Hi all, I have been using ggplot for a few months and ran into this
porblem, I am trying to use ggplot in a for loop and it is not working. if
I do the following:
data=as.data.frame(cbind(rnorm(10),rnorm(10),rnorm(10)))
pp=ggplot(data, aes(x=(1:10), y=data[,1]))
Hello-
In the notes for the lm function it states Offsets specified by offset
will not be included in predictions by predict.lm, whereas those
specified by an offset term in the formula will be. I would like to
extract fitted values in just this way from a glm model, those with the
offset
Hi
It seems to me that probably split.screen or layout is preferable if you
want specify graph for identification. But I am not an expert in this and
after some testing identification does not work well with splitted screen.
So you are probably out of luck.
Regards
Petr
Please forgive my
[See at end]
On 05-Apr-2012 00:34:30 Peter Ehlers wrote:
Hi Ted,
On 2012-04-04 15:06, Ted Harding wrote:
Greetings!
I want to have the coefficients that R uses in shapiro.test()
for the Shapiro-Wilk test for a prticular sample size, i.e.
the a[i] in
W = Sum(a[i]*x[i])/(Sum(x[i] -
This is because of lazy evaluation.
Try this:
pp=ggplot(data, aes(x=(1:10), y=data[,1]))
for(i in 1:3){
pp=pp+geom_line(aes(x, y), data = data.frame(x=1:10,y = data[,i]),lty=2)
}
print(pp)
2012年4月5日14:36 Tarek Haddad tarekdhad...@gmail.com:
pp=ggplot(data, aes(x=(1:10), y=data[,1]))
for(i in
Hi Rui,
Thanks a lot it works
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Hi to all,
Is there a way to use the API bloomberg functions BAddPeriods Binterpol
Bcountperiods in RBloomberg?
tnks
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On Apr 05, 2012; 1:47am John Sorkin wrote:
Is the sigma from a lm...the RMSE (root mean square error)
John,
RMSE is usually calculated using the number of observations/cases, whereas
summary.lm()$sigma is calculated using the residual degrees of freedom. See
below:
## Helps to study the
Hi to all,
Do you know how I can use Baddperiods from RBloomberg
tnks
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On Wed, 04-Apr-2012 at 02:58PM -0700, kickout wrote:
| Having problems with the write.table function. I can write a tab delimited
| file just fine, but for each line in my matrix its inputs a carriage return
| when i dont want it to.
|
| For example my matrix might be:
|
| ID V1 V2 V3
|
Hi,
Some additional information from you would make it more likely that the list
can help you.
What's your sessionInfo?
Does the same thing occur if you don't wrap both plots in a single function?
Can you provide a small reproducible example so we can try it out?
Sarah
On Apr 4, 2012, at 7:48
Dear R-users,
I'd like to use an xyplot(lattice) in which in each panel I have points with
different point-character and color, and additional lines with the same color.
Please find below a toy example in which I did not manage to change such
parameters, and the associated basic plot() in
On 04/05/2012 08:41 PM, Camarda, Carlo Giovanni wrote:
Dear R-users,
I'd like to use an xyplot(lattice) in which in each panel I have points with
different point-character and color, and additional lines with the same color.
Please find below a toy example in which I did not manage to change
vasilis vasilis.dakos at gmail.com writes:
Hi there,
do you know if there is a package that fits spatio temporal autoregressive
models in R?
If by spatio temporal autoregressive models, you mean spatial panel models,
please see the splm package on R-Forge:
Dear R users,
how do I e.g. square each second element of a vector with an even
number of elements? Or more generally to apply a function to every
'nth' element of a vector. I looked into the apply functions, but
found no hint.
For example:
v - c(1, 2, 3, 4)
mysquare - function (x) { return
At 18:39 04/04/2012, mp.sylves...@gmail.com wrote:
Greetings,
I wish to conduct a meta-analysis for which the outcome is a continuous
variable measured on the same individuals before and after an intervention.
Hence, the comparison is not made between two groups, but within groups, at
diffrent
Good morning Michael,
On Thu, Apr 5, 2012 at 7:01 AM, Michael Bach pha...@gmail.com wrote:
Dear R users,
how do I e.g. square each second element of a vector with an even
number of elements? Or more generally to apply a function to every
'nth' element of a vector. I looked into the apply
To add to Michael's response:
There are several things you can do:
1) If the dependent variable is the same in each study, then you could conduct
the meta-analysis with the (raw) mean changes, i.e., yi = m1i - m2i, where m1i
and m2i are the means at time 1 and 2, respectively. The sampling
Michael Bach phaebz at gmail.com writes:
how do I e.g. square each second element of a
vector with an even
number of elements? Or more generally to
apply a function to every
'nth' element of a vector. I looked into the
apply functions, but
found no hint.
For example:
v - c(1, 2, 3, 4)
ken knoblauch ken.knoblauch at inserm.fr writes:
Michael Bach phaebz at gmail.com writes:
how do I e.g. square each second element of a
vector with an even
number of elements? Or more generally to
apply a function to every
'nth' element of a vector. I looked into the
apply
I do not see any major difficulties with this case either. Suppose you have OR
= 1.5 (with 95% CI: 1.19 to 1.90) indicating that the odds of a particular
outcome (e.g., disease) is 1.5 times greater when the (continuous) exposure
variable increases by one unit. Then you can back-calculate the
Hello David,
yes! this is what I was looking for!
Thank you very much for your help.
Marion
2012/4/2 David Winsemius dwinsem...@comcast.net
On Apr 2, 2012, at 7:11 AM, Marion Wenty wrote:
Dear people,
I would like to create a table out of a data.frame.
How can I determine, which
LIKE:)
On 2012-4-5 15:03, Viechtbauer Wolfgang (STAT) wrote:
I do not see any major difficulties with this case either. Suppose you have OR
= 1.5 (with 95% CI: 1.19 to 1.90) indicating that the odds of a particular
outcome (e.g., disease) is 1.5 times greater when the (continuous) exposure
Hi to everyone,
Recently I became aware of an R package for Sequential Monte Carlo
particle filtering called pomp [Check the CRAN site]
I have found hard to learn and understand the package at a first passage
and I was wondering if someone of you would like to share her/his experience
of a
Hello,
These functions are not available in RBloomberg. As far as I can tell,
Bloomberg does not expose these functions in the general API; they are
specific to the Excel version.
R has other mechanisms for performing date arithmetic, both in the
Date class and the POSIXct/POSIXlt classes. This
Hi to all
I am using GEL function of GMM package to fit a ts
I use gmm to feed initial values to GEL as:
temp3M=gmm(fgmm,rf3M[[i]],tet03M[[i]],wmatrix=ident)$coef
gel3M[[i]]=gel(g=fgmm, # Function GMM
x=rf3M[[i]], #
Hi,
I am learning decisions trees using R ..I used RPART to create decision
maps. when i saw the summary .. i got
CPnsplit rel errorxerror xstd
Could anyone make me understand terms here CP,relerror xerror and xstand.
or could you please provide the detailed blog where i can
i have a character variable
tablename=DressMaterials
var1=(red,blue,green,white)
My output should be like
select * from DressMaterialswhere colors in (red,blue,green,white)
i'm not able to get the where part.
my code
paste(select * from , tablename , where colors in ,paste(var1,
Hello everyone,
I want to estimate a function for the relationship between the distance
and the cross-correlation coefficients. This means that I have several
pairs of distance and cross-correlation coefficients.
Hence, I have a function which includes two vectors with the same length
(for
Many thanks to both of you for the helpful responses to my post. The
outcomes are all measured with the same units and I can indeed calculate
the sampling variance from the 2 SDs I get from each study.
MP
Le , Viechtbauer Wolfgang (STAT)
wolfgang.viechtba...@maastrichtuniversity.nl a écrit
For some reason I was under the false impression that these packages were
made for meta-analyses of RCT-like studies in which two groups are
compared. I am glad to see that I was wrong and that I can use one of these
packages.
All studies reported using the same units for the exposure so
Hi,
The code below does exactly what I want in sequential mode. But, it is slow and
I want to run it in parallel mode. I examined some windows version packages
(parallel, snow, snowfall,..) but could not solve my specific problem. As far
as I understood, either I have to write a new
Dear list,
I am trying to reclaim what I think is lost memory in R, I have been using
gc(), rm() and also using Rprof to figure out where all the memory is going but
I might be missing something.
I have the following situation
basic loop which calls memoryHogFunction:
for i in (1:N) {
Hello Arun,
paste(select * from , tablename , where colors in
(,paste(var1,collapse=,),))
[1] select * from DressMaterials where colors in (
red,blue,green,white )
Regards!
__
R-help@r-project.org mailing list
Here is Dr. Leisch's advice for dealing with open handles (and it works):
On 4/5/2012 4:22 AM, Friedrich Leisch wrote:
...
You need to close the pdf device, not an open connection:
R Sweave(test.Rnw)
Writing to file test.tex
Processing code chunks with options ...
1 : keep.source term
You can get an OR from a 2x2 table (which is equivalent to doing logistic
regression with a single dummy variable that indicates the group) or from some
continuous exposure (where the logistic regression model will then include that
continuous variable). The various packages are set up to
On Apr 5, 2012, at 7:01 AM, Michael Bach wrote:
Dear R users,
how do I e.g. square each second element of a vector with an even
number of elements? Or more generally to apply a function to every
'nth' element of a vector. I looked into the apply functions, but
found no hint.
For example:
v
On Apr 5, 2012, at 8:55 AM, arunkumar wrote:
i have a character variable
tablename=DressMaterials
var1=(red,blue,green,white)
My output should be like
select * from DressMaterialswhere colors in
(red,blue,green,white)
i'm not able to get the where part.
?match
my code
On Thu, Apr 5, 2012 at 9:18 AM, Pam fkira...@yahoo.com wrote:
Hi,
The code below does exactly what I want in sequential mode. But, it is slow
and I want to run it in parallel mode. I examined some
windows version packages (parallel, snow, snowfall,..) but could not solve my
specific
Thanks Lell
It worked well.
-
Thanks in Advance
Arun
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http://r.789695.n4.nabble.com/file/n4534914/Rplot01.png
I have some dataset
ak[1:3,]
[,1] [,2] [,3] [,4] [,5] [,6] [,7]
[,8] [,9]
[1,] 0.3211745 0.4132568 0.5649930 0.6920562 0.7760113 0.8118568 0.8609301
0.9088819 0.9326736
[2,] 0.3159234
* Duncan Murdoch zheqbpu.qha...@tznvy.pbz [2012-04-04 21:46:57 -0400]:
On 12-04-04 5:15 PM, Sam Steingold wrote:
* Duncan Murdochzheqbpu.qha...@tznvy.pbz [2012-04-04 17:00:32 -0400]:
There's no warning when you mask a function with a non-function at top
level, and little need for one,
To expand on Duncan's answer, you haven't replaced it. The following
should make that clear:
## starting in a fresh session
c
function (..., recursive = FALSE) .Primitive(c)
find('c')
[1] package:base
c - 1
find('c')
[1] .GlobalEnv package:base
c
[1] 1
rm(c)
find('c')
[1] package:base
Thank you very much for your comments Ista and David! I will
experiment and see which one serves my needs best.
__
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https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
Hi all,
I have a matrix (n*2), I want to compare 2 operators (2 normalization for
array results) on these matrix.
The 2 columns should ideally become the same after operations
(normalization). So to compare operations,
I do this for each normalization:
s= sum (apply (normalized.matrix,
Thanks to you both. Calling recover (an option hitherto unknown to me) helped
me identify the problem.
For the record, the error occurred in the geom_path() line, not the list
concatenation, as I had previously thought. It was a logic problem: when
typeof == NULL the function jumped, but i
The compiler doesn't currently look beyond the first definition found
(the generated code does the right thing, but the compiler won't
optimize calls to functions masked by non-functions). I'll look into
whether thechecking can be made to take this into account; it may be
more trouble than it is
hi
I have a dataframe and a parameter
the parameter can have any one value min max mean sum hist
i'm using the function match.fun
fun=match.fun(input)
fun(dataset)
but if input is hist the plot pops up. is there any method to avoid it. else
should use only if condition for histogram
Adding plot=FALSE to the hist() call will prevent it from being plotted.
On Thu, Apr 5, 2012 at 10:52 AM, arunkumar akpbond...@gmail.com wrote:
hi
I have a dataframe and a parameter
the parameter can have any one value min max mean sum hist
i'm using the function match.fun
* yhxr-gvre...@hvbjn.rqh [2012-04-05 09:58:24 -0500]:
I'll look into whether thechecking can be made to take this into
account; it may be more trouble than it is worth though.
Just to clarify: it would be nice if R noticed stupid mistakes like
overriding functions in packages from the
R-helpers:
It looks like http://finzi.psych.upenn.edu/search.html has stopped
spidering the mailing lists -- this used to be my go-to site for
searching for R solutions. Are there any good replacements for this?
I want to be able to search both functions and mailing lists at the
same time.
Don't know how you searched, but perhaps this might help:
https://stat.ethz.ch/pipermail/r-help/2007-March/128064.html
-Original Message-
From: r-help-boun...@r-project.org
[mailto:r-help-boun...@r-project.org] On Behalf Of Jenn Barrett
Sent: Tuesday, April 03, 2012 1:23 AM
To:
On 05.04.2012 17:40, Drew Tyre wrote:
A final, final followup. Uwe, your suggestion is spot on - disabling the
virus scanner fixes the problem. UNL recently changed virus scanning
software, so this issue arose with Windows XP and Symantec Endpoint
Protection. It can be readily disabled and
This example is from The R Book by Michael J. Crawley.
d=read.table(
http://www.bio.ic.ac.uk/research/mjcraw/therbook/data/diminish.txt;
,header=TRUE)
p=qplot(xv,yv,data=d); p
m1=lm(yv~xv,data=d)
p1=p + geom_abline(intercept=coefficients(m1)[1],
slope=coefficients(m1)[2] ); p1
m2=lm(yv~xv +
A final, final followup. Uwe, your suggestion is spot on - disabling the
virus scanner fixes the problem. UNL recently changed virus scanning
software, so this issue arose with Windows XP and Symantec Endpoint
Protection. It can be readily disabled and reenabled from the system tray,
so not too
Ramiro
I think the problem is the loop - R doesn't release memory allocated inside
an expression until the expression completes. A for loop is an expression,
so it duplicates fit and dataset on every iteration. An alternative
approach that I have found successful in similar circumstances is to
http://www.rseek.org/ perhaps. [Take a look at the tabs on the RHS
after you do a search]
Michael
On Thu, Apr 5, 2012 at 11:36 AM, Jonathan Greenberg j...@illinois.edu wrote:
R-helpers:
It looks like http://finzi.psych.upenn.edu/search.html has stopped
spidering the mailing lists -- this
Dear Richard and Jinsong,
Others output with library agricolae. See manual.
##
library(agricolae)
comp1 - LSD.test(x.aov,a, group=FALSE)
comp2 - LSD.test(x.aov,b, group=TRUE)
# interaction ab
# Tukey's test
comp3 - HSD.test(xi.aov,ab)
# graphics
par(mfrow=c(2,2))
bar.err(comp1,ylim=c(0,100),
On 05/04/2012 08:54, arvanitis.christos wrote:
Hi to all,
Do you know how I can use Baddperiods from RBloomberg
Most of us cannot even use 'RBloomberg': it has been removed at the
request of Bloomberg's lawyers.
--
Brian D. Ripley, rip...@stats.ox.ac.uk
Professor of
On 04/04/2012 3:25 PM, Alexander Shenkin wrote:
Hello Folks,
When I run the document below through sweave, rgui.exe/rsession.exe
leaves a file handle open to the sweave-001.pdf graphic (as verified by
process explorer). Pdflatex.exe then crashes (with a Permission Denied
error) because the
Thanks for the nice ideas, Duncan. I think that would work nicely in
most cases. The major issue with that workflow in my case is that the
scripts to set up my workspace take around a half-hour to run (I really
wish CUDA was working with my setup!), so running R each time in that
case is
Use rseek.org
On Thu, Apr 5, 2012 at 10:36 AM, Jonathan Greenberg j...@illinois.eduwrote:
R-helpers:
It looks like http://finzi.psych.upenn.edu/search.html has stopped
spidering the mailing lists -- this used to be my go-to site for
searching for R solutions. Are there any good
I usually use http://www.rseek.org
On Thu, Apr 5, 2012 at 11:36 AM, Jonathan Greenberg j...@illinois.edu wrote:
R-helpers:
It looks like http://finzi.psych.upenn.edu/search.html has stopped
spidering the mailing lists -- this used to be my go-to site for
searching for R solutions. Are there
On Thu, Apr 05, 2012 at 07:46:52AM -0700, ali_protocol wrote:
Hi all,
I have a matrix (n*2), I want to compare 2 operators (2 normalization for
array results) on these matrix.
The 2 columns should ideally become the same after operations
(normalization). So to compare operations,
I do
Hi Thomas,
Thank you so much for your suggestion.
I tried your code and it is working fine. Now when I change the values of Y
in yobs I am getting so many warnings.
say,
yobs - data.frame(
time = 0:7,
Y = c(0.00, 3.40, 4.60 ,5.80, 5.80, 6.00, 6.00 ),
Z = c(0.1, 0.11, 0.119, 0.128, 0.136,
Dear all,
I want to do piecewise CAPM linear regression in R:
RRiskArbâRf = (1âδ)[αMktLow+βMktLow(RMktâRf)] + δ[αMkt High
+βMkt High(RMkt âRf )]
where δ is a dummy variable if the excess return on the value-weighted CRSP
index is above a threshold level and zero otherwise.
Hello,
#Here is how I have tried to sample but it is not sampling from the right
part of the list
bg- z_nonna[sample(1:length(z_nonna), 5000, replace=FALSE)]
You are sampling from the length of z_nonna, with no guarantee that they are
indices to unique list elements.
Try this.
# First,
On Apr 5, 2012, at 12:00 AM, Daisy Englert Duursma wrote:
random selection of cells in raster based on distance from xy
locations
Hi,
I am trying to sample a raster for random cells that occur within a
specific distance of point locations. I have successfully found
multiple
ways of
The sos package is designed to search help pages only and sort the
results by package. It includes a vignette describing how to get the
results as an Excel file giving an efficient summary of which packages
contain help pages of interest including the latest date updated, etc.
I designed the
As you got the error message, to use ggplot function, you had better make a
data.frame with your data d.
for example, d[ n x p], n : observations, p : variables
n = dim(d)
dd = data.frame(x=d[,2:n[2]], y=d[,1])
then, you may get the better result after apply dd to the ggplot function.
p1 +
sos is a great way to search help pages, agreed. But the question is
about functions AND mailing list archives, which requires an online
solution. (See subject line.)
Sarah
On Thu, Apr 5, 2012 at 12:56 PM, Spencer Graves
spencer.gra...@prodsyse.com wrote:
The sos package is designed to search
In terms of editors, I think RStudio is pretty good
(http://www.rstudio.org/download/preview). Or LyX
(http://yihui.name/knitr/demo/lyx/), or TeXmaker, WinEdit
(http://yihui.name/knitr/demo/editors/)... All of them start a new R
session when weaving the document, and all support one-click
Ok, I have a new, multipart problem that I need help figuring out.
Part 1. I have a three dimensional array (species, sites, repeat counts
within sites). Sampling effort per site varies so the array should be
ragged.
Maximum number of visits at any site = 22
Number of species = 161
Number of
Yep, I'm using RStudio, and have used Tinn-R in the past. RStudio does
start a new R session when processing a sweave document via the RStudio
GUI. In my case, this presented a problem for the reasons I stated
before (i.e. that I need to run sweave in the main environment, not a
new one).
Hi, Sarah: You were correct: I failed to read the question with
sufficient care. Thanks for your original reply and for the
correction. Spencer
On 4/5/2012 10:11 AM, Sarah Goslee wrote:
sos is a great way to search help pages, agreed. But the question is
about functions AND mailing list
Well, I do not think it is a good practice (in terms of reproducible
research) to keep on running Sweave in the same R session, because
your previous run and your current workspace could pollute your next
run. To make sure a document compiles on its own, it is better always
to start a new clean R
Reproducibility is important, and as I mentioned in a previous email,
there are probably ways I could avoid running the entire script over and
over again with each sweave compilation. Still, relying on saved
workspaces, temporary files or caches still has some of the issues that
working in the
Hello,
I'm doing some analysis on a rather large data set. In this case,
some simple commands are failing. For example, this one:
x$eventtype - factor(x$eventtype)
Error in unique.default(x) : length 1093574297 is too large for hashing
...I think this is a bug, because hashing should
Things are not that gory with knitr. You only need to use the option
cache=TRUE and it will take care of most of the things you mentioned.
For example, objects in a chunk are automatically saved and lazy
loaded; when code is modified, old cache will be automatically removed
and new cache will be
On 05/04/2012 2:03 PM, Adam D. I. Kramer wrote:
Hello,
I'm doing some analysis on a rather large data set. In this case,
some simple commands are failing. For example, this one:
x$eventtype- factor(x$eventtype)
Error in unique.default(x) : length 1093574297 is too large for hashing
The binaries for RBloomberg are hosted on findata.org. The package is
only useful in combination with a Bloomberg terminal, but users who
have access to one should not be deterred by its absence from CRAN.
John
On Thu, Apr 5, 2012 at 12:18 PM, Prof Brian Ripley
rip...@stats.ox.ac.uk wrote:
On
I found a rather easy solution that circumvents this problem by:
1) creating your own length function using na.omit function
2) calculating variance using tapply
3) calculating length using new length function
4) calculating square root of variance by length
*Code from LeCzar:*
I am wondering if it possible to normalize the slope of a linear regression to
its intercept to allow for valid between-group comparisons.
Here is the scenario:
I need to compare the slopes of biomass increase among NAFO divisions of
Northwest Atlantic cod. However, the initial division
Thanks for your response, Duncan.
x$eventtype is a character vector (because the same hashing error
occurred when I tried to read.table() in the first place specifying
colClasses = c(..., factor, ...).
x really is that long:
dim(x)
[1] 1093574297 12
...the x$eventtype field has
I have an ordered set of numbers, represented by a vector, say
X - c(10:13, 17,18)
X
[1] 10 11 12 13 17 18
then I have a sub-set of X, say
Y - c(11,12,17,18)
Is there a simple way in R to have a logical vector (parallel to X) indicating
what elements of X are in Y, i.e.,
At least two ways
(!is.na(match(X, Y)))
[1] FALSE TRUE TRUE FALSE TRUE TRUE
X %in% Y
[1] FALSE TRUE TRUE FALSE TRUE TRUE
On Thu, Apr 5, 2012 at 3:32 PM, Julio Sergio julioser...@gmail.com wrote:
I have an ordered set of numbers, represented by a vector, say
X - c(10:13, 17,18)
Consider the data.frame:
df - data.frame(A = c(1,4,2,6,7,3,6), B= c(3,7,2,7,3,5,4), C =
c(2,7,5,2,7,4,5), index = c(A,B,A,C,B,B,C))
I want to select the column specified in 'index' for every row of 'df', to
get
goal - c(1, 7, 2, 2, 3, 5, 5)
This sounds a lot like the indexing-by-a-matrix you
Hi, I have the same question as Jason on how to estimate the standard error and
construct CI around S_1(t) - S_2(t). From summary.survfit(obj), how can I
combine the 2 survival estimates and the associated standard errors, to get an
estimate of standard error for the difference / then calculate
Richard M. Heiberger rmh at temple.edu writes:
At least two ways
(!is.na(match(X, Y)))
[1] FALSE TRUE TRUE FALSE TRUE TRUE
X %in% Y
[1] FALSE TRUE TRUE FALSE TRUE TRUE
Thanks Richard!
--Sergio.
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On 05-04-2012, at 21:32, Julio Sergio wrote:
I have an ordered set of numbers, represented by a vector, say
X - c(10:13, 17,18)
X
[1] 10 11 12 13 17 18
then I have a sub-set of X, say
Y - c(11,12,17,18)
Is there a simple way in R to have a logical vector (parallel to X)
You might want to look at the lattice or ggplot2 packages, both of
which can create a graph for each of the classes.
On Tue, Apr 3, 2012 at 6:20 AM, arunkumar akpbond...@gmail.com wrote:
Hi
I have a data class wise. I want to create a histogram class wise without
using for loop as it takes
In trying to streamline various optimization functions, I would like to have a scratch pad
of working data that is shared across a number of functions. These can be called from
different levels within some wrapper functions for maximum likelihood and other such
computations. I'm sure there are
Why not pass around a reference class?
Hadley
On Thu, Apr 5, 2012 at 3:20 PM, John C Nash nas...@uottawa.ca wrote:
In trying to streamline various optimization functions, I would like to have
a scratch pad of working data that is shared across a number of functions.
These can be called from
Hi R People:
What is the best way to learn how to produce vignettes, please?
Any help much appreciated.
Thanks,
Erin
--
Erin Hodgess
Associate Professor
Department of Computer and Mathematical Sciences
University of Houston - Downtown
mailto: erinm.hodg...@gmail.com
I tried your code, first I removed the reference to the global
variable data$Line, then it works if I finish identifying by either
right clicking (I am in windows) and choosing stop, or using the stop
menu. It does as you say if I press escape or use the stop sign
button (both stop the whole
On Thu, Apr 5, 2012 at 1:40 PM, Peter Meilstrup
peter.meilst...@gmail.com wrote:
Consider the data.frame:
df - data.frame(A = c(1,4,2,6,7,3,6), B= c(3,7,2,7,3,5,4), C =
c(2,7,5,2,7,4,5), index = c(A,B,A,C,B,B,C))
I want to select the column specified in 'index' for every row of 'df', to
get
Le jeudi 05 avril 2012 à 12:40 -0700, Peter Meilstrup a écrit :
Consider the data.frame:
df - data.frame(A = c(1,4,2,6,7,3,6), B= c(3,7,2,7,3,5,4), C =
c(2,7,5,2,7,4,5), index = c(A,B,A,C,B,B,C))
I want to select the column specified in 'index' for every row of 'df', to
get
goal - c(1,
If you look at the code for summary.lm the line for the value of sigma is:
ans$sigma - sqrt(resvar)
and above that we can see that resvar is defined as:
resvar - rss/rdf
If that is not sufficient you can find how rss and rdf are computed in
the code as well.
On Tue, Apr 3, 2012 at 8:56 AM,
Probably to pull down the source of one and study it directly: if you
already know LaTeX and R, Sweave isn't much more to master: zoo does
vignettes nicely, but any package with vignettes should be pretty
good.
Michael
On Thu, Apr 5, 2012 at 4:33 PM, Erin Hodgess erinm.hodg...@gmail.com wrote:
Run the examples for the loess.demo function in the TeachingDemos
package to get a better understanding of what goes into the loess
predictions.
On Tue, Apr 3, 2012 at 2:12 PM, Recher She rrrecher@gmail.com wrote:
Dear R community,
I am trying to understand how the predict function,
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