Hello,
For clarification, is it 'GSEA' or 'GSCA' package?
And from where did you get it?
Regards,
Pascal
Le 29/11/2012 07:59, Seb a écrit :
Dear R gurus
I’m trying to use the GSCA package to a series of microarray data (prostate
cancer normal vs tumor (29 vs 29 paired)) but I’m running
Have it for now ...
\preformatted{
..
}
does the job.
On Wed, Nov 28, 2012 at 9:21 PM, Ulrich Staudinger
ustaudin...@gmail.com wrote:
Hi everyone,
following the gentle advice from this list, I write a package
description Rd file.
I have a section in there. In this section, I have a
On Wed, Nov 28, 2012 at 3:06 AM, andrewH ahoer...@rprogress.org wrote:
Dear Michael –
This is _very_ interesting and I want to play around with the functions you
suggest. I had no idea it was so easy to define assignment operators.
However, one question: even after reading the “get”
On 12-11-28 5:00 PM, Nelson Chen wrote:
My version of R (2.15.2), 64 bit version, has been crashing sporadically
running under newly upgraded Windows 8. I suspect it may be some sort of memory
allocation issue. Does anyone know of ways one can diagnose and fix this
problem? Thanks.
How to
Thanks Philippe for your answer!
It doesn't work for me, but I guess I have something wrong with Tcl/Tk.
Ivan
--
Ivan CALANDRA
Université de Bourgogne
UMR CNRS/uB 6282 Biogéosciences
6 Boulevard Gabriel
21000 Dijon, FRANCE
+33(0)3.80.39.63.06
ivan.calan...@u-bourgogne.fr
Dear list,
A new package gdimap titled Generalized Diffusion Magnetic Resonance
Imaging is now available on CRAN.
Best wishes,
Adelino
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r-packa...@r-project.org
Hi Silje,
Thanks for this. I guess RUTE is a numeric variable in this model and
hence only has one associated random coefficient? This then causes a
problem when calling predict.gam as part of processing 'residuals=T'.
I've fixed the problem for the next release, but did you really want a
Hello,
You should post to the list, not just send your questions to me. If you
Cc the list the odds of getting more and better answers are bigger.
As for your question,
1. You forgot a variable X1, like this your code doesn't run. In what
follows I assume it's also a runif(40, 0, 20).
2.
http://stackoverflow.com/questions/5963269/how-to-make-a-great-r-reproducible-example
John Kane
Kingston ON Canada
-Original Message-
From: dtustud...@hotmail.com
Sent: Wed, 28 Nov 2012 18:38:46 -0700
To: michael.weyla...@gmail.com
Subject: Re: [R] error, R commends cannot show
This is not a homework help list and it is even less a homework help list when
there is no clear statement of the problem. I'd suggest reading something
about how R works -there are some very good tutorials and introductions listed
on the R site, and then perhaps coming back here if you have a
Hello,
Try the following function.
ci_lm - function(object, level = 0.95){
summfit - summary(object)
beta - summfit$coefficients[, 1]
se - summfit$coefficients[, 2]
df - summfit$df[1]
alpha - 1 - level
lower - beta + qt(alpha/2, df = df)*se
upper - beta + qt(1
Kirsten,
The overall model is the combination of both models. If you call the
parameter estimates from the logistic regression betas and the parameter
estimates from the linear regression alpha, you could write the predictive
equation something like this (ignoring error terms):
cover
Hi
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
project.org] On Behalf Of Jack Bryan
Sent: Thursday, November 29, 2012 2:39 AM
To: michael.weyla...@gmail.com
Cc: r-help@r-project.org
Subject: Re: [R] error, R commends cannot show the expected
Hi
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
project.org] On Behalf Of maths123
Sent: Wednesday, November 28, 2012 9:11 PM
To: r-help@r-project.org
Subject: Re: [R] Order function
And yes I want the variable 1 to have the identifier 1 etc.
Hi
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
project.org] On Behalf Of maths123
Sent: Monday, November 26, 2012 8:25 PM
To: r-help@r-project.org
Subject: Re: [R] Factor function for coded numerical values
The question says that there is an
Hi
Maybe you could use stack(dat) or melt(dat) from reshape package.
Regards
Petr
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
project.org] On Behalf Of dattel_palme
Sent: Monday, November 26, 2012 12:13 PM
To: r-help@r-project.org
Subject: Re:
Try R package 'brew'? From its package description
Description:brew implements a templating framework for mixing
text and R code for report generation. brew
template syntax is similar to PHP, Ruby's erb
module, Java Server
I've been trying to split a space delimited string with double-quotes in R
for some time but without success. An example of a string is as follows:
/rainfall snowfall Channel storage Rivulet storage/
It's important for us because these are column headings that must match the
subsequent data.
I am developing A Gui using RGtk2 package. I wanted to know how the font
attributes of names of widgets like menu bar, text, label etc. are changed.
i mean to have menu bar item bold, italic and some specific size etc.
Is there a need to create a style using PANGO library???
Krishna
--
View
Hi,
I m working on R plot with Russian label but on windows (adobe) russian text
are not visible. Do i need to install some package to view it.
pdf(sample.pdf,width = 6.6 ,height = 4.2,family= URWHelvetica,
encoding=KOI8-R)
x-c(1,2,3,4,5)
y-c(2,3,4,5,6)
df - df[-which(is.na(df$Field)), ] - removing rows with NULL fields
df - df[-which(df$Field == ), ] - removing rows with empty fields
On Wednesday, November 28, 2012 2:23:00 PM UTC+5:30, catalin roibu wrote:
Dear R users,
I want to remove zero's or NA values after this model.
year
hey,
I have a huge dataset with over 30 rows which contains data about
something from 2009-2012. does anyone know how i can delete all the rows
which contain data from 2009 and only have data from 2010-2012???
is there a particular function i can use on the date column so that all data
from
Hello community,
I have a problem with my survreg function in R-Statistics.
My created code is the following:
library(survival)
surv=Surv(IPT_IN_DAYS,Status)
survival.data.weibull=survreg(surv~AGE_DAYS+KM_COUNT+LL_PER_DAY+IPT_HIS+IPT_SDEV,
data=spss, dist=weibull, scale=2.0)
Dear R community,
I'm trying to graphically illustrate my data with a worlmap.
Unfortunately, my data is partly on country basis and partly on regional
basis (e.g. certain African countries are aggregated to one region). I am
using the package rwoldmap.
The data on country basis can be
I have created a bubble plot in R using the following formula:
symbols(Data$Day.Number,Data$Team,circles=Data$Total.amount, inches=0.5,
fg=white,bg=red,xlab=Day Number,ylab=Team)
The data set is called Data, and I have the columns Day.Number, Team and
Total.amount.
The data is plotting fine,
Hello,I would like to know if there is residue analysis after the Cox model and
make the adjustment for my random cluster?
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
Hello,
I am performing Newton Raphson iteration where the parameter vector which I
want to optimize is an *nx1* vector.
I am running a while loop which will continue unless a stopping condition is
satisfied
Now, the stopping condition will have to be such that the parameter vector
after two
Hi,
You could do this with ?merge() or ?join()
library(plyr)
new-data.frame(ID=1:10,height1=NA)
combo-data.frame(ID=c(3,7,9,10),height=c(185,NA,158,176))
join(new,combo,type=left)[,-2]
#Joining by: ID
# ID height
#1 1 NA
#2 2 NA
#3 3 185
#4 4 NA
#5 5 NA
#6 6
Jean,
Thank you! That is exactly the type of information I was looking for!
The script for the combined model is what I couldn't seem to come up with on
my own.
Thank you again for your help!
Sincerely,
Kirsten
--
View this message in context:
Dear ecology fellows,
I tried to implement Morisita-Horn distance (instead of Bray that is in the
current version) in the code for the Simper analysis in vegan. I would be
very grateful if someone can check if the code is right.
function (comm, group, ...)
{
if (any(rowSums(comm, na.rm =
Thank you both for the extensive amount of help! I am sorry it has taken me a
bit to respond, but i've been trying to plug away at this. I still have a
few questions, if you don't mind giving me some pointers:
Here is the fake data again:
treatment
feeding
avoid
Function LDkl of package gap.
I am also trying to use it.
--
View this message in context:
http://r.789695.n4.nabble.com/Calculating-Linkage-Disequilibrium-for-Microsatellite-Markers-tp4642701p4651285.html
Sent from the R help mailing list archive at Nabble.com.
Hi
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-bounces@r-
project.org] On Behalf Of siddanth911
Sent: Thursday, November 29, 2012 12:10 PM
To: r-help@r-project.org
Subject: [R] deleting data of a given date range.
hey,
I have a huge dataset with over
Thank you very much, I'll look into that package!
Kirsten
_
Kirsten Martin
Von Holle Lab
Department of Biology, BL 405
University of Central Florida
Orlando, FL 32816
From: Jagat.K.Sheth [via R]
On Thu, Nov 29, 2012 at 9:43 AM, downtowater downtowa...@yahoo.ca wrote:
I've been trying to split a space delimited string with double-quotes in R
for some time but without success. An example of a string is as follows:
/rainfall snowfall Channel storage Rivulet storage/
It's important for
Hi!
http://r.789695.n4.nabble.com/file/n4651293/qq.png
We are stuck with a problem considering the qqplot of a dataset.
We are trying to discover what kind of distribution this is. We already
tried to normal, exponential or the logaritmical distribution but none of
those are able to solve our
Hello,
See the ?axis function, argument 'labels'.
Hope this helps,
Rui Barradas
Em 29-11-2012 12:20, seanlilley escreveu:
I have created a bubble plot in R using the following formula:
symbols(Data$Day.Number,Data$Team,circles=Data$Total.amount, inches=0.5,
fg=white,bg=red,xlab=Day
Try using scan(quote='', ...), as in the following
str - 'rainfall snowfall Channel storage Rivulet storage'
scan(text=str, what=, quote='', quiet=TRUE)
[1] rainfallsnowfallChannel storage Rivulet storage
Bill Dunlap
Spotfire, TIBCO Software
wdunlap tibco.com
Hi,
I am trying to convert a colleague from using SPSS to R, but am having
trouble generating a result that is similar enough to a bootstrapped cox
regression analysis that was run in SPSS. I tried unsuccessfully with
bootcens, but have had some success with the bootcov function in the rms
Your subject line says Chinese!
On 29/11/2012 08:42, Manish Gupta wrote:
Hi,
I m working on R plot with Russian label but on windows (adobe) russian text
are not visible. Do i need to install some package to view it.
pdf(sample.pdf,width = 6.6 ,height = 4.2,family= URWHelvetica,
Hi,
The axis function plots an axis ontop of my current axis. So although I am
able to write my labels in, they are written ontop of the numbers in the
current axis rather than replacing them. Any other alternatives?
Sean
--
View this message in context:
On 29-11-2012, at 14:28, soham chakraborty wrote:
Hello,
I am performing Newton Raphson iteration where the parameter vector which I
want to optimize is an *nx1* vector.
Are you trying to solve a system of nonlinear equations?
Have a look at package nleqslv.
Are you max-/min-imizing a
I grab the opportunity to suggest giving a try `pander` package, which
holds a forked version of `brew` called `Pandoc.brew`.
If you are familiar with `brew`, you could easily create nicely formatted
HTML output automatically beside other formats, example:
Hi,
May be this helps:
str1 - 'rainfall snowfall Channel storage Rivulet storage'
res-unlist(strsplit(gsub([\],,str1), ))
res1-c(res[1],res[2],paste(res[3],res[4],),paste(res[5],res[6],collapse=))
res1
#[1] rainfall snowfall Channel storage Rivulet storage
A.K.
-
Hi,
You could also do this:
res-unlist(strsplit(str,[\]))
res1-res[res!= ]
res2-c(unlist(strsplit(res1[grepl(\\s+$,res1)],
)),res1[!grepl(\\s+$,res1)])
res2
#[1] rainfall snowfall Channel storage Rivulet storage
A.K.
- Original Message -
From: downtowater
I'm manipulating a large dataset and need to eliminate some observations based
on specific identifiers. This isn't a problem in and of itself (using which..
or subset..) but an imprint of the deleted observations seem to remain, even
though they have 0 observations. This is causing me
it's the GSCA packagei made a typo in the subject, my apologies
the package is available from here
http://www.biostat.wisc.edu/~kendzior/GSCA/
i am now trying to do co-expression analysis using EBcoexpress but looks
like i have a similar problem due to the sample size!
thanks!
--
View
Have you tried fitting your data to the Pearson family of distributions? In
particular the Pearson Type IV has parameters to fit skewed and kurtotic
distributions. The Pearson library is described here:
http://cran.r-project.org/web/packages/PearsonDS/PearsonDS.pdf
The Type IV is described
Hi Kirk,
It's because tension is a factor with three levels, as you could see with
str(warpbreaks).
Factors are one of the mysteries of R that distinguish a novice from
an initiate.
Reading ?subset directs you to ?droplevels. Here's an example:
summary(warpbreaks)
breaks wool
Hello,
I'd like to use package 'doSMP'. But I can only found source codes in the CRAN.
I tried to build source code using 'r CMD build doSMP' in the source directory,
the following error is shown:
ERROR: dependencies 'foreach', 'iterators', 'revoIPC' are not available for pack
age 'doSMP'
R Users,
I just upgraded my version of R from R-2.15.0 to R-2.15.2 and installed the
latest versions of LyX and MikTex running Windows 7 Ultimate, 64-bit OS. Prior
to the upgrade, I was using Lyx with knitr to generate a document with no
problems. However, after the upgrade, and using the
Hello,
Use argument yaxt = n of function symbols. yaxt means y axis type
and n for none (or no).
Then plot the axis with axis(2, ...)
Hope this helps,
Rui Barradas
Em 29-11-2012 16:17, seanlilley escreveu:
Hi,
The axis function plots an axis ontop of my current axis. So although I am
able
Hello
I am running R versions 2.13 and 2.15. One of my codes run ok on 2.13 but
on 2.15. I have tried to understand what is wrong but come up with
nothing.
Here is the code
rm(list=ls())
graphics.off()
library(R.matlab)
library(zoo);
library(xts);
library(lattice);
Hi Ducan and others,
I am sorry for this such late reply but I did not see that I had a reply...
I have not solved the problem
text3d(1:3, 1:3, 1:3, LETTERS[1:3], cex=1:3) does not work for me
Maybe it is related to my material, I am on linux debian
Sys.info()
sysname Linux
release
Hi,
I have a very large data set (aprox. 100,000 rows.)
The data comes from around 10,000 groups with about 10 entered per group.
The values are in one column, the group ID is an integer in the second column.
I want to normalize the values by group:
for(g in unique(groups){
Quite a few people have had this problem, but since I'm unable to
reproduce it, I'm not exactly sure how to fix it either. A few
references that might be helpful to you:
http://stackoverflow.com/q/12448507/559676
https://github.com/yihui/knitr/issues/413
It is very likely to be a pure LaTeX
Not tested but should work:
sums = tapply(x, group, sum);
sums.ext = sums[ match(group, names(sums))]
normalized = x/sums.ext
It may be that the tapply is just as slow as your loop though, I'm not sure.
HTH,
Peter
On Thu, Nov 29, 2012 at 10:55 AM, Noah Silverman noahsilver...@ucla.edu wrote:
Yes, type in:
?by
for example:
data - data.frame(fac=factor(c(A,A,B,B)), vec=c(1:4) )
by(data$vec,data$fac, FUN=sum)
Best,
MikoÅaj Hnatiuk
2012/11/29 Noah Silverman noahsilver...@ucla.edu
Hi,
I have a very large data set (aprox. 100,000 rows.)
The data comes from around 10,000 groups
Hello,
If yopu want one value per group use tapply(), if you want one value per
value of x use ave()
tapply(x, group, FUN = function(.x) .x/sum(.x))
ave(x, group, FUN = function(.x) .x/sum(.x))
Hope this helps,
Rui Barradas
Em 29-11-2012 18:55, Noah Silverman escreveu:
Hi,
I have a very
try the 'data.table' package. Takes about 0.1 seconds to normalize the data.
x - data.frame(id = sample(1, 10, TRUE), value = runif(10))
require(data.table)
Loading required package: data.table
data.table 1.8.2 For help type: help(data.table)
system.time({
+ x - data.table(x)
Close, but not quite what I need.
That very nicely gives me sums by group.
I need to take each value of X and divide it by the sum of the group it belongs
to.
With your example, I have 100,000 X and only 10,000 group. The by command
gives me 10,000 sums. I still have to loop over all
On 29-11-2012, at 19:55, Noah Silverman wrote:
Hi,
I have a very large data set (aprox. 100,000 rows.)
The data comes from around 10,000 groups with about 10 entered per group.
The values are in one column, the group ID is an integer in the second column.
I want to normalize the
I did not read every reply; perhaps someone has already mentioned
Shiny. There are a few live examples of embedding R in HTML here:
http://www.rstudio.com/shiny/
Regards,
Yihui
--
Yihui Xie xieyi...@gmail.com
Phone: 515-294-2465 Web: http://yihui.name
Department of Statistics, Iowa State
Thanks, Yihui!
Luckily I kept R-2.15.0 and left it untouched (so I can continue to use that
for now). If it helps any, I was able to go back into Lyx and change the path
to point to R-2.15.0 and I also changed the windows path environment variable
to point to the old version. After doing
I haven't used it yet, so I can't comment about the stability or
appropriateness of it, but R.NET looks somewhat promising for this:
http://rdotnet.codeplex.com/
Shiny is another potential way to go.
You could also take a look at David Firth's CGIwithR:
On 29/11/2012 1:34 PM, Stephane Chantepie wrote:
Hi Ducan and others,
I am sorry for this such late reply but I did not see that I had a
reply... I have not solved the problem
text3d(1:3, 1:3, 1:3, LETTERS[1:3], cex=1:3) does not work for me
It works for me. Perhaps if you explained what
That is very helpful! Just to continue debugging, can you save the two
versions of the tex files produced from LyX with different versions of
R and do a diff on them? It sounds like something has changed from R
2.15.0 to 2.15.2.
Regards,
Yihui
--
Yihui Xie xieyi...@gmail.com
Phone: 515-294-2465
yes sorry,
When we use this function
text3d(1:3, 1:3, 1:3, LETTERS[1:3], cex=1:3)
we expect the letters to have different size (increase from 1 to 3). But
when I try this code , all the letter have the same size.
This problem (to not be able to resize character) occurs with diiferent the
The gls function in the nlme package is one approach.
If you know the covariance matrix exactly (it is just numerical with
nothing that needs to be estimated) then you can also take the Cholesky
decomposition of the inverse of the covariance matrix (or other square root
method) and multiply the x
All -
How can I read in a column of alphanumeric values without including
.0 on the numeric values?
Original column:
TeamLeaderID
258
342
316
U8
331
279
D1
116
235
296
...
[truncated]
leaders = read.xlsx2('FILE', sheetIndex = 1, header = T)
Column after it's been read in:
I am trying to use your package gRain using your book on graphical models in
R to do predictions, I have 38 columns of vectors all factors and built a
bayesian network using iamb() function, then I used the following command to
make a grpahNEL (However, I have 38 nodes and 106 edges) using
I'm trying to make a function witch recieves a function f, a and b, and
the error e. When I run the algorithm without labeling it a function and
typing the values it works, but when I just try to save it in a function It
doesn't ' bug but don't do anything. Here's the code, anyone know whats
Hi all,
I think this might be an easy one but I cannot think of a way to do this
other than what I am currently attempting. I simply want to sort my data
frame's rownames by a defined vector so that the plots I generate from that
vector are in the desired order
Consider the test data below:
Help Please
Hello,
I want to find the whole hat matrix not only the hat values. Is there anyway
that could be extracted from lm function ?. If not, please suggest something
else.
Direct computations using chol2inv or solve are not stable if t(X)%*%X has
high determinant. In this case lm is
Eric, the output you showed for anova(out) is not correct. anova.rms does
not produce such output. Please give us the correct script that obtained
those results and let us know if you are overriding the anova command
somehow.
To your point, make sure that SPSS does not use the bootstrap to
Hi,
You haven't given any example dataset. So,not sure about the format of the
date column.
set.seed(5)
dat1-data.frame(Date1=c(10/25/2009,11/25/2009,12/25/2009,5/10/2010,8/10/2010,9/25/2011,11/28/2011,5/3/2012),col2=sample(1:15,8,replace=TRUE))
dat1$Date1-as.Date(dat1$Date1,format=%m/%d/%Y)
Dear R users.
I'm currently making a report with knitr (RStudio) where I would like to
plot a googleVis map. However, the map generated is an HTML file which I
don't know how to integrate it in my report.
So my question is how to include a map generated with googleVis in a PDF
created with
On 29-11-2012, at 16:18, finehko wrote:
I'm trying to make a function witch recieves a function f, a and b, and
the error e. When I run the algorithm without labeling it a function and
typing the values it works, but when I just try to save it in a function It
doesn't ' bug but don't do
Hello,
Actually, it would throw an error, you forgot to assign 'i'.
And in the end your function didn't have a return value. I've edited and
simplified it a bit.
(And what to do if abs(a - b) == e ? The second condition was deleted.)
raiz - function(f,a,b,e){
i - 0
repeat{
And have the function return a value. All values
set in the function will be destroyed when the
function is done - you must return something and
the caller must assign the return value to a variable
if you want to keep it.
E.g.,
raiz
function (f, a, b, e)
{
i - 0
repeat {
if (i
Hello,
The following document is _not_ about lm(), it's about creating packages
but it includes an example that might answer to what you want, a simple
lm() substitute. (It uses the QR decomposition, not Cholesky)
http://cran.r-project.org/doc/contrib/Leisch-CreatingPackages.pdf
Hope this
Hello, this is my first post. I have a large CSV file where I need to fill in
the 1st and 2nd column with a Loan # and Account name that would be found in
a line of text : like this: ,,Loan #:,ML-113-07,Account Name:, Quilting
Boutique,,,
I would like to place the Loan #: ML-113-07 in the
Hi, I am encountering a difficulty I don't understand. Be patient, I'm very
new to analysis of variance.
If I load this data:
example12_7=read.table(http://msemac.redwoods.edu/~darnold/math15/data/chapter12/example12_7.dat,header=TRUE)
The run the oneway.test:
I'm not aware of the possibility of embedding google vis in PDF:
https://developers.google.com/chart/interactive/docs/gallery I do not
think everything has to live in PDF, otherwise what is the point of
HTML/JS and web browsers?
Regards,
Yihui
--
Yihui Xie xieyi...@gmail.com
Phone: 515-294-2465
Hello,
is there a way to compute multilevel (3-stage) regression using weights
matrix (on different levels, just like in HLM) in R ? The nlme package
doesn't seem to get the job done. Do you have any suggestions ? I _really_
don't want to use HLM to do this.
Best,
MikoÅaj Hnatiuk
2012/11/29 Greg
On Nov 29, 2012, at 5:18 AM, Thiago Luiz Nogueira da Silva wrote:
Hello,I would like to know if there is residue analysis after the Cox model
and make the adjustment for my random cluster?
Is this in 'coxme' or in 'survival'. If in 'survival' then there are
residuals functions and when I
On Nov 28, 2012, at 11:32 AM, Kirsten Martin wrote:
Hello all,
I have a data set where the response variable is the percent cover of a
specific plant (represented in cover classes 0,1,2,3,4,5, or 6). This data
set has a lot of zeros (plots where the plant was not present).
I am trying
On Nov 28, 2012, at 5:43 PM, Jack Bryan wrote:
I run
You are asked to state which OS and version of R you are using.
cars - c(1, 3, 6, 4, 9)
plot(cars)
When this happens and you add:
dev.new()
### Do you then see a plot with:
plot(cars)# ???
--
David
No graph pops up.
What is 'i'? I don't see it as a parameter? is it something in the
global environment that you forgot to pass?
On Thu, Nov 29, 2012 at 10:18 AM, finehko j9...@hotmail.com wrote:
I'm trying to make a function witch recieves a function f, a and b, and
the error e. When I run the algorithm
Hi D,
R is taking drug as numeric, you ned indicate to R that drug is a factor:
example12_7$drug -factor(example12_7$drug)
ej2-aov(time~drug,data=example12_7)
summary(ej2)
Df Sum Sq Mean Sq F value Pr(F)
drug 2 21.98 10.991 4.188 0.0345 *
Residuals 16 41.99
Your problem is the the data read in from the spreadsheet is probably
a 'factor' since it has a non-numeric in the column. To change it to
number you have to do the following
as.numeric(as.character(yourdata$TeamLeaderID))
What you as seeing with just the call to as.numeric is the value of
the
Thanks for the replies.
I hadn't considered changing the original spreadsheet to a table as
there are several different analyses using the .xlsx spreadsheet that
contains the alphanumeric data, thus requiring an alteration of all of
our code. However, the first response did prompt me to try
Hi list,
I am writing a for loop that looks like this:
samples-rep(NA,10)
x - rep(c(111, 225), 5)
for(i in 1:10){
If(x[i]200){
samples[i] - x[i]
}else{
i=i-1
}
}
The problem is that the returning vector still contains NA, I think the i
in else is not getting
HI,
Try this:
res2-aov(time~factor(drug),data=example12_7)
summary(res2)
# Df Sum Sq Mean Sq F value Pr(F)
#factor(drug) 2 21.98 10.991 4.188 0.0345 *
#Residuals 16 41.99 2.624
#---
#Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1
A.K.
Hi, Yihui,
Attached is an HTML Diff report of the two files. The left pane contains the
R-2.15.0 file.
Thanks.
--Mark
From: Yihui Xie x...@yihui.name
To: Mark Lamias mlam...@yahoo.com
Cc: r-help@r-project.org r-help@r-project.org
Sent: Thursday,
Hi Frank,
Below is the actual output from the anova(out) command. I had copied in the
p-values and from the previous output from anova(out) and the confidence
intervals from print(quantile(out$boot.Coef[,i], c(.025, .975))) to
illustrate that the confidence intervals were similar to SPSS while
Dear friends,
I am trying to understand and implement instrumental variables
regression using R.
I found a small (simple) example here which purportedly illustrates the
mechanics (using 2-stage least-squares):
http://www.r-bloggers.com/a-simple-instrumental-variables-problem/
Basically, here
Mike,
Based on this example, what do you want
samples
to look like?
It's not clear to me what you're trying to do with
i-1
Jean
C W tmrs...@gmail.com wrote on 11/29/2012 03:55:12 PM:
Hi list,
I am writing a for loop that looks like this:
samples-rep(NA,10)
x -
Use a while loop instead of a for loop. I don't think what you have coded makes
any sense, but fighting the for loop over control of the indexing variable is a
recipe for failure.
---
Jeff Newmiller
On Nov 29, 2012, at 1:55 PM, C W wrote:
Hi list,
I am writing a for loop that looks like this:
samples-rep(NA,10)
x - rep(c(111, 225), 5)
for(i in 1:10){
If(x[i]200){
samples[i] - x[i]
}else{
i=i-1
If you expected the else clause to assign something to the samples
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