In the meanwhile, I found a more minimal example which shows the problem (just
change 'inch' to TRUE to see the difference):
require(grid)
inch - FALSE # TRUE
d - if(inch) 5 else 1
pspc - d*c(0.3, 0.3) # width, height of panels
spc - d*c(0.05, 0.05) # width, height of space
axlabspc - d*c(0.1,
Hi
is there a comfortable way to mark periods on time chart (axis.Date)?
To do it with arrows(...), seems to be irritating.
I want to have something like
---winterspringsummer--
thx
Christof
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HI,
Without using ifelse() on the same example dataset.
d - data.frame(stringsAsFactors = FALSE, transaction = c(T01, T02,
T03, T04, T05, T06, T07, T08, T09, T10),date =
c(2012-10-19, 2012-10-19, 2012-10-19, 2012-10-19, 2012-10-22,
2012-10-23, 2012-10-23, 2012-10-23, 2012-10-23, 2012-10-23),time
Thank you for your replay and help !!
Best Regards, Young.
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Hi there
I almost have the graph I want (except for moving the legend into the
graph).
Can someone please tell me how to put symbols at the means for this graph?
xyplot (anxiety ~ treatment, groups=therapist, data=study2, ylim=c(0,50),
auto.key=T, type='a')
Thank you so much :)
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View this
Hi All,
I'm a little stumped by the following problem. I've got a dataset with
the following structure:
idxyixiycountry(other variables)
111c1x1
212c1x2
313c1x3
... .
On 10/20/2012 01:39 AM, YAddo wrote:
Dear all:
I am trying to center labels on my plot with not much success. I have tried
text(), mtext() but it's not working. I think I am using the wrong function
for my task.
Any help will be appreciated.
My working codes.
axis(1,
On 10/20/2012 01:50 AM, Edward Patzelt wrote:
R-help -
I'm trying to create axis breaks similar to this :
http://www.r-bloggers.com/wp-content/uploads/2010/08/bar-chart-natural-axis-split1.png
.
Hi Edward,
The gap.barplot function in the plotrix package does something like
this, but it is
On 10/20/2012 06:22 AM, Yakamu Yakamu wrote:
Dear all,
I would like to make 6 barplots in one page but with a legend that applies to
all the barplots and would like to put it in the central-bottom of the page.
I know only how to make legend for individual barplot, but since all my
barplots
On 20/10/2012 10:33, Jim Lemon wrote:
On 10/20/2012 06:22 AM, Yakamu Yakamu wrote:
Dear all,
I would like to make 6 barplots in one page but with a legend that
applies to all the barplots and would like to put it in the
central-bottom of the page.
I know only how to make legend for individual
I do not know what algorithms the Excel solver function uses.
See inline for how to do what you want in R.
Forgive me if I have misinterpreted your request.
On 19-10-2012, at 16:25, Richard James wrote:
Dear Colleagues,
I am attempting to develop an optimization routine for a river suspended
Hello,
You should post a data example with ?dput. If your dataset is named
MyData, use
dput( head(MyData, 30) ) # paste the output of this in a post
Anyway, I believe the following function might do what you want. It's
untested, though. (Your example dataset is usefull but could be better)
Hi everybody,
the following alway gives me the error
Fehler in if (File$X.Frame.Number[a] + 1 == File$X.Frame.Number[a + 1])
(File$FishNr[a] - File$FishNr[a - : Fehlender Wert, wo TRUE/FALSE nötig
ist. Maybe its stupid, but i'm not getting why... Maybe someone can help
me. Thanks a lot!
for
Hi List,
when supplying a vector of atomic vector classes to read.table, I get:
# column classes
colClasses=c(character, character,numeric, numeric, numeric,
numeric, numeric, numeric,
numeric, numeric,
numeric, numeric)
# Error:
Error in scan(file,
Hi List,
I would like to optimize some data reading as well as clean up some
code. The manual tells me to supply methods to colClasses but the manual
and the methods documentation aren't helping...
Can someone provide me an example please?
Best,
Brian
R version 2.15.1 (2012-06-22)
Platform:
how about supplying the context of the error. Show the lines in the file where
the error occurred.
Sent from my iPad
On Oct 20, 2012, at 7:21, Brian zenli...@gmail.com wrote:
Hi List,
when supplying a vector of atomic vector classes to read.table, I get:
# column classes
Learn how to debug your programs. Start with
options(error = recover)
this will give you control at the point of the error so you can examine values.
Most likely one of the variables in the 'if' expression is an NA.
Sent from my iPad
On Oct 20, 2012, at 6:27, Janosch janosch1...@web.de
Le samedi 20 octobre 2012 à 03:27 -0700, Janosch a écrit :
Hi everybody,
the following alway gives me the error
Fehler in if (File$X.Frame.Number[a] + 1 == File$X.Frame.Number[a + 1])
(File$FishNr[a] - File$FishNr[a - : Fehlender Wert, wo TRUE/FALSE nötig
ist. Maybe its stupid, but i'm
Hello,
The function below requires package plotrix and is far from fully
tested, but it might do what you want.
library(zoo)
arrowsRange - function(from, to, at = 1, labels = NULL,
length = 1/8, horizontal = TRUE, border = FALSE, ...){
require(plotrix)
f1 - function(){
Hi Jim,
On 10/20/12 13:36, Jim Holtman wrote:
how about supplying the context of the error. Show the lines in the file where
the error occurred.
Sent from my iPad
On Oct 20, 2012, at 7:21, Brian zenli...@gmail.com wrote:
Hi List,
when supplying a vector of atomic vector classes to
Le samedi 20 octobre 2012 à 14:25 +0200, Brian a écrit :
Hi Jim,
On 10/20/12 13:36, Jim Holtman wrote:
how about supplying the context of the error. Show the lines in the file
where the error occurred.
Sent from my iPad
On Oct 20, 2012, at 7:21, Brian zenli...@gmail.com
Hi Milan,
that's right, forgot about that one!
Sorry to bother.
Brian
On 10/20/12 14:37, Milan Bouchet-Valat wrote:
Le samedi 20 octobre 2012 à 14:25 +0200, Brian a écrit :
Hi Jim,
On 10/20/12 13:36, Jim Holtman wrote:
how about supplying the context of the error. Show the lines in the file
Hello,
Sorry, didn't paste the function call.
plot(z)
abline(v = c(start[1], end))
arrowsRange(start, end, at = 0, labels = seasons)
Rui Barradas
Em 20-10-2012 13:19, Rui Barradas escreveu:
Hello,
The function below requires package plotrix and is far from fully
tested, but it might do
Thank you all for your help. I think I now understand the issue.
I tried to write a likelihood function for my binomial model.
Please excuse my ignorance if I am not doing this right; I do not have any
statistical background.
#Example data
x - seq(0, 1000)
y - ifelse(x 300, 0, ifelse(x700, 0,
Zoraida zmorales at ingellicom.com writes:
I need to estimate the parameters for negative binomial distribution (pdf)
using maximun likelihood, I also need to estimate the parameter for the
Poisson by ML, which can be done by hand, but later I need to conduct a
likelihood ratio test between
Brian zenlines at gmail.com writes:
Hi List,
I would like to optimize some data reading as well as clean up some
code. The manual tells me to supply methods to colClasses but the manual
and the methods documentation aren't helping...
Can someone provide me an example please?
Your
Inline.
-- Bert
On Sat, Oct 20, 2012 at 6:44 AM, Véronique Boucher Lalonde
veronique.boucher.lalo...@gmail.com wrote:
Thank you all for your help. I think I now understand the issue.
I tried to write a likelihood function for my binomial model.
Please excuse my ignorance if I am not doing
Received the same error with OpenBUGS322 trying to run the schools example
under Wine 1.5.15, R 2.15.1, R2OpenBUGS_3.2-1.4, on a mac pro with Snow
Leopard . I then tried with OpenBUGS321 and it ran fine.
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https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained,
On Oct 20, 2012, at 7:50 AM, Jonathan Brown wrote:
[[alternative HTML version deleted]]
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The link below is where you most likely subscribed and where you also need to
go to unsubscribe. None of us
I've got another problem.
What if I have another dotchart with same categories, but one of the data
are missing (control A)??
So I want to leave out from the dotchart. In this case in the control
category should have only one dotline, because the other one is empty. Or
mark somehow that it's
Hello,
I have been trying to use a collection of Fortran subroutines to return a 2D
array of calculated values to my R code, calling a Fortran wrapper
subroutine from R. I've done this successfully before with C C++ code.
The Fortran wrapper subroutine which is to be called by R takes a set of
d$flag-unlist(rbind(lapply(split(d,d$date),function(x) x[3]==max(x[3]
I think that line is unnecessarily complicated. lapply() returns a list
and rbind applied to one argument, L, mainly adds dimensions c(length(L),1)
to it (it also changes its names to rownames). unlist doesn't care about
Hi : I looked at the help for system.time but I still have the following
question. Can someone explain the output following output
of system.time :
user system elapsed
12399.681 5632.352 56935.647
Here's my take based on the fact that I was doing ps -aux | grep R off and
on and
See inline.
On 20-10-2012, at 17:18, paulfjbrowne paulfj.bro...@gmail.com wrote:
Hello,
I have been trying to use a collection of Fortran subroutines to return a 2D
array of calculated values to my R code, calling a Fortran wrapper
subroutine from R. I've done this successfully before
You asked several questions.
Elapsed: yes
User + System = CPU: yes
Finally: You have to look at the load and/or cpu core count. Unless you setup
your code to take advantage of multiple cores, R runs on a single core.
Also: Do you really need to ask that question?
On 20/10/2012 17:16, Mark Leeds wrote:
Hi : I looked at the help for system.time but I still have the following
question. Can someone explain the output following output
of system.time :
user system elapsed
12399.681 5632.352 56935.647
Yes, the help page can, via
Hello Rui Barradas
thank you very much. That is exactly what I was looking for.
Christof
Am 20-10-2012 14:19, schrieb Rui Barradas:
library(zoo)
arrowsRange - function(from, to, at = 1, labels = NULL,
length = 1/8, horizontal = TRUE, border = FALSE, ...){
require(plotrix)
f1
d$flag2 - unlist(lapply(unname(split(d[[3]], d$date), function(x)x==max(x
I'm sorry, I stuck in the unname() in the mail but did not run it - its closing
parenthesis should be after split's closing parenthisis, not at the end.
d$flag2 - unlist(lapply(unname(split(d[[3]], d$date)),
Just to let people know
On the Omegahat site (and source on github),
there are packages for working with Office Open
documents (and LibreOffice too), includinging
RWordXML, RExcelXML and the generic package OOXML
on which they rely.
These are prototypes in the sense that they
do not
Dear R users,
When I run the code below, I get the error Error in integrate(integrand, 0,
Inf) : non-finite function value. The code works if the function returns
only sum(integ). However, I want to add cmh to it. When I add cmh I
get that error. I can't figure out why this is happening because
Hi again,
Thank you so much for the script. Unfortunately, I feel like I might not
have explained things clearly enough from the start. What I’m looking for is
the st. errors or CI intervals for the estimate the parameter for slope and
intercept for each level of each factor.
From the summary
HI Bill,
Thanks for the reply.
It was unnecessarily complicated.
d$flag-unlist(lapply(split(d,d$date),function(x)
x[3]==max(x[3])),use.names=FALSE)
#or
d$flag-unlist(lapply(split(d,d$date),function(x) x[3]==max(x[3])))
should have done the same job.
str(d)
#'data.frame': 10 obs. of 4
HI Bill,
I figured it out.
d$flag2-unlist(lapply(unname(split(d[[3]],d$date)),function(x) x==max(x)))
# [1] FALSE FALSE FALSE TRUE TRUE FALSE FALSE FALSE FALSE TRUE
) created the error.
A.K.
- Original Message -
From: William Dunlap wdun...@tibco.com
To: arun
I will look into using inline, but since the Fortran code is several thousand
lines long is comprised of multiple subroutines, compiling it into a
shared object dynamically loading it into R is probably the easier
solution.
I have also noticed a strange numerical problem when calling the
Dear all,
ggmcmc-0.2 has been released.
ggmcmc is a tool for assessing and diagnosing convergence of Markov Chain
Monte Carlo simulations, as well as for graphically display results from
full MCMC analysis. The package also facilitates the graphical
interpretation of models by providing flexible
Look at my comments in between your post.
On 20-10-2012, at 19:18, paulfjbrowne paulfj.bro...@gmail.com wrote:
I will look into using inline, but since the Fortran code is several thousand
lines long is comprised of multiple subroutines, compiling it into a
shared object dynamically
On Oct 16, 2012, at 11:58 AM, Sigrid wrote:
Okay, I've now tried to the predict function and get the SE, although it seem
to calculate SE for each observation from the line (I assume), while I want
the CI-interval and SE for each line fitted line for the treatment. I do not
really understand
On Oct 20, 2012, at 9:23 AM, stats12 wrote:
Dear R users,
When I run the code below, I get the error Error in integrate(integrand, 0,
Inf) : non-finite function value. The code works if the function returns
only sum(integ).
But you never showed us the working code.
However, I want to
I am new to R and I am trying to do a monte carlo simulation where I
generate data and interject error then test various cut points; however, my
output was garbage (at x equal zero, I did not get .50)
I am basically testing the performance of classifiers.
Here is the code:
n - 1000; # Sample size
Dear List,
I couldn't find any package that performs the weight of evidence of
predictors (a transformation usually performed in credit scoring
applications). Is there any that you know?
Thanks,
Axel.
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I have a follow-up question (for either Dr. Therneau, or anybody who
might know).
sum(zz) (see below) estimates the number of events for the cohort.
Now, how can I compute a confidence interval for sum(zz)? Or a
standard error?
My obvious choice, square root of the sum of the squares of the
What do you mean by at x equal zero?
On Sun, Oct 21, 2012 at 8:37 AM, Adel Powell powella...@gmail.com wrote:
I am new to R and I am trying to do a monte carlo simulation where I
generate data and interject error then test various cut points; however, my
output was garbage (at x equal zero, I
Thanks Jim and Rui.
My apologies, i did not give enough info on my plot.
I am using : plot(x,y) for a line plot. I want to center the labels on the
x-axis for each tick.
Thanks.
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Hello all,
I'm trying to plot the effects of variables estimated by a regression model
fit individually, and for categorical predictors, the independent variable
shows up on the y-axis, with the dependent variable on the x-axis. Is there
a way to prevent this reversal?
Sample code with dummy
R Compiliing or installation failure on FreeBSD
9.0-RELEASE FreeBSD ; I386 box.
configuring with the default settings, no 'options' =
./configure
...
...
...
checking whether gcc -std=gnu99 supports -c -o FILE.lo... yes
checking for gcc -std=gnu99 option to support
On Oct 20, 2012, at 3:03 PM, YAddo wrote:
Thanks Jim and Rui.
My apologies, i did not give enough info on my plot.
Nor do you even now. Offer a data example.
I am using : plot(x,y) for a line plot. I want to center the labels on the
x-axis for each tick.
Code. We want code.
--
Hi,
Thank you for your comment. I worked on the code again and was able to make
it work. The only problem I am having right now is that nlm depends on the
initial value.
When the initial value is 1, I get the following estimates
0.1230414 19.6271029
when it is 2, I get the following
29.46874
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