Wow it works :) Thank you SO much!!
I am very new at R and was thinking if you would explain what these to codes
do:
countries-data.frame(country1,country2,stringsAsFactors=FALSE)
# I know this i a vector with both my county lists but what does
stringsAsFacors= FALSE do ?. What if I wantede a
Hi
I'm using the Anderson Darling Normality test in my modelling. I'm finding
the Normality test for residuals. if the values of residuals are very high
the p-value coming out is infinity.
how to interpret this. or is there any means of calculating the normality
test
-
Thanks in Advance
I'll unpack it bit by bit:
stringsAsFactors = FALSE is a command to tell R how to construct the
data frame: this doesn't apply to you because you already have a data
frame, but I need it to set up my examples. By default, when you give
R data that looks like strings/labels, it wants to convert
-BEGIN PGP SIGNED MESSAGE-
Hash: SHA1
On 17/04/12 20:06, David Schaefer wrote:
Hello,
I would like to run some code in parallel with each cluster reading/writing
to a different
working directory. I've tried the following code without success. The error
I get is: Error
in
Hi all,
When I try to estimate the functional response of the Rogers type I
equation (for the mle2 you need the package bbmle):
RogersIbinom - function(N0,attackR2_B,u_B) {attackR2_B+u_B*N0}
RogersI_B -
Hi ,
I am generating one table without using latex.
for (i in 1:LCol3) {
df - data.frame(matrix(ncol = 6, nrow = 0))
datavec-c(formatfile[formatfile[,3]==Col3[i],-3])
df-rbind(df,datavec)
cat(Col3[i],\n)
cat(\\begin{table},\n)
cat(\\begin{tabular}{|l|l|l|},\n)
cat(\\hline,\n)
Hello
I try to create a polar.plot in order to represent some paths. I have one
more information: the signal quality.
I created classes and I used the argument add to superimpose my
different signal
levels.
the result:
http://i180.photobucket.com/albums/x82/zetiem/21.png
Normally, the hotter
Hi,
Without data or script...
Regards,
Pascal
- Mail original -
De : Etienne RIFA etienne.r...@gmail.com
À : r-help@r-project.org
Cc :
Envoyé le : Mercredi 18 avril 2012 16h32
Objet : [R] polar.plot add argument
Hello
I try to create a polar.plot in order to represent some paths. I
I have several large shapefiles that I need to use to draw a map.
I want to simplify the files and then save the output so that I can use them
again.
The methods that I have tried do not allow me to save the simplified output
as a shapefile.
I have tried:
thinnedSpatialPoly in the package
I improved yesterday a bit your script (mostly according to station numbers
for the automatization). Here's the final version. thanks again!
filenames - list.files(pattern=\\_2008_reconstruit.csv$)
Sensors - paste(capteur_, 1:4, sep=)
Stations -substr(filenames,1,5)
nsensors - length(Sensors)
On 18.04.2012 10:48, mail.bioi...@fr.netgrs.com wrote:
Hi
I created a directory which contains just the two packages marginalmodelplots_0.4.2.tar.gz
and locfit_1.5-7.tar.gz called test
I launched the command write_PACKAGES as follows
write_PACKAGES(/home/bioadm/install/R_packages/test/,
Hi R-experts,
I have a problem using nlme. I use the following code to group my data:
Parameterg - groupedData( result ~ time | Batch,
data = Batchdata,
labels = list( x = Time, y = analysis)
)
and then uses the nlme function to fit a nonlinear mixed model
Dear R and hydrological/environmental community,
I would like to draw your attention to hydroPSO, a newly developed R
package for the calibration/optimisation of (complex) environmental models.
hydroPSO implements a state-of-the-art Particle Swarm Optimisation (PSO)
algorithm, which is a
I have been using plotmeans() from the gplots package to create graphs, and I
would like to display the mean values instead of dots on the graphs. I tried
adding mean.labels=TRUE to the command, but the graph displays the dot with the
mean value overwritten. Has anyone else encountered this
Hi
I created a directory which contains just the two packages
marginalmodelplots_0.4.2.tar.gz and locfit_1.5-7.tar.gz called test
I launched the command write_PACKAGES as follows
write_PACKAGES(/home/bioadm/install/R_packages/test/, type =source)
As you can see I have now in my directory
On 04/18/2012 05:32 PM, Etienne RIFA wrote:
Hello
I try to create a polar.plot in order to represent some paths. I have one
more information: the signal quality.
I created classes and I used the argument add to superimpose my
different signal
levels.
the result:
On 18.04.2012 09:43, Manish Gupta wrote:
Hi ,
I am generating one table without using latex.
for (i in 1:LCol3) {
df- data.frame(matrix(ncol = 6, nrow = 0))
datavec-c(formatfile[formatfile[,3]==Col3[i],-3])
df-rbind(df,datavec)
cat(Col3[i],\n)
cat(\\begin{table},\n)
Thank you both for your answers. Sorry if I haven't explained myself
well, Michael, that is what I was looking for. Using get(n) works,
thank you. I wish I could have used saveRDS and readRDS, but it was
not my saved object⦠In any case thanks again.
2012/4/17 Michael Weylandt [via R]
Hello ALL!
I am running Fedora 16 x86_64. Due to some dubious problems with the
TeXLive (2007, which is a default), I removed it. That removed R as
well, and some other dependent packages. Then, I installed TeXLive 2011
from CTAN. However, when I wanted to install R, from Fedora's
repositories, it
This moment I got stuck with one interpolation issue
the sample data which I have is as follows
pre1 - c(10.34615 , 52.02116, 146.17357, 243.28644, 347.41504, 431.67105,
521.42712, 629.00446 ,729.95941,827.86279,
921.55078, 956.6)
pre2 - c( 983.4477692,
Hi Uwe
I tried
install.packages(marginalmodelplots, dependencies=TRUE,
contriburl=/home/bioadm/install/R_packages/test)
But I got always the same error
install.packages(marginalmodelplots, dependencies=TRUE,
contriburl=/home/bioadm/install/R_packages/test/)
Warning: unable to access index
On 12-04-18 4:12 AM, Tomas Bayer wrote:
Hello,
when I tried to create 3D graph from attached file (at first: columns 1,
2, and 3 (longitude, latitude, altitude), then columns 1, 2 and 4 , then
the same for column 5 etc) using Akima library for 3D interpolation (the
data are neither equidistant
hwouters heidiwout at gmail.com writes:
Hi R-experts,
I have a problem using nlme. I use the following code to group my data:
Parameterg - groupedData( result ~ time | Batch,
data = Batchdata,
labels = list( x = Time, y = analysis)
)
While
Joachim Audenaert Joachim.Audenaert at pcsierteelt.be writes:
When I try to estimate the functional response of the Rogers type I
equation (for the mle2 you need the package bbmle):
RogersIbinom - function(N0,attackR2_B,u_B) {attackR2_B+u_B*N0}
RogersI_B -
On 04/18/2012 05:00 AM, r-help-requ...@r-project.org wrote:
Hi,
I'm trying to use the R Survival analysis on a windows 7 system.
The input data format is described at the end of this mail.
1/ I tried to perform a survival analysis including stratified variables
using the following formula.
I can't make any guaranties, but placing a symbolic link at /usr/share/texmf,
pointing at /usr/local/texlive/2011 might do the trick. It's a bit of a hack,
but that often works for me.
Best,
Randy
On Apr 18, 2012, at 7:31 AM, Petar Milin wrote:
Hello ALL!
I am running Fedora 16 x86_64. Due
HughSt hughsturrock at hotmail.com writes:
I am trying to run a logistic regression to look at the risk of malaria
infection in individuals. I want to account for intra household correlation
and so want to include a household level random effect. I have been using
the lmer command in lme4
On 18.04.2012 14:01, mail.bioi...@fr.netgrs.com wrote:
Hi Uwe
I tried
install.packages(marginalmodelplots, dependencies=TRUE,
contriburl=/home/bioadm/install/R_packages/test)
Whoops, this was untested an it turns out you need:
contriburl=file:/home/bioadm/install/R_packages/test
reaing
On Apr 18, 2012, at 6:31 AM, Petar Milin wrote:
Hello ALL!
I am running Fedora 16 x86_64. Due to some dubious problems with the
TeXLive (2007, which is a default), I removed it. That removed R as
well, and some other dependent packages. Then, I installed TeXLive 2011
from CTAN. However, when
On Wed, Apr 18, 2012 at 03:55:07AM -0700, uday wrote:
This moment I got stuck with one interpolation issue
the sample data which I have is as follows
pre1 - c(10.34615 , 52.02116, 146.17357, 243.28644, 347.41504, 431.67105,
521.42712, 629.00446 ,729.95941,
Thanks very much! However, I tried with that
(ln -s /usr/local/texlive/2011 /usr/share/texmf)
without luck. yum is still asking for a list of dependencies, including
several texlive files.
All the best,
Petar
On Wed, 2012-04-18 at 08:58 -0400, Randy Johnson wrote:
I can't make any guaranties,
Thanks all for the excellent thought-provoking comments.
I want to clarify that these students are, for good or for ill, already
doing all these analytical and graphical things for their projects. They
are doing them with Excel and SPSS. One of my goals would be to teach
them how they can be done
Thanks for the clarification Dr. Therneau. Until I learn more about this I can
at least remember that plain is bad.
Thanks,
Paul
--- On Mon, 4/16/12, Terry Therneau thern...@mayo.edu wrote:
From: Terry Therneau thern...@mayo.edu
Subject: Re: Kaplan Meier analysis: 95% CI wider in R than in
Christopher,
I originally thought about writing off list to avoid a plethora of babble.
However here goes.
I don't see any reason why good students can 't learn the fundamentals of
R. It has lots of advance methods that perhaps are too complex to handle
for younger - less experienced people.
Indrajit,
As a former math teacher I understand your concerns wholly. My perspective is
that this must be approached with caution so you don't miss out on the
important learning but I think with proper guidance and scaffolding this could
be an amazing tool. We already using the graphing
This is a question relating to the Trellis function in R. I have a set of
socioeconomic data that I would like to display with the xyplot() function
for several states. I will have a total of 6 plots, with the y-variable as
Age Group, and the x-variable as Median Income.
Suitability of the plots
Hi Uwe
It works modifying a little bit your command instead of file:=/home/... I
used file:///home/...
install.packages(marginalmodelplots, dependencies=TRUE,
contriburl=file:///home/bioadm/install/R_packages/test/)
Thanks for your time and your patience
Regards
Joël
-Message
Dear list,
I can't use the choose.files for list the 2,000 files in directory.
# list files
names - (tk_choose.files(default = , caption = Select the files
,
+multi = TRUE, filters = Filt,
+index = 1))
names
character(0)
# names is empty ERROR
Hi,
I am stuck with creating a conditional categorical variable in R
If my dataframe data_2 has 3 variables A,B,CI want to create variable D
which would be something like :
data_2$D - ifelse(data_2$A data_2$B promotion_ind ==N,1,0),
this throws up an error In
Thanks for your reply!
As I write the script to export the data from the database myself, I'm free
to sort the data (almost) at will.
I can either export to CSV in the form of
sensor1
timestamp1, reading1, timestamp2, reading2, timestamp2, reading2...
sensor2
timestamp1, reading1, timestamp2,
hi Petr ,
Thanks for replay and sorry for typo mistake
approx(pres, sci.pre) its nothing but approx(pre2, pre1).
so for more simplicity
x - c(10.34615 , 52.02116, 146.17357, 243.28644, 347.41504, 431.67105,
521.42712, 629.00446 ,729.95941, 827.86279, 921.55078,
956.6)
y - c(
The preferred format for time series will be something like this:
Sensor1Sensor2 Sensor3
T1 Read1_1 Read2_1 Read3_1
T2 Read1_2 Read2_2 Read3_2
T3 Read1_3 Read2_3 Read3_3
if you can get that. CSV separations are nice but not as essential as
the columnar organization. (It's
Your problem is that length(x) != length(y)
approx uses linear interpolation but there's no way to make sense of
that if you can't match up the x and y coordinates -- and you can't
match up the x and y coordinates if there aren't the same number of
them.
Michael
On Wed, Apr 18, 2012 at 10:15
Your problem is that columns A B contain something that can't be
ordered. (Likely factor (=categorical) data like Male / Female
rather than numeric like 10 and 5)
Use str(data_2) to see what classes your data are -- they sometimes
get converted in unexpected ways if you aren't careful in setting
Hi,
I want to access and modify a multi dimensional array but without
knowing the exact number of dimensions.
Basically. I want something like that for every i (except boundaries of
course):
field[i, ...] - (field[i, ...] + field[i+1, ...] + field[i-1, ...])/3
In principle, ... should just
Hello,
I'm analysing reaction time data from a linguistic experiment (a variant of
a lexical decision task). To ascertain that the data was normally
distributed, I used *shapiro.test *for each participant (see commands
below), but only one out of 21 returns a p value above p.0 05.
f =
By the way, as I've been reading through some other posts on here, let me
clarify that this isn't for a homework assignment or anything. This is
something I am working on as part of my dissertation.
--
View this message in context:
Hello Everyone,
Trying to learn a little bit about data mining. I'm working on a text mining
project that will attempt to predict whether cancer patients got a particular
type of genetic testing. A subsequent stage then will be aimed at predicting
what the results of that testing were.
I've
Hi Ivan,
We are in the process of creating an R mode for highlight.js -- will send
you a pull request as soon as its ready.
Cheers,
J.J. Allaire
j...@rstudio.org
--
View this message in context:
http://r.789695.n4.nabble.com/Support-for-R-in-highlight-js-tp4551547p4568141.html
Sent from the
Hi Michael,
that's exactly the problem. The format for time series you suggest requires
to have a reading from every timestamp of every sensor. But that is not the
case at all, unfortunately :-(
It might well be in my case, that one sensor reports 1000 readings during
one day while the other
On Wed, Apr 18, 2012 at 8:45 AM, slavrenz stevelavr...@hotmail.com wrote:
I would like to display with the xyplot() function
for several states. I will have a total of 6 plots, I need to plot the
points of one of the states in a different color than all the rest, such
that they can be more
Try recording the data as a rectangle with 3 entries in each row
timestamp, sensor_id, sensor_reading
You can read this into an R data.frame, sensorData, with a call to read.csv
then use
z - split(sensorData, sensorData$sensor_id)
to make a list of data.frames, one for each sensor, that you
I think that mostly avoiding the statistics and matrix capabilities is wise.
You might want to (re-)read Burns' article on Spreadsheet Addiction for help in
justifying the effort required to learn R.
In that vein, there is a classic experiment where a small ball is rolled down
an inclined pane
Hello,
I have two date strings, say 1972-06-30 and 2012-01-31, and I'd like to
get every quarter period end date between those dates? Does anyone know how
to do this? Speed is important...
Here is a small sample:
Two dates:
2007-01-31
2012-01-31
And I'd like to get this:
[1] 2007-03-31
Hi Ben,
A couple of quick comments:
the semicolons at the end of each line are unnecessary (they're
harmless, but considered bad style -- most common in code of C and
MATLAB coders
yes, I know, just forgot to clean it up after translating :)
You don't need to source(getband.R) inside
On Apr 18, 2012, at 12:31 PM, Jeff Newmiller wrote:
I think that mostly avoiding the statistics and matrix capabilities
is wise. You might want to (re-)read Burns' article on Spreadsheet
Addiction for help in justifying the effort required to learn R.
In that vein, there is a classic
Hi,
Encountering the following error using Amelia -
Error in if (sum(non.vary == 0)) { :
argument is not interpretable as logical
In addition: Warning message:
In FUN(X[[34L]], ...) : NAs introduced by coercion
Seems like a bug.
__
Now I have to put my money where my mouth is. I've offered to visit a
high school and introduce R to some fairly advanced students
participating in a longitudinal 3-year science research class.
I anticipate keeping things very simple:
--objects and the fact that there is stuff inside them.
Do you mean the Amelia package? Or a function named Amelia()?
What is your OS and version of R and package?
What are the commands you are using?
What do your data look like?
Can you provide a reproducible example?
Did you read the posting guide?
Your problem doesn't seem like a bug rather
Hi Rainier,
Thanks for your suggestions. I should have been more specific, I am using
multiple cores on a Mac Pro running Snow Leopard. I can see where that makes a
difference.
--David
On 4/18/12 12:13 AM, Rainer M Krug r.m.k...@gmail.com wrote:
-BEGIN PGP SIGNED MESSAGE-
Hash:
On Apr 18, 2012, at 11:58 AM, Ben quant wrote:
Hello,
I have two date strings, say 1972-06-30 and 2012-01-31, and I'd like to
get every quarter period end date between those dates? Does anyone know how
to do this? Speed is important...
Here is a small sample:
Two dates:
2007-01-31
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf
Of Hadley Wickham
Sent: Wednesday, April 18, 2012 10:37 AM
To: Christopher W Ryan
Cc: R-help
Subject: Re: [R] introducing R to high school students
Now I have to put my money
Using: Amelia::amelia
R version: 2.15
OS: Windows 7 Enterprise
data = National Election Studies (cross-sectional); mostly ordinal
variables, some nominal
summary(ad04)
insurance jobs services sswomen
Min. :1.000 Min. :1.000 Min. :1.000
I've had a little experience using the package, Amelia. Are you sure that
your nominal variables - race, south, etc - are in your ad04 data frame ?
David Freedman
--
View this message in context:
http://r.789695.n4.nabble.com/Amelia-error-tp4568455p4568600.html
Sent from the R help mailing
Hi,
On Wed, Apr 18, 2012 at 2:18 PM, Gaurav Sood gsoo...@gmail.com wrote:
Using: Amelia::amelia
R version: 2.15
OS: Windows 7 Enterprise
data = National Election Studies (cross-sectional); mostly ordinal
variables, some nominal
summary(ad04)
insurance jobs services
On 2012-04-18 11:18, Gaurav Sood wrote:
Using: Amelia::amelia
R version: 2.15
OS: Windows 7 Enterprise
data = National Election Studies (cross-sectional); mostly ordinal
variables, some nominal
summary(ad04)
insurance jobs services sswomen
Min.
Sarah -
I have all the vars.. they all look sensible. I have been able to
trace the problem to NAs in the nominal variable, which is a bit
strange. The error that the program spits out is a class logical
equating error in presence of NAs etc. and hence was my hunch that it
was a bug.
On Wed,
Easily fixed, Peter -
str(ad04)
'data.frame': 1195 obs. of 15 variables:
$ V040001 : num 1 2 3 4 5 6 7 8 9 10 ...
$ insurance: num 7 2 4 1 5 2 7 1 5 5 ...
$ jobs : num 7 3 4 1 6 5 7 5 4 7 ...
$ services : num 5 2 5 1 5 2 7 1 4 7 ...
$ ss : num 2 2 2 1 2 1 2 1 1 3 ...
$
On 12-04-17 11:50 PM, David Bapst wrote:
Hi all-
Henrik, packageDescription informs me that I have Matrix version 1.0-6,
which is the newest version on CRAN.
The --as-cran check in R 2.15.0 is a little bit too aggressive: this
was a spurious error. If your package depends on another
On Apr 18, 2012, at 2:05 PM, Marc Schwartz wrote:
On Apr 18, 2012, at 11:58 AM, Ben quant wrote:
Hello,
I have two date strings, say 1972-06-30 and 2012-01-31, and I'd
like to
get every quarter period end date between those dates? Does anyone
know how
to do this? Speed is important...
Cecile:
On Wed, Apr 18, 2012 at 8:21 AM, Cecile De Cat c.de...@leeds.ac.uk wrote:
Hello,
I'm analysing reaction time data from a linguistic experiment (a variant of
a lexical decision task). To ascertain that the data was normally
distributed, I used *shapiro.test *for each participant
On Apr 18, 2012, at 1:49 PM, David Winsemius wrote:
On Apr 18, 2012, at 2:05 PM, Marc Schwartz wrote:
On Apr 18, 2012, at 11:58 AM, Ben quant wrote:
Hello,
I have two date strings, say 1972-06-30 and 2012-01-31, and I'd like to
get every quarter period end date between those dates?
Hi,
I am trying to use xyplot to plot the relationship between size and day
(y~x) by a food factor that has two levels, low and high. I have 3 reps per
factor/day. I want the plots from each food treatment on the same axiss,
so I used this code:
xyplot(Size ~ Day, groups = Food, data =
If the students are in a science research class, does that mean they
have data from their own research that they would want to understand
better? I think that would be much more motivating than anything else.
It might depends on the class - most high school science experiments
aren't that
Please read ?panel.superpose again and pay attention to the
panel.groups argument, where this can be specified.
-- Bert
On Wed, Apr 18, 2012 at 12:34 PM, Louis Plough lplo...@usc.edu wrote:
Hi,
I am trying to use xyplot to plot the relationship between size and day
(y~x) by a food factor
Dear R experts:
could someone please point me to a page that explains how to set up
more than 1 machine for library parallel (which is quickly becoming my
favorite!)
my dream setup would be a design where I just pass a list of
hostnames:user:password to my parallel master, and then start R
dear list members
I tried to install qvalue package from biocLite, and I am confronted with
the following error:
Tcl/Tk support is not available on this system.
I installed the newest version of Tcl/Tk in my system, and then uninstall
and install R 2.15.0 again.
I did the command line as
I ues R on a Linux server running under Screen or Emacs server from a Mac
desktop.
I use Screen and/or Emacs server so that I can reattach to long running
sessions, and this works well except...
If X11 server on my desktop is shut down, or my ssh connection is broken, I get
this error on the
So the lapply function checks every country pair row for row (in my country1
and country2 column) and send back a true if both countries are EU?
How do I get a 1 instead of true and 2 instead of false?
You have been a BIG help.
I have a WHOLE assignment to get done, so maybe I'll post some more
If you could lead me to an example with code, that would help me figure out
how to do it for my function
On Wed, Apr 18, 2012 at 3:57 PM, Louis Plough lplo...@usc.edu wrote:
I read it, but I guess I don't quite understand which arguments to pass
panel.groups to get different lm objects based
Cecile De Cat c.decat at leeds.ac.uk writes:
I'm analysing reaction time data from a linguistic experiment (a variant of
a lexical decision task). To ascertain that the data was normally
distributed, I used *shapiro.test *for each participant (see commands
below), but only one out of 21
I wanted to do an F-test to compare model L2 with L3 assuming
heteroskedasticity. The variable KONK2 only has three levels and are for
that reason replaced by dummyvariables KONKD1 and KONKD2 in L3. Hence making
L4 equivalent to L2.
L2-lm(PRMRES ~ factor(NYPR) + KONK2 + OMS + factor(NYPR)*OMS )
Oh... I see!!! I very appreciate for your clear explanation! Thank you, Uwe
Ligges.
--
View this message in context:
http://r.789695.n4.nabble.com/General-question-on-the-message-with-non-zero-exit-status-tp4551438p4568839.html
Sent from the R help mailing list archive at Nabble.com.
Dear useRs,
A colleague has sent me several batches of output I need to process, and I'm
struggling with the format to the point that I don't even know how to extract a
test set to upload here. My apologies, but I think that my issue is
straightforward enough (for some of you, not for me!)
Is there a way to find all roots of a polynomial equation?
Lets say
x^5+a*x^4+b*x^3+c*x^2+d*x+e=0
how to find its all roots?
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
On 12-04-18 4:14 PM, Michael wrote:
Is there a way to find all roots of a polynomial equation?
Lets say
x^5+a*x^4+b*x^3+c*x^2+d*x+e=0
how to find its all roots?
polyroot() should be able to do it, assuming that a,b,c,d and e are
numeric or complex values, not just symbols.
Duncan
On 19/04/12 08:14, Michael wrote:
Is there a way to find all roots of a polynomial equation?
Lets say
x^5+a*x^4+b*x^3+c*x^2+d*x+e=0
how to find its all roots?
I believe that Galois (or maybe it was Abel) proved that this
is *NOT* possible, a couple of centuries ago.
However if you are
please look at the ancova function in the HH package.
On Wed, Apr 18, 2012 at 3:34 PM, Louis Plough lplo...@usc.edu wrote:
Hi,
I am trying to use xyplot to plot the relationship between size and day
(y~x) by a food factor that has two levels, low and high. I have 3 reps per
factor/day. I
Le mercredi 18 avril 2012 à 13:13 -0700, Vining, Kelly a écrit :
Dear useRs,
A colleague has sent me several batches of output I need to process, and I'm
struggling with the format to the point that I don't even know how to extract
a test set to upload here. My apologies, but I think that
On Wed, Apr 18, 2012 at 07:15:45AM -0700, uday wrote:
hi Petr ,
Thanks for replay and sorry for typo mistake
approx(pres, sci.pre) its nothing but approx(pre2, pre1).
so for more simplicity
x - c(10.34615 , 52.02116, 146.17357, 243.28644, 347.41504, 431.67105,
521.42712,
On Wed, Apr 18, 2012 at 2:07 PM, Louis Plough lplo...@usc.edu wrote:
If you could lead me to an example with code, that would help me figure out
how to do it for my function
The states example in ?xyplot uses groups and subscripts in a panel function
I read it, but I guess I don't quite
x - rep(1:10,4)
y - runif(40)
z - sample(letters[1:4],40,rep=TRUE)
grp - sample(LETTERS[1:2],40,rep=TRUE)
xyplot(y~x|z, group=grp, panel = panel.superpose,
panel.groups = function(...){
panel.xyplot(...)
panel.lmline(...)
})
Keys (legends), colors, line styles,etc, can all be
Thanks for your help, Milan, in showing me a way to exhibit the structure of my
data.
# Again, my data sets are:
[1] res.Callus.Explant res.Callus.Regen res.Explant.Regen
# Structure is:
str(res.Callus.Explant)
List of 18
$ name : chr two group comparison
$ group1 : chr
Try this (NOT tested) or something similar:
all.comps - ls(pattern=^res)
for(i in all.comps) {
obj - all.comops[[i]]
gene.ids - rownames(obj$counts)
x - data.frame(gene.ids = gene.ids, obj$counts,
obj$e1, obj$e2,
obj$log.fc, obj$p.value,
obj$q.value)
x -
On Wed, Apr 18, 2012 at 12:58 PM, Ben quant ccqu...@gmail.com wrote:
Hello,
I have two date strings, say 1972-06-30 and 2012-01-31, and I'd like to
get every quarter period end date between those dates? Does anyone know how
to do this? Speed is important...
Here is a small sample:
Two
Hi all,
Here is an integration function
require(pracma) # for 'quadinf'
myint=function(j) {
quadinf(function(x)
(1/(1+exp(-x)))^j*(1-1/(1+exp(-x)))^(k-j)*dnorm(x,mu,casigma),-Inf,Inf)
}
in any optimization routine. It works fine most of the time but failed with
some particular sets of
Hello all,
I would like to rigorously test whether observations in my dataset are
outliers. I guess all the main tests in R (Grubbs) impose the assumption
of normality. My data is surely not normal, so I would like to use
something else. As far as I can tell from wikipedia, Peirce's criterion
Hello,
I'd be very grateful for help with some ggplot2's stat_density2d issues.
First issue is with data limits. xlim() and ylim() doesn't seem to
work; instead, estimates (and plotting) seems to be constrained to
range(x), range(y) no matter what i do. The documentation says i can
pass in
On Apr 18, 2012, at 6:55 PM, Dmitriy Lyubimov wrote:
Hello,
I'd be very grateful for help with some ggplot2's stat_density2d
issues.
First issue is with data limits. xlim() and ylim() doesn't seem to
work; instead, estimates (and plotting) seems to be constrained to
range(x), range(y) no
Is there a way to find all roots of a polynomial equation?
Lets say
x^5+a*x^4+b*x^3+c*x^2+d*x+e=0
how to find its all roots?
The package rootSolve might proove interesting
__
R-help@ mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
1 - 100 of 121 matches
Mail list logo
