Hello R-help list
I'm trying to run 1 billion iterations of a code with calls to random
distributions to implement a data generating process and subsequent
computation of various estimators that are recorded for further
comparison of performance. I have two question about how to achieve
Jurgens de Bruin debruinjj at gmail.com writes:
Hi,
I do not have much R experience just the basics, so please excuse
any obvious questions.
I would like to create bubble plot that have Categorical data on the x and y
axis and then the diameter if the bubble the value related to x and
1. The three levels of the vector DrugPair actually represent three
genotypes, which are some randomly chosen genotypes from a population of
many genotypes. That's why I thought it was justified as random effect.
Does estimating them as random make sense then?
2. Also could you please elaborate
Dear All,
I would like to generate m positive real numbers c_i, I=1,...,m, such that
(1) c_1 + c_2 + ... + c_m=m,
(1) after being ordered into c_1 = c_2 = =c_m0, we have that c_m is
of the same order of m^(-1/8), when m is sufficiently large.
Thanks,
-Chee
[[alternative HTML
On Thu, Apr 14, 2011 at 7:41 PM, Marion Dumas mario...@gmail.com wrote:
Hello R-help list
I'm trying to run 1 billion iterations of a code with calls to random
distributions to implement a data generating process and subsequent
computation of various estimators that are recorded for further
On Thu, Apr 14, 2011 at 7:02 PM,
rcpp-devel-requ...@r-forge.wu-wien.ac.at wrote:
I was able to write a very short C++ function using the Rcpp package
that provided about a 1000-fold increase in speed relative to the best
I could do in R. I don't have the script on this computer so I will
Dear Ivan,
first, it would pay-off in terms of readability to employ line breaks and
second to provide a reproducable code snippet and third which package you have
used. Now to your questions:
1) What happens if you provide colnames for your objects?
2) What happens if you omit the $ after
Ben,
This example of pgfSweave looks like it would address my problem. I
installed this package, but I cannot determine how to use it to make R
convert LaTeX commands into mathematical symbols on an R plot. The
documentation does not seem to address this. I tried to mimic the
example from
We do not know the details of the kinds of computations you intend to do within
each iteration, but if, let's say, each iterations takes around 1 second, then
your simulation will run for the next 30+ years (on a single core). Even if
each iteration only takes a fraction of a second, you are
Dear Bernhard,
thank you very much for the response. Yes, I am using the packsges
vars with fuchrions VAR() and causality().
1)Giving colnames to the objects does unfortunately not change anything.
2) I am not sure if I understood you right. Did you mean to insert
Countml$Granger$p.value
Hi,
Through pgfSweave you can use the tikz device, which is the one that
can interpret Latex code (package tikzDevice). I would start with a
minimal self-contained plot with this function. see ?tikz for
examples.
HTH,
baptiste
On 15 April 2011 20:03, Michael McAssey mpmcas...@gmail.com
Hello Ivan,
see example(causality) for the first question and use count[[i]] and not
count$[[i]] for the second. The following works for me:
example(causality)
test1 - causality(var.2c, e)
test2 - causality(var.2c, prod)
tl - list(test1, test2)
res - matrix(NA, ncol = 1, nrow = length(tl))
Dear R users,
I presume there is something foul with system:
a - c(1,2,3,4)
as.matrix(a, ncol=2)
Output:
[,1]
[1,]1
[2,]2
[3,]3
[4,]4
The vignette for as.matrix says nrow (ncol) will be deduced from length
and ncol (nrow). It does not work even when I additionally
Liviu Andronic landronim...@gmail.com writes:
Not a solution that would work in all cases, have you tried reducing
the font size?
Yes, I have done this. I've also eliminated all the stuff that beamer
puts on the screen (title bars, navigation symbols, etc), to the point
that I probably
Hallo Michael,
check ?matrix and compare to as.matrix.
as.matrix does not provide a ncol argument. To get a 2 by 2 matrix use
matrix(a, ncol=2)
Regards
Adrian
Am 15.04.2011 11:42, schrieb Michael Bach:
Dear R users,
I presume there is something foul with system:
a- c(1,2,3,4)
as.matrix(a,
Sorry, my previous mail was incomplete.
I mean, one of my xyplot is build with the command doubleYScale (in order to
overlap two line with different Y-axis).
But doubleYScale doesn't run with the nice command that you have suggested:
first plot:
a-xyplot(NDVI_P10~dek_num
| Year,
Hi
r-help-boun...@r-project.org napsal dne 15.04.2011 01:34:22:
Hi everyone.
I am quite frustrated that this doesn't work, as all the functions
within
work fine by themselves. I'd also like any pointers to how to avoid
'for'
loops in my code. I understand it's less than desirable, but
Baptiste,
Thank you. The examples in the documentation for tikz helped me solve
this problem, and give me a good tool for future plots. I only need
to figure out how to incorporate LaTeX packages like amssymb so that I
can use \mathbb{} to put the real numbers symbol in my plot.
Regards,
On 04/14/2011 11:48 PM, Jurgens de Bruin wrote:
Hi,
I do not have much R experience just the basics, so please excuse
any obvious questions.
I would like to create bubble plot that have Categorical data on the x and y
axis and then the diameter if the bubble the value related to x and y.
Hi Adrian,
thanks for the hint. The problem was that it showed me help for matrix
when I did ?as.matrix. I thought it was some kind of convention that
data type conversion functions start with as., so now I will take more
care in the future.
With matrix() it works as expected, thanks again.
Hi,
Could you not simplify your a and b plots into one like
xyplot(NDVI_P10 + AVG_NDVI_P10 ~ dek_num | Year,
data=data, lty = 3:2, col = c(darkgrey, black), ..., [etc]
auto.key = list(lines = TRUE, points = FALSE))
Otherwise please provide a commented, minimal, self-contained,
On 04/14/2011 10:49 PM, Serdar Akin wrote:
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained, reproducible code.
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal,
Generate random numbers from a multinomial.
?rmultinom
# The following will generate n multinomial vectors each of size m
rmultinom(n, size=m, prob=m^(-1/8)) # you need to specify probabilities
appropriately
Ravi.
From: r-help-boun...@r-project.org
Hello..
How do I get str() to show all variables in a data frame? It seems to be
list output truncated at about 99 variables, the data frame has over
600 but i can't seem to figure out how to show all variables, we see
list.len() but again can't seem to figure this out - help will be
appreciated.
Hi,
I've got something strange going on. I'm trying to compile a vignette using
Sweave(vignette.Rnw), and in the first code chunk that illustrates an
example, I noticed from the output text I have inside the function, that it is
running it twice, because the sequence of message() statements is
It has always been my understanding that deviance for GLMs is defined
by;
D = -2(loglikelihood(model) - loglikelihood(saturated model))
and this can be calculated by (or at least usually is);
D = -2(loglikelihood(model))
As is done so in the code for 'polr' by Brian Ripley (in the
On 15/04/2011 7:00 AM, Dario Strbenac wrote:
Hi,
I've got something strange going on. I'm trying to compile a vignette using
Sweave(vignette.Rnw), and in the first code chunk that illustrates an
example, I noticed from the output text I have inside the function, that it is running it
twice,
On Apr 15, 2011, at 7:19 AM, zubin wrote:
Hello..
How do I get str() to show all variables in a data frame? It seems to be
list output truncated at about 99 variables, the data frame has over
600 but i can't seem to figure out how to show all variables, we see
list.len() but again can't
On 15/04/2011 8:19 AM, zubin wrote:
Hello..
How do I get str() to show all variables in a data frame? It seems to be
list output truncated at about 99 variables, the data frame has over
600 but i can't seem to figure out how to show all variables, we see
list.len() but again can't seem to
On 4/14/2011 7:22 PM, Dirk Eddelbuettel wrote:
Sorry, but this is the r-help list. The 'R Spam' list is over at /dev/null.
Clearly a fortune candidate!
--
Michael Friendly Email: friendly AT yorku DOT ca
Professor, Psychology Dept.
York University Voice: 416 736-5115 x66249 Fax:
On 04/15/2011 01:13 AM, Jurgens de Bruin wrote:
Thanks for the reply...
with reproducible I am believe you require a dataset?
yes -- but you can make one up if you like. e.g.
dd - expand.grid(drugclass=LETTERS[1:5],
plant=c(cactus,sequoia,mistletoe))
set.seed(101)
dd$fitvalue -
On Thu, Apr 14, 2011 at 11:47 PM, Christian Gunning x...@unm.edu wrote:
On Thu, Apr 14, 2011 at 7:02 PM,
rcpp-devel-requ...@r-forge.wu-wien.ac.at wrote:
I was able to write a very short C++ function using the Rcpp package
that provided about a 1000-fold increase in speed relative to the best
Hello,
I am exporting a graph in gml format from igraph 0.5.5. When I open the
file in Cytoscape v.2.7 I can't map the color attribute that I assign to the
graph when I export it from igraph. Could anyone help me in this?
Thanks.
--
Warm Regards,
Sandeep Amberkar
BioQuant,BQ26,
Im Neuenheimer
Listers,
I have created a cross-tab matrix using the following code:
S -
c(1,2,3,1,2,3,1,2,3,1,2,3,1,2,3,1,2,3,1,2,3,1,2,3,1,2,3,1,2,3,1,2,3,1,2,3,1,2,3,1,1,2,3,1,1,2,3,1,2,2)
F -
c(1,2,3,1,2,3,1,1,1,1,2,3,1,1,3,2,2,2,1,2,3,1,1,1,1,2,3,3,1,3,1,3,1,1,2,3,1,1,3,2,3,2,1,1,1,2,3,1,1,2)
table(S,F)
fF
Hi Dmitry,
Nothing is seriously wrong.
You want to set the fourth column name, so take column names THEN
the fourth element:
colnames(PiD)[4] - total
Thank you for providing a clear and simple reproducible example.
Sarah
On Fri, Apr 15, 2011 at 9:29 AM, Dmitry Berman ravenb...@gmail.com
which(data==max(data),arr.ind=TRUE)
gives you the indices of the largest element.
which(data==data[order(data)[2]],arr.ind=TRUE)
the indices of the second largest.
Best
Jannis
On 04/14/2011 10:23 PM, Nicolas Gutierrez wrote:
hi All,
I have a matrix Ufi (x by y)
1 2 3 4 5
1 0 0 0
perfect! thx
On 4/15/2011 8:43 AM, Duncan Murdoch wrote:
On 15/04/2011 8:19 AM, zubin wrote:
Hello..
How do I get str() to show all variables in a data frame? It seems to be
list output truncated at about 99 variables, the data frame has over
600 but i can't seem to figure out how to show
Kevin Wright kw.stat at gmail.com writes:
I am trying to teach myself R and replicate some previous SAS analysis.
Could someone please help me translate the following SAS code into R.
Proc mixed method=ml
Class Group Treatment Stream Time Year;
Model Logrpk=Treatment Time
Hi.
Have a look also at ?addmargins.
addmargins(table(fS,fF),c(1,2),FUN=list(total.row=sum,total.col=sum))
Andrija
On Fri, Apr 15, 2011 at 3:29 PM, Dmitry Berman ravenb...@gmail.com wrote:
Listers,
I have created a cross-tab matrix using the following code:
S -
On 14.04.2011 18:04, Paul78 wrote:
I have got the same problem. Can anybody help me why R just shuts down?
1. please quote the original message, mailing list readers do not see it
and it is hard to access it.
2. please specify a reproducible example as the posting guide quoted
below
On 14.04.2011 18:14, rbali wrote:
Same problem with Vista
1. Please quote the original message, mailing list readers are not able
to follow otherwise!
2. Peter Dalgaard wrote that it is a bug in the ctv package, so
everything is said already. And rather than posting here, why not ask
the
Sorry, I've just reversed the names of dimensions :)
addmargins(table(fS,fF),c(1,2),FUN=list(total.col=sum,total.row=sum))
Andrija
On Fri, Apr 15, 2011 at 3:50 PM, andrija djurovic djandr...@gmail.comwrote:
Hi.
Have a look also at ?addmargins.
Hi Michael,
It helps to look at the Usage section of the help pages. There you
will see that matrix() has an ncol argument, but as.matrix() does not.
Best,
Ista
On Fri, Apr 15, 2011 at 7:08 AM, Michael Bach pha...@gmail.com wrote:
Hi Adrian,
thanks for the hint. The problem was that it
Hello,
quick question I reckon.
Is there a way to add to time series to a dataframe without knowing their
name in advance?
I can figure it out the following but wondered if there is a better way
Thanks
Paolo
a = data.frame(i = rep(100, 12))
colnames(a)[length(colnames)] = i
Hi,
the problem is that igraph puts node colors into the GML file as
simple vertex attributes, but this is not what Cytoscape expects.
Plus, it seems that Cytoscape does not read all the node/edge
attributes from the GML file, only the ones it interprets, so the
color information is lost.
Sadly,
Dear R users,
Hi. I am using prediction function in ROCR package.
y consists of two classes 0 and 1.
However, since I am using cross-validation, a sampled small number of
y may consist of only one class
y
[1] 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
In this case, prediction function gives an
On 13.04.2011 02:11, jkang wrote:
I have an ubuntu image with R installed. I want to install a list of
packages that does not come with R. eg. cluster, gplots, hacks, mapdata.
etc. Over time this list may grow.
Is there a config file that can tell R what and where to install additional
On 14.04.2011 19:48, droberts wrote:
I apologize for the slow response, but I just registered with Nabble.
The duleg function in labdsv was renamed indval to be more consistent with
its use in the literature. Typing ?indval will provide more information.
As an aside, all R functions have
On 14.04.2011 12:47, taby gathoni wrote:
Hi R-users,
This is a generic question, is there a way to plot a line graph for the output
from crosstable function? one of the inputs to the crosstab function is
categorical.
Generic answer: probably yes.
According to the posting guide, you have
On 12.04.2011 21:52, Zd Gibbs wrote:
Sorry, the first version was incomplete. I'm trying again.
I am running a regression equation and i want to enter in 12 IV then stepwise
enter 8 variables and not have an origin.
DV is shfl.
I want to enter in the following 12 independent dummy variables
On 15.04.2011 17:00, Soyeon Kim wrote:
Dear R users,
Hi. I am using prediction function in ROCR package.
y consists of two classes 0 and 1.
However, since I am using cross-validation, a sampled small number of
y may consist of only one class
y
[1] 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0 0
Sounds like homework. Anyway, lookup rank correlations (Spearman,
Kendall, etc.) and correpsonding tests.
Uwe Ligges
On 14.04.2011 17:00, Baoqiang Cao wrote:
Hi,
I have to one set of inputs and their observed true values of each
input. Now I have a model takes the input and predict a value.
Hi,
I am a complete newcomer to R and although I can plot standard box-plots I am
struggling with this...
I have two treatments - A B, and 2 variables 1 2. I want to compare
boxplots of variable 1 with variable 2 for each treatment. I would also like
them to all be on the same graphic.
I
I am making the question clear. Please help.
Dear R experts
I was using kinship package to fit mixed model with kinship matrix.
The package looks like lme4, but I could find a way to extract p-value
out of it. I need to extract is as I need to analyse large number of
variables ( 1).
I calculate an anova test in the following way:
expdata-read.table(/home/dorien/UA/meta-music/optimuse/optimuse1-build-desktop/results/results_processedCP,
header=TRUE)
names(expdata)-c('nh1','nh2','nh3','randsize','aweights','tt1','tt2','tt3','path','iters','type','length','tos','tws','time')
I have a question, What is the maximum storage capacity of data that R has?
Thanks
Pamela Santelices Elgueta
Estadístico
Instituto Nacional de Estadísticas
Fono: (56-2) 7962491
Paseo Bulnes 209 oficina 82
Santiago
[[alternative HTML version deleted]]
baptiste auguie-5 wrote:
I wish to modify programmatically only a few factor levels, according
to a named list. I came up with this function..
.
It seems to work, but the original order of the levels is changed.
The split-and-unite policy you use makes it a bit difficult to
dorien wrote:
I calculate an anova test in the following way:
... aov example
I want to check the fit of the model with Rsquared
Try summary(lm(...)) instead.
Dieter
--
View this message in context:
http://r.789695.n4.nabble.com/Rsquared-for-anova-tp3452399p3452434.html
Sent
On 15/04/2011 12:05 PM, Pamela Santelices Elgueta wrote:
I have a question, What is the maximum storage capacity of data that R has?
There isn't a simple answer to this question. Vectors have a maximum
length of about 2 billion entries, and matrices are stored as vectors.
Most often you
Hi there,
I have two data sets, one of locations at different elevations (x,y,z) and
the other of points that make up topographic contours (also x,y,z). I have
used:
result-apply(distppll(data2,cbind(topocon[-nrow(topocon),],topocon[-1,])),1,min)
where 'data2' are my measurement coordinates (x,
Thanks Petr,
Actually, I figured it out last night. Please read on only if you're sort of
interested.
You're absolutely right, I hastily changed my function to be more 'readable'
without thinking that I was using a name that was already a function.
What I wanted was a cross-tabulation of f1 and
Hi,
I have found quite a few posts on normality checking of response variables, but
I am still in doubt about that. As it is easy to understand I'm not a
statistician so be patient please.
I want to estimate the possible effects of some predictors on my response
variable that is nº of males
Dear list,
I want to loop over a list through lapply and at the same time I want to
extract some information from the names of the list elements. lapply does
not seem to carry the names. Is there anyway to access the names of a list
within lapply? Thanks.
Jun
[[alternative HTML version
Normality of the predictors doesn't belong to the assumptions of the GLM,
so you don't have to check this.
Note, however, that there are all kinds of potential problems which to
detect is fairly hopeless with n=11 and three predictors, so you shouldn't
be too confident about your results
Hi Jun,
On Fri, Apr 15, 2011 at 11:14 AM, Jun Shen jun.shen...@gmail.com wrote:
Dear list,
I want to loop over a list through lapply and at the same time I want to
extract some information from the names of the list elements. lapply does
not seem to carry the names. Is there anyway to access
Try this:
lapply(mtcars, function(.)names(mtcars)[match.call()[[2]][[3]]])
On Fri, Apr 15, 2011 at 3:14 PM, Jun Shen jun.shen...@gmail.com wrote:
Dear list,
I want to loop over a list through lapply and at the same time I want to
extract some information from the names of the list elements.
Hello, R friends...
I am very new to R, and I need some help. I am trying to construct a
simulation for my dissertation.
I need to create 1000 datasets of 1000 subjects with the following variables...
Treatment variable - Drawn from a binomial distribution (1 run, prob=.13)
Covariate 1 -
Hi,
I was wondering I'm going about this in the correct way. I need to test if
there are coding sequences or exons in hg19 which match a string of 100bp
D i.e. [A,G or T]. However I'm getting a strange result.
I get a hit on chr7, using the 100bp search however when I search with 60bp
sequence of
What have you tried so far?
It is often helpful to begin with a much simpler problem, then add
complexity incrementally until you've constructed the desired model.
Best wishes.
Charles Annis, P.E.
charles.an...@statisticalengineering.com
561-352-9699
http://www.StatisticalEngineering.com
Here's a script of what I have so far. I have a few problems. First, the
correlations. Next, recoding that categorical variable into dichotomous
variables. Finally, the iterative filename thing.
Thanks!
S
-Original Message-
From: Charles Annis, P.E.
Am 15.04.2011 20:14, schrieb Christian Hennig:
Normality of the predictors doesn't belong to the assumptions of the
GLM, so you don't have to check this.
Note, however, that there are all kinds of potential problems which to
detect is fairly hopeless with n=11 and three predictors, so you
Hi Shane,
See ?rbinom, ?rnorm, ?mvrnorm (in the MASS package), ?sample, ?for and
?write.table
Best,
Ista
On Fri, Apr 15, 2011 at 2:49 PM, Shane Phillips
sphill...@lexington1.net wrote:
Hello, R friends...
I am very new to R, and I need some help. I am trying to construct a
simulation for
Thanks, Joshua and Henrique.
Henrique's solution is very interesting. Could you explain a bit more? What
does this grammar mean?
match.call()[[2]][[3]]
Jun
On Fri, Apr 15, 2011 at 1:27 PM, Henrique Dallazuanna www...@gmail.comwrote:
Try this:
lapply(mtcars,
Hi,
When I install R in Ubuntu/Linux, is it possible to view only the error
messages without the installation progress? And how?
Regards,
Iurie Malai
Moldova Pedagogical State University
[[alternative HTML version deleted]]
__
Sorry,
I meant: when installing R packages with 'install.packages()'.
2011/4/15 Iurie Malai iurie.ma...@gmail.com
Hi,
When I install R in Ubuntu/Linux, is it possible to view only the error
messages without the installation progress? And how?
Regards,
Iurie Malai
Moldova Pedagogical
Hi all,
Suppose I have 2 data.frame , a and b, how can I add them together to get c?
Thanks
a
A
a 1
b 2
c 3
b
A
a 6
c 1
c
A
a 7
b 2
c 4
--
Best,
Zhenjiang
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
On 15 April 2011 12:03, Shane Phillips sphill...@lexington1.net wrote:
Here's a script of what I have so far. I have a few problems. First, the
correlations. Next, recoding that categorical variable into dichotomous
variables. Finally, the iterative filename thing.
Where?
Perhaps give
Try performing stratified sampling when doing cv.
cran.r-project.org/web/packages/ipred
On Fri, Apr 15, 2011 at 11:00 AM, Soyeon Kim yunni0...@gmail.com wrote:
Dear R users,
Hi. I am using prediction function in ROCR package.
y consists of two classes 0 and 1.
However, since I am using
Hi:
Here's one approach:
df1 - data.frame(x = letters[1:3], y = 1:3)
df2 - data.frame(x = c('a', 'c'), z = c(6, 1))
dfm - merge(df1, df2, all.x = TRUE)
dfm
x y z
1 a 1 6
2 b 2 NA
3 c 3 1
sumdf - data.frame(x = dfm$x, y = rowSums(dfm[, -1], na.rm = TRUE))
x y
1 a 7
2 b 2
3 c 4
HTH,
How to make a launcher for Rattle?
Regards,
Iurie Malai
Moldova Pedagogical State University
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting
Hello R users!
I have several data frames where some of the variables have many missing
observations. For example, Q1 in one of my data frames has over 66% of its
observations missing. I have tried imputation with mice but it does not work
for all the data frames and I get the following
Thanks, Dennis! I'll go with it. It's surprising there is no ready way to do
that. I imagine it should be a common data manipulation to add two
data.frame from two different sources. It could happen that one data.frame
is missing some rows while the other have some more.
On Fri, Apr 15, 2011 at
Rita Carreira ritacarreira at hotmail.com writes:
I have several data frames where some of the variables have many
missing observations. For example, Q1 in
one of my data frames has over 66% of its observations missing.
I have tried imputation with mice but it does
not work for all the data
Amos Folarin amosfolarin at gmail.com writes:
I was wondering I'm going about this in the correct way. I need to test if
there are coding sequences or exons in hg19 which match a string of 100bp
D i.e. [A,G or T]. However I'm getting a strange result.
I get a hit on chr7, using the 100bp
I tried this:
sh -c 'R_DEFAULT_PACKAGES=$R_DEFAULT_PACKAGES rattle R $@'
but without success. I get this message:
R version 2.13.0 (2011-04-13)
Copyright (C) 2011 The R Foundation for Statistical Computing
ISBN 3-900051-07-0
Platform: i486-pc-linux-gnu (32-bit)
R is free software and comes
I apologize for my last post. here is the script I forgot to paste!
subject=1:1000
treat=rbinom(1*1000,1,.13)
gender=rbinom(1*1000,1,.5)
eth=runif(1*1000, min=1, max=4)
cogat=rnorm(1*1000, 100, 16)
map=rnorm(1*1000, 200, 9)
growth=0
simtest=data.frame (subject=subject, treat=treat,
Sacha Viquerat tweedie-d at web.de writes:
Am 15.04.2011 20:14, schrieb Christian Hennig:
Normality of the predictors doesn't belong to the assumptions of the
GLM, so you don't have to check this.
On Fri, 15 Apr 2011, Simone Santoro wrote:
I want to estimate the possible effects of
See below:
--
Don MacQueen
Lawrence Livermore National Laboratory
7000 East Ave., L-627
Livermore, CA 94550
925-423-1062
-Original Message-
From: Jeremy Miles jeremy.mi...@gmail.com
Date: Fri, 15 Apr 2011 14:17:13 -0700
To: Shane Phillips sphill...@lexington1.net
Cc:
The filenames can be done within a loop, like this:
for (id in 1:1000) {
## the filename
fname - paste('sample', formatC(id,width=4,flag='0'),'.tsv',sep='')
## more stuff
}
-Don
--
Don MacQueen
Lawrence Livermore National Laboratory
7000 East Ave., L-627
Livermore, CA 94550
On Fri, Apr 15, 2011 at 6:10 PM, zhenjiang xu zhenjiang...@gmail.com wrote:
Thanks, Dennis! I'll go with it. It's surprising there is no ready way to do
that. I imagine it should be a common data manipulation to add two
data.frame from two different sources. It could happen that one data.frame
On 16/04/11 04:18, sam.e wrote:
Hi there,
I have two data sets, one of locations at different elevations (x,y,z) and
the other of points that make up topographic contours (also x,y,z). I have
used:
result-apply(distppll(data2,cbind(topocon[-nrow(topocon),],topocon[-1,])),1,min)
where 'data2'
On 16/04/11 00:38, Duncan Murdoch wrote:
SNIP
In version 2.14.0 in the fall, this will no longer be the default
behaviour. Perhaps it will be possible to suppress the multiple runs
before then, but I think it is unlikely that the default will change.
SNIP
It already ***is*** the fall (or
I recently installed version 2.13, however when I click the manual
from the console, the error message appears
Error: 'doc\manual\refman.pdf' not found
Error: 'doc\manual\R-intro.pdf' not found
Does anyone know about what's happening?
Thank you very much
Hi Everyone,
I am trying to figure out the spatstat package for the first time and am having
some trouble. Unfortunately, I can't post my data set but I'll hopefully post
enough details for some help.
I want to model the intensity of a spatial point process using 2 covariates
from my data.
On 11-04-15 10:20 PM, Fred wrote:
I recently installed version 2.13, however when I click the manual
from the console, the error message appears
Error: 'doc\manual\refman.pdf' not found
Error: 'doc\manual\R-intro.pdf' not found
Does anyone know about what's happening?
We just noticed this
I am having the same problem on R-2.13.0. Anybody have ideas? Thanks!
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Hi,
Thank you for your suggestion.
I am stil quite new to the syntax of R. I tried in a few ways but all
produced errors:
fit - lm((tos~nh1*nh2*nh3*randsize*aweights*tt1*tt2*tt3*iters*length,
data=expdata))
Error: unexpected ',' in fit -
Hi R community,
I am new bird to R and moved recently from SAS. I am no means expert on
either but very curious learner. So your help crucial for me to learn R.
I have already got positive expression.
I was trying to fit a mixed model in animal experiment but stuck at simple
point. The following
Hi,
Is there a function somewhere that does a patterned jitter of data?
I've googled and the problem is that I don't know what to google for.
The setting is in grouped data. I have plots which overlay jittered
points on a boxplot. I simply jitter the x-value, and the y-value
has no
My question was how can we estimate effects and define correct
model equivalent to SAS code provided.
On Fri, Apr 15, 2011 at 10:21 PM, Nilaya Sharma nilaya.sha...@gmail.comwrote:
Hi R community,
I am new bird to R and moved recently from SAS. I am no means expert on
either but very curious
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