On Mon, 2 May 2011, baptiste auguie wrote:
Unfortunately, it seems that vcd doesn't return grobs but draws
directly to the device, which prevents a concise solution.
Yes. The reason is that vcd was first written before grobs were available.
When we need multiple plots in a single layout, we
To get the statsitics, you will have to run each wilcox.test manually.
the pairwise... version just extracts the p-values and adjusts them.
Uwe Ligges
On 28.04.2011 15:18, JP wrote:
Hi there,
I am trying to do multiple pairwise Wilcoxon signed rank tests in a
manner similar to:
a-
My current code looks like this. Anything that can be improved?
#! /usr/bin/rscript
# install.packages(c('zoo','xts'))
library(zoo)
library(xts)
req_stats - function(data, type = NA)
{
if (is.na(type))
csv - data
else
# subset of data matching our request type
csv -
Hi,
I'm quite new to R so this question will sound quite fundamental. I need to
create a vector of length 160. The first element should be (1+r)^159 and each
element thereafter should decrease by a factor of (1+r) until the 160th element
that should be 1. Is there a function similar to seq()
On 29.04.2011 09:01, mimato wrote:
I want to classify bipolar neurons in human cochleas and have data of the
following structure:
Vol_Nuc Vol_Soma
1 186.23 731.96
2 204.58 4370.96
3 539.98 7344.86
4 477.71 6939.28
5 421.22 5588.53
6 276.61 1017.05
7 392.28 6392.32
8
Thank you very much.
Despite prof. Harrell's support (for whom I feel great
esteem) I still remain doubtful about this feature.
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
On 02-May-11 07:55:27, andre bedon wrote:
Hi,
I'm quite new to R so this question will sound quite fundamental.
I need to create a vector of length 160. The first element should
be (1+r)^159 and each element thereafter should decrease by a
factor of (1+r) until the 160th element that should
On 02.05.2011 09:55, andre bedon wrote:
Hi,
I'm quite new to R so this question will sound quite fundamental. I need to
create a vector of length 160. The first element should be (1+r)^159 and each
element thereafter should decrease by a factor of (1+r) until the 160th element
that should
On 01.05.2011 22:52, Doran, Harold wrote:
Can anyone point me to examples with R code where bwplot in lattice is used to
order the boxes in ascending order? I have found the following discussion and
it partly works. But, I have a conditioning variable, so my example is more like
bwplot(var1
Hello Meilan:
'ect' is shorthand for error-correction-term, 'sd' signify seasonal dummy
variables and 'LRM.dl1' is the lagged first difference of the variable 'LRM'
(the log of real money demand).
HTH,
Bernhard
-Ursprüngliche Nachricht-
Von: r-help-boun...@r-project.org
Hi,
Is it possible (i am sure it is) to subset data from a data.frame on the basis
of SQL LIKE operator. I.e., i would like to subset a data where only values
which contains a string GP would be used?
Example:
Gp-subset(DF, DF$USCS like GP)
This like of course is not working,
On 29.04.2011 23:38, Alexander Senger wrote:
Hello expeRts,
here is something which strikes me as kind of odd and I would like to
ask for some enlightenment:
First let's do this:
tkern - kernel(modified.daniell, c(5,5))
test - rep(1,100)
system.time(kernapply(test,tkern))
User System
I wonder if grep() will help you?
Cheers
Andrew
On Mon, May 02, 2011 at 11:03:52AM +0200, Matev? Pavli? wrote:
Hi,
Is it possible (i am sure it is) to subset data from a data.frame on the
basis of SQL LIKE operator. I.e., i would like to subset a data where only
values which
Hi,
When I use your code i get this :
dat-data.frame(test=c(abc,cdf,dabc))
d-subset(dat,grepl(test,abc))
d
Warning message:
In grepl(test, abc) :
argument 'pattern' has length 1 and only the first element will be used
d
test
1 abc
2 cdf
3 dabc
I can't seem to make it
On 02.05.2011 11:47, Matevž Pavlič wrote:
Hi,
When I use your code i get this :
dat-data.frame(test=c(abc,cdf,dabc))
d-subset(dat,grepl(test,abc))
d - subset(dat, grepl(abc, test))
d
Warning message:
In grepl(test, abc) :
argument 'pattern' has length 1 and only the
Hell is new and improved.
The new version is in the same old place:
http://www.burns-stat.com/pages/Tutor/R_inferno.pdf
An explanation of the changes is at:
http://www.portfolioprobe.com/2011/05/02/the-r-inferno-revised/
--
Patrick Burns
pbu...@pburns.seanet.com
twitter: @portfolioprobe
On 29.04.2011 22:14, kparamas wrote:
Hi,
I am calculation pairwise correlation coefficient for a matrix of 234 X
3.
I am getting the following error,
Error in cbind(as.vector(row(cl)), as.vector(col(cl)), as.vector(cl)) :
allocMatrix: too many elements specified
The problem is that
Dear all,
I have written a quite big piece of code that takes like 6 hourse to execute
(measured that with system.time).
I was wondering if it is possible to try to further understand which are the
pieces of code that are more time consuming so to try to improve them.
Could you please help me
Yeah, that didn't work. Use
fitControl-trainControl(index = list(seq(along = mdrrClass)))
See ?trainControl to understand what this does in detail.
Max
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do
On 02.05.2011 12:35, Alaios wrote:
Dear all,
I have written a quite big piece of code that takes like 6 hourse to execute
(measured that with system.time).
I was wondering if it is possible to try to further understand which are the
pieces of code that are more time consuming so to try to
From the manual R Installation and Administration (that you should have
read yourself before posting):
You can install into another directory tree by using
make prefix=/path/to/here install
Uwe Ligges
On 29.04.2011 19:42, Saptarshi Guha wrote:
Hello,
I notice that e.g /home/sguha/lib64
On 29.04.2011 18:29, Biedermann, Jürgen wrote:
Hi there,
I have the problem, that I'm not able to reproduce the SPSS residual
statistics (dfbeta and cook's distance) with a simple binary logistic
regression model obtained in R via the glm-function.
I tried the following:
fit - glm(y ~ x1 +
On 29.04.2011 17:10, Michael Bach wrote:
Dear R Users,
I am doing stats::decompose() on 4 different time series. When I issue
csdA- decompose(tsA)
plot(csdA)
I get a summary plot for observed, trend, seasonal and random components
of decomposed time series tsA. As I understand it, the
Hi Mary,
I'm not sure I understood your question.
Are you using this package:
http://cran.r-project.org/web/packages/prabclus/index.html
http://cran.r-project.org/web/packages/prabclus/index.htmlAnd asking how
to decide if to use it or not?
Contact
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained,
I discovered that a row of a rectangular array returns, but a function
parameter is not sent to Java.
Appended bare test code: My simple Java test class source and R test code
follow:
public class RJavTest {
public static void main(String[]args) { RJavTest rJavTest=new RJavTest();
}
public
Dear All
I trained a neural network for 200 data and I did prediction for a grid file
(e.g. 100 points) such as below:
snn-predict(nn, newdata=data.frame(wetness=wetnessgrid$band1,
ndvi=ndvigrid$band1))
the pixels of snn is same with wetnessgrid or ndvigrid
I want to convert this
You can use grepl:
dat-data.frame(test=c(abc,cdf,dabc))
d-subset(dat,grepl(test,abc))
d
test
1 abc
3 dabc
On Mon, May 2, 2011 at 7:03 PM, Matevž PavliÄ matevz.pav...@gi-zrmk.siwrote:
Hi,
Is it possible (i am sure it is) to subset data from a data.frame on the
basis of SQL LIKE
On May 01 (2011) Harold Doran wrote:
Can anyone point me to examples with R code where bwplot in lattice is
used to order the boxes in
ascending order?
You don't give an example and what you want is not entirely clear.
Presumably you want ordering by the median (boxplot, and based on the
Hi all, I am new to R programming and I was trying to write a simple code in
order to plot my data. The problem is that I am not able to insert a legend
corresponding to each column of the data matrix. Please can someone help me
out. How can i directly get the legend relating to each data curve.
I'm having that problem, what did you do?
--
View this message in context:
http://r.789695.n4.nabble.com/Problem-installing-new-packages-tp1589974p3489573.html
Sent from the R help mailing list archive at Nabble.com.
__
R-help@r-project.org mailing
Hi all,
Is there an argument in the axis() function to change the colour of
the tick labels? I only found col.ticks, and col.lab, but they're not
doing what I want.
Thanks,
KM
__
R-help@r-project.org mailing list
Well, what would be really helpful is to restrict the scope of all
non-function variables, but keep a global for scope of all function
variables. Then, you still have access to all loaded functions, but you
don't mix up variables.
How would one do that?
Adi
Is there a way I can prevent global
Dear All,
Probably a very basic question, but can't seem to work my way around it.
I want to which row has the maximum value. But what if the row names do not
correspond with the row numbers. In the example below, you'll see that the max
of example is row 4, but the name of row 4 is 9. How do
Uwe Ligges lig...@statistik.tu-dortmund.de writes:
On 29.04.2011 17:10, Michael Bach wrote:
Dear R Users,
I am doing stats::decompose() on 4 different time series. When I issue
csdA- decompose(tsA)
plot(csdA)
I get a summary plot for observed, trend, seasonal and random components
of
Doesn't seem to work. My data structure is below (I will send data to anyone
off-list who could offer support).
The following code below does work, but since I concatenate Region and Gender,
the labels on the lattice are ugly.
dat$test - factor(paste(dat$Region, dat$Gender, sep='_'))
bymedian
Perhaps not the most elegant.
rownames(example)[which.max(example)]
If you wanted to type less, you could always write a function.
names.max - function(x){
return(rownames(example)[which.max(example)])
}
-Mitch
-Original Message-
From: r-help-boun...@r-project.org
On Mon, 2 May 2011, Michael Bach wrote:
Uwe Ligges lig...@statistik.tu-dortmund.de writes:
On 29.04.2011 17:10, Michael Bach wrote:
Dear R Users,
I am doing stats::decompose() on 4 different time series. When I issue
csdA- decompose(tsA)
plot(csdA)
I get a summary plot for observed,
Hallo,
when I plot figures with Sweave, I get the message pdflatex: Permission
denied. This problem only occurs while working on local system. When I copy
the *.rnw-File to my AFS drive, there is no problem at all.
Here is a small example:
\documentclass{scrartcl}
Hi all,
I have just installed R 2.13.0 and I am experiencing problems with the
terminal, but not the with the GUI interface.
I am Windows 7.
When running R or Rterm from a commandline I receive the following:
Warning message:
In normalizePath(path.expand(path), winslash, mustWork) :
Why not do `zero padding' to improve the efficiency, i.e. add a bunch of zeros
to the end of the data vector such that the resulting vector is a power of 2?
This is very common in signal processing, and is legitimate since zero padding
does not add any new information.
Ravi.
On 02/05/2011 7:19 AM, abhagwat wrote:
Well, what would be really helpful is to restrict the scope of all
non-function variables, but keep a global for scope of all function
variables. Then, you still have access to all loaded functions, but you
don't mix up variables.
How would one do that?
On May 2, 2011, at 2:48 AM, Kang Min wrote:
Hi all,
Is there an argument in the axis() function to change the colour of
the tick labels? I only found col.ticks, and col.lab, but they're not
doing what I want.
You just need to read a bit further down in the help page for `axis`.
--
David
On Mon, May 2, 2011 at 2:19 PM, abhagwat bhagwatadi...@gmail.com wrote:
Well, what would be really helpful is to restrict the scope of all
non-function variables, but keep a global for scope of all function
variables. Then, you still have access to all loaded functions, but you
don't mix up
Hi David,
thanks for your quick response. It was really helpful.
--
Kind regards,
Mathias
2011/4/29 David Winsemius dwinsem...@comcast.net:
On Apr 29, 2011, at 6:47 AM, Mathias Walter wrote:
Hi,
I have large data frame with many columns. A short example is given below:
dataH
host
Hi,
despite the fact that pie charts often fail, I'll draw them anyway (in
a case were they are not fail ;-) ).
Does anybody know a package/methods which can draw pie of pie or bar
of pie charts similar to that in MS Excel?
--
Kind regards,
Mathias
The package ggplot2 can do this using a density statistic, polar
coordinates, and faceting.
Extra documentation for the package can be found at the author's site [1].
[1] http://had.co.nz/
On Mon, May 2, 2011 at 10:06 AM, Mathias Walter mathias.wal...@gmx.net wrote:
Hi,
despite the fact that
Please elaborate.
Thanks
Frank
Marco Barbàra-2 wrote:
Thank you very much.
Despite prof. Harrell's support (for whom I feel great
esteem) I still remain doubtful about this feature.
__
R-help@r-project.org mailing list
On 02.05.2011 10:47, liyatle wrote:
I'm having that problem, what did you do?
1. This is the mailing list R-help, not an individual person. I guess
you sent to the wrong address.
2. PLEASE do read the posting guide
http://www.R-project.org/posting-guide.html and provide commented,
The message is pretty clear. Access denied means you don't have
permission to access the path. This also explains why the packages
fail to load - you don't have access to R's package library. It most
likely works on RGui because you are clicking it/running it as admin
(you did not specify how you
Have you checked the permissions in the working directory? Is there a
blank in your path (LaTeX does not like spaces in the path).
Uwe Ligges
On 02.05.2011 14:51, Frank Lehmann wrote:
Hallo,
when I plot figures with Sweave, I get the message pdflatex: Permission
denied. This problem only
rownames(which(example == max(example), arr.ind=TRUE))
Uwe Ligges
On 02.05.2011 13:54, Schumacher, G. wrote:
Dear All,
Probably a very basic question, but can't seem to work my way around it.
I want to which row has the maximum value. But what if the row names do not correspond with the row
Prof Brian Ripley rip...@stats.ox.ac.uk writes:
On Mon, 2 May 2011, Michael Bach wrote:
Uwe Ligges lig...@statistik.tu-dortmund.de writes:
On 29.04.2011 17:10, Michael Bach wrote:
Dear R Users,
I am doing stats::decompose() on 4 different time series. When I issue
csdA- decompose(tsA)
Hi Mary,
Are you using R for your other analysis?
If so, What commands are you using for your analysis?
p.s: please keep the rest of the R-help mailing list in the loop.
Cheers,
Tal
Contact
Details:---
Contact me:
Hi,
I am currently using STATA in my analysis. STATA has a cluster option but
does not have any tests for whether cluster analysis is necessary or not for
a dataset. So I am trying to figure out whether R could be used to test
whether I need to be doing cluster analysis or not. If R does tests
Hi! This is my first time posting. I've read the general rules and
guidelines, but please bear with me if I make some fatal error in
posting. Anyway, I have a continuous response and 29 predictors made
up of continuous variables and nominal and ordinal categorical
variables. I'd like to do lasso
Hello,
I am apparently confused about the use of an id parameter for an event
history/survival model, and why the EHA documentation for aftreg does
not specify one. All assistance and insights are appreciated.
Attempting to specifiy an id variable with the documentation example
generates an
Hi,
On Mon, May 2, 2011 at 12:45 PM, Clemontina Alexander ckale...@ncsu.edu wrote:
Hi! This is my first time posting. I've read the general rules and
guidelines, but please bear with me if I make some fatal error in
posting. Anyway, I have a continuous response and 29 predictors made
up of
On May 2, 2011, at 10:51 AM, Steve Lianoglou wrote:
Hi,
On Mon, May 2, 2011 at 12:45 PM, Clemontina Alexander ckale...@ncsu.edu
wrote:
Hi! This is my first time posting. I've read the general rules and
guidelines, but please bear with me if I make some fatal error in
posting. Anyway, I
MARY A. WEISS mweiss at temple.edu writes:
Hi,
I am currently using STATA in my analysis. STATA has a cluster option but
does not have any tests for whether cluster analysis is necessary or not for
a dataset. So I am trying to figure out whether R could be used to test
whether I need
Hi. I need a very short piece of help regarding colouring segments plotted
on a graph.
When I am plotting segments for the graph, I am using red and darkgreen
for the values 1 and 2 respectively. Heres the relevant line of code in
R:
+ col = c(red, darkgreen)[line.colour.value])
I just need to
I'm trying to insert rows of a data.frame into a database table, or update
where the key fields of a record already exist in the table. I've come up with
a possible solution below, but would like to hear if anyone has a better
solution.
# The problem demonstrated:
# Create a data.frame with
I have a 96x34 array of Likert scale data (96 cases, 34 items) of
ordered factors (strongly disagree, disagree, neutral, agree, strongly
agree) that are coded numerically (1 through 5).
I cannot seem to convert this array (in any class) into ordered vectors.
I have all the cases as vectors of
Dear all,
I am facing the following problem in optimization:
w = (d, o1, ..., op, m1, ..., mq) is a 1 + p + q vector
I want to determine:
w = argmin (a - d(w))' A (a - d(w))
where a is a 1xK marix, A is the covariance matrix of vector a, d(w) is a
1xK vector which parameters are functions of
I am happy to report that the author and maintainer of rJava informed me
that the 2-dim array in java needs sapply and .jevalArray as follows:
conn2Arr- sapply(.jfield(rJavaTst,sig=[[D,con2Arr),.jevalArray)
conn2ArrRet -
sapply(.jcall(rJavaTst,returnSig=[[D,retCon2Arr),.jevalArray)
# I
I would use the vis.test function along with vt.qqnorm (both in TeachingDemos
package). This will create several plots, one of which is your data, the rest
are simulated normals with the same mean and standard deviation. If you can
tell which plot stands out (and it is your real data) then
The R cut command is entirely different from the UNIX cut command.
The latter retains selected fields in a line of text. I can do that kind
of manipulation using sub() or gsub(), but it is tedious. I assume there
is an R function that will do this, but I don't know its name. Can you
tell
Robert -
It would be helpful to know what you've tried that didn't
work, but the data.frame() function is the usual way of combining
things like this:
a = factor(sample(1:5,100,replace=TRUE),ordered=TRUE)
b = factor(sample(1:5,100,replace=TRUE),ordered=TRUE)
ab = data.frame(a,b)
Rather than selecting all the keys, then having R loop through them, why not
have postgres do it for you with something like:
#go through each line in our entry table
for (i in 1:dim(tbl)[1]){
#check if the pkey already exists
q - paste (SELECT key1, key2 FROM tabl WHERE key1=,tbl[i,1],
On Fri, 29 Apr 2011, William Dunlap wrote:
-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of
luke-tier...@uiowa.edu
Sent: Friday, April 29, 2011 9:35 AM
To: Jonathan Daily
Cc: r-help@r-project.org; Hadley Wickham; Barry Rowlingson
Hi Mike,
try substr()
Cheers
Andrew
On Mon, May 02, 2011 at 03:53:58PM -0500, Mike Miller wrote:
The R cut command is entirely different from the UNIX cut command.
The latter retains selected fields in a line of text. I can do that kind
of manipulation using sub() or gsub(), but it is
Hello,
optim() works for more than one dimension. You might also find this
page helpful:
http://cran.r-project.org/web/views/Optimization.html
Cheers
Andrew
On Mon, May 02, 2011 at 12:41:19PM -0700, petrolmaniac wrote:
Dear all,
I am facing the following problem in optimization:
w =
Thanks Steven. It obviously makes sense to loop on the much smaller dataset
that is being added than the set of everything that might already be in the
database. I've added your message in plain text, so that others can see it too.
Mikkel
From: Steven Kennedy stevenkennedy2...@gmail.com
Hi,
I've got a matrix, Z, of values representing (as it happens) optical
power at each pixel location. Since I know in advance I've got a
single, convex peak, I would like to do a 2D parabolic fit of the form
Z = poly((x+y),2) where x and y are the x,y coordinates of each pixel
(or
Hi Paul,
not to seem naive, but have you actually tried the code below? It
doesn't seem that you have, from your text. I think that if you try
it and hack then ask concrete questions (e.g. can anyone explain why
the following simple, reproducible, commented code does not work) then
you'll have
Hi Shane,
it sounds to me as though you have a fairly well-defined problem. You
want to generate random numbers with a specific mean, variance, and
correlation with another random varaible. I would reverse-enginerr
the fuinctions for simple linear regression to get a result like
y = beta_0 +
Thanks for your response, but I guess I didn't make my question clear.
I am already familiar with the concept of dummy variables and
regression in R. My question is, can the lars package (or some other
lasso algorithm) handle factors? I did use dummy variables in my
original data, but lars (lasso)
Hi, I have a similar question:
ir - irf(varsumm, impulse=c(prod, rea, rpo) n.ahead=20, runs=500,
ci=0.95)
will calculate the orthogonalized impulse responses from prod, rea, and
rpo, i.e. a (1, 1, 1)' vector. What do I need to do to make the impulse
(-1, 1, 1)', i.e. I want the the first shock
Hi,
I'd like to ask a installation question. I want to install a source code
through the following command,
R CMD INSTALL RDCOMClient
but get Error: unexpected symbol in r cmd
Please let know if I miss anything. I my utils package loaded.
Thanks,
Richard
[[alternative HTML version
I'm trying to create a list of Data Frames. I have 17 data frames that I need
to move through in a loop, but if I simply make a list of them, then they do
not stay data frames, and I can't sort through them. I tried to create an
array, but the data frames can have anywhere from 14-16 rows,
On Mon, 2011-05-02 at 16:42 -0700, Mike Smith wrote:
I'm trying to create a list of Data Frames. I have 17 data frames
that I need to move through in a loop, but if I simply make a list of
them, then they do not stay data frames, and I can't sort through
them. I tried to create an array, but
On 03/05/11 11:42, Mike Smith wrote:
I'm trying to create a list of Data Frames. I have 17 data frames that I need
to move through in a loop, but if I simply make a list of them, then they do
not stay data frames,
That is simply not true. Just ***how*** did you ``make a list of
them''???
On May 2, 2011, at 2:22 PM, Clemontina Alexander wrote:
Thanks for your response, but I guess I didn't make my question clear.
I am already familiar with the concept of dummy variables and
regression in R. My question is, can the lars package (or some other
lasso algorithm) handle factors?
On Mon, May 02, 2011 at 05:22:57PM -0400, Clemontina Alexander wrote:
Thanks for your response, but I guess I didn't make my question clear.
I am already familiar with the concept of dummy variables and
regression in R. My question is, can the lars package (or some other
lasso algorithm)
You may want to consider spatial::surf.ls
Or, a simplistic approach where you fit a model such as using `lm':
E[Z | x, y] = a + b(x - x0)^2 + c(y - y0)^2
where (x0, y0) is the location of maximum.
Ravi.
From: r-help-boun...@r-project.org
Clementonia,
It sounds like you are looking for the group lasso (Yuan Lin, 2006). There
are two packages on CRAN that have implemented this idea: grpreg and grplasso.
The syntax of each is similar to lars (in particular requiring a numeric design
matrix as produced by model.matrix), except
On Tue, 3 May 2011, Andrew Robinson wrote:
try substr()
OK. Apparently, it allows things like this...
substr(abcdef,2,4)
[1] bcd
...which is like this:
echo abcdef | cut -c2-4
But that doesn't use a delimiter, it only does character-based cutting,
and it is very limited. With cut -c
On Mon, May 2, 2011 at 10:32 PM, Mike Miller mbmille...@gmail.com wrote:
On Tue, 3 May 2011, Andrew Robinson wrote:
try substr()
OK. Apparently, it allows things like this...
substr(abcdef,2,4)
[1] bcd
...which is like this:
echo abcdef | cut -c2-4
But that doesn't use a delimiter,
Hi Carl,
Here is another slightly different (not necessarily the easiest) approach that
uses a profiling technique. An advantage is that you get the maximum location
directly.
n - 20
x - sort(rnorm(n))
y - sort(rnorm(n))
xy - expand.grid(x, y)
zfn - function(x) 0.5 - 2.2 * (x[1] - 0.5)^2 -
On Mon, 2 May 2011, Gabor Grothendieck wrote:
On Mon, May 2, 2011 at 10:32 PM, Mike Miller mbmille...@gmail.com wrote:
On Tue, 3 May 2011, Andrew Robinson wrote:
try substr()
OK. Apparently, it allows things like this...
substr(abcdef,2,4)
[1] bcd
...which is like this:
echo abcdef
Hello,
I am trying to use adaptIntegrate function but I need to pass on a few
additional parameters to the integrand. However, this function seems not to
have the flexibility of passing on such additional parameters.
Am I missing something or this is a known limitation. Is there a good
Mike Miller wrote:
On Mon, 2 May 2011, Gabor Grothendieck wrote:
On Mon, May 2, 2011 at 10:32 PM, Mike Miller mbmille...@gmail.com wrote:
On Tue, 3 May 2011, Andrew Robinson wrote:
try substr()
OK. Apparently, it allows things like this...
substr(abcdef,2,4)
[1] bcd
...which is like
92 matches
Mail list logo
