Of course the OP failed to note that no pictures can come through...
But anyway,
Do not do this! It can be highly misleading (due to arbitrariness of
binning). See
?qqplot
for a much better way to compare distributions.(alas, rarely used
except by statisticians)
-- Bert
Bert Gunter
How can I see the code for boxcox.default?
library(MASS)
boxcox.default
Error: object 'boxcox.default' not found
[[alternative HTML version deleted]]
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PLEASE
The original has not reached me yet
latexVerbatim is in Hmisc and appears similar to xtable::xtable
using xtable
library(xtable)
x - matrix(rnorm(25), 5,5,dimnames=list(c(1:5),LETTERS[1:5]))
x
fhtml - latex.tex
file.create(fhtml)
# open to append
ff - file(fhtml, a+)
writeLines(print(
I wish to compare prices in a dataframe to calculated upper limits and
then reject (collect in a reject dataframe) those rows with prices that
are above the upper limit but I am having trouble aligning the variable
value in the Prices dataframe with the names in the upper limit file.
upperLimit
Many of the statistics reported don't make sense with only two
items--for example the alpha if an item is dropped makes no sense
because dropping an item leaves only one remaining.
Best,
Ista
On Fri, Feb 14, 2014 at 5:24 PM, Johannes Moser joh...@web.de wrote:
Dear R-help,
I try to estimate
Dear All,
I am a bit puzzled.
I am developing a random forest model.
The data is large and it involves hundred of predictors, but the code I
have written is relatively simple.
After training my random forest model, I apply it on some new data set to
carry out some prediction, as you can see
On Feb 14, 2014, at 11:04 PM, Gene Leynes wrote:
How can I see the code for boxcox.default?
http://cran.r-project.org/doc/Rnews/Rnews_2006-4.pdf
library(MASS)
boxcox.default
Error: object 'boxcox.default' not found
[[alternative HTML version deleted]]
Please learn to post in
I have a 7-parameter model to fit using mle. I would like to generate
fits for all
pairs of parameters (with others fixed)
The following code looked like it should work:
library(stats4)
# dummy mll function for sake of example
mll = function
Hi,
I have some question of using R. As we know R is connecting to CRAN Mirror
for packages update, I am afraid that the data we import into R will be
uploaded to somewhere i.e. server. Could you confirm that R is purely run on
the local machine without connecting to any server for data
fit is initialized as a vector of integers. How can you assign an mle
fit to an element of an integer vector?
Initialize fit as a list, use lapply, or whatever. Have you read An
Intro to R (ships with R) or other R (e.g. web) tutorial? This looks
like the sort of basic misunderstanding that one
On Sat, Feb 15, 2014 at 8:43 AM, Lorenzo Isella
lorenzo.ise...@gmail.com wrote:
Dear All,
I am a bit puzzled.
I am developing a random forest model.
The data is large and it involves hundred of predictors, but the code I have
written is relatively simple.
After training my random forest
May be this helps:
Prices.df - read.table(text=rowID Price
1 'Full Season' 417.95
2 'Full Season' 679.43
3 'Full Season' 839.79
4 'Half Season' 159.39
5 'Half Season' 256.93,sep=,header=TRUE,stringsAsFactors=FALSE)
upperLimit - c(`Full Season`=779.12, `Half Season`=231.11)
rejectdf -
Also, you could try:
library(plyr)
indx - ddply(Prices.df,.(rowID),summarise,
!findInterval(Price,unique(upperLimit[match(rowID,names(upperLimit))])))[,2]
Prices.df[indx,]
Prices.df[!indx,]
#or
indx1 - !with(Prices.df,ave(seq_along(Price),rowID,FUN=function(x)
Thank you, Arun. Your first suggestion works perfectly and I will use that.
- Barry
On Sat, Feb 15, 2014 at 12:45 PM, arun smartpink...@yahoo.com wrote:
Also, you could try:
library(plyr)
indx - ddply(Prices.df,.(rowID),summarise,
Thank you A.K. and Ista. The answer that eliminates duplicated rows is
A.K.'s first solution (brilliant idea using which.max!).
The version of Ista's solution without duplicates is
ddply(data, state, function(x) x[which.max(x$date), ])$value
Thanks again!
Dan
On Thu, Feb 13, 2014 at 8:36 AM, arun
Hi folks,
I'm having trouble with code that used to work, and I can't figure out
what's going wrong. I'd be grateful for any help in sorting this out.
Suppose I define a matrix
mm - matrix(1:15, 25,2)
and compare the first 15 values of column 1 of mm to the values remaining
in the same column
On 02/16/2014 07:16 AM, David Romano wrote:
Hi folks,
I'm having trouble with code that used to work, and I can't figure out
what's going wrong. I'd be grateful for any help in sorting this out.
Suppose I define a matrix
mm- matrix(1:15, 25,2)
and compare the first 15 values of column 1 of
Hi David,
Try:
Check the output of:
lapply(mm,function(x) x) #mm is matrix
#and
lapply(as.data.frame(mm),function(x) x)
sapply(split(mm,col(mm)),function(x){out -
t.test(x[1:15],x[16:25])$p.value})
# 1 2
#0.1091573 1.000
#or
sapply(as.data.frame(mm), function(x)
I need to retrieve the data from my Database.
later send the data and the .r script to R engine and do the execution.
-
Regards,
Yuvaraj R
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View this message in context:
http://r.789695.n4.nabble.com/Writing-R-code-in-C-and-Executing-tp4685380.html
Sent from the R help mailing list
Hi,
In my case I don't have any static data to be written in the .r file.
I need to retrieve the data from my Database.
later send the data and the .r script to R engine and do the execution.
--
View this message in context:
Hi,
May be this helps:
vec1 - c(victory,happiness,medal,war,service,ribbon, dates)
vec2 - c(The World War II Victory Medal was first issued as a service ribbon
referred to as the Victory Ribbon., By 1946, a full medal had been
established which was referred to as the World War II Victory
Hi all,
I would like to reorder the leaves of a dendrogram. I attached the tree in
the attachment.
The code I apply is
reorder.tree = function(
Dend, # the dendrogram you want to order
order.n){ # the order of leaves from left to right
new.order = rbind(order.n, 1:length(order.n))
wts =
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