On Jun 17, 2009, at 1:03 PM, David Winsemius wrote:
On Jun 17, 2009, at 12:35 PM, amor Gandhi wrote:
Hello,
I am using
mod1 - lrm(y~x1+x2,na.action=na.pass,method=lrm.fit)
summary(mod1)
and I've got the following error:
Error in summary.Design(mod1) : adjustment values not defined here
try this:
dat1 - data.frame(x = rnorm(5))
dat2 - data.frame(y = rnorm(5))
dat3 - data.frame(z = rnorm(5))
lis - list(dat1 = dat1, dat2 = dat3)
c(lis, list(dat3 = dat3))
I hope it helps.
Best,
Dimitris
Steve Jaffe wrote:
I'm trying to build up a list of data.frames by appending one by one.
Hi everyone,
I have a test set with more than 1000 cases, when I use
evaluate_Weka_classifier(RWeka)to evaluate my classifier on this test
set, the output shows me the result of only 83 cases. I do have
missing values in predictors, so I tried na.acton=na.pass, but it
dosen't help. Now I
On Jun 17, 2009, at 2:45 PM, Dimitris Rizopoulos wrote:
try this:
dat1 - data.frame(x = rnorm(5))
dat2 - data.frame(y = rnorm(5))
dat3 - data.frame(z = rnorm(5))
lis - list(dat1 = dat1, dat2 = dat3)
c(lis, list(dat3 = dat3))
Or:
lis[[dat3]] - dat3
I hope it helps.
Best,
Dimitris
Thank you; that is perfect!
Should this bug be reported somewhere?
--Avraham
Ravi Varadhan
rvarad...@jhmi.e
As you seem to be aware, the matrix is poorly conditioned:
kappa(PLLH,exact=TRUE)
[1] 115868900869
It might be worth your while to think about reparametrizing.
albyn
On Wed, Jun 17, 2009 at 11:37:48AM -0400, avraham.ad...@guycarp.com wrote:
Hello.
I am trying to invert a matrix, and I
(sorry to post it again with plain text).
I recently use gbm for a binary classification problem. As expected, it gets
very good results, based on Area under ROC with 7-fold cross validation.
However, the application (malware detection) is cost-sensitive, getting a FP
(classify a clean sample
Hi *,
I solved the tick problem somehow (or rather I noticed that they are
actually drawn on a xyplot which is there I really want them), but I'm still
wondering and cannot find any information on that, how I align my
axis in a xyplot that they both go through 0 (leftsided y-axis through x=0,
Steve Jaffe wrote:
I'm trying to build up a list of data.frames by appending one by one.
If x,y,z are data.frames, I can do
somelist - list(x, y, z) (or even somelist - list(x=x, y=y, z=z) to get
names)
But if I start with
somelist - list(x,y) and now want to go from this to
Dear R Helper Community!
Thank you for all your help and suggestions.
For your reference and any future person searching the archives, here is the
solution that did what I wanted it to do.
As background, my goal was to find the coefficients for the following
equation form:
y ~ c1 * x1
Hello!
I've just discovered that my package fails to pass CRAN checks on w32
due to capabilities('cairo') == FALSE. The particular functionality I
use is SVG device.
According to http://cairographics.org/, Cairo supports w32 platform.
Could you please tell me about the reasons to disable Cairo
Hi all,
Sorry, David has just told my that it was a mistake in my example (Thanks
David). I had a wrong idea.
The right idea is: make a ip range, when the number increament without an gap
(and with maximum number: 255, see example down).
In case my initial example would be:
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