What part of read the posting guide did you not understand? The provide
commented, minimal, self-contained, reproducible code part?
---
Jeff NewmillerThe . . Go Live...
On Wed, Feb 15, 2012 at 02:17:35PM +1000, Redding, Matthew wrote:
Hi All,
I've been trawling through the documentation and listserv archives on this
topic -- but
as yet have not found a solution. I'm sure this is pretty simple with R, but
I cannot work out how without
resorting to
On 15 February 2012 19:00, Jeff Newmiller jdnew...@dcn.davis.ca.us wrote:
What part of read the posting guide did you not understand? The provide
commented, minimal, self-contained, reproducible code part?
Off topic: why is there so much unfriendliness on this thread ? Both
the above and DW's
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On 15/02/12 05:17, Redding, Matthew wrote:
Hi All,
I've been trawling through the documentation and listserv archives
on this topic -- but as yet have not found a solution. I'm sure
this is pretty simple with R, but I cannot work out how
On 14-02-2012, at 22:14, Hasan Diwan wrote:
dput(sensor.sample)
structure(c(1328565718.65, 1328566608.9, 1328566162.65, 1328566571.1,
1328566598.85, 1328565634.3, 1328566513.95, 1328565123.65, 1328565827.1,
..
What I'd like to do is get a spline through all the points. I'm
thinking the
this is ugly, but...
l -length(patrn)
l2 -length(exmpl)
out - vector(list)
for(i in 1:(l2-l+1))
{
exmpl[i:(i+l-1)]
patrn==exmpl[i:(i+l-1)]
if(all(patrn==exmpl[i:(i+l-1)]))
{ out[[i]] - i } else { out[[i]] - NA}
}
out - do.call(c, out)
as.numeric(out[which(out!=NA)])
## Cheers and
hi,
i am using R for first time. i am trying to do T-test for a sample set with
three variables. i attached my data set as CSV file.
but when i do t.test(data$Day.1,data$Day.2,var.equal=T) i get this
following error. Can anyone please help e identify the problem.
Error in if (stderr 10 *
hi
My data looks like
x=c(0,0,0,0,0)
y=c(10,20,30,40,50)
i want to generate 5 random numbers between x and y keeping x values as
min and y value as max using apply
it takes time when it is run using for
-
Thanks in Advance
Arun
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I have a dataset which has a predictor (Temperature), a response
(Developmental Time) and two separate factors Species ( A B) and
Population (High, Low, Middle). I want to compare whether the populations
and the species differ from each other (is A different from B or is low A
different to high
On 15/02/12 21:25, Michael Bedward wrote:
On 15 February 2012 19:00, Jeff Newmillerjdnew...@dcn.davis.ca.us wrote:
What part of read the posting guide did you not understand? The provide
commented, minimal, self-contained, reproducible code part?
Off topic: why is there so much
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On 15/02/12 05:17, Redding, Matthew wrote:
Hi All,
I've been trawling through the documentation and listserv archives
on this topic -- but as yet have not found a solution. I'm sure
this is pretty simple with R, but I cannot work out how
On Wed, Feb 15, 2012 at 12:31:54AM -0800, arunkumar wrote:
hi
My data looks like
x=c(0,0,0,0,0)
y=c(10,20,30,40,50)
i want to generate 5 random numbers between x and y keeping x values as
min and y value as max using apply
it takes time when it is run using for
Hi.
A
On 15-02-2012, at 05:17, Redding, Matthew wrote:
Hi All,
I've been trawling through the documentation and listserv archives on this
topic -- but
as yet have not found a solution. I'm sure this is pretty simple with R, but
I cannot work out how without
resorting to ugly nested loops.
On Tue, Feb 14, 2012 at 2:31 PM, William Dunlap wdun...@tibco.com wrote:
If you must repeatedly append rows to a data.frame,
try making the dataset you are filling in a bunch
of independent vectors, perhaps in a new environment
to keep things organized.
One complication is I don't know the
Hi:
I wonder if anyone may know the answer to this question:
COnsider the following data frame (DF):
ColumnA ColumnB ColumnC
a d d
s s e
e r e
y w y
t u i
q e l
What I need is to
Is this what you want:
x - read.table(text = ColumnA ColumnB ColumnC
+ a d d
+ s s e
+ e r e
+ y w y
+ t u i
+ q e l, as.is = TRUE, header = TRUE)
x$ColumnC[1:3] - runif(3)
x
ColumnA
try this:
x=c(0,0,0,0,0)
y=c(10,20,30,40,50)
mapply(runif, 1, x, y)
[1] 3.6958437 0.1190025 23.1382387 35.8738653 28.6983410
On Wed, Feb 15, 2012 at 3:31 AM, arunkumar akpbond...@gmail.com wrote:
hi
My data looks like
x=c(0,0,0,0,0)
y=c(10,20,30,40,50)
i want to generate 5
On Wed, Feb 15, 2012 at 10:26:44AM +0100, Berend Hasselman wrote:
On 15-02-2012, at 05:17, Redding, Matthew wrote:
Hi All,
I've been trawling through the documentation and listserv archives on this
topic -- but
as yet have not found a solution. I'm sure this is pretty simple
Hi
hi,
i am using R for first time. i am trying to do T-test for a sample set
with
three variables. i attached my data set as CSV file.
but when i do t.test(data$Day.1,data$Day.2,var.equal=T) i get this
following error. Can anyone please help e identify the problem.
Error in if
On 12-02-14 10:58 PM, Jooil Kim wrote:
Hello,
I'm wondering if I can get some help with reading Fortran binary unformatted
output files into R.
The Fortran output files were generated in Ubuntu 10.04 LTS using gfortran4.4,
on a 32bit Intel Core 2 Duo 3.16 GHz machine, with little-endian and
Hello everybody,
Can anyone tell me, how to obtain standardized regression coefficients
(betas) for
my independent variables when doing a multiple linear regression?
height-c(180,160,150,170,190,172)
sex-c(1,2,2,1,1,2)
age-c(40,20,30,40,20,25)
fit-lm(height~age+sex)
summary(fit)
I already
It's a bit dangerous to call them betas in this list. Standardized
regression coefficients sounds much better :)
A simple way is to first standardize your variables and then run lm again.
lm(scale(height)~scale(age) + factor(sex))
# or, depending on what you want:
Dear Jim,
Thank you so much, I really apreciate you advice. That was what I was trying to
do so much!!!.
I just wanted to create a new variable depending of these criteria of office
time.
I realize in this issue the function format is good to understand well.
Saludos,
José
Sorry about that -- forgot the case where you might only have a
certain entry once: try this,
sapply(split(GS, rownames(GS)), function(x) colSums(as.matrix(x)))
or
sapply(split(GS, rownames(GS)), function(x) if(is.matrix(x)) colSums(x) else x)
I'm not sure if there's a way to force split to
Blah! Forget that first one -- the second one should be fine. (or at
least, I don't see a problem with it immediately)
sapply(split(GS, rownames(GS)), function(x) if(is.matrix(x)) colSums(x) else x)
Michael
On Wed, Feb 15, 2012 at 7:19 AM, R. Michael Weylandt
michael.weyla...@gmail.com wrote:
Hi David
This should do the trick:
data - cbind(height, sex, age)
data.scaled - data.frame(apply(data, 2, scale))
fit.scaled - lm(height ~ age + sex - 1, data = data.scaled)
summary(fit.scaled)
HTH
Jo
==
Hello everybody,
Dear All,
I have a function that it works in all of data.
dim(data)
24(sample) 2600(variable)
data
[1][2] [3] [4] ... [2600]
[1] 10.73140 9.89450 9.12233 8.33994 9.43412 [2] 10.58010 10.02023 8.69257
8.46640 9.05038 [3] 10.80644 9.59991 8.71311 8.64168
Hi, I am working under R2.11.1 Windows.
I work with a set of parameters which is save under a vector. I think it is
easier to understand, which parameter is called in the vector by naming all
vector elements. For example, we have a vector which the parameters a,b,c,d.
Is it normal to allow, that
Hi,
I wonder if there is a direct interface between R and Cassandra. According
to my searches there isn't.
Has anyone worked with Cassandra?
I would appreciate to know if there is a work-around to the problem.
Thanks
Giuseppe
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View this message in context:
Dear Sir/Madam
it is my the first time in using R-help center.
I would like to know how can I install DEA package on my R program.
moreover, is there any example of using R for calculating Malmquist?
and should I necessarily install DEA package for that reason?
I have some problems in importing my
Hi ,
Thanks for reply
My latitude and longitude contains 9-10 observations per file
when I run coords - expand.grid(lat=1:5,long=1:5) then my computer
*** caught segfault ***
address 0x6951c20, cause 'memory not mapped'
Traceback:
1: .C(spline_eval, z$method, nu = as.integer(n), x
Dear All,
I have a very simple question to which I did not find any
answer online (apologize if it exists).
I have an XML file (attached) on which I just want
to modify the info of a node.
So, I load my xml file:
current = xmlTreeParse(file, useInternalNodes=T)
and I want to change the
Hi All,
This might be simple question, I need to retrive data for modelling from the
databases. Eveytime date values changes so I countnot fix date value in the
code, it is required to pass as parameter.
When I pass the date as parameter, it throws error.
(ERROR: column start_dt does not exist
Dear Sir/Madam,
I am a phd student and I am trying to implement a new approach for the knot
selection procedure in MARS algorithm. In order to apply and test the
efficiency of my method, is it possible to get the code (sourse) of earth
library?
Thank you for your interest and concern.
Best
Hello,
I installed R--2-1.14.1.pkg on mac OS v 10.7.2 and when I wanted to invoke
hist, I got the following error msg:
Error in title(main = main, sub = sub, xlab = xlab, ylab = ylab, ...) :
could not find any X11 fonts
Check that the Font Path is correct.
In addition: Warning messages:
1: In
On Wed, Feb 15, 2012 at 02:13:28PM +0100, Soheila Khodakarim wrote:
Dear All,
I have a function that it works in all of data.
dim(data)
24(sample) 2600(variable)
data
[1][2] [3] [4] ... [2600]
[1] 10.73140 9.89450 9.12233 8.33994 9.43412 [2]
1) The DEA package appears to have been removed from CRAN in 2008, so
it is not likely to be readily available. Old versions are available
from the CRAN archives though but I don't imagine you'll get much
support if you try to use them:
ftp://cran.r-project.org/pub/R/src/contrib/Archive/DEA/
2)
http://cran.r-project.org/web/packages/earth/index.html
Click on package source and have fun.
Michael
2012/2/15 Elçin Kartal kartalel...@gmail.com:
Dear Sir/Madam,
I am a phd student and I am trying to implement a new approach for the knot
selection procedure in MARS algorithm. In order to
Uday, maybe you could have a look at the raster package.
Etienne
2012/2/15 uday uday_143...@hotmail.com
Hi ,
Thanks for reply
My latitude and longitude contains 9-10 observations per file
when I run coords - expand.grid(lat=1:5,long=1:5) then my computer
*** caught segfault ***
On Wed, 15 Feb 2012, carol white wrote:
Hello,
I installed R--2-1.14.1.pkg on mac OS v 10.7.2 and when I wanted to invoke
hist, I got the following error msg:
Error in title(main = main, sub = sub, xlab = xlab, ylab = ylab, ...) :
could not find any X11 fonts
Check that the Font Path is
On Feb 15, 2012, at 7:19 AM, R. Michael Weylandt wrote:
Sorry about that -- forgot the case where you might only have a
certain entry once: try this,
sapply(split(GS, rownames(GS)), function(x) colSums(as.matrix(x)))
or
sapply(split(GS, rownames(GS)), function(x) if(is.matrix(x))
But that's dropping unused factor levels, not the drop of `[`
Michael
On Wed, Feb 15, 2012 at 9:16 AM, David Winsemius dwinsem...@comcast.net wrote:
On Feb 15, 2012, at 7:19 AM, R. Michael Weylandt wrote:
Sorry about that -- forgot the case where you might only have a
certain entry once:
On Wed, Feb 15, 2012 at 7:24 AM, aajit75 aaji...@yahoo.co.in wrote:
Hi All,
This might be simple question, I need to retrive data for modelling from the
databases. Eveytime date values changes so I countnot fix date value in the
code, it is required to pass as parameter.
When I pass the date
On 02/14/2012 11:45 PM, Petr Savicky wrote:
On Wed, Feb 15, 2012 at 02:17:35PM +1000, Redding, Matthew wrote:
Hi All,
I've been trawling through the documentation and listserv archives on this
topic -- but
as yet have not found a solution. I'm sure this is pretty simple with R, but I
Dear community,
I've plotted data and coloured depending on the factor variable v3.
In the legend, I'd like to assign properly the same colors than in the
factor (the factor has 5 levels).
I've been trying this but it doesn't work.
plot(var1, var2, xlab = var1, ylab = var2, col =var3 ,
Hello to everybody !!! I am a student in the Mathematics department of the
university of Milano.
I am interested in an r -package or an available code for fitting two
component mixtures of generalized linear mixed effects models for cluster
correlated data. In particular with normal random
I want to use spplot function for plotting data on wold map
spplot.points(obj, zcol = names(obj), ..., names.attr,
scales = list(draw = FALSE), xlab = NULL, ylab = NULL, aspect =
mapasp(obj,xlim,ylim),
panel = panel.pointsplot, sp.layout = NULL, identify = FALSE, formula,
Gab,
Make sure you have variables for each training.
training - data.frame(Training_2006, AST_L1B_1, AST_L1B_2, AST_L1B_3N)
If you can't do that, then you don't have as many training observations
than you have predictive informations. Make sure to create a line for each
set of predictive pixels
I am completely new to LaTeX and Sweave, so I am trying to follow the
tutorial in the following link:
http://www.r-bloggers.com/using-latex-r-and-sweave-to-create-reports-in-
windows/
I installed MiKTeX 2.9 and TeXnicCenter, but I get a build error when
compiler the example file:
The two errors
s_elternmz - function(Var=balt)
{
Dg_a-mz[,c(asbhh,apkz,Var)]
colnames(Dg_a)[colnames(Dg_a)==apkz]-bpkzm
colnames(Dg_a)[colnames(Dg_a)==Var]-paste(Var,_m,sep=)
mz_int-merge(mz,Dg_a,by=c(asbhh,bpkzm),all.x=T)
colnames(Dg_a)[colnames(Dg_a)==bpkzm]-bpkzv
On Wed, Feb 15, 2012 at 06:27:01AM -0800, Martin Morgan wrote:
On 02/14/2012 11:45 PM, Petr Savicky wrote:
On Wed, Feb 15, 2012 at 02:17:35PM +1000, Redding, Matthew wrote:
Hi All,
I've been trawling through the documentation and listserv archives on
this topic -- but
as yet have not
On 15-02-2012, at 15:27, Martin Morgan wrote:
On 02/14/2012 11:45 PM, Petr Savicky wrote:
On Wed, Feb 15, 2012 at 02:17:35PM +1000, Redding, Matthew wrote:
Hi All,
I've been trawling through the documentation and listserv archives on this
topic -- but
as yet have not found a solution.
Tom Roche Fri, Feb 3, 2012 at 11:16 AM
summary: image.plot-ing two sets of netCDF data, with the second
derived from the first.
Should have noted that the data (atmospheric emissions) in
* the second dataset is heavily positively-skewed. (This leads to a
problem with the legend when
Dear All,
I tried to invoke plot for a matrix of 196475 x2 dimension. I loaded the data
with read.table. On one dimension, there are strings (names) and on the other
dimension, the floats between 0 and 1. When I invoked plot by setting x to
names and y to floats and ylim = c(0,1), I got the
Hi
Hi, I am working under R2.11.1 Windows.
Rather old one, consider upgrading
I work with a set of parameters which is save under a vector. I think it
is
easier to understand, which parameter is called in the vector by naming
all
vector elements. For example, we have a vector which the
Sorry for the error: the first column is of the string type and the second
column of float, respectively.
- Forwarded Message -
From: carol white wht_...@yahoo.com
To: r-h...@stat.math.ethz.ch r-h...@stat.math.ethz.ch
Cc:
Sent: Wednesday, February 15, 2012 4:46 PM
Subject: Error in
Hi,
I am trying to estiamte parameters for gamma distribution using mle for
below data using fitdist fitdistr functions which are from fitdistrplus
MASSpackages . I am getting errors for both functions. Can someone
please let me know how to overcome this issue??
data
y1-
c(256656, 76376,
Hello.
I'm getting an unexpected result when running smooth.spline(). Here is a
simple example that replicates the error I'm getting:
aa - c(1, 2, 3, 8, 8, 8, 8, 8, 8, 8, 8, 8, 12, 13, 14)
bb - 1:length(aa)
plot(aa, bb)
smooth.spline(aa, bb)
Error in smooth.spline(aa, bb) : need at least
Hello!
I'm trying to build a lower triangular matrix (with zeros in the diagonal)
from a particular dataframe.
The matrix I have to construct has 203 rows and 203 columns and that makes
20503 values to be included within (that's why I can't do it manually).
To illustrate the dataframe I have,
Hi all,
I was wondering if there is a function kind of similar that splits a
dataframe, applies a function to each row and returns in a data frame. I
know ddply but this one isn’t useful in this situation.
I have a dataframe with values for each day (rows) for different objects
(columns). I have
Hi Nymphita,
?upper.tri
x - as.data.frame(matrix(1:6,6,6))
x[upper.tri(x,diag=TRUE)] - 0
x
Cheers,
Tsjerk
On Wed, Feb 15, 2012 at 4:33 PM, nymphita nymph...@gmail.com wrote:
Hello!
I'm trying to build a lower triangular matrix (with zeros in the diagonal)
from a particular dataframe.
Thanks for your help. I already considered using list. But as I want to put
some constraints on the entries and the form of the vector, I thought it
would be easier to verify them by using a vector instead of a list.
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Dear Reasearchers,
I am writing a report and i need (and wish) cite R. somebody know the
citation of R for the 2012? or the more actual?
thanks in advance
Gianni
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
Hi gianni,
Type citation() without quotes in the R console. You will get something
like
To cite R in publications use:
R Development Core Team (2011). R: A language and environment for
statistical computing. R Foundation for Statistical Computing, Vienna,
Austria. ISBN 3-900051-07-0,
Typing
citation()
at an R prompt will provide you with complete citation information for
the version of
R you are using. Same goes for packages, with citation(pkgname).
Sarah
On Wed, Feb 15, 2012 at 11:29 AM, gianni lavaredo
gianni.lavar...@gmail.com wrote:
Dear Reasearchers,
I am writing a
Dear all,
I am currently running an experiment using quantile regression. In order to get
more accurate results for a hypothesis test, I need to run a bootstrapping
version of quantile regression and I need to find the estimated covariance
matrix among all the coefficients for several
Dear all,
I am trying to use the integrate function in R but it seems that it does not
work in my example and I cannot figure out why. I create a function Mu1
(which works fine) and try to integrate by the code:
n - 100
Ctrl- as.matrix(cbind(runif(n, -30, 30)))
W
Hi Tsjerk!
Thanks for your quick reply!
It's a nice way to built a lower triangular matrix with zeros in the
diagonal, but what I can't work out is *how to include the values of the
third column of the dataframe inside the matrix*.
I just realized that I forgot to explain something about the
Hi, all,
I am currently trying to learn this example.
http://learnr.wordpress.com/2009/03/17/ggplot2-barplots/
I created the stack bar easily.
If I would like to rank the stack bar from the highest on the right,
shortest on the left and eventually
I could show the data 1991-00 on the left
On 15/02/2012 14:18, Yogs wrote:
Hi,
I am trying to estiamte parameters for gamma distribution using mle for
below data using fitdist fitdistr functions which are from fitdistrplus
MASSpackages . I am getting errors for both functions. Can someone
please let me know how to overcome this
You could use [[ instead of [, as the latter drops
the names. E.g., after
v - c(a=3,a=4,c=5,d=6)
change your
c(n=v[a]+v[c],n1=v[d]*3) # n.a=8 n1.d=18
n.a n1.d
8 18
to
c(n=v[[a]]+v[[c]],n1=v[[d]]*3) # n=8 n1=18
n n1
8 18
Bill Dunlap
Spotfire, TIBCO Software
wdunlap
Sorry, I just realized that it's not a lower triangualr matrix, but an upper
triangular matrix!
But still the solution/s should be rather similar in both cases.
http://r.789695.n4.nabble.com/file/n4391127/matrix2.png
I apologize for creating confusion...
Nymphita
--
View this message in
Typo below, 'latter' - 'former'. namedVector[[i]]
drops the names and namedVector[i] does not.
Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of William Dunlap
Sent:
Perhaps ignore the lower-triangularity for a moment and do something like this:
x - matrix(NA, ncol = max(j), nrow = max(i))
x[i, j] - k
Your code will be clearer if you use with() rather than df$i constructs.
Hope this helps,
Michael
On Wed, Feb 15, 2012 at 11:47 AM, nymphita
Integrate works on functions that are vectorized (i.e., the algorithm
puts in N inputs and expects N outputs) -- your function is not
vectorized (and I'm not sure what integrating it means, but I'm not
looking too closely) but you can make it look vectorized with the
Vectorize() HOF. Note that
On 15.02.2012 17:33, Dimitris.Kapetanakis wrote:
Dear all,
I am trying to use the integrate function in R but it seems that it does not
work in my example and I cannot figure out why. I create a function Mu1
(which works fine) and try to integrate by the code:
n - 100
Ctrl-
On Feb 15, 2012, at 11:47 AM, nymphita wrote:
Hi Tsjerk!
Thanks for your quick reply!
It's a nice way to built a lower triangular matrix with zeros in the
diagonal, but what I can't work out is *how to include the values of
the
third column of the dataframe inside the matrix*.
I just
Sorry
I don't know the citation inside the report is corret
The Analysis was done using a script written in the statistical computing
environment of R (R Development Core Team, 2011)
is It correct the form statistical computing environment ?
Gianni
On Wed, Feb 15, 2012 at 5:38 PM, Sarah
On 15/02/2012 15:00, Nicholas Reich wrote:
Hello.
I'm getting an unexpected result when running smooth.spline(). Here
is a simple example that replicates the error I'm getting:
aa- c(1, 2, 3, 8, 8, 8, 8, 8, 8, 8, 8, 8, 12, 13, 14) bb-
1:length(aa) plot(aa, bb) smooth.spline(aa, bb)
Error in
Inline
On Wed, Feb 15, 2012 at 3:04 AM, uday uday_143...@hotmail.com wrote:
Hi ,
Thanks for reply
My latitude and longitude contains 9-10 observations per file
when I run coords - expand.grid(lat=1:5,long=1:5) then my computer
You don't have to run this part. As your original post
runif's min and max argument may be vectors:
x=c(0,0,0,0,0)
y=c(10,20,30,40,50)
runif(length(y), min=x, max=y)
[1] 7.005180 14.035296 9.388089 22.094211 43.624606
This is equivalent to x + (y-x)*runif(length(y)) but
such a transformation is not always so easy for nonuniform
random
Please read the very last two lines in the footer of your email below.
Regards,
Yihui
--
Yihui Xie xieyi...@gmail.com
Phone: 515-294-2465 Web: http://yihui.name
Department of Statistics, Iowa State University
2215 Snedecor Hall, Ames, IA
On Wed, Feb 15, 2012 at 8:55 AM, Bos, Roger
Dear R-Users,
I'm a R beginner and I have a similar problem:
I fitted a SurvivalTree with rpart and I'm tryng to plot with the partykit
package by the funcion as.party but it sends me this error:
plot(as.party(rpartSurv))
Error in plot.constparty(as.party(rpartSurv)) :
node_surv not yet
Hello,
I'm trying to build a lower triangular matrix (with zeros in the diagonal)
from a particular dataframe.
This example constructs a lower triangular matrix from a vector, not a
data.frame.
(In your example, you also use a vector, the last column of the DF.)
x - runif(15)
y - matrix(0,
Dear list,
The new package 'multivator' is now available on CRAN. This presents
a multivariate generalization of the emulator package.
The corresponding JSS article is:
Robin K. S. Hankin (2012), Introducing multivator: A Multivariate Emulator,
Journal of Statistical Software, 46(8), 1-20.
Dear R Community,
I am happy to introduce the next release of the *dclone* package (see
R Journal, 2(2): 29-37, 2010) which now includes a suite of functions
for parallel computations:
- see functions parJagsModel, parUpdate, parCodaSamples using 'snow'
type clusters; and the
- jags.parfit
Thank you,
Its looking like your package will work for me. I have two questions.
First, how do I rotate the plot 90 degrees so the group labels are on
the x axis and the response value on the y axis?
Second, I'm having trouble with the group labels. I need to order my
groups into meaningful
environment[[names[j]]][i]-I does seem to take longer than
environment$name[i]-I when looping over the length of the
vector involved. Using a list instead of an environment seems
to work better.
Below are 4 functions that populate a data.frame row by row.
f0 : the naïve approach
f1 : use 3
Greetings,
Any suggestions for approaching the fitting of the function
y = b/exp(a*x) + c*x + y0
where a, b, c, and y0 are unknown constants and y and x are variables in a
give dataset.
Thanks
Tony
[[alternative HTML version deleted]]
Hi Tony,
?nls
Cheers,
Tsjerk
On Feb 15, 2012 8:03 PM, Anthony Fristachi antak...@gmail.com wrote:
Greetings,
Any suggestions for approaching the fitting of the function
y = b/exp(a*x) + c*x + y0
where a, b, c, and y0 are unknown constants and y and x are variables in a
give dataset.
Dear All,
I am using package fPortfolio to run minimum variance portfolio
optimizations in R. I already know how to set portfolioSpecs, portfolio
objects and constraints. Unfortunately I am not able to set the following
type of constraints.
I have a timeSeries object with returns data for
On Wed, 15 Feb 2012, dlofaro wrote:
Dear R-Users,
I'm a R beginner and I have a similar problem:
I fitted a SurvivalTree with rpart and I'm tryng to plot with the partykit
package by the funcion as.party but it sends me this error:
plot(as.party(rpartSurv))
Error in
First, in R there is no need to declare the dimensions of your objects
before they are populated so couldn't you reduce some run time by not
going through the double data.frame step ?
df- data.frame()
df
data frame with 0 columns and 0 rows
for(i in 1:100) for(j in 1:3) df[i,j]- runif(1)
I have some data set which is available from 2005-2010 . I would like plot
monthly maps out of it.
So how I should write loop that can plot this yearly data to for every month
and write title for individual months too.
--
View this message in context:
On Feb 15, 2012, at 15:17 , R. Michael Weylandt wrote:
But that's dropping unused factor levels, not the drop of `[`
Is there a good reason that nobody has suggested looking at aggregate()? There
would seem to be a little red tape to sort out, but, I mean, this is generally
speaking what
. you don't really consider this a well formed question do you?
(Among others:)
http://stackoverflow.com/questions/5963269/how-to-make-a-great-r-reproducible-example
http://www.gerv.net/hacking/how-to-ask-good-questions/
What immediately comes to mind:
i) Plotting engine? (base, lattice, or
Hey,
I keep getting the following warning:
data(GSE19829-GPL570_eset)
Warning in data(GSE19829 - GPL570_eset) :
data set GSE19829 - GPL570_eset not found
## maybe str(GSE19829-GPL570_eset) ; plot(GSE19829-GPL570_eset) ...
if(require(affy)){
+ summary(GSE19829-GPL570_eset$vital_status)
I'm not sure what the official description of R is beyond that given
in citation(), but the R FAQ gives this: [R] consists of a language
plus a run-time environment. Part of R's personality, as far as I can
tell, comes from the fact it straddles the general purpose
language/domain specific
Greetings,
I am creating a standalone executable script using Rscript and have run
into problems when I define a new S4 class. Here is a small script that
demonstrates my problem:
#!/usr/bin/env Rscript
#
# toy.Rscript -- testing S4 class creation in an Rscript
setClass(toy,
Hello List !
I'm a bright new R user, and I encounter a problem when trying to use the
neuralnet package.
I have a training set with 8 inputs, and there are 3 outputs (I need 3 distinct
neurones as output). Although I read the examples, and the package article, I
don't know how to tell R
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