Dear all,
I am using modified LARS algorithm (ref: The Adaptive Lasso and Its Oracle
Properties, Zou 2006) for adaptive lasso penalized linear regression.
1. w(j) - |beta_ols(j)|^(-gamma) gamma0 and j = 1,...,p
2. define x_new(j) - x(j)*w(j)
3. apply LARS to solve modified lasso
Hi all,
I've searched threads and read up on some ways of doing this but I'm having
a hard time to get it to work. Here's my basic problem. I have the
following linear mixed model
y = Xb+Zu+e
where u~N(0,s^2*K) where K is a matrix.
I read a thread that basically suggested to decompose Zu into
Hi, I am trying to use the nls() function to closely approximate a vector of
values, colC and I'm running into trouble. I am not sure how if I am asking
the program to do what I think its doing, because the same minimization in
Excel's Solver does not run into problems. If anyone can tell me
threeftmetered
Sent from my Windows Mobile® phone.
-Original Message-
From: Muenchen, Robert A (Bob) muenc...@utk.edu
Sent: Saturday, July 11, 2009 4:43 PM
To: R-help@r-project.org R-help@r-project.org
Subject: [R] Reading data entered within an R program
Dear R-helpers,
I know of two
Hi Benoit,
What do you expect width to do? You are already setting the left and
right extents with xmin and xmax.
Hadley
On Thu, Jul 9, 2009 at 10:37 AM, Benoit
Boulinguiezbenoit.boulingu...@ensc-rennes.fr wrote:
Hi all,
quick question: is the optional command width effective in the
Hi Benoit,
Have a look at http://had.co.nz/ggplot2/stat_function.html. Does that help?
Hadley
On Tue, Jul 7, 2009 at 11:15 AM, Benoit
Boulinguiezbenoit.boulingu...@ensc-rennes.fr wrote:
Hi all,
I'm smoothly transferring my lattice graphs to ggplot2 graphs, but I'm stuck
on representing a
Hi all,
Where can I find detail of use of seewave?
Seems no help included in the package using ??seewave does not provide
anything.
Tnx
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting
I added a reproducible example to my question...
ts-dummyDailySeries(x = rnorm(365), units = NULL, zone = , FinCenter =
)
(ts[1,0]) #returns first date in return series
GMT
1970-01-01
ttt-(sprintf(%s,ts[1,0]))
print(ttt)
character(0)
ttt-(ts[1,0])
print(ttt)
GMT
1970-01-01
what I
On Sat, 11 Jul 2009, saurav pathak wrote:
I have so far used the following command
glm(formula = s ~ age + gender + gemedu + gemhinc + es_gdppc +
imf_pop + estbbo_m, family = binomial(link = probit))
My question is
1. How do i discard the non significant selection variables (one out of the
On Jul 9, 2009, at 6:52 PM, Hayes, Rachel M wrote:
I'm trying to automate a data summary using summary or describe from
the
HMisc package. I want to stratify my data set by patient_type. I was
hoping to do something like:
Describe(myDataFrame ~ patient_type)
by(myDataFrame,
You might also want to look at the doBy package - one function is summaryBy:
summaryBY(var1 + var2 ~ patient_type, data=d, FUN=summary)
david freedman
Hayes, Rachel M wrote:
Hi All,
I'm trying to automate a data summary using summary or describe from the
HMisc package. I want to
On Jul 12, 2009, at 8:10 AM, tradenet wrote:
I added a reproducible example to my question...
ts-dummyDailySeries(x = rnorm(365), units = NULL, zone = ,
FinCenter =
)
Heads up is an English colloquial warning.
It may be reproducible on a machine that has all of your particular
Hi
I have been trying so many different things to get my Inverse Mills Ratio
going for a Two stage Heckman Model, I have tried the following so far (the
commands are listed below till teh point where I get an error), I get an
error in the last sentence (marked in bold below), if this were
On Jul 12, 2009, at 1:05 PM, David Winsemius wrote:
On Jul 12, 2009, at 8:10 AM, tradenet wrote:
I added a reproducible example to my question...
ts-dummyDailySeries(x = rnorm(365), units = NULL, zone = ,
FinCenter =
)
Heads up is an English colloquial warning.
It may be
I have no idea to be honest. I have never used the package, I simply did a
search for it. Hopefully a more experienced user can help
--- On Sun, 7/12/09, maram salem marammagdysa...@yahoo.com wrote:
From: maram salem marammagdysa...@yahoo.com
Subject: Re: [R] (no subject)
To: John Kane
Hi,
Newbie alert on for loops...
I have a bunch of data.frames built using rbind that have repeated
values in the EnTime column. I want to read the value in the EnTime
column and use it as an input to a function, but only down to the
first occurrence of the string (all) where I want to
On Sun, Jul 12, 2009 at 11:53 AM, Mark Knechtmarkkne...@gmail.com wrote:
SNIP
So this gets better in terms of error messages but still has problems
for(n in SystemResults$EnTime) {
if ( SystemResults$EnTime[n] == (all)) break else X =
SystemResults$EnTime[n]
print(X)
}
for(n
Dear group,
Thank u so much 4 ur help. I've tried the link,
http://finzi.psych.upenn.edu/R/library/quantreg/html/akj.html
for adaptive kernel density estimation.
But since I'm an R beginer and the topic of adaptive estimation is new for me,
i still can't figure out some of the arguments of
On Jul 12, 2009, at 2:53 PM, Mark Knecht wrote:
Hi,
Newbie alert on for loops...
I have a bunch of data.frames built using rbind that have repeated
values in the EnTime column. I want to read the value in the EnTime
column and use it as an input to a function, but only down to the
first
On Jul 12, 2009, at 3:21 PM, maram salem wrote:
Dear group,
Thank u so much 4 ur help. I've tried the link,
http://finzi.psych.upenn.edu/R/library/quantreg/html/akj.html
for adaptive kernel density estimation.
But since I'm an R beginer and the topic of adaptive estimation is
new for me, i
On Jul 12, 2009, at 3:35 PM, David Winsemius wrote:
On Jul 12, 2009, at 2:53 PM, Mark Knecht wrote:
As a test I tried to print down to the string (all) and then
break but this code and everything I've tried so far is terribly
wrong. Every attempt prints lots of error messages. I'm not
On Fri, 10-Jul-2009 at 09:41AM -0700, Michael wrote:
| Here is my code:
| mygbm-gbm.fit(y=mytraindata[, 1], x=mytraindata[, -1],
| interaction.depth=4, shrinkage=0.001, n.trees=2, bag.fraction=1,
| distribution=bernoulli)
|
| Here is the error:
| Error in gbm.fit(y = mytraindata[, 1], x =
On Sun, Jul 12, 2009 at 1:05 PM, David Winsemiusdwinsem...@comcast.net wrote:
On Jul 12, 2009, at 3:35 PM, David Winsemius wrote:
On Jul 12, 2009, at 2:53 PM, Mark Knecht wrote:
As a test I tried to print down to the string (all) and then
break but this code and everything I've tried so
On 13/07/2009, at 8:05 AM, David Winsemius wrote:
Appears I am wrong about this. I was basing my assumption on this
interaction with the R interpreter:
?break
Error in genericForPrimitive(f) :
methods may not be defined for primitive function break in this
version of R
Since ``break''
On Jul 12, 2009, at 2:56 PM, David Winsemius wrote:
On Jul 12, 2009, at 3:21 PM, maram salem wrote:
Dear group,
Thank u so much 4 ur help. I've tried the link,
http://finzi.psych.upenn.edu/R/library/quantreg/html/akj.html
for adaptive kernel density estimation.
But since I'm an R beginer
Hi,
I am using mgcv:gam and have developed a model with 5 smoothed predictors
and one factor.
gam1 - gam(log.sp~ s(Spr.precip,bs=ts) + s(Win.precip,bs=ts) + s(
Spr.Tmin,bs=ts) + s(P.sum.Tmin,bs=ts) + s( Win.Tmax,bs=ts)
+factor(site),data=dat3)
The total deviance explained = 70.4%.
I would
I have a long text file with uneven record length and variable structure.
Therefore I have to read it line-by-line.
I found out I can open a connection to the file and read in one line at a time.
Something like:
con - file(MyFle.txt,r)
while (End-Of-File) {
line - readLines(con,n=1)
Hi,
My question might be a little general.
I have a number of values to select for the complexity parameters in some
classifier, e.g. the C and gamma in SVM with RBF kernel. The selection is based
on which values give the smallest cross validation error.
I wonder if the randomized splitting
Neotropical bat risk assessments-2 wrote:
Hi all,
Where can I find detail of use of seewave?
Seems no help included in the package using ??seewave does not provide
anything.
help(package=seewave)
which includes information on a vignette.
Please try to remember to use an
Dear Saurav,
If you don't wish to calculate it by hand, you can extract the Inverse Mill's
Ratio using the function invMillsRatio from the sampleSelection package.
(http://cran.r-project.org/web/packages/sampleSelection/index.html).
You can also use the heckit function in the same package
Dear R users,
Thanks in advance.
I am using R 2.9.1 on Windows XP.
I am trying to install above, but faced problem.
I have described the steps below.
1. I like to install locally. That means I like to install after downloading
the required files into my hard drive.
2. Java Runtime
You can do something like this:
con - file(MyFle.txt,r)
repeat {
line - readLines(con,n=1)
if (length(line) == 0) break
ParseLine(line)
}
On Sun, Jul 12, 2009 at 6:20 PM, mau...@alice.it wrote:
I have a long text file with uneven record length and variable structure.
Therefore I have
On Jul 12, 2009, at 5:06 PM, Kayce Anderson wrote:
Hi,
I am using mgcv:gam and have developed a model with 5 smoothed
predictors
and one factor.
gam1 - gam(log.sp~ s(Spr.precip,bs=ts) + s(Win.precip,bs=ts) +
s(
Spr.Tmin,bs=ts) + s(P.sum.Tmin,bs=ts) + s( Win.Tmax,bs=ts)
Hi Saurav!
On Sun, Jul 12, 2009 at 6:06 PM, Pathak,
Sauravs.patha...@imperial.ac.uk wrote:
I am new to R, I have to do a 2 step Heckman model, my selection equation is
below which I was successful in running but I am unable to proceed further,
I have so far used the following command
Hi all, whenever I try to plot a histogram using qplot() function of
ggplot2 library, I get error like this :
qplot(rnorm(1000), geom=histogram, binwidth=0.2, main = , xlab=,
ylab=)
Error in scale[[1]] : subscript out of bounds
However if I remove ylab= argument, then it is working fine. Am I
I have not used 'sna'.
Have you tried using debug to walk through the code line by
line, examining and even changing things at will?
For example, how big is rho, passed as starting values to
optim? If that matches the size of your adjacency matrix, it could
expose a
On Jul 11, 2009, at 8:42 PM, Jonathan Greenberg wrote:
I'm a bit confused why the following command is taking an
extrodinarily long time ( 2-3 hours) to run on an 3.06ghz iMac
(brand new). I'm trying to do a stratified random sample, drawing
only a single value per UniqueID from the
Here is what I do:
R library(fBasics)
R ts-dummyDailySeries(x = rnorm(365), units = NULL, zone = ,
FinCenter =)
R class(ts)
[1] timeSeries
attr(,package)
[1] timeSeries
R (s - as.character(time(ts)[1]))
[1] 1970-01-01
R class(s)
[1] character
tradenet wrote:
I added a reproducible
Hi, there:
Assume I have a dataframe with rownames like A with rownames like a to e,
A
[,1] [,2]
a16
b27
c38
d49
e5 10
when I use A[1,], I lost the rowname for it, like below. How could I keep
it? Is there an easy way instead that I have to modify by
Hello Everyone
I am calculating Fleiss Kappa, I have 28 raters, 5 Subjects and 5 ratings.
The problem is that there are 2 missing values in the data.
Would it better to replace those with 0 or should those be omitted? By
omission I will be left wit only 3 subjects.
and my second problem is
Hi megh,
Unfortunately there's a known bug which prevents you from setting the
y axis title in this way. Instead you can do :
qplot(...) + scale_y_continuous()
I think I've figured out a work around and it will be fixed in a future release.
Hadley
On Mon, Jul 13, 2009 at 2:15 AM,
In this simple example, it took less than half a second to generate the
result. That is on a 2.93 Ghz MacBook Pro.
So, for your data, the code would look something like this:
system.time(DF.new - do.call(rbind,
lapply(split(patch_summary,
Try A[1,,drop=FALSE] - see help(\[)
--- On Mon, 13/7/09, Weiwei Shi helprh...@gmail.com wrote:
From: Weiwei Shi helprh...@gmail.com
Subject: [R] how to keep row name if there is only one row selected from a
data frame
To: r-h...@stat.math.ethz.ch r-h...@stat.math.ethz.ch
Received: Monday,
On Mon, Jul 13, 2009 at 5:55 AM, Weiwei Shihelprh...@gmail.com wrote:
Hi, there:
Assume I have a dataframe with rownames like A with rownames like a to e,
A
[,1] [,2]
a 1 6
b 2 7
c 3 8
d 4 9
e 5 10
when I use A[1,], I lost the rowname for it, like below.
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