#Use the indexes of S in a sapply function.
N - 10
S - sample(c(0,1), size=N, replace=TRUE)
v1 - sapply(c(1:N-1), function(i) S[i]S[i+1])
# Then
v2 - (P m)
# And I guess you can fill up the rest. Beware of the boundary
condition (the NA in v1)
Cheers,
jcb!
___
?sample
-Oprindelig meddelelse-
Fra: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] På
vegne af cassie jones
Sendt: 8. april 2011 03:16
Til: r-help@r-project.org
Emne: [R] Simulation from discrete uniform
Dear all,
I am trying to simulate from discrete uniform
2011/4/8 Juan Carlos Borrás jcbor...@gmail.com:
#Use the indexes of S in a sapply function.
N - 10
S - sample(c(0,1), size=N, replace=TRUE)
v1 - sapply(c(1:N-1), function(i) S[i]S[i+1])
You can achieve the same v1 using
v1.2 - S[2:N-1] S[2:N]
.. or if you insist on having NA as the first
Dear all,
i have a dataset of about 400 records , with a variable that has two levels 40
bad and 360 good among other variables,how do i come up with10 random samples
that have the composition of as the main sample but maintaining the 40 bad 360
good with replacement, i recently discovered
Thanks,
The first literal solution does not do what I want: the 'meanplot' was
not a background but a smaller object in the middle of the barcharts.
The second solution is exactly what I want. I just changed the plotting
order and the global ylim in order to have a better plot.
Thanks for
Hi,
Sorry for my ignorance, but how can I see if a function is 'compiled code' or
plain R? E.g. the daisy
function from the cluster package.
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting
Dear R helpers,
Thanks a lot for your kind help. The xtab function suggested by Mr. Henrique
Dallazuanna produces following output for me
xtabs(values ~ name + period + cy_date, rat_dat)
, , cy_date = 31-May-11
period
name 29-Mar-11 30-Mar-11 31-Mar-11
A 10.37
Thanks a lot for the answer.
So in fact, without knowing, I was already doing the correct thing ;-)
Regards,
Ivy
-Oorspronkelijk bericht-
Van: Søren Højsgaard [mailto:soren.hojsga...@agrsci.dk]
Verzonden: donderdag 7 april 2011 17:05
Aan: JANSEN, Ivy; r-help@r-project.org
Onderwerp:
On Apr 8, 2011, at 06:08 , Russ Abbott wrote:
Haskell is the prototypical lazy evaluation language. One can compute a
Fibonacci sequence by the Haaskell equivalent of the following R code.
fibs - c(0, 1, rep(0, 8))
fibs[3:10] - fibs + fibs[-1]
This works as follows.
fibs = 0, 1, 0,
Kenn,
I find your solution more elegant.
2011/4/8 Kenn Konstabel lebats...@gmail.com:
2011/4/8 Juan Carlos Borrás jcbor...@gmail.com:
#Use the indexes of S in a sapply function.
N - 10
S - sample(c(0,1), size=N, replace=TRUE)
v1 - sapply(c(1:N-1), function(i) S[i]S[i+1])
You can achieve
Hi,
this response uses the previous responses with an example:
#Assume you have 100 observations
n=100
#Simulate a time series of prices
error=rnorm(n,0,3)
raw.price=rpois(n,100)
lag.price=c(rpois(1,100),raw.price[1:99])
price=lag.price+error
#Say you want the moving average based on this
#and
If you want perfect equality, split the data in good and bad and sample from
the two samples individually.
On average, however, random sampling from the entire data will reproduce the
proportion of good and bad in the data.
hth,
Daniel
--
View this message in context:
Hi:
Here's one approach using the reshape package:
library(reshape)
rat_melt - cast(rat_dat, period ~ name)
rat_melt
period A B C D
1 29-Mar-11 10.37 12.61 14.08 11.17
2 30-Mar-11 10.46 12.65 14.12 11.15
3 31-Mar-11 10.42 12.62 14.10 11.11
# To get the dates in reverse
Thank you for your response, but these changes doesn't seem to change
anything, outcomes of effect command is still the same - error.
Tomas
On Fri, Apr 1, 2011 at 5:03 AM, John Fox j...@mcmaster.ca wrote:
Dear Tomas,
Write the model as
mreg01 = lm(enep1 ~ enpres * proximity1), data=a90)
Hi
r-help-boun...@r-project.org napsal dne 08.04.2011 09:31:44:
Dear all,
i have a dataset of about 400 records , with a variable that has two
levels
40 bad and 360 good among other variables,how do i come up with10
random
samples that have the composition of as the main sample but
Hi,
I am not perfectly sure what you want to do, but here is what I would do
to maintain good/bad ratio in the sample (as Daniel posted, split the
data and sample from the groups):
df - data.frame(V1 = 1:400, V2 = c(rep(good,360), rep(bad,40)))
isGood - which(df$V2==good)
isBad -
# The code demonstrating the final version I am going to use is as follows
rm(list=ls()) # Beware of this one so it doesn't spoil your workspace
N - 100
M - 2
x - matrix(data=rnorm(N*M, 0, 3)-10, ncol=M, nrow=N)
y - matrix(c(1,-2,-2,1), ncol=M, nrow=M)
z - data.frame(x %*% y)
colnames(z) -
Thank you for your reply.
forest(log(rr), ci.lb=lci, ci.ub=uci, xlab=Log Relative Risk)
Error in sei^2 : 'sei' is missing
Regards,
Cheba
2011/4/7 Viechtbauer Wolfgang (STAT)
wolfgang.viechtba...@maastrichtuniversity.nl
Actually, Scott suggested ggplot2, which is available on CRAN:
What version of the metafor package are you using? The option of directly
providing the CI bounds was added in version 1.5-0, so make sure you are using
the newest version.
Best,
--
Wolfgang Viechtbauer
Department of Psychiatry and Neuropsychology
School for Mental Health and Neuroscience
I have just installed the package as
install.packages(metafor)
--- Please select a CRAN mirror for use in this session ---
.
downloaded 403 Kb
package 'metafor' successfully unpacked and MD5 sums checked
library(metafor)
Loading required package: Formula
Loading required package: nlme
Hi,
I have a very simple doubt.
Look:
teste - c(A,B,C)
teste2 - paste(teste[1],teste[2],teste[3],sep=+)
teste2
[1] A+B+C
How to make it automatic, like I try to use paste(teste,sep=+) but the
paste dont get the teste elements separately to join again in a unique
element.
Exist any
paste(teste, collapse=+)
ciao!
mario
On 08-Apr-11 12:44, Ronaldo Reis Junior wrote:
teste - c(A,B,C)
--
Ing. Mario Valle
Data Analysis and Visualization Group| http://www.cscs.ch/~mvalle
Swiss National Supercomputing Centre (CSCS) | Tel: +41 (91) 610.82.60
On 04/08/2011 08:44 PM, Ronaldo Reis Junior wrote:
Hi,
I have a very simple doubt.
Look:
teste - c(A,B,C)
teste2 - paste(teste[1],teste[2],teste[3],sep=+)
teste2
[1] A+B+C
How to make it automatic, like I try to use paste(teste,sep=+) but the
paste dont get the teste elements
On 04/08/2011 09:44 AM, Stefan Petersson wrote:
Hi,
Sorry for my ignorance, but how can I see if a function is 'compiled code' or
plain R? E.g. the daisy
function from the cluster package.
__
R-help@r-project.org mailing list
Thanks Daniel,
Its a long way but it will work.
--- On Fri, 4/8/11, Daniel Malter dan...@umd.edu wrote:
From: Daniel Malter dan...@umd.edu
Subject: Re: [R] random sampling with levels and with replacement
To: r-help@r-project.org
Date: Friday, April 8, 2011, 10:08 AM
If you want
Dear all,
I've tried an lm model. I want to check indepence of the residuals, so I was
trying the following:
library(ape)
plot.correlogram(residuals(model1))
I obtain this error:
Error en x$p.values : $ operator is invalid for atomic vectors
Any idea? Thanks in advance, u...@host.com
Hi,
try
paste(teste,collapse=+)
cheers.
Am 08.04.2011 12:44, schrieb Ronaldo Reis Junior:
Hi,
I have a very simple doubt.
Look:
teste - c(A,B,C)
teste2 - paste(teste[1],teste[2],teste[3],sep=+)
teste2
[1] A+B+C
How to make it automatic, like I try to use paste(teste,sep=+) but
I have the following questions about the variance of the random effects in the
survreg() function in the survival package:
1) How can I extract the variance of the random effects after fitting a model?
For example:
set.seed(1007)
x - runif(100)
m - rnorm(10, mean = 1, sd =2)
mu - rep(m,
Exist any function to associated with paste make this result more
automatically.
you can try with gsub.
Alfredo
2011/4/8 Ronaldo Reis Junior chrys...@gmail.com:
Hi,
I have a very simple doubt.
Look:
teste - c(A,B,C)
teste2 - paste(teste[1],teste[2],teste[3],sep=+)
teste2
[1]
I installed R 2.12 and it works now, thank you Wolfgang.
Servus
Cheba
library(metafor)
Error: This is R 2.11.0, package 'metafor' needs = 2.12.0
2011/4/8 cheba meier cheba.me...@googlemail.com
I have just installed the package as
install.packages(metafor)
--- Please select a CRAN mirror
Dear useRs:
I try to plot an rpart object but cannot get a nice tree structure plot. I
am using plot.rpart and text.rpart (please see below) but the branches that
connect the nodes overlap the text in the ellipses and rectangles. Is there
a way to get a clean nice tree plot (as in the Rpart
On Apr 7, 2011, at 9:46 PM, mavkoup wrote:
I have a for loop with counter i and I'm producing plots where I
ultimately
want to label the axes:
Entry a_i from P^q, where a, P and q are just letters, and i is
the value
of the for loop counter.
I've tried various combinations of paste,
Hi:
I didn't see anything on first blush from the mod1 or summary(mod1) objects,
but it's not too hard to compute:
names(mod1)
[1] coefficients icoef var
[4] var2 loglikiter
[7] linear.predictors frail fvar
[10] dfpenalty
Try this:
reshape(rat_dat, direction = 'wide', idvar = 'period', timevar = 'name')
On Fri, Apr 8, 2011 at 4:44 AM, Sandeepa Ramakrishnan
sandeepa_ramakrish...@yahoo.com wrote:
Dear R helpers,
Thanks a lot for your kind help. The xtab function suggested by Mr.
Henrique Dallazuanna
Dear ExpeRts,
I am trying to plot a bunch of growth curves and would like to get
some more control over groups and line colors than I seem to have.
Example:
# make some data
dat - Orange
dat$group - ifelse(dat$Tree%in%c('1','4','5'), 'A', 'B')
# plot
xyplot(circumference~age, dat,
On Apr 8, 2011, at 4:24 AM, Tomii wrote:
Thank you for your response, but these changes doesn't seem to change
anything, outcomes of effect command is still the same - error.
Tomas
On Fri, Apr 1, 2011 at 5:03 AM, John Fox j...@mcmaster.ca wrote:
Dear Tomas,
Write the model as
mreg01 =
Use 'diff' to determine where the changes are:
S - sample(0:1,30,TRUE)
S
[1] 0 0 1 1 0 1 1 1 1 0 0 0 1 0 1 0 1 1 0 1 1 0 1 0 0 0 0 0 1 0
which(diff(S) == -1)
[1] 4 9 13 15 18 21 23 29
then use the indices for the other processing.
On Thu, Apr 7, 2011 at 10:30 PM, Worik R wor...@gmail.com
On Apr 8, 2011, at 8:06 AM, Philipp Pagel wrote:
Dear ExpeRts,
I am trying to plot a bunch of growth curves and would like to get
some more control over groups and line colors than I seem to have.
Example:
# make some data
dat - Orange
dat$group - ifelse(dat$Tree%in%c('1','4','5'),
Philipp,
I would do the following with ggplot2:
# Set up data
require(ggplot2)
dat - Orange
dat$group - ifelse(dat$Tree%in%c('1','4','5'), 'A', 'B')
# Specify the ggplot group aesthetic as Tree
g1 - ggplot(data = dat, aes(x = age, y = circumference, group=Tree))
# Specify the geom_point and
Hi Tudor,
What type of tree did you create? (classification or regression?)
Could you give an explanation as to what is not looking nice?
Contact
Details:---
Contact me: tal.gal...@gmail.com | 972-52-7275845
Read me:
Hadley -
Thanks for your answers. I didnt think of it that way and what you say makes
complete sense. Truthfully, however, I dont care to maintain an equal area for
each increment. When discussing frequency distributions on the rose, having a
diagram with equally spaced intervals would be
Dear Tomas,
On Fri, 8 Apr 2011 10:24:45 +0200
Tomii dioge...@gmail.com wrote:
Thank you for your response, but these changes doesn't seem to change
anything, outcomes of effect command is still the same - error.
It's not really possible to help you with so little information; if you send a
Hi Chris,
Sorry for the late response. The following selects all students that have
never been suspended:
with(susim, tapply(sus, id_r, function(x) all(x == 0)))
999881 999886 999890 999892 999896 999897
FALSE TRUE TRUE TRUE FALSE TRUE
r - with(susim, tapply(sus, id_r, function(x)
Hello R users,
I have a problem to delete rows in a table which are not duplicated in order
of an id number
a short example:
x - data.frame(cbind(id=c(1,2,2,2,3,3,4,5,6,6), value=1:10))
x_new - x[which(duplicated(x$id)),]
x_new
id value
3 2 3
4 2 4
6 3 6
10 610
Hi:
This seems to 'work':
xyplot(circumference~age, dat, groups=Tree, type='l',
col.line = c('red', 'blue', 'blue', 'red', 'red'))
After a little more fiddling around, this also works, and seems a bit less
kludgy:
dat$group2 - factor(dat$group, labels = c('red', 'blue'))
paul4 wrote:
Hello all,
I am new in R language . I want to forecast a univariate time series by
arima model. Could you please help me finding a good document that
describes this problem by a simple example and step by step ?
?arima
and follow the links in the See also section such as
As I understand it, you are trying to subset the data frame to include only
rows with a non-unique id.
Try this:
x - data.frame(cbind(id=c(1,2,2,2,3,3,4,5,6,6), value=1:10))
id.table - table(x$id)
x_new - subset(x, id %in% id.table[id.table 1])
Jeremy
Running a binary logit model on the data
df - data.frame(y=sample(letters[1:3], 100, repl=T),
x=rnorm(100))
reveals some residual deviance:
summary(glm(y ~ ., data=df, family=binomial(logit)))
However, running a multinomial model on that data (multinom, nnet)
reveals a residual deviance:
Sorry, I left out the names() function in the last step.
Try this instead:
x - data.frame(cbind(id=c(1,2,2,2,3,3,4,5,6,6), value=1:10))
id.table - table(x$id)
x_new - subset(x, id %in% names(id.table[id.table 1]))
Jeremy
__
R-help@r-project.org
Sir or Madam:
I am new to R and the use of quantile regeression. In addition, I am a
finance person not a true statistcian. Basic regression form is Y =
(Coefficient * Variable) + Error Term
I have results from a quantile regression where I used the Barro and
Roberts method with bootstrapping
Dear Sir\ Madam
I am trying to maximise a complicated loglikelihood function via EM algorithm
which consists of two step E-step and M-stepand in this case I need to
maximize the expected of like lihood function which I get from E- step and
take those estimates of parameter to update the
Hi,
I am trying to add text to the bottom of a lattice bwplot with
multiple panels. I would like to add a label below each boxplot, but
the labels do not come from the data. I've tried the following, code:
f1 - c(rep(c(rep(a, 3), rep(b, 3), rep(c, 3)), 2))
f2 - c(rep(A, 9), rep(B, 9))
dv -
Hi!
I'm very new user of R! I need to learn more about! My problems are to
create a time series with exiting data and to make an study:
1 ) I have column with DD-MM-YR, to transform from string text to date,
and use it as to use as time series, I've made the transformation with
command
I'm working in Rosario, Argentina, trying to plot some contours.
I found the function draw.contour created by James Forester at
R-bloggers. If you take a look at that function you'll see it's very
useful!
But I have a problem with it and James is trying to help me (but also
asked me to seek for
hello
I am at the very beginneing of using the R program
I just don't understand how one can save a programfile
For exemple, if I type in R 23+456 and want to save this file under a ceratin
name to reload it later, i just don't get the way to do it
I can save it with the save function;I
I have been trying ot post through R-help and it asks me to subscribe. I have
subscribed may times but did not get a confirmation. can you check to see what
is wrong with my subscription. I can not post on the R-help mailing list at
this
time.
thanks
[[alternative HTML
Dear users,
I want to set up R to use one R-script directory and one R-library (directory
for packages) for many end-users. I try to do this by using one network-share.
This works fine as long as we don't use the snowfall package with parallel=TRUE
(sfInit(parallel=TRUE, cpus=4,
Thanks a lot, Jeremy!
It's working perfectly.
With best regards
--
View this message in context:
http://r.789695.n4.nabble.com/Removing-not-duplicated-rows-tp3436600p3436736.html
Sent from the R help mailing list archive at Nabble.com.
__
I'm assuming that English is not your first language. In light of that, I
would suggest that you post your question in a language that we both
speak: R. Please include:
1) E-step and M-step functions.
2) The proposed optim/maxLik call.
Mostly because (at least optim) does not have a parameter
Hi,
On Fri, Apr 8, 2011 at 10:33 AM, gauri j gauri.ja...@gmail.com wrote:
hi,
I have problem in following code, error is occurred. I have attached my data
herewith. and my code is as following,
library(lars)
Loaded lars 0.9-8
Warning message:
package 'lars' was built under R version 2.12.2
Thanks
That is it really simple.
Ronaldo
Em 08-04-2011 07:48, Mario Valle escreveu:
paste(teste, collapse=+)
ciao!
mario
On 08-Apr-11 12:44, Ronaldo Reis Junior wrote:
teste - c(A,B,C)
--
1ª lei - Suas férias começam após a defesa e entrega de sua dissertação.
On Fri, 8 Apr 2011, tudor wrote:
Dear useRs:
I try to plot an rpart object but cannot get a nice tree structure plot. I
am using plot.rpart and text.rpart (please see below) but the branches that
connect the nodes overlap the text in the ellipses and rectangles. Is there
a way to get a clean
On 08/04/2011 9:16 AM, nferr...@fceia.unr.edu.ar wrote:
I'm working in Rosario, Argentina, trying to plot some contours.
I found the function draw.contour created by James Forester at
R-bloggers. If you take a look at that function you'll see it's very
useful!
But I have a problem with it and
For simple permutation tests I usually just code it up in regular R without
worrying about any packages. R is powerful enough that it is simple to do a
permutation test in only a few lines ( or sometimes just one long line). And
that way you know exactly what it is doing.
--
Gregory (Greg)
Brittain Briber brittbriber at yahoo.com writes:
Do you two or anyone
else out there happen to know if it is possible to specify the
width of the intervals in windrose? Is there
a parameter that I can pass along that would do this?
Below is a reproducible script in which you can see
I too am encountering this problem. When I have a large script, if I select
all in the editor and then ctrl-r to run, if it encounters a stop() function
it simply prints an error message and continues to execute the remainder of
the script, as opposed to terminating execution at that line. The
Look at the updateusr function in the TeachingDemos package.
--
Gregory (Greg) L. Snow Ph.D.
Statistical Data Center
Intermountain Healthcare
greg.s...@imail.org
801.408.8111
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
project.org] On Behalf Of
On 08/04/2011 9:20 AM, DEBERGH Patrick wrote:
hello
I am at the very beginneing of using the R program
I just don't understand how one can save a programfile
For exemple, if I type in R 23+456 and want to save this file under a ceratin
name to reload it later, i just don't get the way to do
On 08/04/2011 11:47 AM, algorimancer wrote:
I too am encountering this problem. When I have a large script, if I select
all in the editor and then ctrl-r to run, if it encounters a stop() function
it simply prints an error message and continues to execute the remainder of
the script, as opposed
Put an open brace in the first line of your file
and a close brace in the last line.
I encourage people with scripts long enough that this
is a problem to divide up their work into functions
that a shorter script calls. (This is akin to UCSD
Pascal on the Osbourne II that refused to deal with
a
Is anyone aware of a fast way of doing fisher's exact test for a series of 2
x 2 tables in R? The fisher.test is really slow if n1=1000 and n2 = 1000.
--
Thanks,
Jim.
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
Some of the functions that were the first in the TeachingDemos package were
originally written to help me visualize something, so it is not just teachers
demoing, but people demoing to themselves. It has become a bit of a misc
package with several utilities that are useful in themselves, but
On 08/04/2011 12:40 PM, William Dunlap wrote:
Put an open brace in the first line of your file
and a close brace in the last line.
This shares an advantage with the method I suggested: if there's a
syntax error somewhere in the script, *nothing* will be executed. It
has the disadvantage of
Dear Peter,
Quantile regression is a nice tool but one that requires some statistical
training in order to use it and interpret the results properly. I suggest
backing up a bit.
Frank
Sheldrick,
Peter (Specialty Casualty UW Support) wrote:
Sir or Madam:
I am new to R and the use
Would options(error = recover) be of some help?
--
Jonathan P. Daily
Technician - USGS Leetown Science Center
11649 Leetown Road
Kearneysville WV, 25430
(304) 724-4480
Is the room still a room when its empty? Does the room,
the thing itself have purpose? Or do
Hi:
After a number of false starts, I finally consulted Deepayan's book and the
example on p. 73, suitably adapted, yielded a solution. Add a variable for
the labels and then...
df$lab - rep(1:6, each = 3)
bwplot(dv ~ f1 | f2, data = df, ylim = c(0.5, 1),
panel = function(x, y, ..., subscripts)
On 08/04/2011 1:29 PM, Jonathan P Daily wrote:
Would options(error = recover) be of some help?
No, that will probably be very confusing. The problem is that the
Windows GUI uses Ctrl-R as a short form of cut from the editor, paste
to the console, and it will paste the whole text regardless
Hi R community,
I posted a question on using the R maximum likelihood functions a short
while ago and got an email saying that some of the content was
unprocessed. Hence, I am reposting the question just to be sure (sorry for
the multiple emails if both reached you).
My question is reagarding
Dear all,
Do you know how to check redundancy of variables and reduce the dimension in R?
It seems PCA can do this. Is there any other better way to implement in R? Many
thanks!
Bill
__
R-help@r-project.org mailing list
Thank you all for the astoundingly quick responses. I think that the
bounding open/closed braces approach sounds like the easiest solution for
the moment -- though I look forward to seeing this all automated in a future
version of R :)
Incidentally, I have indeed encapsulated much of the code as
1. I am not an expert on this.
2. However, my strong prior would be no, since because it is exact it has
to calculate all the possible configurations and there are a lot to
calculate with the values of n1 and n2 you gave.
-- Bert
On Fri, Apr 8, 2011 at 9:43 AM, Jim Silverton
Hi,
First: Please make sure you CC R-help when responding to messages on
the list so that more people can help you, and more people can benefit
from help that is provided. You can do so easily by replying with
reply-all.
Now:
Look at the help for the lars function:
R ?lars
You'll see that `x`
I believe the solutions proposed ignore the recursive nature of the
original problem and hence produce wrong solutions.
P - c(5, 7, 6.01, 6.01, 7)
m - rep(6, 5)
S0 - as.numeric(P(m*1.005))
Then the original loop from Worik gives
S - S0
for(i in 2:length(S)){
if(S[i]==0 S[i-1] == 1){
On 2011-04-08 09:26, Ben Bolker wrote:
Brittain Briberbrittbriberat yahoo.com writes:
Do you two or anyone
else out there happen to know if it is possible to specify the
width of the intervals in windrose? Is there
a parameter that I can pass along that would do this?
Below is a
Try
Sys.setenv(LANGUAGE=Fr)
Uwe Ligges
On 07.04.2011 10:29, Raji wrote:
Hi R-helpers,
Is it possible to localise the error messages/warnings that comes from
R.My application takes in a locale information.I used the following command
to set the locale in R.But in RGui, i still get the
Greetings All!
After much trial and error, and an exhaustive search of the archives, I'm
writing to solicit help with a problem.
I want to dynamically modify variable names and values as function arguments
inside a loop.
I have a canned function from a package that takes ellipsis (...)
Hi Achim:
I will give it a try and let you know how it goes.
Thanks.
Tudor
--
View this message in context:
http://r.789695.n4.nabble.com/Rpart-decision-tree-tp3435888p3437212.html
Sent from the R help mailing list archive at Nabble.com.
__
HI,
Thank you, I will try this, and let you know about the results.
Thanks once again.
Gauri
2011/4/8 Steve Lianoglou mailinglist.honey...@gmail.com
Hi,
First: Please make sure you CC R-help when responding to messages on
the list so that more people can help you, and more people can
I have used R for years but run into a seemingly simple problem involving
'ifelse'. condensed code like this
a=c(2,NA,NA,NA,2,2,NA,2,NA,2)
b=c(NA,1,1,NA,2,2,2,2,2,2)
#I want to combined a and b into c so that c would be a valid number either a
or b is not missing
Greetings, all ...
I'm trying to find documentation on the use of the local() function, and
am drawing a complete blank; would someone please send me a pointer to where
I can learn what it is intended for, and how to correctly use it?
Many thanks!
Doug
[[alternative HTML version
Hi Tal:
Thanks for your quick reply.
I tried to create a classification tree.
The problem is that the branches overlap the text in the ellipses (inner
nodes) and rectangles (terminal nodes) - At times this makes it difficult
for the reader to correctly process the results. One way to
On 08/04/2011 2:11 PM, Doug Elias wrote:
Greetings, all ...
I'm trying to find documentation on the use of the local() function, and
am drawing a complete blank; would someone please send me a pointer to where
I can learn what it is intended for, and how to correctly use it?
Try ?local. As
Hi,
The problem is that (a == 1 | b == 1) returns some NAs. NAs are not
treated as strictly TRUE or FALSE. From the documentation (see
?ifelse) Missing values in 'test' give missing values in the result.
You need to use a construct designed to force a TRUE/FALSE value OR
something that handles
On 04/08/2011 11:11 AM, Doug Elias wrote:
Greetings, all ...
I'm trying to find documentation on the use of the local() function, and
am drawing a complete blank; would someone please send me a pointer to where
I can learn what it is intended for, and how to correctly use it?
Hi Doug --
Hello,
I am interested in using the hscat command in the gstat package to create
h-scatterplots of snow depth measurements over a given area (spatial
autocorrelation). Unfortunately I do not understand how to format my data
for import into R for use with the hscat command. I have checked the
Dear Rxperts!
A simple example where write.csv does not seem to accept user specified
arguments.. Why?
write.csv(t(1:10),./te1.csv,quo=F,col.names=F)
Warning message:
In write.csv(t(1:10), ./te1.csv, quo = F, col.names = F) :
attempt to set 'col.names' ignored
However, write.table does
Please read the documentation where this is clearly explained. See ?write.csv
Best,
Ista
On Fri, Apr 8, 2011 at 4:18 PM, Santosh santosh2...@gmail.com wrote:
Dear Rxperts!
A simple example where write.csv does not seem to accept user specified
arguments.. Why?
Hi. I am trying to run perl script from R. Here's what happens.
setwd(C:\\Terri\\perl)
getwd()
[1] C:/Terri/perl
list.files()
[1] hello.pl lines1_10.txt try_my.pl try_my.txt
system(hello.pl)
Warning message:
In system(hello.pl) : Impossible to run C:\Terri\perl\hello.pl
Does anyone
Dear R users,
I am using package mice and I am getting the error
Error in if (meth[j] != ) { : argument is of length zero. I have tried using
several different versions of R (even the one that will be coming out this
month) to no avail. I am using RStudio as my interface with R. Also note that
I believe write.csv had been revamped and some options are no longer available.
--- On Fri, 4/8/11, Santosh santosh2...@gmail.com wrote:
From: Santosh santosh2...@gmail.com
Subject: [R] a bug in write.csv?
To: r-help r-help@r-project.org
Received: Friday, April 8, 2011, 4:18 PM
Dear
1 - 100 of 127 matches
Mail list logo