Better, I don't know...
But alternatively, and maybe thinning the fog a bit:
set.seed(42)
xxx - rnorm(300,10,2)
hist(xxx,main=bquote(Heart~~Attackbar(x) == .(mean(xxx
Cheers,
Bert
On Fri, Oct 11, 2013 at 10:23 PM, Rolf Turner r.tur...@auckland.ac.nz wrote:
On 10/12/13 11:39, Emily
Hi,
A slight modification would be:
hist(xxx,main=bquote(Heart Attack ~ bar(x) == .(mean(xxx
#or use ?substitute()
hist(xxx,main=substitute(Heart Attack ~ bar(x) == mx,list(mx=mean(xxx
A.K.
On Saturday, October 12, 2013 1:26 AM, Rolf Turner r.tur...@auckland.ac.nz
wrote:
On 10/12/13
Hi,
Try:
segmentf_df - function(df) {
out.lm-lm(deltaWgt~Cycle, data=df)
segmented(out.lm,seg.Z=~Cycle,
psi=(Cycle=NA),control=seg.control(stop.if.error=FALSE,n.boot=0))
}
library(plyr)
library(segmented)
dlply(df,.(Lot.Run),segmentf_df)
$`J062431-1`
Call: segmented.lm(obj = out.lm, seg.Z =
Modified Bert's solution for non-square matrices. For the tested vectors, it
worked. There, could still be some bugs.
x1- c(3,2,1,4)
x2- c(2,0,4,3,1)
x3 - c(2, 1, 2.2)
x4 - c(a,1,3)
makeMat3 - function(x,n){
if(is.numeric(x)){
x - as.integer(round(x))
x}
Le vendredi 11 octobre 2013 à 18:49 +0200, Thibault Helleputte a écrit :
Hello,
Working on an ubuntu 13.04 with a sessionInfo() specified below, I try to
update my packages, and RSQLite update consistently fails like this:
update.packages(checkBuilt=TRUE, ask=FALSE)
Warning: package
We have created two introductory screencast tutorials on R, using
RStudio, and released them under a CC license. These are available at
http://www.spoken-tutorial.org/list_videos?view=1foss=Rlanguage=all -
one may view them on a web browser or download them - without any
registration, whatsoever.
Hi,
I want to export the result of glht in R into a LaTeX table, such as that
result:
Linear Hypotheses:
Estimate Std. Error z value
Pr(|z|)
Group1 - Group2 == 0 -0.140070.01589 -8.813 0.001 ***
Group1 - Group3 == 0-0.09396
This seems to do it, but as I mentioned in my original post, my
solution was tricky. Thinking about it some more, I now realize that
it was too tricky and has the additional flaw of using underlying
representations of objects rather than their exposed interfaces -- i.e
it treats a matrix as a
Hello,
I'd like to produce a ggplot where the order of factors within facets is
based on the average of another variable.
Here's a reproducible example. My problem is that the factors are ordered
similarly in both facets. I would like to have, within each facet of `f1',
boxplots for 'x' within
This looks better. My previous solution (makeMatrix2) also did the matrix
indexing without using sapply() route. Replacing the max(x) by n for
non-symmetric matrix:
makeMatrix2- function(x,n){ #including n
if(is.numeric(x)){
x - as.integer(round(x))
x}
stopifnot(is.integer(x))
m1-
Some speed comparison:
set.seed(124)
xtest- sample(0:9,1e7,replace=TRUE)
system.time({res1 - makemx(xtest,9)})
# user system elapsed
# 51.124 0.812 52.039
system.time({res2 - makeMatrix2(xtest,9)})
# user system elapsed
# 3.460 0.168 3.631
identical(res1,res2)
#[1] TRUE
Dear R users,
I am pretty new to programming in R. So I guess there is some obvious mistake I
am making. I hope you can help me.
I have a data frame that looks like this:
AB
timexy z gene part
1 03:27:58 1 23grom
Thank you very much.
On Fri, Oct 11, 2013 at 10:40 PM, kan...@iitb.ac.in wrote:
We have created two introductory screencast tutorials on R, using
RStudio, and released them under a CC license. These are available at
http://www.spoken-tutorial.org/list_videos?view=1foss=Rlanguage=all -
one
Apologies, in case it is double posting (I think my previous message didn't
make it to the list)
Hope the new version of `makeMat3` is bug free:
makeMat3 - function(x,n){
if(is.numeric(x)){
x - as.integer(round(x))
x}
stopifnot(is.integer(x))
if(length(x)=n max(x)=n){
Hi,
Not sure if you have any restrictions in using ?lapply().
AB - read.table(text=
time x y z gene part
1 03:27:58 1 2 3 grom 1
2 03:27:58 2 3 4 grom 1
3 03:27:58 3 4 5 grom
On Sat, Oct 12, 2013 at 12:01 PM, Lars Bishop lars...@gmail.com wrote:
Hello,
I'd like to produce a ggplot where the order of factors within facets is
based on the average of another variable.
Here's a reproducible example. My problem is that the factors are ordered
similarly in both
Hi,
As you using library(plyr), you may try:
library(ggplot2)
library(plyr)
df2 - df
d1 - dlply(df2,.(f1),function(u) {
u$f2- reorder(u$f2,u$Avg_x)
ggplot(mapping=aes(x=f2,y=x))+
Hi,
I'm trying to user lmer function from lmerTest package because, if I
understood correectly, it allows to make better inference than lmer method
from lme4 package. However, whatever I do I keep getting this error:
Error in lme4::lFormula(formula = mark ~ ssCount + sTime+ : rank of X =
1660
Any idea what could be the problem? Hmmm... posting in html? No reproducible
example? Not posting on R-sig-ME? Just some ideas... reading the Posting Guide
might be helpful to you.
---
Jeff Newmiller
ok, ok... thanks.
I'll try with R-sig-ME
On Sat, Oct 12, 2013 at 5:43 PM, Jeff Newmiller jdnew...@dcn.davis.ca.uswrote:
Any idea what could be the problem? Hmmm... posting in html? No
reproducible example? Not posting on R-sig-ME? Just some ideas... reading
the Posting Guide might be
The trick for latexing glht objects is recognizing that they are very complex.
It is necessary to isolate the part you want first,
then the latex() function in Hmisc works very well.
This example is based on one of the examples in ?glht
library(Hmisc)
library(multcomp)
### set up a one-way
On 10/13/2013 02:12 AM, anna berg wrote:
Dear R users,
I am pretty new to programming in R. So I guess there is some obvious mistake I
am making. I hope you can help me.
I have a data frame that looks like this:
AB
timexy z gene part
1
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