Ok, I forgot to say that 't' is also an R function, the matrix transpose.
Sorry, but after 'par' I thought (in my mind) I had said it when in fact I
even talked about 't'!
Use 'tt'.
If 'tt' is a vector you must first define it, in your code it doesn't exist.
That's why R searches for and finds an
Hello Rui,
First of all, thanks a lot!
1. I changed par to param,
2. t is a variable too, a binary one, b is the parameter associated to it,
4. Yes, this is where I am stuck actually.
I fixed the code for likelihood functions as follows, but still getting the
same error:
L3 -
hi all,
my data is here,
--
data
clss number
1A 1
2B 2
3C 3
4A 4
5B 5
6C 6
7A 7
8B 8
9C 9
Hi all,
I've just downloaded and installed the latest R 32-bit version plus RExcel
and R Commander.
I'm having several problems in loading gogarch package:
The command *library(gogarch, pos=4)* returns *ERROR: package/namespace load
failed for 'gogarch'*
The command *require(gogarch)* returns
If I use gogarch_0.7-1 the command *require(gogarch)* returns the following
error: *Error in get(.packageName, where) : cannot allocate memoby block
of size 3.2 Gb*
--
View this message in context:
http://r.789695.n4.nabble.com/R-i386-2-15-0-gogarch-package-issue-tp4629888p4629889.html
Sent from
On May 14, 2012, at 02:24 , Luna wrote:
Thanks!
Do you think if the correctness of the such results could be generalized to
other future cases?
If correctly generalized, yes
(Apologies for being slightly facetious; the point is that the properties you
build on are part of the
Ok, solved.
If anyone had the same problem, just install the last gogarch pacakge (vers.
0.7-1) and restart R + R Commander after the package installation.
When you've restarted it, the command *require(gogarch)* should load fastICA
package in the end and it will work ;)
--
View this message in
On 14-05-2012, at 07:14, mrzung wrote:
hi all,
my data is here,
--
data
clss number
1A 1
2B 2
3C 3
4A 4
5B 5
6C 6
7A 7
Hi,
How is it possible to change the character size of labels in a histogram
(labels parameter in hist)?
How is it possible to display the ranges of an axis in 3 significant digits?
Thanks
Carol
[[alternative HTML version deleted]]
__
Sir,
I have large data sets of economic indicators and would like to align
them to a reference series - say the unemployment rate or industrial
production.
Is there a canned routine that returns the optimal lead / lag
according to some (or a variety) of algorithims? not all series will
be of the
Thanks for the suggestion. The file name in my case is Chinese, which
makes the regular expression less useful.
Anyway, I would like to pose a followup question.
I have a character string of ABC\D, and want to strip away the \
and want a returned character of ABCD. How can I do it with gsub() ?
Hi, Carol!
How is it possible to change the character size of labels in a histogram
(labels parameter in hist)?
See
?par
- cex.axis
How is it possible to display the ranges of an axis in 3 significant
digits?
See
?axis
and its argument at together with
?signif
Hth -- Gerrit
Thanks Gerrit.
cex.axis changes the size of the axis label. I want to change the size of data
labels that are displayed at the top of the bars in the histogram. What we
obtain by
histogram(...,labels=T)
Any clue?
Cheers,
From: Gerrit Eichner
No, but make.names only makes syntactically valid names of R object.
I think I have mentioned what I did in the first email, although no
concrete example was provided. Let me explain a bit. I have a text
file like this,
Title:AA?
Content: 1xx1
Title:BA
Content: 2xx2
I want
This works on Mac:
str - abc/d
gsub(/, , str)
Return:
abcd
Sent from my iPhone
On May 14, 2012, at 4:28 AM, Wincent ronggui.hu...@gmail.com wrote:
Thanks for the suggestion. The file name in my case is Chinese, which
makes the regular expression less useful.
Anyway, I would like to pose
Emm, my bad.
I meant str - abc\d.
Any ideas?
On 14 May 2012 18:02, Baoqiang bqcaom...@gmail.com wrote:
This works on Mac:
str - abc/d
gsub(/, , str)
Return:
abcd
Sent from my iPhone
On May 14, 2012, at 4:28 AM, Wincent ronggui.hu...@gmail.com wrote:
Thanks for the suggestion. The
Hello all,
here's a real-world example: I'm measuring a quantity (d) at five
sites (site1 thru site5) on a silicon wafer. There is a clear
site-dependence of the measured value. To find out if this is a
measurement artifact I measured the wafer four times: twice in the
normal position (posN), and
On 14-05-2012, at 12:07, Wincent wrote:
Emm, my bad.
I meant str - abc\d.
Any ideas?
gsub(, , str)
Berend
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide
Dear R users,
I am building a packaged where I want to use the update.formula function, but
modifying the option simplify = FALSE to TRUE. Since this is not an
argument, I modified the code and created a new function as:
update.formula2 - function (old, new, ...)
{
tmp -
Hello.
I'm trying to see clusters into a certain number of classes as seeing they are
too many of them see entirely on dendrogram. So I did the following:
d - dist(as.matrix(medData)) hc - hclust(d, method=average) plot(hc)
plot(hc, hang = -1)
But when it came to this: rect.hclust(hc, 3)Error
Carol,
it is not clear to me which function histogram() you use (package lattice,
package histogram ...?), but -- if it is not a lattice function -- a quick
hack _might_ be to use
par( cex = 2)
or whatever magnification you wish followed by a reduction of cex.axis,
cex.labels etc.
On Mon, May 14, 2012 at 5:09 AM, Matthew Johnson mcoog...@gmail.com wrote:
Sir,
I have large data sets of economic indicators and would like to align
them to a reference series - say the unemployment rate or industrial
production.
Is there a canned routine that returns the optimal lead /
On 13.05.2012 14:37, Rui Barradas wrote:
Hello,
It seems like a feature. When trying the example below with more
atops, the two bottom most lines, and only those two lines, feature
character expansion relative to the default size and relative to the
line before last.
plot(1, type=n,
On 11.05.2012 11:06, achughes wrote:
Dear All
I would really appreciate some help with a script which a colleague wrote
for me (attached), but I am having problems running (and have not been able
to contact my colleague).
I think you have to contact your colleague or you have to provide
Hello,
Probably you should try:
update.packages(checkBuilt=TRUE)
install.packages('gogarch', dependencies=TRUE)
Best Regards,
Pascal
- Mail original -
De : Cren oscar.soppe...@bancaakros.it
À : r-help@r-project.org
Cc :
Envoyé le : Lundi 14 mai 2012 16h06
Objet : [R] R i386 2.15.0
Hi,
I'm still having problems putting the variance components of my model in to
a data frame, it is a continuation of this discussion,
http://r.789695.n4.nabble.com/ANOVA-problem-td4609062.html, but now focussed
on the problem of extracting variance components. I have got my mixed
effects model
Hey guys,
i have a strange problem reading a .csv file.
Seems not to be covered by the usual read.csv techniques.
The relevant data i want to use, seems to be saved as the label of the data
point.
Therefore i can not really use it
spec-EU2001
Hi
I am comparing the output of rollmax in two versions of R. In the
current version, the column names are 'lost' ie NULL in the output; in
the earlier version they were retained.
Function rollapply has the same behaviour as before.
Is this change in rollmax behaviour deliberate?
Thanks
I am new to R and starting to explore its functionality. I wondered if anyone
could advise whether R supports non-linear canonical correlation and/or the
specification of models using alternating least squares?
Thanks
Ron
[[alternative HTML version deleted]]
Hello again,
I changed the name to tt.
and for a and tt actually I was getting them from data, I didn't put them
here in the question. Now I restructured my code and below I copy the full
code, I tried many things but still getting the same error, I don't
understand where is the mistake.
I also
Dear Uwe
I did previously attach the script, but I include it again here in addition to
current and future projections (which come from different directories).Help
would very much be appreciated!
Alice
Date: Mon, 14 May 2012 04:52:04 -0700
From: ml-node+s789695n4629915...@n4.nabble.com
To:
I am using cv.glmnet from glmnet package for logistic regression.
my dataset is very imbalanced, 5% sample from one group, the rest from the
other. I'm wondering when doing cv.glmnet for choosing lambda, is every fold
having the same ratio for two groups(every fold has 5% sample from one
group,
Hi everyone,
I am having some problems with making a new colomn wit data in it.
I have this one column named: Fulfilled
Fulfilled
1
1
0
1
1
1
1
0
0
1
And now I would like to add another colum to my .csv file (Finished)
In this Finished column I would like to have Yes or No.
Where in colomn
That script is simple broken, the object bat.asc is used but not defined
anywhere. Since the code is also not really optimal, you may want to ask
an expert who knows how to write such script and how to test if their
code work in the end.
Best,
Uwe Ligges
On 14.05.2012 14:12, achughes
Hello,
How could we get the confidence interval when using the whittleFit
method from fArma package?
--
Thanks,
Barun Saha
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PLEASE do read the posting guide
Pascal Oettli-2 wrote
Hello,
Probably you should try:
update.packages(checkBuilt=TRUE)
install.packages('gogarch', dependencies=TRUE)
Best Regards,
Pascal
Dear Pascal Oettli-2,
thank you for your suggestment; I was not aware of that command and it will
be very useful when new
Hi Rui,
Thanks once again for all the help. I need to ask for one more help from you. I
have two matrices, with probesets as rows and samples as columns.
The samples in the two matrices are matched (from the same animal but two
different tissues). I want to create a correlation matrix of
Giles,
thanks for the bug report:
I am comparing the output of rollmax in two versions of R. In the
current version, the column names are 'lost' ie NULL in the output; in
the earlier version they were retained.
Yes, this was an error. I just fixed it in the devel version on R-Forge.
Assuming you actually have a data frame or matrix, and not a csv file, ifelse()
is the general solution to your problem.
Sarah
On May 14, 2012, at 8:45 AM, Yellow s1010...@student.hsleiden.nl wrote:
Hi everyone,
I am having some problems with making a new colomn wit data in it.
I have
I just upgraded to Ubuntu Quantal from Precise and RJava stopped working,
log follows:
0}% /usr/bin/find $HOME/workspace/FinanceOCR/visualizations/ -name '*R'
-print | /usr/bin/xargs -n 1 -i% /usr/bin/Rscript % $1 [~]
Loading required package: RJDBC
Loading required package: methods
Loading
Oh, so we can always combine model matrices and formulas in regression in R?
Thanks!
On Mon, May 14, 2012 at 2:41 AM, peter dalgaard pda...@gmail.com wrote:
On May 14, 2012, at 02:24 , Luna wrote:
Thanks!
Do you think if the correctness of the such results could be generalized
to
How do I do group wise clustering in R?
Hi all,
I have N x K data matrix, where N is the number of observations, K is the
number of variables.
The N observations fall into M categories or groups.
Now I want to cluster the groups, instead of the observations, how do I do
that?
i.e. the
Something along the lines of
dat2 - ifelse( dat1==1 , yes, no)
should do it.
John Kane
Kingston ON Canada
-Original Message-
From: s1010...@student.hsleiden.nl
Sent: Mon, 14 May 2012 05:45:38 -0700 (PDT)
To: r-help@r-project.org
Subject: [R] Add column from other columns data.
I don't think this is so hard to explain. If you evaluate AUC using either OOB
prediction or on a test set (or something like CV or bootstrap), that would be
what I expect for most data. When you add more variables (that are, say, less
informative) to a model, the model has to look harder to
That worked.
Thanks. :)
--
View this message in context:
http://r.789695.n4.nabble.com/Add-column-from-other-columns-data-tp4629921p4629937.html
Sent from the R help mailing list archive at Nabble.com.
__
R-help@r-project.org mailing list
One way is to use the reshape2 package
===
library(reshape2)
dcast(xx, A ~ . , sum)
John Kane
Kingston ON Canada
-Original Message-
From: mrzun...@gmail.com
Sent: Sun, 13 May 2012 22:14:02 -0700 (PDT)
To:
Hi,
I was trying to create a dendrogram using ggplot2. Everything seems to be
looking ok except that the text labels are too close to the dendrogram (in
the example below, 'a','b', ..). Is there a way that I can put a little gap
between where the dendrogram ends and the label begins?
thanks!!
On May 14, 2012, at 6:35 AM, Berend Hasselman wrote:
On 14-05-2012, at 12:07, Wincent wrote:
Emm, my bad.
I meant str - abc\d.
Any ideas?
gsub(, , str)
#1: One cannot execute: str - abc\d , at least on my machine,
since that throws an error because \d is an unrecognized escape.
Dear R-helpers, Christoph (author of phyloclim) and Luke (author of
tkrplot),
I would like to get your helps on installing of phyloclim in Ubuntu linux.
It seems a package named 'tkrplot' could not be installed at firstly, then
packages depends on it could not be installed latter.
As I have
Wow, I'll have to study this one for a bit. Thanks!
Ben
On Sat, May 12, 2012 at 3:09 PM, William Dunlap wdun...@tibco.com wrote:
Here is some code that I've been fiddling with for years
(since I wanted to provide evidence that our main office
needed more modems and wanted to show how often
On May 14, 2012, at 5:33 AM, barb wrote:
Hey guys,
i have a strange problem reading a .csv file.
Seems not to be covered by the usual read.csv techniques.
The relevant data i want to use, seems to be saved as the label of
the data
point.
Therefore i can not really use it
spec-EU2001
Great solution! Thanks!
Ben
On Sat, May 12, 2012 at 12:50 PM, jim holtman jholt...@gmail.com wrote:
Here is an example of how you might do it. It uses a technique of
counting how many items are in a queue based on their arrival times;
it can be used to also find areas of overlap.
Note
It doesn't: You just get an error if there are NAs in the data; e.g.,
R rf1 = randomForest(iris[1:4], iris[[5]])
R predict(rf1, newdata=data.frame(Sepal.Length=1, Sepal.Width=2,
Petal.Length=3, Petal.Width=NA))
Error in predict.randomForest(rf1, newdata = data.frame(Sepal.Length = 1, :
I'm using glmnet for logistic regression, I got a fairly sparse dataset,
20,000 samples(very imbalanced too, 5% from one group), 1500 variables,.
the code have beed running for 2 hours, still waiting for result, I am doing
lasso here(alpha=1), my computer is core 2 due CPU @3Ghz, 4GB ram, why
cloudRmpi v 1.2 is now available on CRAN.
cloudRmpi is a means for doing parallel processing in R, using MPI on a
cloud-based network. It currently
supports the use of Amazon's EC2 cloud computer service.
Changes in v 1.2:
Support for RStudio. RStudio Server is available on new AMIs.
If you have a data.frame and you want a table in Microsoft Word, the
quickest path (without additional packages and assuming you are using
Windows) is
write.table(DataFrameName, file=clipboard, sep=\t, row.names=FALSE)
# If the file is large, you may need clipboard-128 instead of clipboard.
Now
You didn't tell us what your problem is, but it probably relates to the fact
that mydata is never defined.
--
David L Carlson
Associate Professor of Anthropology
Texas AM University
College Station, TX 77843-4352
-Original Message-
From:
Look at the aggregate function to create a new data.frame in which you have
M rows that have the means of the K variables for each group. Then use
cluster analysis to cluster the M groups.
--
David L Carlson
Associate Professor of Anthropology
Texas AM
Dear all,
I am sure it won't be difficult for you!!
I need to calculate the average among variables for the single units of my
dataset.
But, while doing it, I need to do not consider some values.
To better explain, think like there are two units and three variables:
V1V2 V3
[1] 3
You will find functions such as these in the thousands of packages that are
available once you have installed R. You can use rseek.org to search for
specific topics. Good overviews are found in the CRAN Task Views (from the
main R webpage, click on CRAN, select a mirror host, and then select Task
On Sun, May 13, 2012 at 7:10 PM, Ruijie breakaw...@gmail.com wrote:
Hi all,
I have data collected from a survey administered on a subset of the
population. I also have the population proportions of variables such as
gender, race and housing type. I would like to combine the weights from
each
By the way, in my last post I forgot to return negative of llfn, hence the
llfn will be as follows:
llfn - function(param) {
bx - param[1]
b1 - param[2]
b2 - param[3]
b3 - param[4]
b - param[5]
lL1 - log(L1(bx,b1,b2,b,tt))
lL2 - log(L2(bx,b1,b2,b3,b,tt))
lL3 - log(L3(bx,b1,b2,b3,b,tt))
But shouldn't it be resolved when I set mtry to the maximum number of
variables?
Then the model explores all the variables for the next step, so it will
still be able to find the better ones? And then in the later steps it could
use the (less important) variables.
Matthijs
--
View this message
Hey David,
thanks for your fast reply, i really appreciate that you answer so many
posts.
Unfortunately it´s not that easy. Try to operate with the output:
e.g
file-read.csv2(tmp,sep=;,skip=5)
a-(relevant-file[,2][1])
a*5
# or
as.numeric(relevant-file[,2][1])
a is saved in the workspace as
Well, I'm going to reply to my own thread with a solution here, turns out
one attempt we made last week nearly had it, slight adjustment made it work.
For anyone that is interested / in the future wants to achieve the same
thing
*varcomp - matrix(nrow=0, ncol=3)
for (i in
Hello again,
You are absolutely right about probabilities.. Thanks for reminding me about
that.
I did exactly how you said but in the end I receive the error : objective
function in optim evaluates to length 12 not 1.
I checked how llfn give a vector instead of scalar, but couldn't figure it
Hello, again.
Bug report:
1. Your densities can return negative values, 1 - exp(...) 0.
Shouldn't those be 1 PLUS exp()?
P3 - function(bx,b3,b,tt) {
P - exp(bx*x+b3+b*(tt == 1))/(1+exp(bx*x+b3+b*(tt == 1)))
return(P)
}
And the same for P2 and P1?
2. Include 'a' and 'tt' as
This was actually discussed about a week and a half ago with many good
solutions offered, but I think the most idiomatic would be something
like this:
apply(dataset, 1, function(x) mean(x[x0]))
The reasons I like it:
i) It uses the apply function to do the same operation row-wise
(that's what
Hello. I have a 4 dimensional array and I want to fill in the slots with
values which are a function of the inputs. Through searching the forums here
I found that the function outer is helpful for 2x2 matrices but cannot be
applied to general multidimensional arrays. Is there anything which can
On Mon, May 14, 2012, at 02:33, barb wrote:
Hey guys,
i have a strange problem reading a .csv file.
Seems not to be covered by the usual read.csv techniques.
The relevant data i want to use, seems to be saved as the label of the
data
point.
Therefore i can not really use it
On May 14, 2012, at 12:32 PM, Andrea Sica wrote:
Dear all,
I am sure it won't be difficult for you!!
I need to calculate the average among variables for the single units
of my
dataset.
But, while doing it, I need to do not consider some values.
To better explain, think like there are two
Once again, sorry.
I had a different llfn in my R session and it messed with yours.
llfn - function(param, a, tt) {
llfn - sum((a==1)*lL1+(a==2)*lL2+(a==3)*lL3) # sum of logs, it's a
log-likelihood.
return(-llfn)
}
Rui Barradas
infinitehorizon wrote
Hello again,
You are absolutely
Thank you all. Really!
I have used the following function:
apply(dfrm, 1, function(x) mean(x[x=0]) )
Someone of you even gave me a few interesting explanations
about why to use it.
Still thank you all.
Andrea
On Mon, May 14, 2012 at 6:52 PM, David Winsemius dwinsem...@comcast.netwrote:
On
Hello,
Try
K - array(0,dim=c(2,2,2,2)) #dimensions will be much larger
for(x1 in 1:2){
for(y1 in 1:2) {
for(x2 in 1:2){
for(y2 in 1:2) {
K[x1,y1,x2,y2] - x1*y2 - sin(x2*y1) #this is just a dummy
function.
}
}
}
}
fun - function(x){
x1 - x[1]
On May 14, 2012, at 11:23 AM, barb wrote:
Hey David,
thanks for your fast reply, i really appreciate that you answer so
many
posts.
Unfortunately it´s not that easy. Try to operate with the output:
e.g
file-read.csv2(tmp,sep=;,skip=5)
a-(relevant-file[,2][1])
a*5
# or
Of course, that was the trick! It works now. Thank you very much Rui, I am
very grateful.
I hope this thread will help others as well.
Best,
Rui Barradas wrote
Once again, sorry.
I had a different llfn in my R session and it messed with yours.
llfn - function(param, a, tt) {
llfn
Hi all,
I try to convert the VBA code below to run it from R using rcom and Power Point.
The VBA code creates a shape and will move the handle of the the shape to
another position.
This fails using rcom and I do not understand what I am doing wrong...
### VBA ###
I usually try google searches first. While not always successful, I am
frequently surprised by how well it does.
I strongly second the use of CRAN task views. IMHO, some fine folks
have volunteered their time and efforts to produce this very well
written series of guides to what's in R. It and
Something weird must be going on in your s641_social object. Can you
just simply check that the vertex names look OK with
'V(s641_social)$name'?
If they look good, then can you send me the s641_social object in
private? (Or part of it, assuming a part is enough to reproduce the
problem.)
Best,
This overwrites the data so you might want to create a copy first.
example - data.frame(V1=c(3, -1), V2=c(-2, 4), V3=c(4, 1))
tf - ifelse(example0, TRUE, FALSE)
example[tf] - NA
apply(example, 1, mean, na.rm=TRUE)
--
David L Carlson
Associate Professor
On May 14, 2012, at 10:09 AM, math_daddy wrote:
Hello. I have a 4 dimensional array and I want to fill in the slots
with
values which are a function of the inputs. Through searching the
forums here
I found that the function outer is helpful for 2x2 matrices but
cannot be
applied to
See below.
On 14-05-2012, at 13:21, infinitehorizon wrote:
Hello again,
I changed the name to tt.
and for a and tt actually I was getting them from data, I didn't put them
here in the question. Now I restructured my code and below I copy the full
code, I tried many things but still
Hi,
On Mon, May 14, 2012 at 12:44 PM, Bert Gunter gunter.ber...@gene.com wrote:
I usually try google searches first. While not always successful, I am
frequently surprised by how well it does.
rseek.org is simply a custom Google search for R-related things. It
does an even better job pulling
On 10/03/2012 9:44 AM, Duncan Murdoch wrote:
My first reply to this went privately, by accident. I've done a little
editing to it, but mainly this is for the archives.
On 12-03-09 2:36 PM, Michael Friendly wrote:
For a paper dealing with generalized ellipsoids, I want to illustrate in
3D
Hi,
~ well that seems to be a better solution.
Question is how much an enviroment for each node costs in terms of
save space..
The example code is hard to present, because it is really based on that
problem.
The frame of the problem is, that I have to write a program that gives
each node in a
Turns out this solution doesn't work if the s range is outside the range of
the x range. I didn't include that in my examples, but it is something I
have to deal with quite often.
For example s1_rng below causes an issue:
x_rng = c(-100,100)
s1_rng = c(-250.5,30)
s2_rng = c(0.77,10)
s3_rng =
On May 14, 2012, at 1:56 PM, jackl wrote:
Hi,
~ well that seems to be a better solution.
Question is how much an enviroment for each node costs in terms of
save space..
Seems unlike that it would expand you space very much. Every function
you create will have an environment.
The
To the list of function I sent, add another that converts a list of intervals
into a Ranges object:
as.Ranges.list - function (x, ...) {
stopifnot(nargs() == 1, all(vapply(x, length, 0) == 2))
# use c() instead of unlist() because c() doesn't mangle POSIXct and Date
objects
x
Yes, it is. I'm looking into understanding this now...
thanks!
Ben
On Mon, May 14, 2012 at 12:38 PM, William Dunlap wdun...@tibco.com wrote:
To the list of function I sent, add another that converts a list of
intervals
into a Ranges object:
as.Ranges.list - function (x, ...) {
That's not how RF works at all. The setting of mtry is irrelevant to this.
Andy
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org] On
Behalf Of matt
Sent: Monday, May 14, 2012 10:22 AM
To: r-help@r-project.org
Subject: Re: [R] Random forests
Hi all,
Nice code samples presented all around.
Just wanted to point out that I think the stuff found in the
`intervals` package might also be helpful:
http://cran.at.r-project.org/web/packages/intervals/index.html
HTH,
-steve
On Mon, May 14, 2012 at 2:54 PM, Ben quant ccqu...@gmail.com
Hi,
I have a question involving Inf, lazy evaluation, and maybe argument
recycling. I have a directory where I am trying to check for the
existence of files of a certain pattern, basically something like
filename-#, where # is an integer. I can do something like this,
which works.
?list.files
-- Bert
On Mon, May 14, 2012 at 12:34 PM, J Toll jct...@gmail.com wrote:
Hi,
I have a question involving Inf, lazy evaluation, and maybe argument
recycling. I have a directory where I am trying to check for the
existence of files of a certain pattern, basically something like
R is lazy, but not quite that lazy ;-)
It's likely much easier to do this with regexps
something like
list.files()[grepl(paste0(filename, -[0123456789]+), list.files())]
Michael
On Mon, May 14, 2012 at 3:34 PM, J Toll jct...@gmail.com wrote:
Hi,
I have a question involving Inf, lazy
Thank you Steve!
This does everything I need (at this point):
(this excludes ranges y2 from range y1)
library('intervals')
y1 = Intervals(c(-100,100))
y2 = Intervals(rbind(
c(-100.5,30),
c(0.77,10),
c(25,35),
c(70,80.3),
c(90,95)
))
interval_difference(y1,y2)
Object of class
Hello,
I am trying to make a plot of the rates of an enzyme against three different
protein concentrations (there are 45 rates in total and split up into 3 groups
of 15, each receiving one of the 3 protein concentrations). When I enter the
following code I instead get 3 separate boxplots for
Dear R-helpers,
I am stuck on an error in R: When I run my code (below), I get this error
back:
Error in names(x) - value :
'names' attribute must be the same length as the vector
Then when I use traceback(), R gives me back this in return:
`colnames-`(`*tmp*`, value = c(Item, Color
Thank for your response. It is oddly working now.
Thanks again,
Brenda
On 5/14/12 10:36 AM, Gábor Csárdi-2 [via R]
ml-node+s789695n4629973...@n4.nabble.com wrote:
Something weird must be going on in your s641_social object. Can you just
simply check that the vertex names look OK with
Yes, package:intervals uses the same idiom as my code.
Mine allows Date and POSIXct objects as interval endpoints
(which is why it represents the objects as data.frames instead
of matrices). package:intervals has more than basic set
opertions on the collections of intervals.
Bill Dunlap
Thank you all for the replies.
On Mon, May 14, 2012 at 2:45 PM, R. Michael Weylandt
michael.weyla...@gmail.com wrote:
R is lazy, but not quite that lazy ;-)
Oh, what is this world coming to when you can't count on laziness to
be lazy. ;) I should probably stop reading about Haskell and their
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