On Sun, Feb 26, 2012 at 11:39:01AM -0800, mari681 wrote:
SORRY!
The data in MyTable are tagsets of photos, like this:
V1 V2 V3 V4 V5 V6V7 V8
230green nailpolish barrym 0 00 00
231 ny green
Dear R buddies,
Recently, I attempt to model the US/RMB Exchange rate log-return time series
with a *Hidden Markov model (first order Markov Chain mixed Normal
distributions). *
I have applied the RHmm package to accomplish this task, but the results are
not so satisfying.
So, I would like to
Dear all,
Newbie: What is the fastest way to combine all columns of a matrix to one
column?
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Hi,
The work around this is to use printRandomForests function in Rattle
package. It outputs the forest in the form of rules.
For ex:
#Load libraries
library(rattle)
library(randomForest)
#Load sample data
data(iris)
#Build a forest
iris.rf - randomForest(Species ~ ., data=iris,
Dear all, I was trying to fit a GLM on the following data (this data was
taken from Agresti):
Dat - matrix(c(24, 1355, 35, 603, 21, 192, 30, 224), 4, byrow = TRUE)
Here the 1st column denotes the success and the second column is for
failure. We have 4 rows represeting the 4 states of some
Hi
SORRY!
The data in MyTable are tagsets of photos, like this:
V1 V2 V3 V4 V5 V6V7 V8
230green nailpolish barrym 0 00 00
231 ny green brooklyn cleanup clean gowanus volunteer gcc
232
Hi
Dear all,
Newbie: What is the fastest way to combine all columns of a matrix to
one
column?
If mm is your matrix use
dim(mm) -NULL
Regards
Petr
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Hi Elai and Peter,
thanks a lot for your suggestions. I am still reading your answers, but I
didn't get at the begining the difference between
c-NULL
for (i in seq(3)) c[[i]]-i
c
and the exempel with the tcl tk buttons. Now I think, it is clear. Its due
to the interaction between R and tcl. The
Dear James,
Although designed for the analysis of copy number CGH microarrays, RJaCGH
uses a Bayesian HMM model.
Cheers,
Oscar
On 27/2/12 08:32, monkeylan lanjin...@yahoo.com.cn wrote:
Dear R buddies,
Recently, I attempt to model the US/RMB Exchange rate log-return time series
with a
Le lundi 27 février 2012 à 10:47 +1100, Sachinthaka Abeywardana a
écrit :
Hi all,
I am trying to do some text mining with twitter and I am getting the error:
Error in structure(names(sapply(possibleCompletions, [, 1)), names = x) :
'names' attribute [1] must be the same length as the
Hi
Hi,
Thank you. I actually wanted to reserve the rows, I dont know how to
do this with
dim(mm) -NULL
I do not understand. What does it mean reserve rows. Matrix is a vector
with dimension so you can change dimensions freely with
dim(mm) - any suitable combination
dim(mm) -NULL
gives
what does 'str' of the object show? are the columns factors/characters? does
the comparison have to consider the date?
Sent from my iPad
On Feb 27, 2012, at 0:37, Edgar Alminar eaalmi...@ucsd.edu wrote:
Oh, haha -- sorry for the vagueness:
I was expecting to get the comparison to work.
Steven, sorry for the delay in responding,
I have been investigating this also and here is the way I do it (though
probably not the best way):
# .. define a 3D array
ngen = 904
gratios - ff(NA, dim=rep(ngen,3), vmode=double)
# .. fill the array with standard R functions
ffsave (gratios,
Hello,
I have a CSV file with region codes listed in a column. E.g. 'AS' for Asia,
'AU' for Australia and 'NA' North America.
However, the data frame created using read.csv shows NA where the string
variable should have had the value 'NA'.
How can I input the value 'NA' present in a column in a
I believe read.csv(..., na.strings = ) will do it.
Michael
On Mon, Feb 27, 2012 at 8:15 AM, nikhil abhyankar nsabhyan...@gmail.com wrote:
Hello,
I have a CSV file with region codes listed in a column. E.g. 'AS' for Asia,
'AU' for Australia and 'NA' North America.
However, the data frame
On Feb 27, 2012, at 14:15 , nikhil abhyankar wrote:
Hello,
I have a CSV file with region codes listed in a column. E.g. 'AS' for Asia,
'AU' for Australia and 'NA' North America.
However, the data frame created using read.csv shows NA where the string
variable should have had the value
Dear all,
I want to delete the exact matches in a large dataset based on a smaller
dataset. In other words I want to subtract the smaller dataset from the larger
one. The smaller dataset is a part of the larger one. The datasets contains
hundred of thousands of lines (1 column) and the content
Dear all,
I am tryng to solve a nonlinear optimization probel using the solnp function.
I have different datasets. For the smaller I get full solutions, for
the bigger I got an error message stating:
Iter: 1 fn: 101.8017 Pars: 0.21000 0.21000
Hello,
I'm very new in working on R and maybe that's a simple thing I'm trying to
do, but I am really stuck.
I have a data point set of animal tracking coordinates and I have
implemented a kernel utilization distribution analysis in order to find the
home range for 95% of the relocation data. I
My data have heterogeneity of variance (in a categorical variable), do I need
to specify a variance structure accounting for this in my model or do GLMMs
by their nature account for such heterogeneity (as a result of using
deviances rather than variances)? And if I do need to do this, how do I do
2012/2/27 Petr Savicky [via R] ml-node+s789695n4423895...@n4.nabble.com
On Sun, Feb 26, 2012 at 11:39:01AM -0800, mari681 wrote:
SORRY!
The data in MyTable are tagsets of photos, like this:
V1 V2 V3 V4 V5 V6V7 V8
230green nailpolish
I've tried to create a loop for the following code but have failed miserably.
This is what the code is:
pnorm((Normal.Team.LnAveragePPPConceded.LnAveragePPPScores.HA.pred[1,1]
-Normal.Team.LnAveragePPPConceded.LnAveragePPPScores.HA.pred[50,1])/
sqrt(prediction.SE[1]^2 + prediction.SE[50]^2))
We are working on trying to find how well glm models fit our set of sports
results. We want to consider the following two models and work out which one
fits the data better:
summary(Tries.Team.Ha.glm)
(Dispersion parameter for poisson family taken to be 1)
Null deviance: 321.46 on 269
i have one file as
munnabhai-read.table(hyphen[1],skip=1)
munnabhai
V1 V2 V3 V4 V5 V6 V7
1 1 12AS_A 4 A0.0 157.8994119 2
2 2 12AS_A 5 Y -41.61818 -56.8011795 1
3 3 12AS_A 6 I -55.47021 -51.1328352 1
4 4 12AS_A 7 A -54.43085
Hi,
I do not know what part of my code should I post here (I use large size of
data, the loop for contains many lines). The situation is difficult to
post here, but I hope these lines would be useful for help:
hcEndDateTmp = userDateStart
if((hcStartTime=23:59) (hcEndTime = 00:00)){
Dear List,
I want to compare and return the rows which are NOT in the two data frames.
Classic methods don't work as the df have NOT the same dimensions.
Here are one example of my df:
reported -
structure(list(Product = structure(c(1L, 1L, 1L, 1L, 2L, 2L,
3L, 4L, 5L, 5L), .Label = c(Cocoa,
Dear helpers,
I would like to install R on a computer with Ubuntu Jaunty.
Unfortunately, Jaunty does not appear in any CRAN mirror website I
have tried (France, Canada, Italy, Germany).
Could you give me any mirror website allowing installation on
Jaunty?or could you give me a procedure
Is this what you want:
ds1 - read.table(text = 1 A
+ 2 B
+ 3 X
+ 4 AA
+ 5 A
+ 6 D
+ 7 XA
+ 8 C, as.is = TRUE)
ds2 - read.table(text = 1 A
+ 2 X
+ 3 A, as.is = TRUE)
# find matches
ds3 - ds1[!(ds1$V2 %in% ds2$V2), ]
ds3
V1 V2
2 2 B
4 4 AA
6 6 D
7 7 XA
8 8 C
On Mon, Feb 27, 2012
I don't understand where is your problem. Are you looking for jaunty as a
package on R Crans?? Are you looking to install R package on your Ubuntu box?
As you know, Jaunty is no more supported by Ubuntu, so packets have been moved
in Archives.
Arnaud Gaboury
A2CT2 Ltd.
-Original
set.seed(1)
(DFid - data.frame(
x = sample(1:20,10),
y = sample(1:20,10),
IDs = sapply(1:10,function(i) paste(ID,i,sep=
require(spdep)
coordinates(DFid) - ~x+y
coords - coordinates(DFid)
dnn4 - dnearneigh(DFid,0,4)
summary(dnn4)
plot(DFid)
plot(dnn4,coords,add=T,col=2)
nb2mat(dnn4,
is.na(POSIXltObject) can behave oddly if you manipulate
the fields of the POSIXlt object directly so as to
cause illegal combinations of values. E.g., the 35th
of February, 2009, is not considered an NA but the 36th
and above are:
z - as.POSIXlt(2009-02-25 06:30:00)
for(i in 1:20){ z$mday
So, how is the correct way to increment the day ?
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__
Hello,
RStudio displays errors in french . I'd like to change it in english
Please help,
Thanks
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Hi all,
I have a matrix with values between 0 and 1. I want to plot this matrix on a
heat map so anything 0.05 is blue, anything =0.05 and 0.01 is yellow, and
anything else is grey. I am using the heatmap.2 function. I searched around
but did not find an efficient way to set colour ranges as I
On 27/02/2012 15:29, ikuzar wrote:
Hello,
RStudio displays errors in french . I'd like to change it in english
See the 'R Installation and Administration' manual. If that does not
help, ask RStudio's help (it is not a product supported here).
Setting the LANGUAGE environment variable to
Then why don't you ask about it on the RStudio support forum?
---
Jeff NewmillerThe . . Go Live...
DCN:jdnew...@dcn.davis.ca.usBasics: ##.#. ##.#. Live Go...
Thanks,
That helped. Maybe when I get a chance I will do some blog posts on the
basics of ff
I think some tutorials would be a good idea
Steve
On Mon, Feb 27, 2012 at 3:47 AM, Djordje Bajic je.li@gmail.com wrote:
Steven, sorry for the delay in responding,
I have been investigating
On Mon, Feb 27, 2012 at 1:44 AM, Christofer Bogaso
bogaso.christo...@gmail.com wrote:
Here I was expecting those 2 approaches should give exactly same result
(i.e. same estimates and same SE), which is not the case. Can somebody
point me what I am missing here?
The vector of weights as
Dear list,
I am still struggling with something that should be easy: I compare two data
frames with a lot of common rows and want to keep only rows that are NOT in
both data frames, unique.
Here are an example of these data frame.
reported -
structure(list(Product = structure(c(1L, 1L, 1L,
Dear list members,
does anyone have an idea why the following construction does not work
but gives the following error message:
assign('test', array(1:10, dim=c(10,10)))
dimnames(get('test')) - list(1:10,1:10)
Error in dimnames(get(test)) - list(1:10, 1:10) :
target of assignment expands
is this what you want:
v - rbind(reported, exportfile)
v[!duplicated(v), ]
ProductPrice Nbr.Lots
1Cocoa 2331.00 -61
2Cocoa 2356.00 -61
3Cocoa 2440.005
4Cocoa 2450.001
6 Coffee C 204.55 40
7 Coffee C
On Mon, Feb 27, 2012 at 9:41 AM, Jannis bt_jan...@yahoo.de wrote:
Dear list members,
does anyone have an idea why the following construction does not work but
gives the following error message:
assign('test', array(1:10, dim=c(10,10)))
dimnames(get('test')) - list(1:10,1:10)
Error in
Hi,
On Mon, Feb 27, 2012 at 12:41 PM, Jannis bt_jan...@yahoo.de wrote:
Dear list members,
does anyone have an idea why the following construction does not work but
gives the following error message:
assign('test', array(1:10, dim=c(10,10)))
dimnames(get('test')) - list(1:10,1:10)
Error
No, but I tried your way too.
In fact, the only three unique rows are these ones:
Product Price Nbr.Lots
Cocoa 24405
Cocoa 24501
Cocoa 24406
Here is a dirty working trick I found :
df-merge(exportfile,reported,all.y=T)
df1-merge(exportfile,reported)
On 24/01/2012 7:44 PM, R. Michael Weylandt wrote:
I'm skeptical that CRAN would produce a bug, but it's not unheard of
for anti-viruses to not like its compiled code. Are you able to
compile locally? That might make it more comfortable -- if you do so,
you could also white list those files
Sarah Gosless said
But frequently there are better options than the
use of get/assign for solving particular problems.
I tend to be more extreme say recommend that you forget
you ever heard of the get and assign functions.
First, out-of-the-local-evaluation-environment assignments
make for
On Feb 27, 2012, at 11:26 AM, Wendy wrote:
0.05 is blue, anything =0.05 and 0.01 is yellow, and
anything else is grey
No data structures offered, but this may be a useful example:
col= c(grey, yellow, blue)[findInterval(X, c(-.01, 0.01, 0.05,
1.1))]
--
David Winsemius, MD
Heritage
Hi All,
I have a CITATION file in inst for my package, however I would like to have
our relevant paper to show up in the package documentation file as well.
I tried to put the paper in the Description field but that does not seem to
allow formatting (like a new line before the reference) it is a
Hi,
I am having real problems downloading the package 'QRMlib'. The tar.gz file
is shown here:
http://cran.r-project.org/src/contrib/Archive/QRMlib/
I have downloaded this to my local folder and entered the following command:
nstall.packages(myLocalFolder/QRMlib_1.4.5.1.tar.gz, repos = NULL)
hi,
I know how to use the for loop function like:
for(i in 1:ncol(mat)){
mat[i]-b[i,2]
}
but, in this case
r1-b[1,1]
r2-b[2,1]
r3-b[3,1]
r4-b[4,1]
*
*
*
r3002-b[3002,1]
r3003-b[3003,1]
- must make vectors
how should I make a efficient code for that?
Is there anything in R like SAS MACRO
Hello,
In fact, the only three unique rows are these ones:
Product Price Nbr.Lots
Cocoa 24405
Cocoa 24501
Cocoa 24406
The code below doesn't give the three in one step.
(ixmat - apply(reported, 1, function(x) apply(exportfile, 1, function(y)
any(x
On Feb 27, 2012, at 1:32 PM, David Winsemius wrote:
On Feb 27, 2012, at 11:26 AM, Wendy wrote:
0.05 is blue, anything =0.05 and 0.01 is yellow, and
anything else is grey
No data structures offered, but this may be a useful example:
col= c(grey, yellow, blue)[findInterval(X, c(-.01,
On Mon, Feb 27, 2012 at 9:56 AM, mrzung mrzun...@gmail.com wrote:
hi,
I know how to use the for loop function like:
for(i in 1:ncol(mat)){
mat[i]-b[i,2]
}
but, in this case
r1-b[1,1]
r2-b[2,1]
r3-b[3,1]
r4-b[4,1]
*
*
*
r3002-b[3002,1]
r3003-b[3003,1]
- must make vectors
On Mon, Feb 27, 2012 at 07:10:57PM +0100, Arnaud Gaboury wrote:
No, but I tried your way too.
In fact, the only three unique rows are these ones:
Product Price Nbr.Lots
Cocoa 24405
Cocoa 24501
Cocoa 24406
Here is a dirty working trick I found :
Hadley's lubridate package might be of some help to you.
Michael
On Mon, Feb 27, 2012 at 11:40 AM, ikuzar raz...@hotmail.fr wrote:
So, how is the correct way to increment the day ?
--
View this message in context:
Do you perhaps need to add install.packages(..., type=src)? Just a
(untested) guess...
Michael
On Mon, Feb 27, 2012 at 12:07 PM, DT54321 deepan.tailo...@gmail.com wrote:
Hi,
I am having real problems downloading the package 'QRMlib'. The tar.gz file
is shown here:
On 27/02/2012 3:01 PM, R. Michael Weylandt wrote:
Do you perhaps need to add install.packages(..., type=src)? Just a
(untested) guess...
That should be type=source, and that should solve the problem,
assuming Deepan has the necessary tools installed. If not, he can get
them from CRAN in
Hello,
I have a matrix with 267 columns, all rows of which have at least one
column missing (NA).
All three methods i've tried (pcs, princomp, and prcomp) fail with either
Error in svd(zsmall) : infinite or missing values in 'x' (latter two)
or
Error in cov.wt(z) : 'x' must contain finite
Hi,
I'm interested in incorporating some interaction terms between my
explanatory variables (distance matrices in this case) when I'm using the
function MRM of the package ecodist. The function is doing a multiple
regression on distance matrices. I can get the function to work perfectly on
my
Hi,
On Mon, Feb 27, 2012 at 2:28 PM, Hossm_R hossamesap...@gmail.com wrote:
Hi,
I'm interested in incorporating some interaction terms between my
explanatory variables (distance matrices in this case) when I'm using the
function MRM of the package ecodist. The function is doing a multiple
I am trying to invoke an in house developed java program from R and am
running into some confusing issues.
I've written this function:
DoNormalSkew - function() {
.jaddClassPath(U:/development/software/untilities/ELVeSkew/dist/ELVeSkew.jar)
On 27/02/12 20:57, ali_protocol wrote:
Dear all,
Newbie: What is the fastest way to combine all columns of a matrix to one
column?
What (on earth!) do you mean by ``combine''? *You* understand
what you mean; I doubt that anyone else does. For Pete's sake, if
you are going to ask a
Hi,
I am doing some bootstrap. This the is the method I am procceding:
I select a value of sigma and set the sharp ratio = 4. From this I can
compute the mean mu.
For a set sample size say n = 11, I generate 999 samples of size 11 with
the sigma and mean above.
This is a 11 x 999 matrix. Now, I
Hello,
I could find the maximal set of columns such that there exists a subset of
rows with non NA values for every column in the set - what is an
efficient
way to do that?
Try 'na.exclude' on the transpose matrix.
Example:
set.seed(1)
x - matrix(1:200, ncol=25)
f -
Hi all,
Is it possible to model a function where the unknown parameter appears both
in the fitted equation AND in the determination of other parameters? E.g.
y = a^2 + b/2 + k
where a = 2/k and b = k^2
and the model needs to determine k? I know this is a very simple equation
(its just an
m - rbind(reported, exportfile)
m1 - m[duplicated(m),]
m[is.na(match(m$key, m1$key)),]
On Mon, Feb 27, 2012 at 9:46 AM, Arnaud Gaboury
arnaud.gabo...@a2ct2.com wrote:
Dear List,
I want to compare and return the rows which are NOT in the two data frames.
Classic methods don't work as the df
Hey,
I have an array with the dimensions 200x6x200 and I want to save it in a
textfile. I want to be able to reload the text file to get the same array
again: new.array-load(mytextfile.txt) or something similar. I was not
able to figure out a way to do that with write.table without having to
It appears that the intermediate data in functions is never GCed even
after the return from the function call.
R's RSS is 4 Gb (after a gc()) and
sum(unlist(lapply(lapply(ls(),get),object.size)))
[1] 1009496520
(less than 1 GB)
how do I figure out where the 3GB of uncollected garbage is hiding?
Dear who may concern,
I am sending you this email to ask if I could have someone help me to write
this script I am interested in.
I am requesting the script for performing variance-stabilizing normalizations
on the R language. Could you please help me on that?
If I am asking a wrong person,
I get this (twice):
Note: no visible binding for global variable 'Dimnames'
Note: no visible binding for global variable 'Dimnames'
on the __first__ invocation of a function which does this:
sm - sparseMatrix(i = ..., j = ..., x = ...)
for (i in 1:length(mynames))
usr[[mynames[i]]] - sm[,i]
You can save it directly as an R object with save() and load with
load() -- that's probably easiest. It should be portable between R
platforms and sesions, but won't be easily accessible to other
programs.
Michael
On Mon, Feb 27, 2012 at 3:45 PM, frauke fh...@andrew.cmu.edu wrote:
Hey,
I have
why a text file? are you going to pass it to another program? 'load'/'save'
has already been suggested. if you really want text, try 'dump'.
Sent from my iPad
On Feb 27, 2012, at 15:45, frauke fh...@andrew.cmu.edu wrote:
Hey,
I have an array with the dimensions 200x6x200 and I want to
Mod Rolf's question, the answer probably is: do nothing -- it already
**is** a single column.
If you read the section on arrays and matrices in An Intro to R
*carefully* (this is part of every standard R distro) you will be
enlightened. Have you read it? If not, why not?
If mat is your matrix,
Hello All,
I have a data.frame with this structure:
m - matrix(sample(c(rep('yes', 10, replace = TRUE), rep('no', 10,
replace = TRUE), NA), 500, replace = TRUE), nrow = 100, ncol = 5)
colnames(m) - colnames(m, do.NULL = FALSE, prefix = col)
m - as.data.frame(m)
I need to generate a Venn diagram
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
On Behalf Of Lara Poplarski
Sent: Monday, February 27, 2012 5:24 PM
To: r-help@r-project.org
Subject: [R] from data.frame to Venn diagram
Hello All,
I have a data.frame with this
Your question is (completely) ill-posed. What is your actual
model? What you have said makes no sense at all as it stands.
(Minimal self-contained example .)
cheers,
Rolf Turner
On 28/02/12 09:25, jeff_hawkes wrote:
Hi all,
Is it possible to model a function where the
Hi Rs,
I am analyzing a time to event dataset with several competing risks.
0 = Active by end of study
1 = Stopped treatment to start another treatment
2 = Lost
3 = Dead
My event of interest in Lost to Followup but starting a different treatment
and dying are competing risks. All 1,2,3 events
GibsonR rachel.gibson at bristol.ac.uk writes:
My data have heterogeneity of variance (in a categorical variable), do I need
to specify a variance structure accounting for this in my model or do GLMMs
by their nature account for such heterogeneity (as a result of using
deviances rather than
Hello again,
Q: is there a way to do princomp or another method where every row has at
least one missing column?
See also package 'psych', function 'principal'. You can impute mean or
median to NAs.
Rui Barradas
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Hello R Gurus,
I have a matrix for which I am doing a heatmap using heatmap.2. I want to
put the rownames on the lefthand side instead of the right side of the
heatmap. how can i put the rownames on left hand side: I have already tried
axis but could not make it work
ccc-structure(c(1,
Hello,
I'd like to classify data with kmeans algorithm. In my case, I should get 2
clusters in output. Here is my data
colCandInd colCandMed
1 822950.5
2 83 1831.5
3 1192 2899.0
4 1193 2103.5
The first cluster is the
This appears to be the sort of query that (with apologies to other R
gurus) only Brian Ripley or Luke Tierney could figure out. R generally
passes by value into function calls (but not *always*), so often
multiple copies of objects are made during the course of calls. I
would speculate that this
Dear Oscar,
Â
I really appreciate your help for my problem. I have taken a look at the R
package RJaCGH you mentioned roughly, but I am really a little confused by the
CGH microarrays background of the package. Actually, I am a graduate student,
majoring Mathematical Statistics. So, I know
Dear R Development Core Team
R for Mac has been reviewed by Download Typhoon and got Editor's Pick award:
http://www.downloadtyphoon.com/r-for-mac/infoyvnppyhf
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a
Hello,
I've made Petr's solution a bit more general
Petr Savicky wrote
On Mon, Feb 27, 2012 at 07:10:57PM +0100, Arnaud Gaboury wrote:
No, but I tried your way too.
In fact, the only three unique rows are these ones:
Product Price Nbr.Lots
Cocoa 24405
Cocoa 2450
Dear Doctor Oscar,
Â
Sorry for not noticing that you are the author of the RJaCGH package.
But I noticed that hidden Markov model in your package is with non-homogeneous
transition probabilities. Here in my work, the HMM is just a first-order
homogeneous Markov chain, i.e. the transitionÂ
Here's my code:
http://pastebin.com/0yRxEVtm
The important parts are uncommented and should be easy to find using the
link above. For the following line of code, I plan on looking for a way to
offset it up 7 rows so that the 15 minute timestamp would be considered the
median of the subset being
hi. can anybody help me to resolve this problem i am facing?
Warning in odbcDriverConnect(con, tabQuote = c([, ]), ...) :
[RODBC] ERROR: state IM002, code 0, message [Microsoft][ODBC Driver
Manager] Data source name not found and no default driver specified
Warning in odbcDriverConnect(con,
Hello,
Lara Poplarski wrote
Hello All,
I have a data.frame with this structure:
m - matrix(sample(c(rep('yes', 10, replace = TRUE), rep('no', 10,
replace = TRUE), NA), 500, replace = TRUE), nrow = 100, ncol = 5)
colnames(m) - colnames(m, do.NULL = FALSE, prefix = col)
m -
Quite possibly, after you read the posting guide and provide a complete example
of code that is causing the problem.
---
Jeff NewmillerThe . . Go Live...
DCN:jdnew...@dcn.davis.ca.us
Thanks for taking the time to really kick the tires on R for mac and
providing a great service to the community.
The screen shots[1] you chose to use in order to really highlight R
for mac as well as ensuring that you are reviewing the latest and
greatest[2] really says volumes about the
Hi Mr. Uwe Ligges,
I really thankful for the reply. I even tried the same,
means writing the new function. But the result is same as the last. Here is
the picture below,
Telco.Rpart.PLOT.TEXT.Functn -
function(Telco.Rpart.METHOD.CLASS)
On Mon, Feb 27, 2012 at 3:18 PM, ikuzar raz...@hotmail.fr wrote:
Hello,
I'd like to classify data with kmeans algorithm. In my case, I should get 2
clusters in output. Here is my data
colCandInd colCandMed
1 82 2950.5
2 83 1831.5
3
Dear R-society,
I know this is probably a question to LibSVM, but I have not found a
LibSVM mailing list, so I would be really grateful if someone from this
list helped me.
In the LibSVM documentation I have found a passage about dealing with
unbalanced sets, that says that in this case one
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