It depends on which return you want. See
the R computation section of A tale of
two returns.
http://www.portfolioprobe.com/2010/10/04/a-tale-of-two-returns/
Pat
On 05/07/2012 05:58, Akhil dua wrote:
Hello Every one
I have data on Stock prices and I want to calculate the return on all the
I'm a fan of Ggobi--which works well with or without R--but I'm not sure how
it handles enormous data sets. I second the Tufte recommendation, and add:
Interactive and Dynamic Graphics for Data Analysis.
--
View this message in context:
Hello Every one
I have data on Stock prices and I want to calculate the return on all the
stocks
and then replace all the stock prices with the returns
can any one tell me how to do
My data is in the format given below
Date Stock1 Stock2 Stock3
01/01/20001 2
Thanks Petr for the reply.
Let me do implementation and see how how goes.
Enjoy your vacation.
Rest fine
Khris
On Jul 4, 2012, at 8:25 PM, Petr Savicky [via R] wrote:
On Mon, Jul 02, 2012 at 06:11:37AM -0700, khris wrote:
Hi, Petr,
Hi Khris:
If i understand the problem
Hello,
Your eval(tests$rule[1]) needs a slight modification to get the results.
Try this:
tests-read.table(text=
rule
info$country=='Greenland'
info$age50
,sep=,header=TRUE,stringsAsFactors=FALSE)
info-data.frame(first=rep(NA,5),country=c(GReenland,Iceland,Ireland,Greenland,Greenland)
Hi folks,
I'm experiencing some hassle to add some text on a persp plot...
Here is the code to generate the persp plot:
x - seq(-1.95, 1.95, length = 30)
y - seq(-1.95, 1.95, length = 30)
z - outer(x, y, function(a,b) a*b^2)
persp(x, y, z,xlim=c(-2,2),ylim=c(-2,2),zlim=c(-8,8), phi=30,
Hi,
I guess this is what you are looking for:
dat1 - read.table(text=
Date Stock1 Stock2 Stock3 Market
01/01/2000 1 2 3 4
01/02/2000 5 6 7 8
01/03/2000 1 2 3 4
Hi everyone!
I am using the mle {stats4} to estimate the parameters of distributions by
MLE method. I have a problem with the examples they provided with the
mle{stats4} html files. Please check the example and my question below!
*Here is the mle html help file *
On 05.07.2012 06:45, Benjamin Dubreuil wrote:
Hi folks,
I'm experiencing some hassle to add some text on a persp plot...
Here is the code to generate the persp plot:
x - seq(-1.95, 1.95, length = 30)
y - seq(-1.95, 1.95, length = 30)
z - outer(x, y, function(a,b) a*b^2)
persp(x, y,
Please i am Anilkumar G.V studieng MBA final sem for this data i want to
find out non parametric tests please help me
--
Anilkumar G.V
Jr,MBA
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https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting
Dear R-helpers,
currently I am writing a thesis using R in forecasting scenarios.
No the time is shortening and I wanted to set up all test cases, including
the STLF algorithm of the forecast package.
I am using 15 minutes (96 a day) data of two weeks to forecast one week...
The
I have the following in a batch file TLT.BAT:
C:\Program Files\R\R-2.13.2\bin\x64\R.exe CMD BATCH
C:\Users\Frank\Documents\R\Scripts\TLT_2012.txt
C:\Users\Frank\Documents\R\Scripts\TLT_2012.out
PAUSE
The TLT_2012.txt has my R code in it. The TLT_2012.out has the output from R.
Look to
-Original Message-
sample.mean- sum(x*y)/sum(y)
sample.mean
[1] 3.5433
*This is the contradiction!! *
Here I am getting the estimate as 3.5433(which is reasonable
as most of the values are clustered around 3), but mle code
gives the estimate 11.545(which may not be correct as
On Jul 5, 2012, at 10:48 , chamilka wrote:
Hi everyone!
I am using the mle {stats4} to estimate the parameters of distributions by
MLE method. I have a problem with the examples they provided with the
mle{stats4} html files. Please check the example and my question below!
*Here is the mle
hi isabel,
You have to decide if focus is on the survival curves or hazards..
Crossing hazards do not imply crossing survival curves
If you are dealing with crossing hazards, and you are interested in
testing for an effect of a covariate (presumably with a crossing hazard
effect), then a
Hello,
I was just wondering if anyone could recommend a package for R that calculates
2D image correlation, e.g. by 2D canonical correspondence analysis?
Thanks a lot!
MG
[[alternative HTML version deleted]]
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Dear all,
I have got a very big SPSS dataframe and I would like to just import one or
a few variables (the dataframe has got a lot of colums).
I used the package foreign but I couldn't find anything in there for my
problem.
Thank you very much for your help in advance.
Marion
Please read the posting guidelines. So far we have no idea of what you are
doing or how you are doing it.
John Kane
Kingston ON Canada
-Original Message-
From: anilgv...@gmail.com
Sent: Thu, 5 Jul 2012 15:11:20 +0530
To: r-help@r-project.org
Subject: [R] how to analyse non
I don't believe that R-help permits pdf files. A useful workaround is to post
it to a file hosting site like MediaFire and post the link here.
John Kane
Kingston ON Canada
-Original Message-
From: jimmycl...@gmail.com
Sent: Wed, 4 Jul 2012 22:56:02 -0400
To: pauljoh...@gmail.com
if(!require(TTR)){install.packages(TTR); library(TTR)}
? ROC
Michael
On Wed, Jul 4, 2012 at 11:20 PM, Akhil dua akhil.dua...@gmail.com wrote:
Hello Every one
I have data on Stock prices and I want to calculate the return on all the
stocks
and then replace all the stock prices with the
Hi,
I need to create a function from lm formula and coefficients to use it in my
c++ code later.
but when I do it as you said
require(rms)
f - ols( )
g - Function(f)
g(x1=2,x2=3,...)
I realize that it didn't give me the same result as predict.lm?
how can I reach a function to give me the same
Dear list,
Usually we use Hosmer-Lemeshow test to test the goodness of fit for logistic
model, but if I use it to test for Cox model, how can I get the observed
probability for each group?
Suppose I calculated the 5-year predicted probability using Cox model, then
I split the dataset into 10
Dear all,
I'm using the curve() function to plot discharge Q against water depth a.
However, I would like to have a graph of water depth a plotted against
discharge Q. How can this be done?
Minimal working example:
S0 = 0.004
n = 0.04
tanalpha = 1.4/1.5
par(mar = c(5,5,1,1)) # b, l, t, r
Thank you S Ellison-2 for your reply. I will understand it with Prof.Peter
Dalgaard's answer..
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Sent from the R help mailing list archive at
Thanks for your advice.
Sajeeka
From: Bert Gunter gunter.ber...@gene.com
Cc: Rui Barradas ruipbarra...@sapo.pt; r-help@r-project.org
r-help@r-project.org
Sent: Thursday, July 5, 2012 12:43 AM
Subject: Re: [R] how to check convergence of arima model
1.
Hi,
i am new in R development ,
so i need help in documentation from comments in R file
for example
sample-function(filepath)
{
##title read csv file
##author Purushoth
##description this function is used to read a csv file
output-read.csv(filepath)
hi,
i'm trying to figure out if there's any possibility to write a whole vector
into a matrix or data.frame or something like that. i don't mean
transormation. Here an example:
[,1] [,2]
[1,] a d
[2,] b e
[3,] c f
where e.g. a is a-c(0,1) vector of length 2, b a vector of length 4,...
hello,Everyone!
I am a freshman to use R. Can anybody tell me where has scor function which
achieves the skipped correlation?
Thank you very much!
Bset wishes!
Jiaolong Qin
[[alternative HTML version deleted]]
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R-help@r-project.org mailing
Hello,
When I try to save my script file before closing the R console session I get
this error.
Error: invalid input 'C:\Documents and Settings\\\datafile' in
'utf8towcs'
Does anyone know what can cause this error?
I use the RGui (R verison 2.14.0) in Windows and the problem
On 05/07/2012 8:34 AM, Boudewijn Verkooijen wrote:
Dear all,
I'm using the curve() function to plot discharge Q against water depth a.
However, I would like to have a graph of water depth a plotted against
discharge Q. How can this be done?
curve() is designed for plotting y vs x where y is a
Hi all,
My data are binary and within-subject correlated; there are three factors of
interest and two of them are within-subject. So, I have considered modelling
the data using a binomial regression with a GEE approach (which can be
achieved using the function geeglm). One problem is that I got
Thank you very much Professor .Peter Dalgaard for your kind explanations..
This made my work easy.. I am struggling with this for more than 2 days and
now I got the correct reply.
Thank again.
--
View this message in context:
Hello,
I am a Masters student and I am working on my thesis modelling smallholder
farms using a program in R. I have modified the original code and I am
having some issues with lists that I cannot figure out.
Originally, I had list file defining lists such as: Param, Crop1, Crop1,
Soil, etc.
Any method that requires binning is problematic. Instead, take a look at the
calibrate function in the rms package. There is a new option for continuous
calibration curves for survival models.
Frank
jane.wong wrote
Dear list,
Usually we use Hosmer-Lemeshow test to test the goodness of
On 05/07/2012 10:21 AM, Marine Andersson wrote:
Hello,
When I try to save my script file before closing the R console session I get
this error.
Error: invalid input 'C:\Documents and Settings\\\datafile' in
'utf8towcs'
Does anyone know what can cause this error?
I imagine it is
On Jul 5, 2012, at 8:34 AM, Boudewijn Verkooijen wrote:
Dear all,
I'm using the curve() function to plot discharge Q against water
depth a.
However, I would like to have a graph of water depth a plotted against
discharge Q. How can this be done?
Minimal working example:
S0 = 0.004
n = 0.04
Hi!
I'm using the Naive Bayes classifier provided by the e1071 package (
http://cran.r-project.org/web/packages/e1071) and I've noticed that the
predict function has a different behavior when the level set of the columns
used for prediction is different from the ones used for fitting. From
Hi Rachel,
I am having the same problem! My data set is positing around 4400 weights
required.
Have you found a solution to this? Does anyone else know how to adjust this
default to run MICE successfully?
Thanks,
Justin
--
View this message in context:
R does not, to my knowledge, have anything quite like Python's
docstrings (which seems to be what you are talking about) but you
might look at Roxygen2 on CRAN which should get you started in this
direction.
Best,
Michael
On Thu, Jul 5, 2012 at 7:37 AM, purushothaman purushothama...@ge.com
It is possible to put dimensionality on a list (i.e., a generic
vector), which might be what you're looking for.
x - list(1:4, letters[1:4], function(x,y) x + y, rnorm(50))
dim(x) - c(2,2)
x[[1,2]]
x[[2,2]]
x[[3,2]] # Error
Best,
Michael
On Thu, Jul 5, 2012 at 8:19 AM, Thomas C.
Could you make a reproducible example?
[http://stackoverflow.com/questions/5963269/how-to-make-a-great-r-reproducible-example]
I can't run any of your code as is. A few comments inline.
On Thu, Jul 5, 2012 at 9:44 AM, Wageningen-eR igor.milosavlje...@wur.nl wrote:
Hello,
I am a Masters student
library(sos)
findFun(scor)
will get you going in the right direction but I'm not sure I see a
scor function (I presume you're looking for the robust correlation
metric). Do you have a citation for such a function? For a work
around, robust::covRob gives robust covariance which possibly could be
I think you need to (re)read the posting guide and An Introduction to R and
try posting again. Some food for thought:
a) You refer to list files, but this is not a standard term. As the PG says,
you need to supply a self-contained example, which would either include
internal objects in dput
I've successfully reformatted data frames from long to wide with reshape2,
but this time I'm getting errors that I want to understand and resolve.
Here's the data frame structure and the results of the melt() and dcast()
functions:
str(waterchem)
'data.frame': 128412 obs. of 8 variables:
$
Dear Yu,
What do you mean exactly by exmpty cell ?
But you can try, the following packages which might help you: gee and yags.
But I am not sure.
Best
Ozgur
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Sent
Suppose I have a square matrix A like the toy below
set.seed(1234)
(A - matrix(rnorm(9), nrow = 3))
I want to trace of the inverse of A. I could do
sum(diag(solve(A)))
[1] 1.259641
Or I could also do
sum(1/eigen(A)$values)
[1] 1.259641+0i
Now, my actual problem involves a very large,
Hi Marion,
package memisc does what you want, just have a look at ?importers.
Hth
Eik
Am 05.07.2012 15:05, schrieb Marion Wenty:
Dear all,
I have got a very big SPSS dataframe and I would like to just import one or
a few variables (the dataframe has got a lot of colums).
I used the package
On Jul 4, 2012, at 10:10 AM, Lorcan Treanor wrote:
Dear Sir/Madam,
I am desperately in need of some help. I am trying to access tables from
the oracle database and inserting them into R via a data frame and I keep
getting an error saying that Error in .Call(C_RODBCFetchRows,
attr(channel,
It would be very helpful to have some sample data to play with. str() shows
the structure of the data set but it is not the data.
Something like dput(head(100)) would probably be enough.
John Kane
Kingston ON Canada
-Original Message-
From: rshep...@appl-ecosys.com
Sent: Thu, 5
On Jul 5, 2012, at 11:22 AM, R. Michael Weylandt wrote:
It is possible to put dimensionality on a list (i.e., a generic
vector), which might be what you're looking for.
x - list(1:4, letters[1:4], function(x,y) x + y, rnorm(50))
dim(x) - c(2,2)
x[[1,2]]
x[[2,2]]
x[[3,2]] # Error
That
well thank you, i think we get closer to my problem. but i meant it in a
different way. maybe i describe what i intended to do:
i have number of triangles which i'd like to store in a list, matrix,...etc.
i thought it could look sth. like that:
trianglenode1node2
Hi,
I think it is better to store vectors in to list when the vectors are of
different lengths.
#Consider these cases,
#vectors of equal length
set.seed(1)
list1-list(a=rnorm(5,15),b=rnorm(5,25),c=1:5,d=runif(5,0.4),e=16:20,f=rep(1,5))
See also the inlinedocs package, which might be closer to what you're
looking for.
-- Bert
On Thu, Jul 5, 2012 at 8:17 AM, R. Michael Weylandt
michael.weyla...@gmail.com wrote:
R does not, to my knowledge, have anything quite like Python's
docstrings (which seems to be what you are talking
Hello,
I have many hundred variables in my longitudinal dataset and lots of
missings. In order to plot data I need to remove missings.
If I do
data - na.omit(data)
that will reduce my dataset to 2% of its original size ;)
So I only need to listwise delete missings on 3 variables (the ones I am
Rich,
I am not familiar with the NADA package, but the reference manual (
http://cran.r-project.org/web/packages/NADA/NADA.pdf) has many examples
using several data sets included in the package. Look up one of the
functions that you plan to use, run the example in R, and look at the data
that
hi Ozgur,
Thanks for your reply! by empty cell I mean there was a condition in which
all participants showed the same response (let's say response A). In other
words, the probability of A, according to the present data, was 100%; this
led to the empty cell for non-A. The odds or p(A) would be
You have failed to provide a complete, coherent description of what you
wish to do. In the absence of such a description, all suggestions are just
guesses. You need to think carefully about what information you want to
associate with each triangle and the appropriate data structure to use to
do
On Jul 5, 2012, at 1:25 PM, Eiko Fried wrote:
Hello,
I have many hundred variables in my longitudinal dataset and lots of
missings. In order to plot data I need to remove missings.
If I do
data - na.omit(data)
that will reduce my dataset to 2% of its original size ;)
So I only need to
On Thu, 5 Jul 2012, John Kane wrote:
It would be very helpful to have some sample data to play with.
John,
dput() doesn't want to cooperate so here are 100 rows from the raw data
file that can be input with read.table(sample.dat, header = T, sep = |):
thanks a lot, it works
On Thu, Jul 5, 2012 at 11:40 AM, Thomas Lumley-2 [via R]
ml-node+s789695n4635453...@n4.nabble.com wrote:
On Thu, Jul 5, 2012 at 11:40 AM, jacquesliu [hidden
email]http://user/SendEmail.jtp?type=nodenode=4635453i=0
wrote:
I was asked to do a WLS estimation, so I
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
project.org] On Behalf Of Rich Shepard
Sent: Thursday, July 05, 2012 10:36 AM
To: r-help@r-project.org
Subject: Re: [R] reshape2 errors on data frame
On Thu, 5 Jul 2012, John Kane wrote:
It would
Perhaps I've missed something, but if it's really true that the goal is to
remove rows if the first non-zero element is D or d, then how about
this:
tmp - gsub('0','',df$ch)
first - substr(tmp,1,1)
subset(df, tolower(first) != 'd')
and of course it could be rolled up into a single expression,
Be careful!! The plots could be potentially misleading. The problem is the
nature of the missingness. The approach you are taking is based on assuming
MCAR missingness (look it up, if necessary). If that is not the case --
e.g. if there is censoring, MAR, or informative missingness -- the plots
On Thu, 5 Jul 2012, Nordlund, Dan (DSHS/RDA) wrote:
The melt syntax you provided in a previous email runs without error on the
data that you just supplied. So, your comment that dput() doesn't want
to cooperate suggests that maybe there is a problem with your waterchem
data frame. Maybe
On Thu, 5 Jul 2012, Rich Shepard wrote:
I wonder if the issue is with the logical columns; I've not used them
before, only dates, factors, and numerals. I'll try without the logicals
and see if there's a difference.
Nope. Same problem as before.
Someone, please provide a process I can
On Jul 5, 2012, at 1:28 PM, Rich Shepard rshep...@appl-ecosys.com wrote:
On Thu, 5 Jul 2012, Rich Shepard wrote:
I wonder if the issue is with the logical columns; I've not used them
before, only dates, factors, and numerals. I'll try without the logicals
and see if there's a difference.
Hello,
Just to give it a try, you've written 'idvars' when it's 'id.vars'.
After correction I no longer have the error. But, as expected, the
result 'chem.cast' has lots and lots of NAs.
chem.cast - dcast(chem.melt,
site + sampdate + preeq0 + ceneq1 + floor + ceiling ~ param)
#
On Thu, 5 Jul 2012, R. Michael Weylandt michael.weyla...@gmail.com wrote:
What do you mean it won't cooperate? Error message?
Michael,
I get the command echoed rather than results.
Rich
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-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
project.org] On Behalf Of Rich Shepard
Sent: Thursday, July 05, 2012 11:29 AM
To: r-help@r-project.org
Subject: Re: [R] reshape2 errors on data frame
On Thu, 5 Jul 2012, Rich Shepard wrote:
I
Is there a way to suppress the output of 'install.packages()'? I have
seen that the 'download.file' function has a 'quiet' option but I do
not know how to use it.
I do not see any good reason to allow that. A user should see if
software is being installed.
Hi Uwe,
I have a proposed
Hello,
I'm working on a Cox Proportional Hazards model for a cancer data set that has
missing values for the categorical variable Grade in less than 10% of the
observations. I'm not a statistician, but based on my readings of Frank
Harrell's book it seems to be a candidate for using multiple
Dear All:
I am stuck on this problem and I could use some help from folks out there.
I want to build a conditional logistic model with random effects or
logistic regression with 2 random effects. I have data on mothers and their
kids. I want to condition 1 mom predictor(0/1) and also for
I have a column of 1000 datapoints from the normal distribution with mean 2
and variance 4. How can I get a histogram of these observations with 20
bins with each bin having 50 observations?
--
Thanks,
Jim.
[[alternative HTML version deleted]]
HI,
Try this:
set.seed(1)
dat1-data.frame(var1=c(rep(NA,3),1:3),var2=c(1:4,NA,5),var3=c(1:5,NA),var4=rnorm(6,15),var5=runif(6,0.2),var6=rep(NA,6))
dat1[rowSums(is.na(dat1[,c(var1,var2,var3)]))==0,]
var1 var2 var3 var4 var5 var6
4 1 4 4 16.59528 0.5981594 NA
A.K.
-
HI,
Try this:
set.seed(1)
dat1-data.frame(var1=c(rep(NA,3),1:3),var2=c(1:4,NA,5),var3=c(1:5,NA),var4=rnorm(6,15),var5=runif(6,0.2),var6=rep(NA,6))
dat1[rowSums(is.na(dat1[,c(var1,var2,var3)]))==0,]
var1 var2 var3 var4 var5 var6
4 1 4 4 16.59528 0.5981594 NA
A.K.
-
Thanks -- extremely helpful. But what is the mechanism by which this
analysis corrects for the fact that my subjects are clustered (twins)?
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Sent from the R help mailing
Dear list,
is there a way how to add information to internal nodes (branching
points) in dendrogram created via plot.agnes function (package
cluster)?
I wish to place colored circles on the nodes, but I don't know how to proceed...
I'll be grateful for any suggestion
Ondřej
--
Ondřej Mikula
Hi Jim,
You can't specify both number of bins and bin size. You can specify
breaks: either the number of bins or the location of breakpoints. A
histogram with 20 bins of 50 observations each must by definition come
from a uniform distribution.
What are you trying to accomplish?
Sarah
On Thu,
Hello,
Inline
Em 05-07-2012 20:21, Nordlund, Dan (DSHS/RDA) escreveu:
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
project.org] On Behalf Of Rich Shepard
Sent: Thursday, July 05, 2012 11:29 AM
To: r-help@r-project.org
Subject: Re: [R] reshape2 errors
On Jul 5, 2012, at 1:34 PM, David Winsemius wrote:
On Jul 5, 2012, at 1:25 PM, Eiko Fried wrote:
Hello,
I have many hundred variables in my longitudinal dataset and lots of
missings. In order to plot data I need to remove missings.
If I do
data - na.omit(data)
that will reduce my
Hello,
Try the following.
x - rnorm(1000, mean=2, sd=2)
p - seq(0, 1, by=1/20)
quant - quantile(x, probs=p)
hist(x, breaks=quant)
The method is absolutely general, that's why I've separated the several
steps, to make it clear.
Hope this helps,
Rui Barradas
Em 05-07-2012 20:29, Jim
Hi Frank,
It clusters by twin, that is why in Dr. Lumley's example, the id was
twin pair, not individual, and the SE is adjusted accordingly.
Cheers,
Josh
On Thu, Jul 5, 2012 at 12:10 PM, RFrank spark...@gmail.com wrote:
Thanks -- extremely helpful. But what is the mechanism by which this
There's no reason you can't do that with normally-distributed data,
though I'm not sure why you'd want to. My point was rather that you
can't specify the bin width and size both. If you let the bin size
vary, this will work:
set.seed(1234)
mydata - rnorm(1000, mean = 2, sd = 4)
mydata.hist -
On 05/07/2012 3:34 PM, Sarah Goslee wrote:
Hi Jim,
You can't specify both number of bins and bin size. You can specify
breaks: either the number of bins or the location of breakpoints. A
histogram with 20 bins of 50 observations each must by definition come
from a uniform distribution.
Only
Hello,
With the confusion between bin size and width the OP started, I'll
repost my answer with a final line. Sorry for the repetition.
h - hist(x, breaks=quantile(x, probs=seq(0, 1, by=1/20)))
h$counts
[1] 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50 50
Hope this helps,
Rui
I am trying to compare two lm models, one including a categorical variable
and the other excluding the variable...
The residuals of both lm fits are highly non-Gaussian.
Could you please give me some pointers?
Thank you!
[[alternative HTML version deleted]]
I haven't used NADA functions in quite a while, but from what I recall,
you will likely be using the narrow format, and sub-setting as needed
for the different analytes.
As Jean suggested, the examples in the help pages for the NADA function(s)
of interest should make it clear.
This example
On Thu, 5 Jul 2012, Rui Barradas wrote:
Just to give it a try, you've written 'idvars' when it's 'id.vars'.
Rui,
Oops! That was the problem. No matter how often I looked at the syntax I
kept missing that.
Hope this helps,
Most definitely!
Thanks for spotting it,
Rich
Which gives Jim two ways to arrive at exactly the same result, just
different means of specifying the probs for quantile().
Sarah
On Thu, Jul 5, 2012 at 4:01 PM, Rui Barradas ruipbarra...@sapo.pt wrote:
Hello,
With the confusion between bin size and width the OP started, I'll repost my
To second Bert Gunter: you may get better answers if you give us a complete
description.
On Thu, Jul 5, 2012 at 12:37 PM, Thomas C. thomas.csa...@gmail.com wrote:
i have number of triangles which i'd like to store in a list,
matrix,...etc.
i thought it could look sth. like that:
triangle
On Thu, 5 Jul 2012, MacQueen, Don wrote:
This example follows exactly the example in ?cenros.
with( subset(yourdataframe, param=='Ag'), cenros(quant,ceneq1) )
This should do a simple censored summary statistica calculation for silver
(assuming quant contains your reporting level for
Hi Thomas,
This is non trivial to do, but if you will be working with this sort
of data and are inclined to do some programming, you might consider
creating a new class. S4 classes and methods are quite flexible, and
you can allow them to lean on or inherit from existing classes such as
Dear R People:
I'm having trouble installing Rmpi on a debian machine.
Here is my output:
bccd@node000:~$ /bccd/home/bccd
bccd@node000:~$
bccd@node000:~$ export RMPI_TYPE=OPENMPI
bccd@node000:~$ R CMD INSTALL Rmpi_0.5-9.tar.gz
* installing to library
It was looking for the mpi.h file.
Sorry for the trouble.
--
Erin Hodgess
Associate Professor
Department of Computer and Mathematical Sciences
University of Houston - Downtown
mailto: erinm.hodg...@gmail.com
__
R-help@r-project.org mailing list
Seems that I found the problem.
The degree of freedom was missing as a denominator...
Thank you for your help.
Best wishes,
Jie
On Thu, Jul 5, 2012 at 9:28 AM, John Kane jrkrid...@inbox.com wrote:
I don't believe that R-help permits pdf files. A useful workaround is to
post it to a file
If you're going to reply to something from two weeks ago, it's helpful
to include more of the conversation.
However, the mechanism is straightforward. The standard error
estimator assumes only that observations in different clusters are
independent: it approximates the variance of the estimating
Profesor Simon N. Wood
As a student from the Masters on statistics at Nacional University I am
writing to you to ask for some information due to knowledge on the field I
am working on
I wonder if you are so kind as to help out with the mathematical and
stadistical details as well as information
I have a logit model with about 10 predictors and I am trying to plot the
probability curve for the model.
Y=1 = 1 / 1+e^-z where z=B0 + B1X1 + ... + BnXi
If the model had only one predictor, I know to do something like below.
mod1 = glm(factor(won) ~ as.numeric(bid), data=mydat,
On Thu, Jul 5, 2012 at 1:03 PM, craigcitro craigci...@gmail.com wrote:
Is there a way to suppress the output of 'install.packages()'? I have
seen that the 'download.file' function has a 'quiet' option but I do
not know how to use it.
I do not see any good reason to allow that. A user should
You have an about 11-D response surface, not a curve!
-- Bert
On Thu, Jul 5, 2012 at 2:39 PM, Abraham Mathew abmathe...@gmail.com wrote:
I have a logit model with about 10 predictors and I am trying to plot the
probability curve for the model.
Y=1 = 1 / 1+e^-z where z=B0 + B1X1 + ... +
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