li li-13 wrote:
Hi all,
I want to solve the following equation for x with rho - 0.5
pnorm(-x)*pnorm((rho*dnorm(x)/pnorm(x)-x)/sqrt(1-rho^2))==0.05
Is there a function in R to do this?
Or if you wish to try different values of rho
f - function(x, rho) {
I want to output a text file assembeld from various soruces within r (
actually as a genepop file)
the output should be formatted line 1 text comment
line 2:n selected
column names from data frame
OK I see how to remove the line numbers[1] etc by using cat instead of
print, but cannot work out how to remove the column names from the data
frame output
On 13/06/2010 4:21 PM, Nevil Amos wrote:
I want to output a text file assembeld from various soruces within r (
actually as a genepop
Yes i am asking how to install RSQLite packagein windows.Please help on this
regards
On 6/11/10, david.jessop [via R]
ml-node+2251498-1601505055-288...@n4.nabble.comml-node%2b2251498-1601505055-288...@n4.nabble.com
wrote:
Are you asking how to install the RSQLite package or how to create a
Hi,
I have 2 huge datasets - May and Jun - a miniscule sample of one is given
below. I am trying to do 2 things with these datasets. I need to verify if
the weighted average of variable A for a Reason in Jun is same/different
from the same for May. To do this I am first computing the weighted
How about
Sys.sleep(60)
in a loop from 1 to 500?
?Sys.sleep
On Saturday 12 June 2010 08:45:32 pm KstuS wrote:
I have inputs to a function which are changing all the time - I pull these
values from the internet. I then apply a function to the values. What I'd
like to do is automate the
I'm pretty new to R, but have experience with other languages, both OO and
scripting.
I'm trying to add support for R to my text editor of choice and to do this I
need a list of installed commands I can markup with XML.
I'd then simply feed in the marked up list into my text editor's library
Hello dear R-help mailing list members,
I wish to create an hclust object which will be based on
a customized hierarchical clustering algorithm, programmed in R.
After looking into the hclust function, I noticed that the algorithms
themselves are implemented in Fortran. In order for me to
Worik R wrote:
...
N - 10
## x simulate a return series
x - runif(N)-.5
## Build an array of cumulative returns of a portfolio starting with $1 as
it changes over time
y - rep(0, length(x))
y[1] - 1+1*x[1]
for(i in 2:N){
y[i] - y[i-1]+y[i-1]*x[i]
}
## y is that return
On 06/13/2010 01:48 PM, beloitstudent wrote:
Hello all,
I have been having trouble getting a break in my y-axis. All of my data
points are up around 100-200, but the graph has to start at zero, so i would
like to remove all the white space using a break symbol. I have been able
to get the
Hi,
Take a look at any of the R-editors, like Tinn-R, Emacs-ESS, Eclipse
with StatET,... They contain lists you can use. Also the listings
package of LaTeX contains a wordlist for R.
Getting all installed commands out of R is not doable with a single
command as far as I know. R works completely
On Sat, Jun 12, 2010 at 11:40 PM, Worik R wor...@gmail.com wrote:
I was careless.
Here is a better example of what I am trying to. With the '-' you
offered.
?-
That was exactly what I needed, thankyou.
Just as an aside I am assuming these are just examples to illustrate
scope. In
On Sun, Jun 13, 2010 at 3:31 AM, Data Monkey coco.datamon...@gmail.com wrote:
I'm pretty new to R, but have experience with other languages, both OO and
scripting.
I'm trying to add support for R to my text editor of choice and to do this I
need a list of installed commands I can markup
Thanks Joris. Very helpful.
I had thought of that, just curious to see if it was possible to get a fresh
list in R.
After reading your email I think perhaps my wording was a bit loose. I meant
commands in the pre-installed packages.
So basically, out of the box what commands will R recognize.
Charles' hint was what I was looking for. Thanks!
mg.
On Fri, Jun 11, 2010 at 7:40 AM, Charles C. Berry cbe...@tajo.ucsd.eduwrote:
cat(print(eval(sys.calls()[[1]][[2]])),file='test.R')
See
?sys.calls
[[alternative HTML version deleted]]
On Fri, Jun 11, 2010 at 11:30 AM, Henrik Bengtsson
h...@stat.berkeley.eduwrote:
Isn't this what source(..., chdir=TRUE) is for? See help(source).
not really. Imagine you give someone a script, but you have no control over
where and how they run it. They shouldn't be required to put in the
On Thu, Jun 10, 2010 at 8:33 PM, Marcin Gomulka mrgo...@gmail.com wrote:
AFAIK a script run through source() does not have any legit way to learn
about it's own location.
I need this to make sure that the script will find its datafiles after I
move the whole directory. (The datafiles are in
col1-c(2,45,67)
col2-c(a,B,C)
col3-c(234,44,566)
mydf-as.data.frame(cbind(col1,col2,col3),stringsAsFactors=F)
n-ncol(mydf)
nr-nrow(mydf)
#sink(test.txt)
cat(I will be including text of various sorts in this file so cannot
use print table or similar command)
for (i in 1:n){
cat(colnames(mydf[i]),
On 13.06.2010 01:09, Dr. David Kirkby wrote:
On 06/12/10 05:27 PM, Douglas Bates wrote:
On Sat, Jun 12, 2010 at 8:37 AM, Dr. David Kirkby
david.kir...@onetel.net wrote:
R 2.10.1 is used in the Sage maths project. Several recommended packages
(Matrix, class, mgcv, nnet, rpart, spatial, and
Hello:
I use R with MAC
I have a simple data table, numeric and text columns, named dt. The table is
imported through read.csv from a csv file. Row numbers are automatically
assigned, header is set to TRUE. there are 599 rows and several columns.
I am trying to plot using the stripchart command:
Hi
I want to write a C function for the R Code below and call it with .Call:
SimPoisson - function(lambda,tgrid,T2M)
#Simulation eines Poissonprozesses
{
NT - 0
Ni - rep(0,length(tgrid))
tau - 0
sign - 0
if(lambda != 0)
{
i=1
Hi R users,
This seems like a simple problem but I have searched nabble for the answer
and can't seem to find it.
All I want to do is produce a boxplot where I have two boxes for one
Individual but on the xaxis I only have one tick mark centred between the
boxes so I can add the Individuals'
Henrik,
the methods you use are NOT applicable to directed graphs, in the
contrary even. They will split up what you want to put together. In
your data, an author never cites himself. Hence, A and B are far more
different than B and D according to the techniques you use.
Please check out
Hi Ross,
You are indeed missing something simple. If there are 60 bars, the axis
runs from 1 to 60, and you want a label at every second one, rather than
at every one.
Like this (with 10 instead of 60):
testdata - matrix(runif(100), ncol=10)
boxplot(testdata, xaxt=n)
axis(1, at=seq(1.5, 9.5,
Hello all,
I manually created an hclust object.
Now I am looking to reorder the leafs so they won't intersect with each
other, and would be happy for advises on how to do that.
Here is an example code:
#-
a - list() # initialize empty object
# define
hi,
I am trying to label data points within a scatter plot using thigmophobe.
While the data set consists of about 3000 points I only would like to label
a subset of these points.
I read the x and y coordinates in from a txt file and define them as:
MLPM1-log2(Ratio.M.L.G2.PM)
On Sun, 13 Jun 2010, Tal Galili wrote:
Hello all,
I manually created an hclust object.
Now I am looking to reorder the leafs so they won't intersect with each
other, and would be happy for advises on how to do that.
Have a look at the code for hclust().
If you can instead create an object
Thanks Charles.
In the meantime, I found out the following code does the trick.
But I am wondering if:
1) I might have made a mistake in it somewhere
2) If there are other (smarter) ways of going about this.
Here is the solution I wrote:
# -
On Jun 1, 2010, at 4:17 AM, Wilson, Andrew wrote:
Can anyone tell me how to calculate a mid-p value for a chi-squared
test
in R?
I cannot see that this has been answered. It has a date from 12 days
ago but I cannot see a reply in the archives.
So, what is a mid-p value and which
On Sun, 13 Jun 2010, Fabian Zäpernick wrote:
Hi
I want to write a C function for the R Code below and call it with .Call:
SimPoisson - function(lambda,tgrid,T2M)
#Simulation eines Poissonprozesses
snip
return(list(NT=NT,Ni=Ni,tau=tau))
}
I read the manual writing R extensions over
o.k,
I found an example where my algorithm can't fix the tree order.
But I don't know how to resolve it.
Here is the code to reproduce the problem:
#
order.a.tree - function(tree)
{
num.of.leafs - length(tree$order)
for(i in
Dear list,
Following up on an earlier post, I would like to reorder a dataset and
compute pairwise correlations. But I'm having some real problems
getting this done.
My data looks something like:
Participant Stimulus Measurement
p1 s`15
p1 s`2
joerg wrote:
I am trying to label data points within a scatter plot using thigmophobe.
While the data set consists of about 3000 points I only would like to
label a subset of these points.
I read the x and y coordinates in from a txt file and define them as:
I have a data frame with two factors (sampling 'unit', 'species'). I want to
calculate the number of unique 'species' per 'unit.' I can calculate the
number of unique values for each variable separately, but can't get a count
for each ‘unit’.
data=read.csv(C:/Desktop/sr_sort_practice.csv)
Giuseppe wrote:
Hello:
I use R with MAC
I have a simple data table, numeric and text columns, named dt. The table
is imported through read.csv from a csv file. Row numbers are
automatically assigned, header is set to TRUE. there are 599 rows and
several columns.
I am trying to plot
I think ?tapply will help here. But *please* read the posting guide and provide
minimal, reproducible examples!
Birdnerd wrote:
I have a data frame with two factors (sampling 'unit', 'species'). I want to
calculate the number of unique 'species' per 'unit.' I can calculate the
number of
Hi there,
Try
with(data, tapply(species, unit, function(x) length(unique(x
HTH,
Jorge
On Sun, Jun 13, 2010 at 12:07 PM, Birdnerd wrote:
I have a data frame with two factors (sampling 'unit', 'species'). I want
to
calculate the number of unique 'species' per 'unit.' I can calculate
Silly question, but, can I test to see if any value of list a is contained in
list b without doing a loop? A loop is easy enough, but wanted to see if
there was a cleaner way. By way of example:
List 1: a, b, c, d, e, f, g
List 2: z, y, x, w, v, u, b
Return true, since both lists contain b
On 13-Jun-10 17:12:45, David Winsemius wrote:
On Jun 1, 2010, at 4:17 AM, Wilson, Andrew wrote:
Can anyone tell me how to calculate a mid-p value for a chi-squared
test in R?
I cannot see that this has been answered. It has a date from 12 days
ago but I cannot see a reply in the
On Jun 13, 2010, at 1:47 PM, Claus O'Rourke wrote:
Dear list,
Following up on an earlier post, I would like to reorder a dataset and
compute pairwise correlations. But I'm having some real problems
getting this done.
My data looks something like:
Participant Stimulus Measurement
p1
On Jun 13, 2010, at 2:17 PM, GL wrote:
Silly question, but, can I test to see if any value of list a is
contained in
list b without doing a loop? A loop is easy enough, but wanted to
see if
there was a cleaner way. By way of example:
List 1: a, b, c, d, e, f, g
List 2: z, y, x, w, v,
Hi GL,
Tr this:
# example 1
list1 - list(letters[1:7])
list1
list2 - list(c('z','y','x','w','v','u','b'))
list2
mapply(function(x, y) any(x %in% y), list1, list2)
# example 2
list2 - list(c('z','y','x','w','v','u','t'))
list2
mapply(function(x, y) any(x %in% y), list1, list2)
HTH,
-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of GL
Sent: Sunday, June 13, 2010 11:18 AM
To: r-help@r-project.org
Subject: [R] Are any values in one list contained within a second list
Silly question, but, can I test to
I have a simple graph (oode below) which looks fine on the screen but when
I save it in png format the title (actually the last mtext line) is cut off.
I am pretty sure that I am doing something very stupid but
other than playing around with the png height and width commands which don't
seem
I think the simplest way is to translate the English
directly :-)
list1 = c('a','b','c','d','e','f','g')
list2 = c('z','y','x','w','v','u','b')
any(list2 %in% list1)
[1] TRUE
list2 = c('z','y','x','w','v','u','t')
any(list2 %in% list1)
[1] FALSE
-
select a cran mirror Packages Select Cran Mirror
In R use the following command
install.packages(RSQLite)
--- On Sun, 6/13/10, vijaysheegi vijay.she...@gmail.com wrote:
From: vijaysheegi vijay.she...@gmail.com
Subject: Re: [R] HOW to install RSQLite database
To: r-help@r-project.org
Hey John,
I believe this issue is that the png device is different from the
onscreen one. You set the margins for the on screen with a call to
par() but not for the png(). The code below works for me.
mydata - data.frame(kel=c(13,253,263,273,283,292,303,313,323,333,573,853),
Oh, how embarrassing! I made the exact same mistake about 2-3 years ago.
Thanks a lot.
It was not even that important a graph but
it was really bothering me.
--- On Sun, 6/13/10, Joshua Wiley jwiley.ps...@gmail.com wrote:
From: Joshua Wiley jwiley.ps...@gmail.com
Subject: Re: [R] losing
Try this:
sapply(installed.packages()[,1], function(x)try(ls(asNamespace(x
On Sun, Jun 13, 2010 at 9:30 AM, Data Monkey coco.datamon...@gmail.comwrote:
Thanks Joris. Very helpful.
I had thought of that, just curious to see if it was possible to get a
fresh list in R.
After reading your
On Jun 13, 2010, at 2:19 PM, (Ted Harding) wrote:
On 13-Jun-10 17:12:45, David Winsemius wrote:
On Jun 1, 2010, at 4:17 AM, Wilson, Andrew wrote:
Can anyone tell me how to calculate a mid-p value for a chi-squared
test in R?
I cannot see that this has been answered. It has a date from 12
Giuseppe,
See comments below.
On 2010-06-13 10:24, David Winsemius wrote:
Giuseppe wrote:
Hello:
I use R with MAC
I have a simple data table, numeric and text columns, named dt. The table
is imported through read.csv from a csv file. Row numbers are
automatically assigned, header is set to
You can also use the sqldf package:
x
unit species
1 123ACMA
2 123LIDE
3 123LIDE
4 123SESE
5 123SESE
6 123SESE
7 345HEAR
8 345LOHI
9 345QUAG
10 345TODI
require(sqldf)
sqldf('select unit, count(distinct species) as count from x group
On Jun 13, 2010, at 3:44 PM, Henrique Dallazuanna wrote:
Try this:
sapply(installed.packages()[,1], function(x)try(ls(asNamespace(x
You could clean that up a bit with:
funlist - sapply(installed.packages()[,1],
function(x)try(ls(asNamespace(x
function.list -
On Jun 13, 2010, at 3:49 PM, Peter Ehlers wrote:
Giuseppe,
See comments below.
On 2010-06-13 10:24, David Winsemius wrote:
Giuseppe wrote:
Hello:
I use R with MAC
I have a simple data table, numeric and text columns, named dt.
The table
is imported through read.csv from a csv file.
On Sun, 13 Jun 2010, Birdnerd wrote:
I have a data frame with two factors (sampling 'unit', 'species'). I want to
calculate the number of unique 'species' per 'unit.' I can calculate the
number of unique values for each variable separately, but can't get a count
for each ‘unit’.
If I
Peter Ehlers wrote:
Giuseppe,
See comments below.
On 2010-06-13 10:24, David Winsemius wrote:
Giuseppe wrote:
Hello:
I use R with MAC
I have a simple data table, numeric and text columns, named dt. The
table
is imported through read.csv from a csv file. Row numbers are
Hi all,
This should be a very simple question for you, whereas it is proving devilish
for me.
How do I output the STANDARD ERROR of the regression coefficient (i.e., the
standard error of b) from a simple linear regression?
Consider this data, taken directly from ?lm:
ctl -
Josh B wrote:
Hi all,
This should be a very simple question for you, whereas it is proving devilish
for me.
How do I output the STANDARD ERROR of the regression coefficient (i.e., the
standard error of b) from a simple linear regression?
The first 'See Also' in ?lm is for ?summary.lm,
I would like to get rid of the double precision round off chaff, so is the
following the best way to handle it?
0.625-0.8+0.45-0.275
[1] -5.551115e-17
round(0.625-0.8+0.45-0.275, digits=4)
[1] 0
Motivation for removing the chaff is for no other reason than to titty up the
digits for display
Jason:
Many print methods have specific options to control this: ?print.default
See also the digits and scipen settings in ?options for global control
(these can be put in your startup file, for example).
See also ?format and e.g. ?sprintf for more precise control of print format.
All of this
The final registration deadline for the R User Conference is June 20,
2010, one week away. Later registration will not be possible on site!
Conference webpage: http://www.R-project.org/useR-2010
Conference program: http://www.R-project.org/useR-2010/program.html
Registration:
Enrique,
That's fantastic. Thanks for that1
I got a couple of warnings but for the most part it looks like it gives what I
want.
Cheers.
On 14/06/2010, at 5:44 AM, Henrique Dallazuanna wrote:
Try this:
sapply(installed.packages()[,1], function(x)try(ls(asNamespace(x
On Sun, Jun 13,
Hi:
Another possibility:
as.data.frame(with(data[!duplicated(data), ], table(unit))
unit Freq
1 1233
2 3454
HTH,
Dennis
On Sun, Jun 13, 2010 at 9:07 AM, Birdnerd haaszool...@gmail.com wrote:
I have a data frame with two factors (sampling 'unit', 'species'). I want
to
calculate
Hi,
Could you please tell me whether SVM can do multiple regression or not?
Cheers,
Amy
_
Browse profiles for FREE! Meet local singles online.
[[alternative HTML version deleted]]
Hi, this is not R technical question per se. I know there are many excellent
statisticians in this list, so here my questions: I have dataset with ~1800
observations and 50 independent variables, so there are about 35 samples per
variable. Is it wise to build a stable multiple logistic model
Hi,
On Sun, Jun 13, 2010 at 8:30 PM, Amy Hessen amy_4_5...@hotmail.com wrote:
Hi,
Could you please tell me whether SVM can do multiple regression or not?
Yes, an SVM can.
-steve
--
Steve Lianoglou
Graduate Student: Computational Systems Biology
| Memorial Sloan-Kettering Cancer Center
|
I am not exactly sure whether this is the right place to ask this but I hope
this might be relevant to some other users of ubuntu linux as well.
I've installed R-2.11.1 in my ubuntu 10.04 LTS.
When I tried to generate a simple plot, however, it crashed:
plot(rnorm(100))
Error in axis(side =
On Sun, Jun 13, 2010 at 10:10 AM, Joe P King j...@joepking.com wrote:
I am wanting to plot a 95% confidence band using segplot, yet I am wanting
to have groups. For example if I have males and females, and then I have
them in different races, I want the racial groups in different panels. I
68 matches
Mail list logo
