So this is an alternative method. The package can be installed from
source() rather than rebuilt. Although the warnings exist, the package
itself may still be useful. Can you let me know how to installed from
source?
Thanks a lot!
Zuofeng
2013/8/19 David Winsemius dwinsem...@comcast.net
On
I wrap functions to run via multicore with tryCatch() to gather stats on
failure rate and capture state.
I'm still interested in how/whether core fuctions were verified as being
threadsafe.
Bill Hopkins
Written using a virtual Android keyboard...
-- Original message --
From:
I am running permutation regressions in package lmPerm using lmp(). I
am getting what I find to be confusing results and I would like help
understanding what is going on. To illustrate my problem, I created a
simple example and am running lmp() such that the results of the lmp()
models should be
On 20/08/2013 03:13, Hopkins, Bill wrote:
I wrap functions to run via multicore with tryCatch() to gather stats on
failure rate and capture state.
I'm still interested in how/whether core fuctions were verified as being
threadsafe.
What does 'threads' have to do with this? Multicore
I've spent a bit too long searching the help history and attempting to apply
some logic to the following:
I have two 3D arrays each with same dim. I wish to run lm on the respective
columns of each array, preferably without loops.
We often hear chatter that sometimes apply() won't be faster just
I suggest you post (a shortened version of?) your tome to the
r-sig-ecology list instead.
Cheers,
Bert
On Mon, Aug 19, 2013 at 3:47 PM, Ann Marie Reinhold
reinh...@montana.edu wrote:
I am running permutation regressions in package lmPerm using lmp(). I
am getting what I find to be confusing
Hello
This is probably a really basic question, still I couldn't find an answer in
the web.
I am running more than 200 regressions, but I can only see about 40 in the
console display.
Is there any possibility to change the number of rows which are displayed in
the console?
Many thanks already in
On 20/08/2013 09:58, TMiller wrote:
Hello
This is probably a really basic question, still I couldn't find an answer in
the web.
I am running more than 200 regressions, but I can only see about 40 in the
console display.
Is there any possibility to change the number of rows which are displayed in
I have a kohonen object generated with grid parameters grid =
somgrid(20, 20, hexagonal). Standard plot shows the codebook vectors
for all variables. I want to have a hexagonal heatmap for each
variable.
I found in Applied Spatial Data Analysis with R code to generate hexagonal grid.
library(sp)
I have problems to install the FAME package. I have installed the fame
client 9.3.32.2 and the environmental variable is set. However, for
some reason, the warnings error: argument lib.loc is missing,
with no default pops up under the i386 installation and LoadLibrary
failure: %1 is not a valid
I am sorry for the confusing message. I am using R-Studio. In the picture you
see a print screen, I mean the console at the bottom left. I am using Mac OS
X. If anyone could help me, I'd really appreciate it.
Many thanks
Tom
Hi,
May be this helps.
a1- data.frame(a)
b1- data.frame(b)
lapply(seq_len(ncol(a1)),function(i) lm(b1[,i]~a1[,i]))
lapply(seq_len(ncol(a1)),function(i) summary(lm(b1[,i]~a1[,i]))$coef)
A.K.
- Original Message -
From: Folkes, Michael michael.fol...@dfo-mpo.gc.ca
To:
Also, if you need ?mapply()
linRegFun- function(x,y){
res- summary(lm(y~x))$coef}
res1-sapply(seq_len(ncol(a1)),function(i) summary(lm(b1[,i]~a1[,i]))$coef)
res2-mapply(linRegFun,a1,b1)
attr(res2,dimnames)-NULL
identical(res1,res2)
#[1] TRUE
A.K.
- Original Message -
From: arun
For tasks which don't involve I/O but fail with mclapply, how does one
work out where the problem is? The handy browser() function which
allows for interactive diagnosis won't work with parallel jobs.
What other approaches can one use?
?dump.frames - interactive debugging after the fact.
On 20-08-2013, at 13:40, TMiller thomas.muel...@student.unisg.ch wrote:
I am sorry for the confusing message. I am using R-Studio. In the picture you
see a print screen, I mean the console at the bottom left. I am using Mac OS
X. If anyone could help me, I'd really appreciate it.
Many thanks
Then you are asking your question in the wrong forum. RStudio has their own
support website.
Please read the Posting Guide and list topic info before posting again. Many
people also find [1] helpful in getting of on the right foot here.
[1]
Hello,
I am fitting a weibull regression model to a survival data set, using survreg
from the survival package.I would like to obtain the confidence interval for
the regression coefficients estimates, but I not seeing how.Can anyone help me?
Thanks,Luis
Hi,
Does anybody know how to incorporate panel data into Hoareau et al *easi*
Package?
In Hoareau et al easi Package they use cross sectional data and I would
like to know how I could include 5 years worth of panel data?
Many thanks,
Neil
--
View this message in context:
Dear R community,
I am creating my own package which uses functions from other packages.
After reading several books/help pages I now would do the following to
safely use some functions from other packages:
1. list them in Imports: (DESCRIPTION file)
2. put importFrom(packagename,
On 20/08/2013 15:51, Jannis wrote:
Dear R community,
I am creating my own package which uses functions from other packages.
After reading several books/help pages I now would do the following to
safely use some functions from other packages:
1. list them in Imports: (DESCRIPTION file)
2. put
Would like to plot vertex labels without serif.
there is vertex.label.font param but he lets me choose only between
one font type in normal bold and emph.
any suggestions welcome.
--
Witold Eryk Wolski
__
R-help@r-project.org mailing list
recall. it's:
vertex.label.family
sorry
On 20 August 2013 17:30, Witold E Wolski wewol...@gmail.com wrote:
Would like to plot vertex labels without serif.
there is vertex.label.font param but he lets me choose only between
one font type in normal bold and emph.
any suggestions welcome.
Samuel,
Typically when someone specifies 10-fold cross validation, it implies that
a single series of 10 validations are run. No repeats.
You can read more about cross-validation here ...
http://en.wikipedia.org/wiki/Cross-validation_(statistics)#K-fold_cross-validation
.
Jean
On Mon, Aug
library(abind)
library(plyr)
c - abind(a,b, along = 4)
results - alply(c, c(2,3), function(x) lm(x[,2] ~ x[,1]))
ldply(results, function(x) summary(x)$coef)
Jason Law
Statistician
City of Portland
Bureau of Environmental Services
Water Pollution Control Laboratory
6543 N Burlington Avenue
Well that was frightfully simple. It's true that if data structure allows it
seems best to flatten the data, yes?
Thanks to A.K.
Michael
-Original Message-
From: arun [mailto:smartpink...@yahoo.com]
Sent: August 20, 2013 4:43 AM
To: Folkes, Michael
Cc: R help
Subject: Re: [R] function
I know have multiple ways to skin the metaphorical cat.
Thanks to Jason and A.K.
Michael
-Original Message-
From: Law, Jason [mailto:jason@portlandoregon.gov]
Sent: August 20, 2013 9:54 AM
To: Folkes, Michael
Cc: R help
Subject: RE: function on columns of two arrays
library(abind)
Really a question for RStudio support and I don't know if this is still true
http://support.rstudio.org/help/discussions/questions/724-console-line-limit
but I'd also suggest just using sink() and viewing the results in a text editor
or word processor.
John Kane
Kingston ON Canada
Dear R users
I have a question concerning applying a function to each element of a dataframe:
1)
-- I have a dataframe like this: d:
(columnames: names of Landcovertypes, rownames: coordinates, nr:
rowsums, nc:colummnsums)
(look at the end of the mail for the structure of d, dput(d) )
here, d
Here's a tiny summary of the speed results using different methods to
run lm on common columns from two arrays.
Sadly looping is fastest. I don't know if any are sensitive to array
dimensions (more columns, fewer layers etc).
I invite correction, or suggestions for improvement to avoid looping.
Hello,
Address your questions to R-Help, please:
r-help@r-project.org
I don't use VBA, so I can't help you with what you need.
Does your code run in R?
As a first line of code, you should have written
library(forecast)
rest of answer inline.
Em 20-08-2013 17:10,
Hi Michael,
I run it on my system after deleting one of the lines from method1 (as it was
not necessary)
method1 - function(){
a1- data.frame(a)
b1- data.frame(b)
lapply(seq_len(ncol(a1)),function(i) summary(lm(b1[,i]~a1[,i]))$coef)
}
linRegFun- function(x,y){
res-
That's much more fair I failed to note that extra line of work.
Good to know looping can be avoided.
Thanks!
-Original Message-
From: arun [mailto:smartpink...@yahoo.com]
Sent: August 20, 2013 11:11 AM
To: Folkes, Michael
Cc: R help
Subject: Re: function on columns of two arrays
Hi
On 08/12/2013 05:55 PM, Pablo Menese Camargo wrote:
fitcfa - cfa(mcfa, data = data_analisis)
summary(fitcfa, standardized = TRUE, fit.measure=TRUE)
standardizedSolution(fitcfa, type = std.all)
anyone know what y should do to apply polychoric?
See the manual:
On Aug 20, 2013, at 7:04 AM, Luis Antunes wrote:
Hello,
I am fitting a weibull regression model to a survival data set, using survreg
from the survival package.I would like to obtain the confidence interval for
the regression coefficients estimates, but I not seeing how.Can anyone help
You have been trapped by attempting to use double quotes inside double
quotes.
Use single quotes on the inside
etsz - ets(zz,model='ZZZ')
Please send only minimal data to the list.
dput(head(mydata))
is the preferred format. That way a reader of this list can pick it up
from the email and
Hello:
I have somewhat of a generic question. How do you use multiple CPU/core
processors in R? For those familiar with Mplus software, I'm looking for
something analogous to PROCESSORS command in Mplus to speed up processing.
I searched previous helps/googled it and see that there is a
Hi,
I would like to include the greek letter mu, in italics, in an axis title. The
following gets close, but the mu isn't italicized.
x - 1:10
y - 1:10
plot(y ~x, ylab = expression(paste('Greek ', italic(mu
Anybody know how to accomplish this?
Thanks,
Jake
Thanks, Bert. Perhaps it would serve me to be more direct and
concise. Why am I unable to replicate lm() results using lmp() when
the documentation indicates that the results should be the same when
perm=, seqs=TRUE, center=FALSE? Some of the estimates are
different. In addition, the standard
Hi,
Please find attached rcode and my data.There seems to be a problem in the
following rcodes:
plot(diet~class.f, data=nuru)
points(pred.mod1~midpoints,type=b)
please I need your help.
Kind Regards,
Nuru
Species Fish ID DateTimeDepth (m) Haul.No.Longitude
Good afternoon,
I have two years of count data (daily time-series data). My Y variable can be
modeled using a ZINB model with day of the week and month effects (both x
variables retained in the logistic and negative binomial part of the model).
Now I would like to simulate 100 years of count
Dear Ariel
Thank you for your detailed explanations and the example. Indeed, it
should be rather straightforward to implement observation-specific
weights in systemfit (i.e. in the estimation of systems of linear or
non-linear equations). As you indicated that many people are looking
for this
HI,
nuru-
read.table(NS.diet.txt,header=TRUE,stringsAsFactors=FALSE,sep=\t,fill=TRUE,check.names=FALSE)
colnames(nuru)
# [1] Species Fish ID Date
#[4] Time Depth (m) Haul.No.
#[7] Longitude
My problem is to evaluate several conditional moments nonparametrically.
That is to evaluate E(y|x=x_0) and Var(y|x=x_0) with y a 2x1 variable.
I have tried several commands in np package, like npregbw. I cannot
find a command that can apply to the case with multivariate dependent
variables,
Hey All,
I wanna to fit a model y~x/(a+x) to my data, here is the code I use now:
lm((1/y-1)~I(1/x)+0, data=b)
and it will return the coefficient which is value of a
however, if I use the code above, I am not able to draw a curve the
presents this equation. How can I do this?
Thanks for your
?curve
set.seed(42)
x - 1:15
y - x/(1+x)+rnorm(15, 0, .02)
plot(y~x)
lm.out - lm((1/y-1)~I(1/x)+0)
curve(x/(coef(lm.out)+x), 1, 15, add=TRUE)
-
David L Carlson
Associate Professor of Anthropology
Texas AM University
College Station, TX 77840-4352
PLEASE do not crosspost to Rhelp and googlegroups. (removed that address.)
On Aug 20, 2013, at 9:43 AM, Jacqueline Oehri wrote:
Dear R users
I have a question concerning applying a function to each element of a
dataframe:
1)
-- I have a dataframe like this: d:
(columnames: names
On Aug 20, 2013, at 12:06 PM, Beaulieu, Jake wrote:
Hi,
I would like to include the greek letter mu, in italics, in an axis title.
The following gets close, but the mu isn't italicized.
x - 1:10
y - 1:10
plot(y ~x, ylab = expression(paste('Greek ', italic(mu
The Symbol font
(1) It is not acceptable to use wanna in written English. You should say
I want to fit a model .
(2) The model you have fitted is *not* equivalent to the model you first
state.
If you write y ~ x/(a+x) you are tacitly implying that
y = x/(a+x) + E
where the errors E are
T
hanks for your insights Rolf! The model I want to fit is y=x/a+x with no
intercept, so I transformed it to 1/y=1+a/x as they are the same. but i
will look up nls() and see how to fit the model without transformation.
On Tue, Aug 20, 2013 at 2:45 PM, Rolf Turner rolf.tur...@xtra.co.nz wrote:
On 21/08/13 11:23, Ye Lin wrote:
T
hanks for your insights Rolf! The model I want to fit is y=x/a+x with
no intercept, so I transformed it to 1/y=1+a/x as they are the same.
For crying out loud, they are ***NOT*** the same. The equations y =
x/(a+x) and
1/y = 1 + a/x are indeed
I tried
lapply(split(Clean,list(Clean$TERM,Clean$INST_NUM)),function(x)
shapiro.test(x$GRADE))
and I got
Error in shapiro.test(x$GRADE.) : sample size must be between 3 and 5000
I also tried
with(Clean, aggregate(GRADE,list(TERM,INST_NUM),FUN=shapiro.test))
and got
Group.1 Group.2 x
Rolf:
Thanks for this.
It nicely illustrates what to me is a fundamental problem: For many
scientists, it is not math (stats) that is the stumbling block, but
rather the failure to understand how variability (noise) affects the
experimental/observational process. One does tend to get more
A minimal R source code file producing this is:
data=c(1,2)
pdf(file=error.pdf)
barplot(data)
legend(1.5,c(expression(italic(C.sativa),italic(B.rapa))),horiz=TRUE)
dev.off()
The problem is that the two italicised strings are not aligned in the pdf
output, with the string on the left being lower
On Aug 20, 2013, at 2:28 PM, Nixon, John wrote:
A minimal R source code file producing this is:
data=c(1,2)
pdf(file=error.pdf)
barplot(data)
legend(1.5,c(expression(italic(C.sativa),italic(B.rapa))),horiz=TRUE)
dev.off()
The problem is that the two italicised strings are not aligned
HI,
I guess your original dataset would have some list elements as empty.
Clean- structure(list(GRADE = c(1, 2, 3, 1.5, 1.75, 2, 0.5, 2, 3.5,
3.5, 3.75, 4), TERM = c(9L, 9L, 9L, 8L, 8L, 8L, 9L, 9L, 9L, 8L,
8L, 8L), INST_NUM = c(1L, 1L, 1L, 2L, 2L, 2L, 2L, 2L, 2L, 1L,
1L, 1L)), .Names =
Hello,
You may find hints in the following thread:
https://stat.ethz.ch/pipermail/r-help/2011-June/281493.html
Regards,
Pascal
2013/8/21 Beaulieu, Jake beaulieu.j...@epa.gov
Hi,
I would like to include the greek letter mu, in italics, in an axis title.
The following gets close, but the
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