On Fri, Feb 24, 2012 at 01:00:00PM +0530, Apoorva Gupta wrote:
Dear R users,
I have a data.frame as follows
a b c d e
[1,] 1 1 1 0 0
[2,] 1 1 0 0 0
[3,] 1 1 0 0 0
[4,] 0 1 1 1 1
[5,] 0 1 1 1 1
[6,] 1 1 1 1 1
[7,] 1 1 1 0 1
[8,] 1 1 1 0 1
[9,] 1 1 1 0 0
[10,] 1 1 1 0
On 24-02-2012, at 08:30, Apoorva Gupta wrote:
Dear R users,
I have a data.frame as follows
a b c d e
[1,] 1 1 1 0 0
[2,] 1 1 0 0 0
[3,] 1 1 0 0 0
[4,] 0 1 1 1 1
[5,] 0 1 1 1 1
[6,] 1 1 1 1 1
[7,] 1 1 1 0 1
[8,] 1 1 1 0 1
[9,] 1 1 1 0 0
[10,] 1 1 1 0 0
Within these 4
Ok. So I'm a little closer to figuring this thing out. I didn't realize I
needed to run the javareconf command as root like so.
sudo R CMD javareconf
JAVA_CPPFLAGS=-I/System/Library/Frameworks/JavaVM.framework/Headers
I'm not getting the permission issue anymore but I'm still getting the
Hi All,
I am asking for some clarification on R package documentation.
The Writing R extension manual did not make this clear for me
the following:
1. How to document a dataset? I know the file format from the
doc, but I cannot figure out what file to put that info in.
I keep getting
Hello, I am using R 2.11.1 under Windows XP.
I would like to know if its possible to use a function with arguments as a
command in tcl tk. For example
require(tcltk)
PressedOK - function()
{
tkmessageBox(message=You pressed OK!)
}
tt - tktoplevel()
OK.but -
One line of the RServe documentation (for Java, which I do not know) is:
Rconnection c = new Rconnection();
1. Is Rserve a COM or ActiveX object? If affirmative, what is the ProgId (or
clsid)?
2. If Rserve is not an ActiveX Object, does Java (like C#) require a reference
to the EXE or DLL
Try RSiteSearch(Venn diagram)
-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of Guang Dai
Sent: 23 February 2012 22:30
To: r-help@r-project.org
Subject: [R] how to draw crossing circles to show relationship?
Dear list,
THANKS a lot Tad!
It is just what I needed to calculate cosine similarities on my matrix.
Best,
AJ
Date: Thu, 23 Feb 2012 12:14:43 -0800
From: tad.dal...@drakeresearchlab.com
To: r-help@r-project.org
Subject: Re: [R] Problems with Cosine Similarity using library(lsa)
The as.matrix
On 02/24/2012 09:30 AM, Laura Matrajt wrote:
Hi,
I found some weird behavior of the function multhist in the plotrix package
and I would like to ask you about it:
so, it works well to put two histograms next to each other, but I don't
understand the breaks…
so for example,
library(plotrix)
Hi Michael,
thanks a lot for the additional tips! So far it all has worked!
Marion
2012/2/17 Marion Wenty marion.we...@gmail.com
Hi Michael and Rui,
thanks a lot for the tips.
It worked with both your suggestions!
I also found out, that this problem only exists if I put header=T.
Thanks
Hello,
from a vector of strings I want to delete everything after the _
v - c(AAA_BB, FF_MM)
gsub(_*, , v)
[1] AAABB FFMM
but should be
[1] AAA FF
Why does * not work? Even perl=TRUE does not give me the right result
Man thanks!
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On 24-02-2012, at 12:48, syrvn wrote:
Hello,
from a vector of strings I want to delete everything after the _
v - c(AAA_BB, FF_MM)
gsub(_*, , v)
[1] AAABB FFMM
but should be
[1] AAA FF
Why does * not work? Even perl=TRUE does not give me the right result
gsub(_.*$, , v)
cool that works! thanks a lot :)
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Sent from the R help mailing list archive at Nabble.com.
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Hi,
On Friday, February 24, 2012 02:52:32 AM Matyas Sustik wrote:
Hi All,
I am asking for some clarification on R package documentation.
The Writing R extension manual did not make this clear for me
the following:
1. How to document a dataset? I know the file format from the
doc, but I
On Fri, 24 Feb 2012, Xiong Deng wrote:
Hi,
I tried to use the given rsync command to make the mirror twice. However, both
failed,
showing:
rsync: read error: Connection reset by peer (104)
rsync error: error in rsync protocol data stream (code 12) at io.c(515)
rsync: connection unexpectedly
Hi Uday,
You could try to include 'write.table' in your loop and use paste to save
every file separately like this:
for ( i in 1:100) {
data- read.table(file_s[i],header=TRUE,skip=55 )
latitude [i] - data[,6]
longitude[i] - data[,7]
time[i]- data[,8]
temp[i ] -
Here is the two functions which I have used during my practice.
*plot(Telco.rpart.METHOD.CLASS,compress=FALSE,uniform=TRUE)
text(Telco.rpart.METHOD.CLASS,use.n = TRUE, cex = .75))*
Telco.rpart.METHOD.CLASS is my rpart object of the method class.
If I run this,
*Telco.Rpart.PLOT.TEXT -
hi Simon
this follows on from the example where gcv increased unexpectedly with
increasing basis dimension. I'm now looking at t2 tensor splines with
REML, and find that the REML score can increase when adding a new
predictor. Again, this seems odd.
thanks
Greg
library(mgcv)
set.seed(0)
hello,
I think my EBImage is succesfully unpacked using R and I receive this
message
package 'EBImage' successfully unpacked and MD5 sums checked
The downloaded packages are in
C:\Users\Yana-Chan\AppData\Local\Temp\Rtmp7VFmH5\downloaded_packages
but when I try to call the library, I
Dear
I am analysing my data wit a mixed model. I used SAS but I want to redo the
same analysis in R. Here the SAS code and what I wrote in R. It seems to
work but the results are not the same. I don't know how to specify the class
variable in R or specify the variance matrix. Can you please help
Hi,
I tried to use the given rsync command to make the mirror twice. However,
both failed, showing:
rsync: read error: Connection reset by peer (104)
rsync error: error in rsync protocol data stream (code 12) at io.c(515)
rsync: connection unexpectedly closed (112150 bytes received so far)
At 07:02 24/02/2012, Kawthar Alajmi wrote:
Hi all,
I am running Stepwise logistic regression and i have :
1- Multiple covatiates included in each model (No missing data)
So there is no missing data on any covariate?
2- Genotype data (SNPs) about 500,000 .
I partitioned the data to multiple
I believe this is what you want to do, though it may need tweaking.
#Make up some data
a=seq(1,100,by=1)
b=runif(100,0,0.5)
#Make a matrix
matrix=cbind(a,b)
#Subset the matrix based upon values of interest
subsetmatrix=matrix[which(b0.1),]
#Plot values
begin included message ---
I have a coxph model like
coxph(Surv(start, stop, censor) ~ x + y, mydata)
I would like to calculate the Schoenfeld residuals for the null, i.e the
same model where the beta hat vector (in practical terms, the coeff
vector spat out by summary()) is constrained to
Thank you!! Using lm.fit did the trick.
2012/2/23 R. Michael Weylandt michael.weyla...@gmail.com
It looks like what you are doing is reasonably efficient: I do think
there's a residuals element to the object returned by lm() so you
could just call that directly (which will be just a little
You have three problems:
1) You don't post with context
2) You have a (likely OS permissions) issue that keeps you from
accessing the RData file
3) You can't put a whole bunch of data in a single element of an
object (ie., you are trying to put a column of data in a single
element of an object:
On Fri, 24 Feb 2012, diyanah wrote:
hello,
I think my EBImage is succesfully unpacked using R and I receive this
message
On Windows it seems, but EBImage is a Bioconductor package and they
have their own lists.
package 'EBImage' successfully unpacked and MD5 sums checked
The downloaded
jurgen_vercauteren jurgen_vercauteren at hotmail.com writes:
I am analysing my data wit a mixed model. I used SAS but I want to redo the
same analysis in R. Here the SAS code and what I wrote in R. It seems to
work but the results are not the same. I don't know how to specify the class
Inline:
On Thu, Feb 23, 2012 at 8:23 PM, R. Michael Weylandt
michael.weyla...@gmail.com michael.weyla...@gmail.com wrote:
Inline:
On Feb 23, 2012, at 6:20 PM, kosmo7 dnico...@hotmail.com wrote:
Dear Elai,
thank you very much for your suggestion. I tried cutting the dendrogram
instead of
Dear list,
n00b question, but still can't find any easy answer.
Here is a df:
df-data.frame(cbind(x=c(AA,BB,CC,AA),y=1:4))
df
x y
1 AA 1
2 BB 2
3 CC 3
4 AA 4
I want to modify this df this way :
if df$x==AA then df$y=df$y*10
if df$x==BB then df$y=df$y*25
and so on with other
Ok this makes a lot of sense, thank you very much Ilai!
Cheers
Guillermo
On Fri, Feb 24, 2012 at 12:16 AM, ilai ke...@math.montana.edu wrote:
On Thu, Feb 23, 2012 at 8:32 PM, Adan Jordan-Garza
ajordangarza2...@my.fit.edu wrote:
Hello Ilai,
thank you very much for your response,
can I
0. Read the posting guide! It tells you to
1. Do not cross post!
2. Do try a recent version of R and all packages you have in use.
3. If it still fails, send a reproducible example.
Uwe Ligges
On 23.02.2012 18:04, Matthew Keller wrote:
Hi all,
I'm trying to use the package read.table
On 24.02.2012 16:25, Arnaud Gaboury wrote:
Dear list,
n00b question, but still can't find any easy answer.
Here is a df:
Change
df-data.frame(cbind(x=c(AA,BB,CC,AA),y=1:4))
to
df - data.frame(x = c(AA,BB,CC,AA), y = 1:4)
to make your object a sensible data.frame.
df
x y
1
On 24.02.2012 12:22, Yashwanth M.R wrote:
Here is the two functions which I have used during my practice.
*plot(Telco.rpart.METHOD.CLASS,compress=FALSE,uniform=TRUE)
text(Telco.rpart.METHOD.CLASS,use.n = TRUE, cex = .75))*
Telco.rpart.METHOD.CLASS is my rpart object of the method class.
If
Ohh! about the reference code for the categorical predictor,
from the McCarthy book, Bayesian Methods for Ecology
(ISBN978-0-521-85057-5) the following ANCOVA model has a Refuge as a
categorical predictor with 3 levels coded as 1, 2 and 3.
This is the cited model:
model
{
a ~ dnorm(1.01, 24.826)
* peter dalgaard cqn...@tznvy.pbz [2012-02-24 08:41:07 +0100]:
On Feb 24, 2012, at 06:58 , Sam Steingold wrote:
batch is a vector of lines returned by readLines from a
NL-line-terminated file, here is the relevant section:
=
AA BB
TY Uwe,
So I will have to write a line for each condition? Right?
In fact I was trying to do something with apply in one line, but couldn't
achieve any result. In fact, all my transformation will be multiplying one
object by a specific number according to the value of df$x.
Arnaud Gaboury
On 24.02.2012 16:59, Arnaud Gaboury wrote:
TY Uwe,
So I will have to write a line for each condition? Right?
In fact I was trying to do something with apply in one line, but couldn't
achieve any result. In fact, all my transformation will be multiplying one
object by a specific number
Ok, I was able to work it out finally.
As I have been aided myself numerous times from posted questions by other
users who have reached in the end a solution to their problem, I will put
the code that worked for me for future googlers - it is certainly not
optimal but it works:
# Initial
Dear list,
n00b question, but still can't find any easy answer.
Here is a df:
df-data.frame(cbind(x=c(AA,BB,CC,AA),y=1:4))
df
x y
1 AA 1
2 BB 2
3 CC 3
4 AA 4
I want to modify this df this way :
if df$x==AA then df$y=df$y*10
if df$x==BB then df$y=df$y*25
and so on with other
This is in a 64 bit CentOS 5.6 instance at Amazon AWS with R version
2.14.1 (2011-12-22). It happens on several packages: RMySQL, RODBC,
FastICA. Many other packages install just fine.
Here's an example error message:
* installing *source* package 'RODBC' ...
** package 'RODBC' successfully
Hey Guys,
i want the degrees of freedom of the student-t distribution to be given out.
Since, i only get the shape parameter, i wanted to ask for help.
On one side i found the same parameter being used for the shape parameter
and df. But df of a std. aren´t allowed to equal decimal numbers!?
I sent it to you and the list, as is standard practice.
You must know in advance what level of your factor goes with what multiplicand.
Use that information to set up the association. The order within your data frame
is irrelevant, only the order R uses for factor levels is of importance.
Sarah
df- data.frame(x = c(AA,BB,CC,AA,DD,DD), y = 1:6)
mult - c(AA = 10, BB = 25,DD=15)
df$y - df$y * mult[df$x]
df
x y
1 AA 10
2 BB 50
3 CC 45
4 AA 40
5 DD NA
6 DD NA
My df is in fact much more longer than the chosen example shown here. It seems
your tip didn't do the job.
I am expecting
On 24.02.2012 17:36, Arnaud Gaboury wrote:
df- data.frame(x = c(AA,BB,CC,AA,DD,DD), y = 1:6)
mult- c(AA = 10, BB = 25,DD=15)
df$y- df$y * mult[df$x]
df
x y
1 AA 10
2 BB 50
3 CC 45
4 AA 40
5 DD NA
6 DD NA
My df is in fact much more longer than the chosen example shown here. It seems
You need, as I already suggested, to use a value of 1 for levels you don't want
to change.
mult - c(AA = 10, BB = 25, CC=1, DD=15)
mult[df$x]
AA BB CC AA DD DD
10 25 1 10 15 15
df$y * mult[df$x]
AA BB CC AA DD DD
10 50 3 40 75 90
On Fri, Feb 24, 2012 at 11:36 AM, Arnaud Gaboury
Dear R users, I am trying to use apply function on a 3D array (get rid of any
loop) but wasn't successfull. Below is a toy example of what I am trying to do:
refID_remNoCat = 1:30;
s_remNoCat = sample(1:length(refID_remNoCat),size=length(refID_remNoCat));
s.sort_remNoCat =
OK Uwe, I understand, and I will be more explicit.
Here is how could my df be:
reported -
structure(list(Product = structure(c(1L, 2L, 2L, 2L, 3L, 3L,
3L, 3L, 3L, 3L, 3L, 4L, 5L, 5L, 5L, 6L, 7L, 7L, 8L, 8L, 9L, 9L,
9L, 9L, 9L, 9L, 9L, 9L, 10L, 10L, 11L, 11L, 11L, 11L, 11L, 11L,
11L, 12L, 12L,
Hi Michael,
something like the following might be a starting point for aggregating
data using arbitrary lists of functions:
(it is lacking a method for data.frame objects)
maggregate-function(...)UseMethod(maggregate)
maggregate.default-function(x, FUN, ...){
My apologies to R-list members, this discussion diverged and is no
longer R related. Probably more fitting in one of the BUGS forums, but
I keep cc ing for any future interested reader that stumbled upon this
post in r-help.
Now to the point. Thank you so much for the reference, I was not aware
A different approach to this problem is via convolutional filtering.
f - function (x, pattern, tolerance = 1e-05)
{
# x is a numeric matrix (or vector or data.frame) of data, pattern is
# a vector. This returns the number of times the pattern is found
# in each column of x.
TY very much Sarah: your tip is doing the job:
reported -
structure(list(Product = structure(c(1L, 2L, 2L, 2L, 3L, 3L,
3L, 3L, 3L, 3L, 3L, 4L, 5L, 5L, 5L, 6L, 7L, 7L, 8L, 8L, 9L, 9L,
9L, 9L, 9L, 9L, 9L, 9L, 10L, 10L, 11L, 11L, 11L, 11L, 11L, 11L,
11L, 12L, 12L, 13L, 14L, 14L), .Label = c(CL,
Use mult[as.character(df$x)] instead of mult[df$x].
They are different when df$x is a factor and the
character version is what you want.
df- data.frame(x = c(AA,BB,CC,AA,DD,DD), y = 1:6)
mult - c(AA = 10, BB = 25,DD=15)
df$y - df$y * mult[as.character(df$x)]
df
x y
1 AA 10
2
On Fri, Feb 24, 2012 at 12:23 PM, William Dunlap wdun...@tibco.com wrote:
Use mult[as.character(df$x)] instead of mult[df$x].
They are different when df$x is a factor and the
character version is what you want.
R will coerce a factor to character to perform the comparison; explicitly
calling
Thanks for the suggestion, Tad, but that's not quite it. That is still taking a
subset of the whole data set, so I am losing some of the x(Window) values. I
need to be able to retain all of the x values (column a in your example), but
not plot any points above. Maybe I need to construct a blank
In fact I need to use William tip: Use mult[as.character(df$x)] instead of
mult[df$x].
Let's try again with a shorter df as example:
The rule: if AA, then multiply y by 2, if BB multiply y by 5, if CC do nothing,
if DD multiply by 2.
Let's say day 1 I have df1:
df1 -
structure(list(x =
Whatever makes you happy.
df1 -
+ structure(list(x = structure(c(1L, 2L, 2L, 3L), .Label = c(AA,
+ BB, CC), class = factor), y = 1:4), .Names = c(x, y
+ ), row.names = c(NA, -4L), class = data.frame)
mult - c(AA=2,BB=5,CC=1,DD=2)
df1$y * mult[df1$x]
AA BB BB CC
2 10 15 4
df1$y *
On 24/02/2012 15:22, Rob Steele wrote:
This is in a 64 bit CentOS 5.6 instance at Amazon AWS with R version
2.14.1 (2011-12-22). It happens on several packages: RMySQL, RODBC,
FastICA. Many other packages install just fine.
Your subject line cannot be really true: R CMD check calls R CMD
When a factor is used as a subscript it is treated
as its integer codes so explicit conversion to character
is needed if you want to subscript by names:
f - factor(c(One,Three,Two), levels=c(One,Two,Three))
x - c(Two=2, One=1, Three=3)
x[f]
Two Three One
2 3 1
Thanks again for your help. I did indeed solve the problem by plotting the
initial graph as type='n', then adding my subset of points using 'points'.
Cheers,
--Kelly V.
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of Dallas
Sent:
Dear R-Users,
I've recently used relsurv package for relative survival analysis. In
particular I've tried to reproduce the examples proposed in the R-documentation
about rsadd, rsmul and rstrans functions in R latest version (R 2.14.1). These
examples don't run and the error message is always
Hi,
I have R code like so:
num.columns.back.since.last.occurence - function(m, outcome) {
nrows - dim(m)[1];
ncols - dim(m)[2];
res - matrix(rep.int(0, nrows*ncols), nrow=nrows);
for(row in 1:nrows) {
for(col in 2:ncols) {
The first item in @ y.values is a NaN
Slot y.values:
[[1]]
[1] NaN 1.000
How do replace it with 1.00 or otherwise get rid of it?
Chet
[[alternative HTML version deleted]]
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Hi Iris,
thanks for reply
but this solution does not work
Uday
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Hi,
I am very new to R and I am trying to write KML files. I am running R-2.13.1
and I have the following packages:
- AKIMA
- RGDAL
- RSAGA
- SP
I was trying to run the simple example that I found at the following web page:
Dear R-help,
The Division of Statistics + Scientific Computation at The University of
Texas at Austin will be hosting the University¹s fifth annual UT Summer
Statistics Institute on the UT Austin campus from May 21 May 24, 2012.
Short courses are offered at all levels including introductory
I want to create r object from my data set.
I have several data files and I would like to read individual parameter
from file and save all 10 files parameter in a single array
e.g
setwd(/temp/)
file_s - list.files(path = ., pattern = 0b.was, all.files = FALSE,
full.names =
Hi,
Does anybody know why get I this kind of strange situation:
Browse[2] hcEnd
[1] 2009-03-29 06:30:00
Browse[2] class(hcEnd)
[1] POSIXlt POSIXt
Browse[2] is.na(hcEnd)
[1] TRUE
This issue is the source of my all issues in my program,
Thanks for your help
--
View this message in context:
Okay. I think I understand now. You would just like nothing to be plotted for
the points below a certain threshold but there will still be that space
indexing where the point would've gone. I hope I have this right.
So what you could do to fix that is to make a new matrix (still including
all
Hi all,
At first I will explain my linear mixed effects model;
lme1 - lme(leaf_length ~
Treatment*Genotype*leaf,random=~Treatment|Set,data=data)
or
lmer1 - lmer(leaf~Treatment*Genotype*leaf+(Treatment|Set),data=data)
Treatment factor has two conditions: mock (=Mo) and treatment(=Tr)
Leaf is
Can you dput(hcEnd) and give a snippet of the code that generates it?
Michael
On Feb 24, 2012, at 12:57 PM, ikuzar raz...@hotmail.fr wrote:
Hi,
Does anybody know why get I this kind of strange situation:
Browse[2] hcEnd
[1] 2009-03-29 06:30:00
Browse[2] class(hcEnd)
[1] POSIXlt POSIXt
Does anybody know why get I this kind of strange situation:
Browse[2] hcEnd
[1] 2009-03-29 06:30:00
Browse[2] class(hcEnd)
[1] POSIXlt POSIXt
Browse[2] is.na(hcEnd)
[1] TRUE
pp-as.POSIXlt(2009-03-29 06:30:00)
pp
[1] 2009-03-29 06:30:00
class(pp)
[1] POSIXlt POSIXt
is.na(pp)
[1] FALSE
What version of R are you using. Here is the results with 2.14.1 under
Windows:
x - as.POSIXlt(2009-03-29 06:30:00)
x
[1] 2009-03-29 06:30:00
class(x)
[1] POSIXlt POSIXt
is.na(x)
[1] FALSE
On Fri, Feb 24, 2012 at 12:57 PM, ikuzar raz...@hotmail.fr wrote:
Hi,
Does anybody know why get
I am trying to install rJava on a WUBI Ubuntu 11.10 installation of R with no
luck. I was originally trying to install the iplots package and encountered
this rJava problem.
Code used:
install.packages(rJava)
(CRAN mirrors --Canada(ON) and Canada(QC2)
I installed iplots with no problem on
On Fri, Feb 24, 2012 at 12:58 AM, Alexander juschitz_alexan...@yahoo.de wrote:
I would like to know if its possible to use a function with arguments as a
command in tcl tk.
Yes
snip
I think
this is due to the fact that the PressedOK(3) was the last call of the
function, but I don't
On Fri, Feb 24, 2012 at 08:59:44AM -0800, robertfeldt wrote:
Hi,
I have R code like so:
num.columns.back.since.last.occurence - function(m, outcome) {
nrows - dim(m)[1];
ncols - dim(m)[2];
res - matrix(rep.int(0, nrows*ncols), nrow=nrows);
for(row in 1:nrows) {
That's it! I was mounting /tmp with the noexec option. That was the
problem. Thanks!
On 2/24/2012 12:56 PM, Prof Brian Ripley wrote:
Guess: did you set TMPDIR to somewhere you are allowed to execute
scripts?
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Ok so my problem is I am running a shell command to copy certain file types
from one directory to another and it returns multiple errors
the code is
models=c(1sFE1cFE,1sFE1cFEp)
for(m in 1:length(models)){
shell(paste(robocopy C:\\Sim_Test_1\\Sim,models[m], ,
As a Linux user, I know you are not running exactly the same Java as on
windows. It exists some copyright issues which prevent you to run Sun Java on
your Linux box.
As shown, you are running in fact openJDK. If result is the same for you, being
able to run Java, it is not the same for most
On 24/02/2012 16:30, Annalisa Orenti wrote:
Dear R-Users,
I've recently used relsurv package for relative survival analysis. In
particular I've tried to reproduce the examples proposed in the R-documentation
about rsadd, rsmul and rstrans functions in R latest version (R 2.14.1). These
On Fri, Feb 24, 2012 at 08:59:44AM -0800, robertfeldt wrote:
Hi,
I have R code like so:
num.columns.back.since.last.occurence - function(m, outcome) {
nrows - dim(m)[1];
ncols - dim(m)[2];
res - matrix(rep.int(0, nrows*ncols), nrow=nrows);
for(row in 1:nrows) {
Hi Jim,
thanks for your reply, I will try using this instead!
best,
Laura
On Feb 24, 2012, at 3:09 AM, Jim Lemon wrote:
On 02/24/2012 09:30 AM, Laura Matrajt wrote:
Hi,
I found some weird behavior of the function multhist in the plotrix package
and I would like to ask you about it:
On Fri, Feb 24, 2012 at 8:11 AM, A2CT2 Trading trad...@a2ct2.com wrote:
Dear list,
n00b question, but still can't find any easy answer.
Here is a df:
df-data.frame(cbind(x=c(AA,BB,CC,AA),y=1:4))
# No, your y is a factor
str(df)
'data.frame': 4 obs. of 2 variables:
$ x: Factor w/ 3
On Fri, Feb 24, 2012 at 09:48:16AM -0800, uday wrote:
I want to create r object from my data set.
I have several data files and I would like to read individual parameter
from file and save all 10 files parameter in a single array
e.g
setwd(/temp/)
file_s - list.files(path = ., pattern =
TY Elai for your answer. One solution has been given earlier in this list by
Sarah Goslee and William Dunlap.
Arnaud Gaboury
A2CT2 Ltd.
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of ilai
Sent: vendredi 24 février 2012 20:14
Ahh, I see it now.
For some reason your original post popped up on the list again, could
be just my mail server, sorry.
Looks like Uwe gave you the same solution (in two lines for better
clarity) right away. Depending on your level of noobiness, my advice
would have been to ignore everything after
On 24-02-2012, at 20:02, Petr Savicky wrote:
On Fri, Feb 24, 2012 at 08:59:44AM -0800, robertfeldt wrote:
Hi,
I have R code like so:
num.columns.back.since.last.occurence - function(m, outcome) {
nrows - dim(m)[1];
ncols - dim(m)[2];
res - matrix(rep.int(0,
Hi
I need a phi restriction in my code. That is 0phi1
How can I do that ?
Linn=function(param){
phi=param[1]
sigw=param[2]
sigv=param[3]
Betam=param[4]
kf=kfilter1(n,st[,k],st[,1],0,1,phi,Betam,sigw,sigv)
return(kf$like)
}
init.par-c(1,1,1,1)
estimate-
Also it copies the files, but I am using this as part of a larger code block
and concerned the errors will kill the loop
--
View this message in context:
http://r.789695.n4.nabble.com/shell-command-with-Robocopy-error-tp4418254p4418345.html
Sent from the R help mailing list archive at
I have one data frame, like below：
kindxy
11 8 9
21443
31257
41 36 20
52 2 14
62 36 20
so, I want to find unique coordinates in
Hello,
I've noticed that SPLUS seems to have a function for evaluating derivative
matrices of splines. I've found the R function that evaluates matrices from
'smooth.spline'; maybe someone has written something to do the same with
smooth.basis?
regards,
s
Dear Forum,
I have installed and used various Weka functions in R - both already
available interfaces or created ones via make_Weka_classifier - without any
trouble. However, the RBFNetwork (RBF Neural Network) function is one that I
have not been able to call. I tried creating the R interface
Hello,
I've noticed that SPLUS has a function for evaluating the derivative matrices
of splines.
I've also noticed that there's a function in R for evaluating matrices from
smooth.spline;
maybe someone knows if something has been written to evaluate matrices from
'smooth.basis'?
regards,
s
On Fri, Feb 24, 2012 at 09:06:28PM +0100, Berend Hasselman wrote:
[...]
I've done some speed tests.
t1 - function(m, outcome) {
nrows - dim(m)[1]
ncols - dim(m)[2]
res - matrix(rep.int(0, nrows*ncols), nrow=nrows)
for(row in 1:nrows) {
for(col in
I don't know about smooth.spline, but the fda package
includes deriv.fd. It also includes eval.fd and predict.fd. If
you only want a first derivative, then differentiating a standard cubic
spline may be adequate. However, the first derivative of a cubic spline
is a quadratic spline,
On Fri, Feb 24, 2012 at 12:18 PM, nserdar snes1...@hotmail.com wrote:
Hi
I need a phi restriction in my code. That is 0phi1
How can I do that ?
init.par-c(1,1,1,1)
estimate- optim(init.par,Linn,gr=NULL,method= BFGS, hessian=FALSE,control
= list(trace=1))
You want method L-BFGS-B not
On Fri, Feb 24, 2012 at 09:06:28PM +0100, Berend Hasselman wrote:
[...]
Summary of results
Nrow - 100
Ncol - 1000
A - matrix((runif(Ncol*Nrow)0.2)+0, nrow=Nrow)
print(rbind(z1,z2,z3,z4,z5,z6))
user.self sys.self elapsed user.child sys.child
z1 0.5430.005 0.551 0
?ks.test
?qqplot
also look at permutation tests and possibly the vis.test function in
the TeachingDemos package.
Note that with all of these large samples may give you power to detect
meaningless differences and small samples may not have enough power to
detect potentially important differences.
Dear R-list,
I am trying to import (all) frames from a Microsoft Access database as
individual data frames in a fancy loop, but I'm having troubles figuring out
how to use the 'sqlFetch' from the RODBS package in a loop (mostly because I
can't figure out how to loop over elements (I came from
Hello,
I want to create 10 dataframe using a for loop.
I don t know what to do to create 10 different dataframes whose name is
parametrized with variable i.
This syntaxe fails. It create a unique fataframe called dfn.
Any input will help
Thanks
for (i in 1:10){
+ filename=paste(avail4,i,sep =
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