Hi,
I have a dataset from ILO, originally in csv-format, that I have read into
R. It is cross-sectional time-series data, so I have a bunch of variables
and dummy variables that I need to extract data from for the entire time
period. However, the years are separated by columns instead of rows, as
Hi all,
I'm still seeking for tweaking the appearance of the color legend in a
bar goemetry with ggplot2.
I can't seem to control the filling of the colour legend squares
take this,
ggplot(diamonds, aes(clarity, fill=color,colour = cut)) +
geom_bar(position = dodge)
and I'd need a white
On 09/13/2010 06:17 AM, Karl Brand wrote:
Cheers!
All excellent, runable examples helping me progress quickly.
Being more a qualitative plot, the y-axis is less important. But it did
get me thinking-
Coloring each of the plotted lines, say 'altitude colors' like the
classic volcano example to
Thank you all for your comments. The bxp() function does the trick well!
Subject: RE: [R] boxplot knowing Q1, Q3, median,upper and lower whisker value
Date: Fri, 10 Sep 2010 11:00:06 -0700
From: wdun...@tibco.com
To: dig...@ohsu.edu; dasol...@hotmail.com
CC: r-help@r-project.org
Dear R,
I have a vector, say a = c(1,2,4,5,6,8). Can I generate a vector or array
(2-by-3-by-3) of this form c(1,2,1,2,1,2,4,5,4,5,4,5,6,8,6,8,6,8), in which
every two elements in a have been repeated twice?
I am to stupid today and could not figure this simple question out... Many
many thanks!
On 09/13/2010 07:19 PM, Feng Li wrote:
Dear R,
I have a vector, say a = c(1,2,4,5,6,8). Can I generate a vector or array
(2-by-3-by-3) of this form c(1,2,1,2,1,2,4,5,4,5,4,5,6,8,6,8,6,8), in which
every two elements in a have been repeated twice?
I am to stupid today and could not figure this
Hi
Im trying to save a plot both to a pdf and as just a picture but without
success so if someone can help me I would be happy :)
my code:
require(party)
irisct - ctree(Species ~ .,data = iris)
data(iris)
attach(iris)
pdf('/home/joel/Skrivbord/mammamu.pdf')
On 13-Sep-10 09:19:21, Feng Li wrote:
Dear R,
I have a vector, say a = c(1,2,4,5,6,8). Can I generate a vector
or array (2-by-3-by-3) of this form
c(1,2,1,2,1,2,4,5,4,5,4,5,6,8,6,8,6,8)
in which every two elements in a have been repeated twice?
I am to stupid today and could not figure
Ted Harding ted.hard...@manchester.ac.uk wrote in message
news:xfmail.100913104250.ted.hard...@manchester.ac.uk...
On 13-Sep-10 09:19:21, Feng Li wrote:
Dear R,
I have a vector, say a = c(1,2,4,5,6,8). Can I generate a vector
or array (2-by-3-by-3) of this form
update.packages(checkBuilt=TRUE)
Uwe Ligges
On 24.08.2010 11:08, Giovanni Azua wrote:
Hello,
I upgraded my Mac R version to the newest 2.11.1, then I ran the option to
update all packages but there was an error related to fetching one of those and
the process stopped. I retried updating
On 07.09.2010 18:53, Tao wrote:
I used Rtools for installing a package under Windows XP. I used commands like
R CMD INSTALL (build, check) in the CMD window. It worked well until I found
that my revised package can be updated with R CMD INSTALL. After I restarted
my computer, R cannot be
Dear useRs from the physiology department,
Does someone know of an implementation of the SF-36 questionnaire scoring in
R? I only found SAS and STATA versions, e.g
http://gim.med.ucla.edu/FacultyPages/Hays/util.htm
Dieter
__
R-help@r-project.org
Sorry. It was my typo. Should be three times as it in the example.
Feng
On Mon, Sep 13, 2010 at 11:32 AM, Jim Lemon j...@bitwrit.com.au wrote:
On 09/13/2010 07:19 PM, Feng Li wrote:
Dear R,
I have a vector, say a = c(1,2,4,5,6,8). Can I generate a vector or array
(2-by-3-by-3) of this
Hello.
I would like to calculate with R
the weighted line integral of a loss field.
Where should I start searching about weighted integration in R?
I would like to thank you in advance for your help
Best Regards
Alex
[[alternative HTML version deleted]]
Thanks. That's what I want. Sorry for the typo:)
Feng
On Mon, Sep 13, 2010 at 11:42 AM, Ted Harding
ted.hard...@manchester.ac.ukwrote:
On 13-Sep-10 09:19:21, Feng Li wrote:
Dear R,
I have a vector, say a = c(1,2,4,5,6,8). Can I generate a vector
or array (2-by-3-by-3) of this form
Hi all, here is my small piece of codes:
fn1 - function(x = 4) {
y - 0
if(y == 0) cat(y value
is zero\n) # I intentionally created 2nd line here
return(4)
}
If I run this function I get following
fn1()
y value
is zero
[1] 4
Here you see
On Mon, Sep 13, 2010 at 11:16 AM, Dieter Menne
dieter.me...@menne-biomed.de wrote:
Dear useRs from the physiology department,
Does someone know of an implementation of the SF-36 questionnaire scoring in
R? I only found SAS and STATA versions, e.g
On Mon, Sep 13, 2010 at 11:53 AM, Christofer Bogaso
bogaso.christo...@gmail.com wrote:
Hi all, here is my small piece of codes:
fn1 - function(x = 4) {
y - 0
if(y == 0) cat(y value
is zero\n) # I intentionally created 2nd line here
return(4)
}
If I run this
Thanks Barry, I agree it will work. But this approach destroys the
indent in the program body therefore entire body of program looks
messy, for example
cat(Here I
put indent)
obviously looks better for someone who reads my code, than
cat(Here I
dont put indent)
Any better approach?
On
On 09/13/2010 11:32 AM, Joel wrote:
Hi
Im trying to save a plot both to a pdf and as just a picture but without
success so if someone can help me I would be happy :)
The problem is that the plot goes only to one graphics device, the last
one you defined. Just make the plot twice:
On Mon, Sep 13, 2010 at 12:11 PM, Christofer Bogaso
bogaso.christo...@gmail.com wrote:
Thanks Barry, I agree it will work. But this approach destroys the
indent in the program body therefore entire body of program looks
messy, for example
cat(Here I
put indent)
obviously looks
Barry Rowlingson wrote:
* SAS CODE FOR SCORING 36-ITEM HEALTH SURVEY 1.0
...
Thanks, Barry, but there was a mistake from my side: I am looking for SF-8.
Anyone else? Google was not successful for me
Dieter
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Dear R gurus,
How do I add dummy variable zero/ one in the ARIMA model both in the
in-sample and outside the sample(forecasts)?
Regards
Peter
South Africa
Tell: +2712 422 7357
Please Note: This email and its contents are subject to our email legal notice
which can be viewed
hello,
can i calculate a sum to infinity in R.
i want to do something like this:
\sum_{i=0}^\infty
\frac{2^{-d-1}}{\Gamma(\frac{d-1}{2})}\left(\frac{\Gamma(2d-3)(2-d)_{i}\Gamma(i+1,-z/2)2^{i+1}}{\Gamma(d-1)(4-2d)_{i}i!}\right)+
\\
\sum_{i=0}^\infty
Hi
I am using the ugarchspec function from the rgarch package to fit a mean
variance model jointly. Following is the code I'm using:
spec = ugarchspec(variance.model = list(model=eGARCH,
garchOrder=c(1,1)), mean.model = list(armaOrder=c(1,1)))
On doing this, I get the following error:
Error
Dear Sir or Madam,
I was trying to log back on to change my details, I want to
stop receiving other user's problems/solutions into my
inbox.
Yours sincerely,
Charlotte Ndiribe
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On Sep 13, 2010, at 1:54 AM, Uwe Dippel wrote:
Though I have read quite a bit, and tried quite a bit, I have yet to
find a nice way to overlay 2 or more curves in the same plot, with
different ranges.
The different axes could be a problem but if you construct both with
predefined
On Sep 13, 2010, at 2:31 AM, Gabriel Bergin wrote:
Hi,
I have a dataset from ILO, originally in csv-format, that I have
read into
R. It is cross-sectional time-series data, so I have a bunch of
variables
and dummy variables that I need to extract data from for the entire
time
period.
On Sep 13, 2010, at 5:32 AM, Joel wrote:
Hi
Im trying to save a plot both to a pdf and as just a picture but
without
success so if someone can help me I would be happy :)
Are you trying to embed a png file in a graphic or do you just want
two different files?
If the first (obviously
Hello everyone,
I have a 2x2 matrix filled with zeros and some more values around zeros. I
would
like to print only the non-zero values
and
to keep the coords of the places that the values are not zero.
Could you please help me with that?
I would like to thank you in advance for your help
Hi, want to shade the area between dotted lines:
x=c(1,5);y=c(1,5)
plot(y~x, type='n')
abline(v=c(2,3), lty=2)
sometnig simple needed. tried with polygon
thx, robert
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Dear list, I making some box-and-whisker plots in R with vertebrate
data. The x axis are species names that must be in italics. I tried
with the axis function but no luck, and it seems that affects both
axes.
Any tip?
Thanks a lot in Advance.
Alej
__
Try this getting the limits of the plot area:
x=c(1,5);y=c(1,5)
plot(y~x, type='n')
abline(v=c(2,3), lty=2)
usr - par('usr')
usr
[1] 0.84 5.16 0.84 5.16
rect(2, usr[3], 3, usr[4], col='green')
On Mon, Sep 13, 2010 at 8:45 AM, threshold r.kozar...@gmail.com wrote:
Hi, want to shade the
Here is how to get the indices of the non-zero values. You can
determine how you want to print them
x - rbind(c(1,0), c(0,3))
# get indices of non-zero
which(x != 0, arr.ind=TRUE)
row col
[1,] 1 1
[2,] 2 2
possible ways of printing:
x.1[x.1 == 0] - NA
x.1
[,1] [,2]
[1,]
Please report to the siar package maintainer (including the package
version of siar you are using).
Best,
Uwe Ligges
On 08.09.2010 00:36, Julio Lucio Lancelotti wrote:
Hi, my name is Julio, I'm trying to run a script, specifically with the siar
package on R (I have attached the script) but
On 28.08.2010 11:07, Samy Khezami wrote:
Hy,
I had a mistake on a function of a package i have created!
I have solved it and then i repackaged and installed the modified package.
Probably you installed the modified package into a diferent location
from the location that is used in Excel.
Thx for all the help!
Dave:
Its the second ones so now it looks like this and works but its abit ugly as
you have to plot the same thing two times but dossent seem to be any other
way or?
try(png('/home/joel/Skrivbord/mammamu2.png'))
plot(irisct)
dev.off()
I know someone who has R code for SF-36 and perhaps SF-12. Aren't there
copyright issues relating to SF-* even if it is reprogrammed?
Frank
-
Frank Harrell
Department of Biostatistics, Vanderbilt University
--
View this message in context:
On Sep 13, 2010, at 8:13 AM, Frank Harrell wrote:
I know someone who has R code for SF-36 and perhaps SF-12. Aren't there
copyright issues relating to SF-* even if it is reprogrammed?
Frank
Yep...
Hi
You may need to investigate ?plotmath and ?expression for the italics or
possibly add a font=... somewhere
Sorry cannot be more help it is too late here
Duncan
Duncan Mackay
Department of Agronomy and Soil Science
University of New England
ARMIDALE NSW 2351
Email home:
Yes: $() has to calculate more on matching the names --- and is more
of a hack anyway.
Although, I would not worry to much about 0.3 seconds in 100
evaluations ...
Uwe
On 08.09.2010 14:31, Søren Højsgaard wrote:
Dear list
It seems to me that extracting elements from a list using '[['
Dear authors! Could you specify the WEB page on which there is a
working version of R-2.11.1 for windows vista 32, of 10 I have
received files from different servers all were broken. The problem
with the file itself r-2.11.1-win 32.exe, as the program for
linux from the same websites will
On 13.09.2010 14:30, Molecular Diagnostic Center IPEE RAS wrote:
Dear authors! Could you specify the WEB page on which there is a
working version of R-2.11.1 for windows vista 32, of 10 I have
received files from different servers all were broken. The problem
with the file itself r-2.11.1-win
Frank Harrell wrote:
I know someone who has R code for SF-36 and perhaps SF-12. Aren't there
copyright issues relating to SF-* even if it is reprogrammed?
You are right. I was not aware of this, and I could not believe it first
that a company holds the right to use an almost trivial
Hello everyone.
I would like to create some agents that span over a specific area map.Every
agent needs to have its own data structures like one or two matrices and one
list.
I think that the best way to do this is to create objects and every instance of
an object will be used for a single
Thanks for replying, indeed works.
I forgot to mention that I am looking for a 'transparent shading' s.t. the
plot symbols are still visible on the shaded area.
robert
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Sent from the
Yes the company behind that probably received federal funds for some of the
research and has been very careful to minimize their contribution to the
community.
I didn't understand your parenthetical remark.
Frank
-
Frank Harrell
Department of Biostatistics, Vanderbilt University
--
View
If it's not possible to use their particular algorithms, does anyone
think it would be helpful/practical to try to write a general scoring
system? I imagine a function with arguments for column names, a list
where each element is a vector that indicates the numbers that
correspond to various
On Sep 13, 2010, at 8:50 AM, Alejo C.S. wrote:
Dear list, I making some box-and-whisker plots in R with vertebrate
data. The x axis are species names that must be in italics. I tried
with the axis function but no luck, and it seems that affects both
axes.
Any tip?
In bwplot just add:
...,
Did you check if the data in da has any NA in the dependent or the
independent data?
Remember that your function llk.mar is going to evaluate dnorm for each pair.
If any of those
pairs has an NA value, your function will return an NA at the end
(sum(c(NA,1,2,3)) = NA)
I would check if the
On Sat, 2010-09-11 at 14:41 -0700, Peng, C wrote:
Is this something you want to have (based on a simulated dataset)?
counts - c(18,17,15,20,10,20,25,13,12)
#risk - round(rexp(9,0.5),3)
risk- c(2.242, 0.113, 1.480, 0.913, 5.795, 0.170, 0.846, 5.240, 0.648)
gm - glm(counts ~ risk,
Hi again everyone.
Anyone know if there's any limitation with gap.plot concerning the fill
color of plotted markers? I would like to fill the circles with a color :
library(plotrix);
gap.plot(c(1,2,3,4,10), c(1,2,3,4,10), c(5,9), pch = 21, col = red);
However, it only change the color of the
check out this link
http://finzi.psych.upenn.edu/R/library/seqinr/html/col2alpha.html
On Mon, Sep 13, 2010 at 9:58 AM, threshold r.kozar...@gmail.com wrote:
Thanks for replying, indeed works.
I forgot to mention that I am looking for a 'transparent shading' s.t. the
plot symbols are still
Hi:
Here's a ggplot2 example:
p - ggplot(mtcars, aes(x = wt, y = mpg))
p + geom_rect(xmin = 2, xmax = 3, ymin = 0, ymax = Inf, fill = 'green',
alpha = 0.2) + geom_point() + theme_bw()
I don't know why the alpha transparency doesn't work in this example, but
plotting the points after
On Sep 13, 2010, at 10:34 AM, Filoche wrote:
Hi again everyone.
Anyone know if there's any limitation with gap.plot concerning the
fill
color of plotted markers? I would like to fill the circles with a
color :
library(plotrix);
gap.plot(c(1,2,3,4,10), c(1,2,3,4,10), c(5,9), pch = 21,
I'm still relatively new to R, so I tried the first of you two solutions:
.First - function(){
source(Friedman-Test-with-Post-Hoc.r.txt)
}
Thanks very much for that, it works perfectly
Cheers
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On Sep 13, 2010, at 8:59 AM, Joshua Wiley wrote:
If it's not possible to use their particular algorithms, does anyone
think it would be helpful/practical to try to write a general scoring
system? I imagine a function with arguments for column names, a list
where each element is a vector
Hi:
demo(graphics) has a lot of nice examples of how to use various features -
one of them is font selection.
font = 3 = italic font = 4 = bold italic
You need to select the correct aspect of the plot, however: font.main,
font.sub, font.lab or font.axis (from par()).
HTH,
Dennis
On Sep 13, 2010, at 15:59 , Joshua Wiley wrote:
If it's not possible to use their particular algorithms, does anyone
think it would be helpful/practical to try to write a general scoring
system? I imagine a function with arguments for column names, a list
where each element is a vector that
Thanks Gábor!
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Hi!
I updated to reshape2 yesterday and tried to make it work. Unfortunately, it
mainly throws error messages at me (good thing it's reshape2 1.0 and not
reshape 2.0). The most recent is:
Error in match.fun(FUN) : object 'id' not found
When I manually create an object 'id', it says:
Error in
Hello all,
I want to specify a minimum number of valid arguments for the mean
function--I have 5 variables but I want the mean only of cases that have at
least 3 valid answers. What is the best way to do that?
Thank you very much!
Luana
[[alternative HTML version deleted]]
Id like to sample the vector y repeatedly. In this dummy dataset, Id
like to sample (and store) it 1, 2, and 3 times.
Is there a straightforward way to do this without using a for loop?
x - c(1 :3)
y - c(1:10)
(run.sample - sample (y, x))
Thanks very much,
James Hudson
Thank you sir.
Regards,
Phil
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I'm trying to understand why as.Date() is converting a the modified date of
a file from August 22 to August 23.
foo - file.info(file.to.process)
str(foo)
'data.frame': 1 obs. of 10 variables:
$ size : num 5.37e+09
$ isdir : logi FALSE
$ mode :Class 'octmode' int 436
$ mtime :
On Mon, Sep 13, 2010 at 8:02 AM, Marc Schwartz marc_schwa...@me.com wrote:
On Sep 13, 2010, at 8:59 AM, Joshua Wiley wrote:
If it's not possible to use their particular algorithms, does anyone
think it would be helpful/practical to try to write a general scoring
system? I imagine a function
Is this a recent version of R? If so, please report to the maintainer.
Otherwise, please also report that it does not work with your version of
R so that the maintainer can add a version dependency.
Best,
Uwe Ligges
On 13.09.2010 17:42, Paul Metzner wrote:
Hi!
I updated to reshape2
On Sep 13, 2010, at 11:56 AM, Andrew Yee wrote:
I'm trying to understand why as.Date() is converting a the modified
date of
a file from August 22 to August 23.
foo - file.info(file.to.process)
str(foo)
'data.frame': 1 obs. of 10 variables:
$ size : num 5.37e+09
$ isdir : logi FALSE
$
The zoomplot or updateusr functions in the TeachingDemos package may help.
But be cautious, the thing that grabs the most attention is where 2 (or more)
lines cross, when you plot multiple lines on different scales the crossing is
meaningless, but that meaningless point is what draws the eyes.
?dev.copy
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-
project.org] On Behalf Of Joel
Sent: Monday, September 13, 2010 7:13 AM
To:
On Sep 13, 2010, at 5:24 AM, tuggi wrote:
hello,
can i calculate a sum to infinity in R.
i want to do something like this:
\sum_{i=0}^\infty
\frac{2^{-d-1}}{\Gamma(\frac{d-1}{2})}\left(\frac{\Gamma(2d-3)(2-
d)_{i}\Gamma(i+1,-z/2)2^{i+1}}{\Gamma(d-1)(4-2d)_{i}i!}\right)+
\\
Without the square term you can just use the rule for addition in sines:
sin(a+b) = sin(a)cos(b) + cos(a)sin(b)
So a regression of y= a + b* sin(2*pi/360*x + c) can be fit as:
lm( y~ sin( 2*pi/360*x) + cos( 2*pi/360/x ) )
If you need the actual values of b and c then you will need to do a
On Sep 13, 2010, at 10:30 AM, James Hudson wrote:
I‚d like to sample the vector „y‰ repeatedly. In this dummy dataset, I‚d
like to sample (and store) it 1, 2, and 3 times.
Is there a straightforward way to do this without using a „for‰ loop?
x - c(1 :3)
y - c(1:10)
(run.sample -
This is to announce that we plan to release R version 2.12.0 on Friday,
October, 2010.
Those directly involved should review the generic schedule at
http://developer.r-project.org/release-checklist.html
The source tarballs will be made available daily (barring build
troubles) via
Thanks David, now I wonder how you can have as.Date() render the date using
local time rather than UTC.
Andrew
On Mon, Sep 13, 2010 at 12:08 PM, David Winsemius dwinsem...@comcast.netwrote:
On Sep 13, 2010, at 11:56 AM, Andrew Yee wrote:
I'm trying to understand why as.Date() is converting
This is to announce that we plan to release R version 2.12.0 on Friday,
October 15, 2010.
Those directly involved should review the generic schedule at
http://developer.r-project.org/release-checklist.html
The source tarballs will be made available daily (barring build
troubles) via
Thank you Marc - the first scenario.
On Mon, Sep 13, 2010 at 2:04 PM, Marc Schwartz marc_schwa...@me.com wrote:
On Sep 13, 2010, at 10:30 AM, James Hudson wrote:
Iâd like to sample the vector âyâ° repeatedly. In this dummy dataset,
Iâd
like to sample (and store) it 1, 2, and
thanks for your help
I am trying to work around this in R but i have the feeling that this is going
to but the center and age next to each other which is not what i need...
it might be me not being able to find my head around this but...
i need a table with age as columns and center as rows
if
You can try this also:
Vectorize(sample, 'size')(y, 1:3)
On Mon, Sep 13, 2010 at 12:30 PM, James Hudson jmghud...@gmail.com wrote:
Id like to sample the vector y repeatedly. In this dummy dataset, Id
like to sample (and store) it 1, 2, and 3 times.
Is there a straightforward way to do
On Sep 13, 2010, at 1:24 PM, Andrew Yee wrote:
Thanks David, now I wonder how you can have as.Date() render the
date using local time rather than UTC.
Since we are both in the EDT TZ at the moment, our times are UTC-4
(hours = 60*60 seconds)
dt - as.POSIXct(2010-08-22 23:14:52)
Henrique, thanks for your suggestion. For my applications, character would
have been sufficient, so your suggestion of using format() works fine too.
Perhaps I should submit a feature request for as.Date() to let you specify
local time.
Thanks,
Andrew
On Mon, Sep 13, 2010 at 2:06 PM, Henrique
Hi guys,
Cant seem to find a solution for this. I am looking for a substitute for
cut that can transform character vectors. So as cut would be used below to
transform YearCat- YearCat2 base on Year and vector
Ag-c(00-'70,'71-'75,'76-'85,'86-'09) using 'cut '
Try this:
format(dt, '%Y-%m-%d'), if you want Date class:
as.Date(format(dt, '%Y-%m-%d'))
On Mon, Sep 13, 2010 at 2:24 PM, Andrew Yee y...@post.harvard.edu
wrote:
Thanks David, now I wonder how you can have as.Date() render the
date using
local time rather than UTC.
Andrew
On Mon,
Hello,
I'm attempting to use the ratetable argument to
survexp in the survival package. I use
the example from the ?survexp help page below,
and then slightly modify it to produce an error.
library(survival)
data(pbc)
#fit a model without any factors
pfit1 - coxph(Surv(time, status 0) ~ trt
CRAN has a significant update to rms. Windows and unix/linux versions
are available and I expect the Mac version to be available soon.
The most significant improvement is addition of latex=TRUE
arguments to model fitting print methods, made especially for use
with Sweave.
Here is a summary
Dears,
does anyone know whether there is any complete list with explanations for the
several Trellis parameters (i.e. the ones you one gets with trellis.par.set() )
available? Many of them are self explanatory or easy to guess but there is such
a vast amount of them that this is not possible
LCOG1 jroll at lcog.org writes:
[snip]
I need to do the same for a fueltype where each record has a character
representing the data instead of a numeral(as in year). No reproducible
code or data because i think this is pretty straight forward. I could do
this using a series of loops but
Hi Uwe,
The problem is most likely because the original poster doesn't have
the latest version of plyr. I correctly declare this dependency in
the DESCRIPTION
(http://cran.r-project.org/web/packages/reshape2/index.html), but
unfortunately R doesn't seem to use this information at run time,
Hello all,
There is currently a (very !) lively discussions happening around the
web, surrounding the following topics:
1) Is R efficient? (scripting wise, and performance wise)
2) Should R be written from scratch?
3) What should be the license of R (if it was made a new)?
Very serious people
All,
For example, I have a dataset named ABC loaded into R
ABC
[,1] [,2] [,3]
[1,]147
[2,]258
[3,]369
and I also have a variable datasetname
datasetname
[1] ABC
and I want to add this ABC dataset to an existing list alldata
alldata -NULL
alldata -
Dear R-Helpers,
I have a list l1 like:
l1[[1]]
a b c
l1[[2]]
d
l1[[3]]
e f
I want an output res like:
res[[1]]
1 1 1
res[[2]]
2
res[[3]]
3 3
Essentially, I want to replicate each index equal to the number of elements
present in that index.
Below is what I do to accomplish this:
l1 -
Se ?get function.
On Mon, Sep 13, 2010 at 3:40 PM, Jie Li ruser...@gmail.com wrote:
All,
For example, I have a dataset named ABC loaded into R
ABC
[,1] [,2] [,3]
[1,]147
[2,]258
[3,]369
and I also have a variable datasetname
datasetname
[1]
Hello,
I am currently using the polar.plot function in the plotrix package to graph
data. Unfortunately, it seems that the default for the labels is to have a
background color that is covering the line representing my data, making it
difficult to read. Is there a way to make this label
Hi,
Just to provide an example:
#Sample data copied to variables X, Y, and Z
Z - Y - X - data.frame(A = 1:10)
# A variable holding the names of the variables
datasetname - c(X, Y, Z)
# Use mget() to collect all the variables in a list
# get() only gets one variable at a t ime, mget() gets
Thanks all for the excellent help!
Kind regards,
Alej
2010/9/13 Dennis Murphy djmu...@gmail.com:
Hi:
demo(graphics) has a lot of nice examples of how to use various features -
one of them is font selection.
font = 3 = italic font = 4 = bold italic
You need to select the
Hello all,
I'm very new to R and am having some trouble with the results of the
interp function. I'm trying to produce a chart roughly akin to a weather map
with natural looking filled contours over a large region of the south pacific.
I've got a list of points and values to be mapped
Sunny -
I don't think mapply is needed:
lapply(1:length(mylist),function(x)rep(x,length(mylist[[x]])))
[[1]]
[1] 1 1 1
[[2]]
[1] 2
[[3]]
[1] 3 3
- Phil Spector
Statistical Computing Facility
Although not an R solution, I would highly recommend the generic mapping tools
GMT for this type of work.
http://gmt.soest.hawaii.edu/
Cheers,
Dylan
On Monday 13 September 2010, Craig Stanton wrote:
Hello all,
I'm very new to R and am having some trouble with the results of the
interp
There was an award session at the Vancouver JSM where both Ross Ihaka
and Robert Gentleman spoke. The simply-start-over post sounds very
much like Ross's JSM talk. Robert's response was much more positive -
coming from the perspective of developing BioConductor I think. I
don't recall the
Hello
On Sun, Sep 12, 2010 at 5:37 PM, Sebastian Gibb li...@sebastiangibb.de wrote:
Hello,
thanks for your answer.
mapply fits to my needs.
One thing that seems strange is that if you use
tree[[1]]$node$values - 1:10
tree[[2]]$node$values - 3:12
you still get
mapply(mean,
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