Hello Tsidkenu,
Not sure that I have well understood your question but maybe you can add
fill to your legend function :
legend(10,90,legend=c(TR=100 años,TR=50 años,TR=25 años,TR=10
años),lwd=2,pt.cex=1.5,bty='n',pch=c(24,22,21,23),
fill=c(red,green,blue,black))
Have a good day,
Ptit Bleu.
--
Hello all,
Sometimes I get to make an R code chunk (in Sweave) which is longer then
the margins of the page. Is there a way to force it to go to the next
line (in Sweave) once that happens?
Here are two cases this happens in the resulting .tex file (one is a hard
case, and the other is simpler)
Do you have a practical case in which you have to print 114 a's
without spaces? I mean this is such an extreme case that is unlikely
to happen in real life. As long as you have spaces in your string, it
will be easy for LaTeX to wrap long lines, although LaTeX should be
able to do it even if the
dear all,
apologizes for this off-topic question.
I am looking for a ecological dataset (n100, say) including
measurements of one or more growth variable and age.
Could anyone to suggest the R package/URL where I can find it?
many thanks,
vito
--
Vito
Hi All, I am wondering if anyone can tell me what the warning message below
the model means?
J
add1(DTA.glm,~ Aeventexhumed + Veg + Berm + HTL + Estuary + Rayos)
Single term additions
Model:
cbind(MaxHatch, TotalEggs - MaxHatch) ~ Aeventexhumed + Veg +
Berm + HTL
Df Deviance
This is a follow-up to a post from 2007:
https://stat.ethz.ch/pipermail/r-help/2007-April/129009.html
Summary of the Problem:
Packages are correctly installed and can be loaded when R is opened
interactively or using a R script. However, a bash scripts produces an
error similar to the following:
On Thu, 19 Jan 2012, Jhope wrote:
Hi All, I am wondering if anyone can tell me what the warning message below
the model means?
Which one?: there are two warnings!
1) most likely indicates that Rayos is a character variable.
2) indicates that you have missing values in the variables you are
Hello,
I have a vector which looks like
x$ART
...
[35415] 0001-1;02-1;05-1;
[35417] 01-1; 01-1;02-1;
[35419] 01-1; 00
[35421] 01-1;04-1;05-1;
Hi Yihui,
The a's case happens when, for example, one prints some long equation
function without using spaces in it. It happened to me in something I
wrote which I will write now while including spaces if I had known it would
solve the issue, but I have yet to have found one (for Sweave, that is
Hello all,
I would like to ask several questions regarding cacheSweave:
1) Is there a way to set cache=true globally? (I tried it
using \SweaveOpts but it didn't seem to work)
2) Is there a way to flush specific cache once it is created? (other
then erasing the entire cache directory)? Changing
Devarayalu,
This is FAQ 7.22:
http://cran.r-project.org/doc/FAQ/R-FAQ.html#Why-do-lattice_002ftrellis-graphics-not-work_003f
use print(qplot())
Regards,
Jan
Sri krishna Devarayalu Balanagu balanagudevaray...@gvkbio.com schreef:
Hi All,
Can you please help me, why this code in not
On Thu, Jan 19, 2012 at 12:13:00AM -0800, Leila Lackey wrote:
This is a follow-up to a post from 2007:
https://stat.ethz.ch/pipermail/r-help/2007-April/129009.html
Summary of the Problem:
Packages are correctly installed and can be loaded when R is opened
interactively or using a R
Hi,
thanks a lot. That was quite helpful, not only in terms of providing a
solution to my problem, but in terms of efficiently explaining, what the
problem is about.
On 17/01/2012 18:26, Jeff Newmiller wrote:
Replying to old messages without including context (particularly old
ones) is
Devarayalu,
Please reply to the list.
And it would have easier if you would have outputted your data using
dput (in your case dput(Orange1)) so that I and other r-help members
can just copy the data into R. Not everybody had Excell available (I
for example haven't). The easier you make it
Hi, Johannes,
maybe
X - unlist( strsplit( as.character( x$ART), split = ;, fixed = TRUE))
X - strsplit( X, split = -, fixed = TRUE)
X - sapply( X, function( x)
if( length(x) == 2)
rep( x[1], as.numeric( x[2])) else x[1]
)
table(X, useNA = always)
Hello,
I'm trying to make a non-linear regression using the attached data and
this model. When I run it I get the following message:
Error in nls(y ~ 1/(a + w * x), data = df, start = list(a = 1, w = 1), :
singular gradient
mod - nls(y~1/(a+w*x),data=df,start=list(a=1,w=1),trace = TRUE)
Hi,
I see the following is the credit scoreing in R guide :
m2-glm(formula = good_bad ~ checking + duration + history+ purpose +amount +
savings + employed + installp + marital +
coapp +age + other + depends + telephon + foreign +checking:amount
What does checking:amount mean?
Regards,
Anyone? ):
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Thank you Prof Ripley, I understand and changed Rayos into a factor.
Can someone please tell me how to change the:
Model:
cbind(MaxHatch, TotalEggs - MaxHatch) ~ Aeventexhumed + Veg +
Berm + HTL
Into a model that has?:
Model:
cbind(MaxHatch, TotalEggs - MaxHatch) ~ 1
Best, J
--
Hi all,
Small problem in generating the line charts.
Question: Legend for the first graph is coming wrong., for second graph
correctly. Please fix the legend postion at the down of graph.
Plesae give me the solution.
Thank you
Devarayalu
Orange1 - structure(list(REFID = c(7, 7, 7, 7, 7,
On 12-01-19 3:24 AM, Tal Galili wrote:
Hello all,
Sometimes I get to make an R code chunk (in Sweave) which is longer then
the margins of the page. Is there a way to force it to go to the next
line (in Sweave) once that happens?
Sweave normally uses a verbatim environment, so you have to
Thank you, William, for your help! It works great. My final call
looks like this:
pars - c(.(nodes), .(load), .(buffer), .(deflections))
ddply(i, pars, summarize,
mm_created = mean(mean_created),
ms_created = mean(sdev_created),
mm_admitted = mean(mean_admitted),
As I mentioned in my previous reply: do not only email to me
personally but also include the mailinglist. This gives other members
also the opportunity to answer your question and lets other members,
who might have a similar question, also see the answer.
As for your first question: put
thank you a lot :)
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Dear all,
Just wondering if someone could help me out converting my code from a for()
loop into a foreach() loop or using one of the apply() function. I have a
very large dataset and so I'm hoping to make use of a parallel backend to
speed up the processing time. I'm having trouble getting
On 19-Jan-2012 Xiaobo Gu wrote:
Hi,
I see the following is the credit scoreing in R guide :
m2-glm(formula = good_bad ~ checking + duration + history +
purpose +amount + savings + employed + installp + marital +
coapp +age + other + depends + telephon + foreign +checking:amount
What does
On Jan 19, 2012, at 8:02 AM, Xiaobo Gu wrote:
Hi,
I see the following is the credit scoreing in R guide :
m2-glm(formula = good_bad ~ checking + duration + history+ purpose
+amount + savings + employed + installp + marital +
coapp +age + other + depends + telephon + foreign
Tal Galili tal.galili at gmail.com writes:
Hello all,
I would like to ask several questions regarding cacheSweave:
1) Is there a way to set cache=true globally? (I tried it
using \SweaveOpts but it didn't seem to work)
2) Is there a way to flush specific cache once it is created? (other
Hello everybody,
I noticed a performance problem when using the source-function in R.
When I try to source an r script that is located in the same directory
as the script I execute via command line ('R -f file.r' contents
'source(someOtherScript.r)') it's very fast. But if I put
On Jan 18, 2012, at 10:48 PM, Jhope wrote:
Hi All,
I am a beginner to R and a prof helped me with some script. I am
having
trouble understanding the below line. Is it finding the file
turtlehatch.csv? I do not have my working directory set to this
file. If so
I tried (file.choose) and
Such a model consists of a series of terms separated by +operators.
In the above ,term means individual variable.
The terms themselves consist of variable and factor names separated by :
operators.
What does term mean in this?
Such a term is interpreted as the interaction of all the variables
On Jan 19, 2012, at 8:56 AM, Xiaobo Gu wrote:
Such a model consists of a series of terms separated by +operators.
In the above ,term means individual variable.
The terms themselves consist of variable and factor names separated
by : operators.
What does term mean in this?
Such a term is
Thanks for the reply but I want to color (of gray) the triangle, square,
circle and the other symbol appear in the legend.
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On 19.01.2012 14:25, Jos van Nijnatten wrote:
Hello everybody,
I noticed a performance problem when using the source-function in R.
When I try to source an r script that is located in the same directory
as the script I execute via command line ('R -f file.r' contents
On 19.01.2012 15:02, Tsidkenu wrote:
Thanks for the reply but I want to color (of gray) the triangle, square,
circle and the other symbol appear in the legend.
PLEASE do read the posting guide.
Uwe Ligges
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On 12-01-19 8:25 AM, Jos van Nijnatten wrote:
Hello everybody,
I noticed a performance problem when using the source-function in R.
When I try to source an r script that is located in the same directory
as the script I execute via command line ('R -f file.r' contents
'source(someOtherScript.r)')
Hello,
Here's my problem :
I have a csv file which I have to read with read.table() function (or
read.csv). The file has about 6 lines whose data are written this way:
character;character;character;character
14/10/2010 13:10;0;49;0;49;
14/10/2010 13:20;0;49;0;49;
14/10/2010
Tal,
You probably need to cc the package author for reliable answers, but
my attempts are below anyway:
1) true or TRUE? I'm not exactly sure how this option is parsed
(checking the source code is one way to go), but for knitr, it does
not allow true to mean TRUE, and \SweaveOpts{cache=TRUE}
Hello Uwe, Duncan and the rest of the community,
It indeed seemed to be a file system problem and I'm lucky to figure
that out before it crashed. New computer's great and everything is
working fine again.
Sorry for wasting your time ;-)
On Thursday, January 19, 2012 15:16, Duncan Murdoch
On Jan 19, 2012, at 9:22 AM, aaurouss wrote:
Hello,
Here's my problem :
I have a csv file which I have to read with read.table() function (or
read.csv). The file has about 6 lines whose data are written
this way:
character;character;character;character
14/10/2010 13:10;0;49;0;49;
dear Julian,
Il 18/01/2012 14.36, crimsonengineer87 ha scritto:
Thanks for the comments. Yes, I also had segmented and then I went away from
that. I can't remember. I've tried using it but I get some sort of strange
error. Here's some code ...
it is difficult for me to help you without
On Jan 19, 2012, at 9:34 AM, David Winsemius wrote:
On Jan 19, 2012, at 9:22 AM, aaurouss wrote:
Hello,
Here's my problem :
I have a csv file which I have to read with read.table() function (or
read.csv). The file has about 6 lines whose data are written
this way:
Hi,
just for explaining it a little bit furhter
here a small sample dataframe (similar to that
I am working with).
var1 -seq(1,5)
var2 -c(A,B,C,D,E)
var3 -c(00,01-1;02-3;04-1,01-2;02-1,01-0;04-12,NA)
x - data.frame(var1,var2,var3)
The final dataframe should look like:
When there is the
I can plot each county of the contiguous 48 states or all of them using
variations of
map('county', region=c('wisconsin' . . . .)
in the maps package. I was wondering whether similar data was available for
Alaska and Hawaii? I was also wondering if there was a database that listed
FIPS
Hi
Hi all,
Small problem in generating the line charts.
Question: Legend for the first graph is coming wrong., for second graph
correctly. Please fix the legend postion at the down of graph.
Plesae give me the solution.
Thank you
Devarayalu
Orange1 - structure(list(REFID
You could look at grid(), but the Note in the documentation suggests If
more fine tuning is required, use abline(h = ., v = .) directly. Also
grid() uses the default axis positions so if you specify details of the axis
with xlim, ylim, etc the grid does not line up on the tickmarks.
Using abline
Hello everyone,
I use Bob Muenchen's approach for reading in in-stream (to use SAS
parlance) delimited data within a script. This works great:
mystring -
id,workshop,gender,q1,q2,q3,q4
1,1,f,1,1,5,1
2,2,f,2,1,4,1
3,1,f,2,2,4,3
4,2, ,3,1, ,3
5,1,m,4,5,2,4
6,2,m,5,4,5,5
7,1,m,5,3,4,4
Hello,
I'm on Windows, and according to the documentation R searches along the
search path when looking for dll's for dyn.load.
For illustration, I've copied the XML.dll from package XML in the C:/Temp
folder
if (file.exists(C:/Temp/XML.dll)) {
Sys.setenv(path = paste(C:/Temp;,
Simply change the sep = , argument of read table: for a space
and \t for a tab. E.g., read.table(text = data3, sep = , header =
TRUE)
Take a look at ?read.table for more info about the sep argument (In
particular the special behavior of the default sep = )
Thanks for the well-posed question
Hi Michael,
Thanks for your responses.
When I do this, I am not successful. What am I doing wrong?
data3-
+ OBSNOAGESEXALKPHOSLABCAMMOLPHOSMMOLAGEGROUP
+ 2176M8453.20.93
+ 2276M52.180.843
+ 2368M8252.150.521
+ 2469M8452.31.361
+ 2576F100325.31.073
+ 2670F903200.972
+ 2771F109322.30.942
+
On Jan 19, 2012, at 11:37 AM, Dan Abner wrote:
Hello everyone,
I use Bob Muenchen's approach for reading in in-stream (to use SAS
parlance) delimited data within a script. This works great:
mystring -
id,workshop,gender,q1,q2,q3,q4
1,1,f,1,1,5,1
2,2,f,2,1,4,1
3,1,f,2,2,4,3
4,2, ,3,1, ,3
Jonas, I've just seen your function 'sistring' code and it's different from
the code in
Thanks a lot for reporting this bug. It is fixed now in the git
repository.
I added some examples, but they do not work:
R CMD check sitools
= snip
### ** Examples
library(sitools)
Cannot see what you are doing wrong, since you don't show that. It looks like
you have eliminated all delimiters from your input data. Perhaps your editor
settings are doing something to your data (though usually tabs if altered
become spaces).
Hello there,
I am trying to fit an exponential model using nls to some data.
#data
t - c(0,15,30,60,90,120,240,360,480)
var - c(0.36,9.72,15.50,23.50,31.44,40.66,59.81,73.11,81.65)
df - data.frame(t, var)
# model
# var ~ a+b*(1-exp(-k*t))
# I'm looking for values of a,b and k
#
Dear R users,
I have been trying to estimate global sensitivity indices such as the sobol
1st and 2nd order indices. I managed to obtain the PRCC.
The example presented in the sensitivity package on sobol2002 seems to work
well for linear models: for example: calculate y for given x values.
Hi,
I am new to R and wondering if it is possible for it to connect to an
Informix database. I tried google but nothing came back that I could figure
out.
Can somebody tell me if its possible (which I believe it is) and how to
connect to an Informix database using R.
Thanks!
--
View this
I have a problem with RODBC statements that seems to be related to inserting
data into a table during an SQL batch (MS SQL Server). It started from a
stored procedure that didn't return data to R but I could boil it down to
the following simplified code snippets.
The first one does work:
If you can't get an answer here it may be worth posting to the R-SIG-DB list in
24 hours or so. (special interest group for databases)
Data bases are not an area I know at all, but I think RODBC attempts to work
with a universal database standard so that might be worth exploring. But like I
On 19/01/2012 11:19 AM, Adrian Dragulescu wrote:
Hello,
I'm on Windows, and according to the documentation R searches along the
search path when looking for dll's for dyn.load.
For illustration, I've copied the XML.dll from package XML in the C:/Temp
folder
if
Hello Chris,
I am trying to fit a 4 state multi-state model using hidden markov routine in
the msm package.
1. initial parameters:
twoway4.q - rbind(c(0, 0.25, 0, 0.25), c(0.166,
0, 0.166, 0.166), c(0, 0.25, 0, 0.25), c(0,
0, 0, 0))
ematrix - rbind(
c(0, 0.01, 0, 0),
c(0.01, 0, 0.01,0),
Hi there,
Is there a way to control the circle diameter in venn.diagram function of
VennDiagram package?
Thanks
Mike
[[alternative HTML version deleted]]
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PLEASE
Fabulous example, Baptiste!
Yeah, the knock is that it's just not at all clear and too often
symptomatic of someone trying to be too clever by half when there's
usually a better way. There are times when these tricks can be really
helpful for non-standard evaluation (e.g., the curve() function --
It doesn't work even if I set it with \\. My path has a mixture of \\ and
/ and other entries work fine.
if (file.exists(C:/Temp/XML.dll)) {
Sys.setenv(path = paste(C:\\Temp;C:/Temp;, Sys.getenv(path), sep=))
dyn.load(XML.dll) # doesn't find it!
}
Error in inDL(x, as.logical(local),
I can't reproduce your problem: both of these work just fine for me.
read.table(text = data3, header = TRUE, sep = , row.names = OBSNO)
read.table(textConnection(data3), header = TRUE, sep = , row.names
= OBSNO, na.string = -99)
dput(data3)
OBSNO AGE SEX ALKPHOS LAB CAMMOL PHOSMMOL
On 19/01/2012 1:42 PM, Adrian Dragulescu wrote:
It doesn't work even if I set it with \\. My path has a mixture of \\ and
/ and other entries work fine.
if (file.exists(C:/Temp/XML.dll)) {
Sys.setenv(path = paste(C:\\Temp;C:/Temp;, Sys.getenv(path), sep=))
dyn.load(XML.dll) # doesn't
Your first email has
data3-
OBSNO AGE SEX ALKPHOS LAB CAMMOL PHOSMMOL AGEGROUP
21 76 M 84 5 3.2 0.9 3
22 76 M 5 2.18 0.84 3
23 68 M 82 5 2.15 0.52 1
24 69 M 84 5 2.3 1.36 1
25 76 F 100 3 25.3 1.07 3
26 70 F 90 3 20 0.97 2
27 71 F 109 3 22.3 0.94 2
28 70 -99 65 3 24.3 1.42 2
29 74 F 61 3 25 0.87
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
On Behalf Of Dan Abner
Sent: Thursday, January 19, 2012 8:51 AM
To: R. Michael Weylandt
Cc: r-help@r-project.org
Subject: Re: [R] Reading in tab (and space) delimited data within a
You might be able to do it with overplotting,(i.e., do the solid grey
using the pch values in the 20s and then use a hollow symbol to put a
black border on it) but I don't see a natural way to change the
background color for just those characters. How'd you do so on the
body of the plot?
Glad you got it worked out -- I don't know C# but if it's portable-ish
to C++ you may also want to look at Dirk's RInside project:
http://dirk.eddelbuettel.com/code/rinside.html
and here in web-deployment
http://dirk.eddelbuettel.com/blog/2011/11/30/#rinside_and_wt
Michael
On Wed, Jan 18,
arivald rzepus.m at gmail.com writes:
I am trying to fit an exponential model using nls to some data.
#data
t - c(0,15,30,60,90,120,240,360,480)
var - c(0.36,9.72,15.50,23.50,31.44,40.66,59.81,73.11,81.65)
df - data.frame(t, var)
# model
# var ~ a+b*(1-exp(-k*t))
# I'm
Sorry I forgot the subject line last time
Dear R experts,
I am using the foreign package to read in Stata and SPSS format data
files (same data but I tried different format). I first tried using
read.dta for the Stata format:
##
library(foreign)
mystata -
Thank you very much for this information.
From: R. Michael Weylandt michael.weyla...@gmail.com
Cc: Richard M. Heiberger r...@temple.edu; R General Forum
r-help@r-project.org
Sent: Thursday, 19 January 2012, 19:17
Subject: Re: [R] Executable Expressions II
* Sarah Goslee fnenu.tbf...@tznvy.pbz [2012-01-18 17:36:16 -0500]:
Here's one way, worked out in lots of steps so you can see
how each works:
thanks, it all makes perfect sense, and I wrote this function based on
your instructions:
drop.levels - function (frame, column, threshold) {
size -
The R Language Definition at
http://cran.r-project.org/doc/manuals/R-lang.html states in the following
section
4.3.2 Argument matching
This subsection applies to closures but not to primitive functions.
What are 'closures'?
[[alternative HTML version deleted]]
Hi Sam,
To be of any use whatsoever, we need a reproducible example.
What's frame?
What's column?
What's threshold?
Remind the list what you're trying to do. The list gets lots of traffic;
if you delete out all the context nobody will remember what you need.
Sarah
On Thu, Jan 19, 2012 at 2:44
http://www.lemnica.com/esotericR/Introducing-Closures/
Any function you work with will be a closure -- primitives are
built-in functions that users can't create. (without source editing
recompiling R) E.g. the function c() (type it without parentheses at
the prompt to see its code)
Let me know
On Fri, 20 Jan 2012, Kevin Burton wrote:
I can plot each county of the contiguous 48 states or all of them using
variations of
map('county', region=c('wisconsin' . . . .)
in the maps package. I was wondering whether similar data was available for
Alaska and Hawaii? I was also
On 20/01/12 06:38, arivald wrote:
Hello there,
I am trying to fit an exponential model using nls to some data.
#data
t- c(0,15,30,60,90,120,240,360,480)
var- c(0.36,9.72,15.50,23.50,31.44,40.66,59.81,73.11,81.65)
df- data.frame(t, var)
# model
# var ~ a+b*(1-exp(-k*t))
# I'm looking for
Michael, thank you, especially for the link. I think I understand.
The vocabulary is so different! I know 'closure' as 'user-defined function'.
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Ajay Askoolum aa2e72e at yahoo.co.uk writes:
Michael, thank you, especially for the link. I think I understand.
The vocabulary is so different! I know 'closure' as 'user-defined function'.
Not quite. All (??) user-defined functions are closures, but lots
of non-user-defined functions
create data:
mydata - data.frame(MyFactor = factor(rep(LETTERS[1:4], times=c(1000, 2000,
30, 4))), something = runif(3034))
define function:
drop.levels - function (df, column, threshold) {
size - nrow(df)
if (threshold 1) threshold - threshold * size
tab - table(df[column])
keep -
First, the reproducable example, showing how converting from character to
POSIXct to character changes the milliseconds in the first time stamp
though not in the second:
as.POSIXct('2010-06-03 9:03:58.324')
[1] 2010-06-03 09:03:58.323 PDT
as.POSIXct('2010-06-03 9:03:58.325')
[1] 2010-06-03
Everywhere that you use
df[column]
should be
df[[column]]
That's the only thing I see, *except* that df() and drop() are base functions,
so you shouldn't use those as variable names.
Remind the list what you're trying to do. The list gets lots of traffic;
if you delete out all the context
That's the only thing I see, *except* that df() and drop() are base functions,
so you shouldn't use those as variable names.
I don't think that is much of a problem. The local
versions will be used in the function.
A bigger problem is naming your function 'drop.levels'.
There is a core R
Thanks for clarifying.
Is my (new) understanding stated below correct?
- A closure is any function (user- or system- defined) where
is.primitive(functionName) is FALSE.
- is.primitive(functionName) is FALSE when functionName is a system-defined
function that is coded in R itself.
On Thu, Jan 19, 2012 at 4:11 PM, William Dunlap wdun...@tibco.com wrote:
That's the only thing I see, *except* that df() and drop() are base
functions,
so you shouldn't use those as variable names.
I don't think that is much of a problem. The local
versions will be used in the function.
On Jan 19, 2012, at 21:39 , Ben Bolker wrote:
Ajay Askoolum aa2e72e at yahoo.co.uk writes:
Michael, thank you, especially for the link. I think I understand.
The vocabulary is so different! I know 'closure' as 'user-defined function'.
Not quite. All (??) user-defined functions
On Thu, Jan 19, 2012 at 1:15 PM, Ajay Askoolum aa2e...@yahoo.co.uk wrote:
Thanks for clarifying.
Is my (new) understanding stated below correct?
No.
-- Bert
- A closure is any function (user- or system- defined) where
is.primitive(functionName) is FALSE.
- is.primitive(functionName)
Wolfgang,
Since you seem to be doing this in the psych package, it would have been faster
to directly ask the author (me). Luckily, I saw the question on R-Help.
The principal components step is being done on the correlation matrix, not on
the raw data matrix, thus, it is not able to find
require(Hmisc)
?spss.get
Xu Jun wrote
Sorry I forgot the subject line last time
Dear R experts,
I am using the foreign package to read in Stata and SPSS format data
files (same data but I tried different format). I first tried using
read.dta for the Stata format:
Hello all,
This is one of those Is there a better way to do this questions. Say
I have a dataframe (df) with a grouping variable (z). This is my base
data. Now I know that there is a higher order level of grouping that
exist for my group variable. So what I want to do is create a new
column that
how bout
levels(df$z)[grep('A',levels(df$z))] - 'A'
levels(df$z)[grep('B',levels(df$z))] - 'B'
levels(df$z)[grep('C',levels(df$z))] - 'C'
does that do what you're wanting?
On Thu, Jan 19, 2012 at 3:05 PM, Sam Albers tonightstheni...@gmail.comwrote:
Hello all,
This is one of those Is there
On Thu, Jan 19, 2012 at 1:45 PM, Ajay Askoolum aa2e...@yahoo.co.uk wrote:
The R Language Definition at
http://cran.r-project.org/doc/manuals/R-lang.html states in the following
section
4.3.2 Argument matching
This subsection applies to closures but not to primitive functions.
What are
On Thu, Jan 19, 2012 at 3:34 PM, Justin Haynes jto...@gmail.com wrote:
how bout
levels(df$z)[grep('A',levels(df$z))] - 'A'
levels(df$z)[grep('B',levels(df$z))] - 'B'
levels(df$z)[grep('C',levels(df$z))] - 'C'
does that do what you're wanting?
Shoot. Might have made my example confusing,
Hi Sam,
Check the examples in
require(car)
?recode
HTH,
Jorge.-
On Thu, Jan 19, 2012 at 6:05 PM, Sam Albers wrote:
Hello all,
This is one of those Is there a better way to do this questions. Say
I have a dataframe (df) with a grouping variable (z). This is my base
data. Now I know that
Dear all,
I am trying to learn Bayesian inference and Bayesian data analysis, I
am new in the field. Would any experts on the list recommend any good
sites or materials for beginners?
My approach is to learn and understand the theory first, then program
on my own using R, though I see there are
I wonder if someone could help me adjusting the following code to parallelized
snow code:
#Creating a data set (not needed to be parallel)
n-100
p-100
x-matrix(rnorm(n*p),p)
y-rnorm(n)
# Bootstrapping
nboot-1000
alpha-0.05
rhoboot - array(0, dim=c(p,nboot))
bootranks - array(0, dim=c(p,nboot))
Hello, I managed to install playwith package and all its prerequisites. My
R version is R 2.14:
R version 2.14.1 (2011-12-22)
Copyright (C) 2011 The R Foundation for Statistical Computing
ISBN 3-900051-07-0
Platform: i486-pc-linux-gnu (32-bit)
All my packages were updated, and recently
Hi,
I 'd like to select the Date where myvalue =1800 appears the* first time*.
For instance:
df =data.frame(date, myvalue, ...)
...
Datemyvalue
2012-01-052500
2012-01-06 2450
*2012-01-07 1800*
2012-01-08
I have a panel data set defined as a simple data.frame with a factor age and
income. I would like to generate the results of a set function such as (sum,
mean, or even diff) separate for each factor (category or age group).
However I want the result to have the same dimension as the overal
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