Hi
I am not an expert in time series modelling but it seems to me that
combination ar model and resid extractor function for result of this model
does not work as anticipated. Check docs for resid and ar if there is some
explanation for this.
resid(ar(logrvar, aic=TRUE))
Error in ar.yw(x, aic
Try:
ar(logrvar, aic=TRUE)$resid
The problem you are running into is that
'resid' is a generic function, and the 'ar'
function neither returns an object with a
class nor returns an object that the default
method works with.
The 'summary' command you used might have
instead used 'str'.
The
Is there any resolution to this? Can RMySQL be used on Windows wit ha remote
MySQL server?
--
View this message in context:
http://r.789695.n4.nabble.com/RMySQL-Load-Error-package-namespace-load-failed-for-RMySQL-tp2289650p2293532.html
Sent from the R help mailing list archive at Nabble.com.
I can bootstrap from observed distribution using 'sample'. But now, the
challenge is to bootstrap from a frequency distribution. I have already
smoothed the distribution and the next step is to bootstrap from the
frequency distribution. I did numerous searches and found nothing.
Last, need to
Can RMySQL run on Windows using a remote MySQL server?
--
View this message in context:
http://r.789695.n4.nabble.com/Can-RMySQL-run-on-Windows-using-a-remote-MySQL-server-tp2293533p2293533.html
Sent from the R help mailing list archive at Nabble.com.
Dear ALL,
I have installed RODBC package in R and successfully connected to Oracle.
Now my question is when I am trying to execute oracle procedures though R, I
am not able to do it.
Simple oracle queries like select * from dbtable are successfully
executed. but the command for execution of
Hi Tim,
You might want to try it with the following:
par(usr=c(-2,1,ymin,ymax)
Where -2 and 1 are the exponents for your x-values, and ymin and ymax the
margins you want for your y-values.
Then you plot as usual adding the following parameters:
# trying to do a copy and a transform within a data frame, but getting the
arguments imply differing number of rows error, and I'm not sure why
a=c(1,2,3)
b=c(2,3,4)
c=c(Yes,No,Yes)
d=c(No,Yes,No)
df=data.frame(a,b,c,d)
# the following works fine!
df = transform(df, new=sapply(df[,c(1,2)], FUN
On 07/18/2010 11:22 PM, Peter Ehlers wrote:
...
[Now, I'm having trouble with the pemqzrsTawYY function;
can anybody help? :)]
Certainly. That is in the WelshRabbit package, which requires the
WalesSpeak and dumbBunny packages.
Jim
__
On 07/19/2010 01:59 AM, mau...@alice.it wrote:
I installed package plotrix because reading its vignette it looks like
it can help me solve a legend problem.
The package instaleed correctly on my Mac OS/X 10.5.8
But I cannot reproduce the examples centered on function lgendg.
library(plotrix)
Dear All,
I am a novice when it comes to time-series analysis and at the moment I
am actually interested in calculating the Hurst exponent of a time
series.
This question has already been asked quite some time ago
http://bit.ly/98dZsi
and I trust some progress has been made ever since.
I was
Hi,
Is there some easy way to split the grid.newpage() into two columns? For
example, how could I put the two forest plots below (meta1 and meta2) next to
each other?
library(meta)
data(Olkin95)
meta1 - metabin(event.e, n.e, event.c, n.c,data=Olkin95,
subset=c(41,47,51,59),sm=RR,
On 07/19/2010 03:59 PM, cob wrote:
...
Error in normalizePath(path) :
path[1]=C:\Program Files\R\R-2.11.1\library/slam: The system cannot find
the file specified
Hi cob,
That path looks like it won't be read properly - the backslashes should
be doubled.
Jim
Hello,
I am plotting a contour map of certain patterns with levelplot and I add a map
of the few countries on the top with the llines command ( I have a data of
longitudes and latitudes for that). But I need to plot a polygon around all the
countries (where the sea is) since the patterns need
Don't thank me, thank the authors of sos (Spencer Graves,
Sundar Dorai-Raj, and Romain Francois) and Jonathan Baron
for hosting the search site.
-Peter Ehlers
On 2010-07-18 23:43, Sean Carmody wrote:
Thanks Peter...I hadn't some across the sos package before, but I'm
sure I'll be putting it
Dear all
(a)in SPSS PASW there is a 'split file' command is repeats the same analysis
for all sub-groups. Is there a split file equivalent in R?
(b) Is there a package in R that will compute immediately statistics like
Hosmer and Lemeshow Test, pseudo-R squares etc without my intervention? I
Hi,
On 07/19/2010 11:56 AM, Iasonas Lamprianou wrote:
(a)in SPSS PASW there is a 'split file' command is repeats the same analysis
for all sub-groups. Is there a split file equivalent in R?
There is a by command in base R, but for this type of problems
Hadley Wickham has written a nice
Thank you, I'll have a look
\
Dr. Iasonas Lamprianou
Assistant Professor (Educational Research and Evaluation)
Department of Education Sciences
European University-Cyprus
P.O. Box 22006
1516 Nicosia
Cyprus
Tel.: +357-22-713178
Fax: +357-22-590539
Honorary Research Fellow
Department of
dear list,
I'm interested in using the 'dspMatrix' class of matrices, from the
R-project recommended package Matrix, to store large symmetric matrices.
I would like to know how to fill such a matrix cell by cell avoiding
coercion to a non-dspMatrix which might not be storing the symmetric
matrix
Esteemed R-users,
heatmap.2() is yielding an inappropriate key based on my colors and
break-points.
In the reproducible example below, the key is inappropriate (to me) because-
1. 'Orange' is simply not represented in the key, despite its prescence
in the heatmap.
2. The proportions of the
Hi,
i have such a code
tau-0
for (i in 1:10)
{
x-rnorm(20,0,1) #
t1=onesampb(x,est=tauloc,SEED=F)$conf.interval
if(t1[1]0 ||t1[2]0)tau=tau+1
}
print (tau)
this code gives me
Error in if (t1[1] 0 || t1[2] 0) tau = tau + 1 :
missing value where TRUE/FALSE needed
what can be done with
Dear R Users,
I am trying to replace a substring in a string with something else.
For example:
if we have abc.degg.hijk
I would like to replace all the . with a SPACE to become
abc degg hijk
I have tried the replace.substring.wild function in the Hmisc package but get
this error:
2010/7/18 Arnaud Trébaol arnaud.treb...@mail.polimi.it:
Hi all,
I am working for my master's thesis and I need to do a neural network to
forecast stock market price, with also external inputs like technical
indicators.
I would like to know which function and package of R are more suitable
Actually, I think I got it, need to use gsub.
From: Tolga I Uzuner
Sent: 19 July 2010 12:11
To: 'r-help@r-project.org'
Subject: Help with replacing a substring in a string
Dear R Users,
I am trying to replace a substring in a string with something else.
For example:
if we have abc.degg.hijk
I
do 'str(t1)' to see what the value returned is. Most likely one of
the comparisons in the 'if' statement is evaluating to NA.
Also PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
2010/7/19 A. Fırat
Look at the error messages generated and you will see:
Error in data.frame(list(a = c(1, 2, 3), b = c(2, 3, 4), c = c(2L, 1L, :
arguments imply differing number of rows: 3, 2
In addition: Warning messages:
1: In if (x == Yes) { :
the condition has length 1 and only the first element will be
Hello R-help,
I built the dendrogram. I would cut the dendrogram. Whatis the function in
R that allows to know how many classes?
Best Regards
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
You are right -- I made a typo. When I fix my code to go through the loop three
times, it works like a charm. THANK YOU!
For the benefit of the listserv, here is the full (WORKING) code:
x - read.table(textConnection(y1 y2 y3 x1 x2
indv.1 bagels donuts bagels 4 6
indv.2 donuts donuts donuts 5 1
Hi,
Have you tried gsub?
a = abc.degg.hijk
gsub(., ,a,fixed=TRUE)
[1] abc degg hijk
Martyn
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
On Behalf Of Tolga I Uzuner
Sent: 19 July 2010 12:38
To: r-help@r-project.org
Subject: Re: [R] Help
gsub(., , abc.degg.hijk, fixed=T)
On Jul 19, 2010, at 7:37 AM, Tolga I Uzuner wrote:
Actually, I think I got it, need to use gsub.
From: Tolga I Uzuner
Sent: 19 July 2010 12:11
To: 'r-help@r-project.org'
Subject: Help with replacing a substring in a string
Dear R Users,
I am trying to
Hi! I am trying to implement non-bipartite matching. I have around 500 sites
which can be clustered by 10 regions. I am able to calculate pairwise
Mahalanobis distances between sites (thanks to another post in the forum).
However, I want to constrain my match to sites within the same region. Thus
Hola amor!
Finalmente llegué a D.C. Ya estoy en el albergue pero el cuarto solo va a
ser liberado a la una o tal vez dos de la tarde. Pero no importa al menos ya
estoy aqui, ya tomé desayuno que por cierto es horrible. Voy a poder tomar
baño y usar un locker por un dolar. Entonces voy a tomar
Hi all,
I have a series of cateogiral variables that look just like this:
welfare=sample(c(less, same, more), 1000, replace=TRUE)
education=sample(c(less, same, more), 1000, replace=TRUE)
defence=sample(c(less, same, more), 1000, replace=TRUE)
egp=sample(c(salariat, routine non-manual,
Very sorry about that!
2010/7/19 marlene marchena marchenamarl...@gmail.com
Hola amor!
Finalmente llegué a D.C. Ya estoy en el albergue pero el cuarto solo va a
ser liberado a la una o tal vez dos de la tarde. Pero no importa al menos ya
estoy aqui, ya tomé desayuno que por cierto es
I've been using the pcaMethods to develop a scores matrix
===
data(iris)
pcIr - pca(iris[,1:4], method=nipals, nPcs=3, cv=q2)
test - scores(pcIr)
What I'm looking to do is to use lattice's barchart to plot the scores
On Jul 19, 2010, at 9:36 AM, Simon Kiss wrote:
Hi all,
I have a series of cateogiral variables that look just like this:
welfare=sample(c(less, same, more), 1000, replace=TRUE)
education=sample(c(less, same, more), 1000, replace=TRUE)
defence=sample(c(less, same, more), 1000, replace=TRUE)
Sorry about not answering sooner and providing code. My company mail
server died this weekend and I could respond without creating a new
account on r-help.
The package I'm using is pcaMethods (1.12)(found in the bioconductor
packages). The following runs
==
replace dist with mahalanobis distance in the following example.
a - cbind(runif(10), sample(1:3, 10, replace=T))
a.L - split(a,a[,2])
dist.L - lapply(a.L, dist)
Nikhil Kaza
Asst. Professor,
City and Regional Planning
University of North Carolina
nikhil.l...@gmail.com
On Jul 19, 2010, at
I'm using nls to fit a variety of different models. Here I use SSgompertz as
an example.
I want the ability to fix one (or more) of the coefficients that would
normally be optimised (e.g. fix b3=0.8).
Examples; based on and using data from example(SSgompertz)
#-
# vanilla
See ?ifelse.
Your num_value function needs to be rewritten in vector form using ifelse.
Al R aneva...@yahoo.com wrote:
# trying to do a copy and a transform within a data frame, but getting the
arguments imply differing number of rows error, and I'm not sure why
a=c(1,2,3)
b=c(2,3,4)
I got plotrix running after updating R. My problem is now solved. Thank you.
Maura
-Messaggio originale-
Da: Jim Lemon [mailto:j...@bitwrit.com.au]
Inviato: lun 19/07/2010 10.58
A: mau...@alice.it
Cc: r-h...@stat.math.ethz.ch
Oggetto: Re: package plotrix
On 07/19/2010 01:59 AM,
Dear R-users,
I got problem when using both RMPI and RMySQL together and I thought some body
in this forum can help me.
I have a huge data set (more than 300,000 rows) and I would like to modify only
few observations. I wrote the modifications in a function form and able to send
the function
Don't send the open connection object... send the connection info (database
name, username, password, etc.) and create new connections as part of the slave
task. The master connection object is not valid on the slaves.
kdbondalap...@jacks.sdstate.edu wrote:
Dear R-users,
I got problem when
I inherited a function written either for an older version of R or SPlus
to draw a brace, {, in a graph. It uses par(uin) to determine the
scaling of the
quarter circles that make up segments of the brace, but that setting
doesn't
exist in current R.
I'm guessing that, in the function below,
http://tinyurl.com/34fhcvg
Am 19.07.2010 17:20, schrieb Michael Friendly:
I inherited a function written either for an older version of R or SPlus
to draw a brace, {, in a graph. It uses par(uin) to determine the
scaling of the
quarter circles that make up segments of the brace, but that
Thanks for the tip, Nikhil. However, i need only one matrix as input for
another to compute for non-bipartite matching which minimizes pairwise
distances between observations. As such, I need the georeference (id) of the
observations for subsequent processing. Below is an illustration.
#generate
Hi,
Excuse me for asking this silly question. But I really couldn't understand
why cov() and ccov() don't work for my calculation of covariance matrix.
a - matrix(1:8, 2, 4)
a
[,1] [,2] [,3] [,4]
[1,]1357
[2,]2468
ccov(a)
Error in solve.default(cov, ...) :
On Mon, Jul 19, 2010 at 9:09 AM, Wendy Han wendyha...@gmail.com wrote:
Hi,
Excuse me for asking this silly question. But I really couldn't understand
why cov() and ccov() don't work for my calculation of covariance matrix.
a - matrix(1:8, 2, 4)
a
[,1] [,2] [,3] [,4]
[1,]13
My question is probably stupid but why don't you use the text() function?
plot(1:10,type=n)
text(4,4,{)
text(6,6,{,cex=3) # if you want it bigger
Alain
On 19-Jul-10 17:20, Michael Friendly wrote:
I inherited a function written either for an older version of R or SPlus
to draw a brace, {,
Is there an easy way to load plots in png files into R? I'm using the png
function to create the plots from a batch job and would like to view them later.
-Original Message-
From: Gavin Simpson gavin.simp...@ucl.ac.uk
Sent: Saturday, July 17, 2010 6:21pm
To: linda.s
From the S+8.1 documentation graphics.pdf
*
uin *information numeric inches per *usr *unit *c(0.73, 0.05)
*
[[alternative HTML version deleted]]
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R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read
John Fox j...@mcmaster.ca 14/07/2010 15:49:21
the development version of the car package on R-Forge, which can be
installed via install.packages(car,
repos=http://R-Forge.R-project.org;
(and which has an argument named center, not location).
Would you consider a plaintive request to
On 2010-07-19 7:50, Shawn Way wrote:
Sorry about not answering sooner and providing code. My company mail
server died this weekend and I could respond without creating a new
account on r-help.
The package I'm using is pcaMethods (1.12)(found in the bioconductor
packages). The following runs
On 2010-07-19 7:35, Shawn Way wrote:
I've been using the pcaMethods to develop a scores matrix
===
data(iris)
pcIr- pca(iris[,1:4], method=nipals, nPcs=3, cv=q2)
test- scores(pcIr)
What I'm looking to do is to use
Thanks for the tip, Nikhil. However, i need only one matrix as input
for another to compute for non-bipartite matching which minimizes
pairwise distances between observations. As such, I need the
georeference (id) of the observations for subsequent processing. Below
is an illustration.
Dear Elaine,
The calibrate package contains a routine for canonical correlation
analysis called canocor. Section 4.3 of the documentation vignette
of the package shows how to make biplots for canonical correlation
analysis.
Hope this helps,
Best regards,
Jan Graffelman.
Message: 13
Date:
Hello,
Iâm using strucchange package in R software in order to apply Bai and
Peron (1998, 2003) structural break tests to a set of n=1671
observations with a constant term (no AR terms).
For that purpose I have read several papers, for instance âValidating
Multiple Structural Change
Hi, are there any library to estima a fractionally integrated
ARFIMA-STVGARCH model? You can read about it in
http://www.greqam.fr/IMG/working_papers/2008/2008-36.pdf
Thanks,
Sebastián.
__
R-help@r-project.org mailing list
I see now my error, several in fact:
The 'breaks' specified need to be of a similar range to the data range,
and they should be equally spaced.
So in my example:
breaks = seq(0, 0.2, 0.001)
If one needs uneqaully spaced coloring, as i do, then this is achieved
by specifying the approprate
Dear all,
I produced a part of code which does what needed but by estimations I would
need to wait for that for 300 hours!!!
Maybe someone can give a me a glance advice or something.
Thanks a lot!
I need to define maximum adjusted R-squares from regression model: returns
as dependent variable(
Iâm using strucchange package in R software in order to apply Bai and
Peron (1998, 2003) structural break tests. This sequential procedure
includes: 1) Sup F test; 2) double maximum tests and 3) supFT (l+1/ l)
tests.
Could anyone help me to perform such tests in R, please?
Kind Regards,
Michael,
You can modify the following code to suit. Also avoid using dist as a
variable name since it is a function in base. However, are you sure
you want to do this? Sx is the variance using sites in all the regions!
d1 - apply(x,1, function(i){mahalanobis(x,i,Sx)})
is.na(d1) -
Hello,
I'm trying to do some differential equation modeling in R using the
package 'deSolve.' Briefly, I'm trying to use the law of mass action
(the details of which aren't really important) to structure a vector
of rate equation which will be passed into an ODE function and solved
with
Hi,
from the documentation of help.search I think that fields like concept
and keywords in the R help database exists. How can I access them from R?
If I do
help-help.search(blabla)
colnames(help$matches)
[1] topic title Package LibPath
then I get back only back these 4 fields.
Thanks
On 2010-07-17 23:03, Peter Dalgaard wrote:
Ista Zahn wrote:
Hi,
On Fri, Jul 16, 2010 at 5:18 PM, CC turtysm...@gmail.com wrote:
I am sure this is a very basic question:
I have 600,000 categorical variables in a data.frame - each of which is
classified as 0, 1, or 2
What I would like to do is
My mistake, instead of colnames(d1)
use substr(colnames(d1),1,1) or similar
On Jul 19, 2010, at 2:15 PM, Nikhil Kaza wrote:
Michael,
You can modify the following code to suit. Also avoid using dist as
a variable name since it is a function in base. However, are you
sure you want to do
Hello All,
Does anyone know how to download historical LIBOR rates of different
currencies into R?
Or if anyone knows of a website that holds all this data...I only need up to
january of 2000.
Also, how can we make the row names the index of a plot (the names of the x
values)?
myDF =
data.frame(id=c(A10,A20),d1=c(.3,.3),d2=c(.4,.4),d3=c(-.2,.5),d4=c(-.3,.6),d5=c(.5,-.2),d6=c(.6,-.4),d7=c(-.9,-.5),d8=c(-.8,-.6))
doit=function(x)c(x[1],sum_LK_positive=sum(x[-1][x[-1]0]),sum_LK_negative=sum(x[-1][x[-1]0]))
myDF
id d1 d2 d3 d4 d5 d6 d7 d8
1 A10 0.3 0.4
jd6688 wrote:
myDF =
data.frame(id=c(A10,A20),d1=c(.3,.3),d2=c(.4,.4),d3=c(-.2,.5),d4=c(-.3,.6),d5=c(.5,-.2),d6=c(.6,-.4),d7=c(-.9,-.5),d8=c(-.8,-.6))
doit=function(x)c(x[1],sum_LK_positive=sum(x[-1][x[-1]0]),sum_LK_negative=sum(x[-1][x[-1]0]))
myDF
id d1 d2 d3 d4 d5 d6
Jason,
Erik already offered a nice solution, but I wanted to comment on why
it did not work. apply() works on arrays and, of course, matrices.
When you pass a data frame to apply, it will try to coerce it to a
matrix. Matrices only contain a single class of data (unlike data
frames which can
Hi all,
I am trying to concatenate words together to create new column names, using a
loop.
Please consider the following toy example:
x - matrix(nrow = 1, ncol = 3)
colnames(x) - c(a, b, c)
x[1,1] - 1
x[1,2] - 2
x[1,3] - 3
I would like to create a new matrix with column names based on the
Try this:
colnames(y) - sprintf('q_%s', colnames(x))
On Mon, Jul 19, 2010 at 4:35 PM, Josh B josh...@yahoo.com wrote:
Hi all,
I am trying to concatenate words together to create new column names, using
a
loop.
Please consider the following toy example:
x - matrix(nrow = 1, ncol = 3)
so I must use a loop. is almost never true in R. This works:
colnames(y) - paste(q_, colnames(x), sep = )
HTH,
Josh
On Mon, Jul 19, 2010 at 12:35 PM, Josh B josh...@yahoo.com wrote:
Hi all,
I am trying to concatenate words together to create new column names, using a
loop.
Please
Josh B wrote:
Hi all,
I am trying to concatenate words together to create new column names, using a
loop.
Please consider the following toy example:
x - matrix(nrow = 1, ncol = 3)
colnames(x) - c(a, b, c)
x[1,1] - 1
x[1,2] - 2
x[1,3] - 3
I would like to create a new matrix with column
You might try asking on the R-SIG-Finance group, if nobody here can answer
your question (https://stat.ethz.ch/mailman/listinfo/r-sig-finance).
Jonathan
On Mon, Jul 19, 2010 at 1:21 PM, Aaditya Nanduri
aaditya.nand...@gmail.comwrote:
Hello All,
Does anyone know how to download historical
Hi Ted,
This is difficult to answer without a self-contained example -- one
that can be cut and pasted into an R session and run. You might also
try coercing each element of aaa to a dataframe before calling rbind.
--Gray
On Fri, Jul 16, 2010 at 4:34 PM, Ted Byers r.ted.by...@gmail.com wrote:
Hi,
I was recently splitting some massive phylo class objects with extract.clade()
and noticed what appears to be a bug in how tip labels are copied from the
full tree to the pruned tree. This possible bug was also mentioned here:
On Jul 19, 2010, at 3:43 PM, Erik Iverson wrote:
jd6688 wrote:
myDF =
data.frame(id=c(A10,A20),d1=c(.3,.3),d2=c(.4,.4),d3=c(-.
2,.5),d4=c(-.3,.6),d5=c(.5,-.2),d6=c(.6,-.4),d7=c(-.9,-.5),d8=c(-.
8,-.6))
doit=function(x)c(x[1],sum_LK_positive=sum(x[-1]
help(integrate)
Nathalie Gimenes ncgmsanc...@gmail.com
Sent by: r-help-boun...@r-project.org
07/19/2010 04:59 PM
To
r-help@r-project.org
cc
Subject
[R] integral in R
Hello All,
I have to create a variable that is a function of another one (already
created), its cumulative
Another option could be:
doit - function(x)c(sum(x[x 0]), sum(x[x 0]))
apply(transform(myDF, row.names = id, id = NULL), 1, doit)
On Mon, Jul 19, 2010 at 4:36 PM, jd6688 jdsignat...@gmail.com wrote:
myDF =
Thank you a lot, Jim.
Issue solved.
Balpo
On 16/07/10 11:27, jim holtman wrote:
Here is a way of creating a separate list of variable length vectors
that you can use in your processing:
# read into a dataframe
x- read.table(textConnection(ABCTLengths
+ 14.0
On Mon, 19 Jul 2010, João Boavida wrote:
I???m using strucchange package in R software in order to apply Bai and
Peron (1998, 2003) structural break tests. This sequential procedure
includes: 1) Sup F test; 2) double maximum tests and 3) supFT (l+1/ l)
tests.
Thanks for your interest, but you
Dylan Beaudette debeaudette at ucdavis.edu writes:
I was recently splitting some massive phylo class objects with
extract.clade()
and noticed what appears to be a bug in how tip labels are copied from the
full tree to the pruned tree. This possible bug was also mentioned here:
Hello All,
I have to create a variable that is a function of another one (already
created), its cumulative distribution function and the integral of this
cumulative distribution, with limits: 0 and the value of the variable.
To be clear, I have the variable called cip. And its cdf called
I have done this from my previous computer, a Windows PC
running Windows XP (32 bit). So in theory it can be done.
I had installed the MySQL Workbench application as well
which no doubt set up the MySQL dll's needed.
My new computer is running Windows 7 64-bit for which
RMySQL is not yet built.
Michael,
I have a very old version of some brace functions somewhere.
I never did combine them into a single function, so there's
one each for left/right/up/down braces. (I used them in
teaching regression to show resids and formulae.)
If you're interested, I'll dig 'em up and send them.
Hi
Also see the xinch() and yinch() functions.
Paul
On 20/07/2010 10:44 a.m., Peter Ehlers wrote:
Michael,
I have a very old version of some brace functions somewhere.
I never did combine them into a single function, so there's
one each for left/right/up/down braces. (I used them in
teaching
Dear R-Listers,
My question concerns indexing vectors by logical vectors that are based
on the original vector. Consider the following simple example to
hopefully make clear what I mean:
a - rnorm(10)
a[a0] - NA
However, I am now working with multiple data frames that I received,
where
On Jul 19, 2010, at 7:16 PM, Christian Raschke wrote:
Dear R-Listers,
My question concerns indexing vectors by logical vectors that are
based on the original vector. Consider the following simple example
to hopefully make clear what I mean:
a - rnorm(10)
a[a0] - NA
However, I am now
Hi:
a - matrix(1:8, 2, 4)
cov(a)# using cov() from stats package
[,1] [,2] [,3] [,4]
[1,] 0.5 0.5 0.5 0.5
[2,] 0.5 0.5 0.5 0.5
[3,] 0.5 0.5 0.5 0.5
[4,] 0.5 0.5 0.5 0.5
After using package sos to discover that ccov() is a function in package
robust (which was
As far as I know the answer to your question is No, but there are things you
can do to improve the readability of your code. One thing I find useful is to
avoid using $ as much as possible and to favour things like with() and
within().
The first thing you might do is think about choosing
Greetings
I have been trying to use metaplot to create a forest plot of my meta-analysis
results. My data is in the form of ORs, so I've been inputting the ORs as the
point estimate (mn) and the SEs of the logORs as the SE (se). However, whilst
the point estimates appear to be displayed
Hi
On 19/07/2010 9:17 p.m., Eleni Rapsomaniki wrote:
Hi,
Is there some easy way to split the grid.newpage() into two columns?
For example, how could I put the two forest plots below (meta1 and
meta2) next to each other?
library(meta) data(Olkin95)
meta1- metabin(event.e, n.e, event.c,
Hi,
I am a newbie in R and was working on some DNA data represented as strings
of A,C,T and G (also wild-character like M and X). I use the Bioconductor
package in R. Currently I need to convert a string of the form ACCTGMX to
1223400 i.e. A is replaced by 1, C with 2, T with 3, G with 4 and any
Thank you very much for your help, Nikhil! The code I'm using now is
#generate data
set.seed(2)
x - as.matrix(runif(5))
id1 - sample(1:2,5,replace=T)
id2 - c(1:5)
rownames(x) - paste(id1, id2)
#create distance matrix if same id1
x.L - split(x,id1)
n.L - split(rownames(x), id1)
for(i in
I have a list of vectors of length 2, each representing a point in 2-space,
and each of which I wish to plot on the current plot.
In a loop, I assign the x and y coordinates of the current element of the
list to variables 'x' and 'y' respectively, then make a call to plot as
follows:
par(new =
I'm using Windows XP.
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R-help@r-project.org
I am designing a package to analyze fire department data. I created an S4
class called CAD (short for Computer Aided Dispatch data) as part of this
package that essentially extends the data.frame class. When the user
initializes a CAD object, a data.frame object is broken down into seperate
Dear All,
I have some data in the following shape:
ID begin_t1end_t1 begin_t2end_t2
Thomas 11/03/0413/05/0604/02/0716/05/08
... ... ... ...
Hi
I have got the same error than you had, calling BUGS from R with the
bugs() function:
/ Error in FUN(X[[1L]], ...) :
//.C(..): 'type' must be real for this format/
but couldn't find the answer on the R help site.
Could you please give me a hint? Could you solve it?
( i am simply trying
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