When i am running a *DELETE * query on MS SQL database I am getting
*[RODBC] ERROR: Could not SQLExecDirect * error. I am getting this error for
the DELETE query that requires more time.
Please suggest workarounds if any.
Thanks
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Dear Members,
I have a dataset that is similar to the first example in the car function, cts
package
data(V22174)
fit - car(V22174,scale=0.2,order=7, ctrl=car_control(trace=TRUE))
summary(fit)
I would like to ask if there is a way to get the predicted/fitted values for
all the timepoints
Hi Tom,
I think you are going to get better answers if you include some code which
helps reproducing what you are doing for other users (posting guide). Exporting
regression outputs to Excel does not seem to be the way to go. Aren't you just
looking for ?predict. I am sure R can do the job for
Dear All
I have a question about combining effect sizes generated by escalc in metafor.
I realise these may be stupid things to do; but they are deliberately so to
explain what I mean - I don't intend doing this!
I have 3 studies; each of which has a different measure of effect/presents the
Hi. I am running the code below. I am getting the error
Error in match.names(clabs, names(xi)) :
names do not match previous names
I don't really want to specify the size of the allFuku data frame at the
beginning but even when I tried it I still got this error.
v12=paste(0,1:9,-,2010,,sep=)
Thanks Bert
- Messaggio originale -
Da: Bert Gunter gunter.ber...@gene.com
A: Massimiliano Tripoli mtrip...@istat.it
Cc: r-help@r-project.org
Inviato: Sabato, 29 marzo 2014 15:52:59
Oggetto: Re: [R] problem of tapply function
The argument to tapply is FUN, not fun. R is case sensitive.
Not sure why but when I change this:
temp.df[,month]-month
temp.df[,year]-year
to this:
temp.df[,2]-month
temp.df[,1]-year
it seems to work.
On Sun, Mar 30, 2014 at 6:01 PM, Bill william...@gmail.com wrote:
temp.df[,month]-month
temp.df[,year]-year
[[alternative HTML version
Hi,
c( factor( 'a'), ( 1))
[1] 1 1
c( factor( 'a'), factor( 1))
[1] 1 1
c( factor( 'a'), factor( 'b'))
[1] 1 1
unlist( list( factor( 'a'), 1))
[1] 1 1
unlist( list( factor( 'a'), factor( 1)))
[1] a 1
Levels: a 1
unlist( list( factor( 'a'), factor( 'b')))
[1] a b
Levels: a b
In an
At 09:42 30/03/2014, Purssell, Ed wrote:
Dear All
I have a question about combining effect sizes generated by escalc
in metafor. I realise these may be stupid things to do; but they
are deliberately so to explain what I mean - I don't intend doing this!
I have 3 studies; each of which
This is definitely not an error, all these behaviours are by design. You need
to (re)read the description of factors in the Introduction to R document that
comes with the software. Factors are not optimized versions of strings, they
are finite sets of category information designed for use in
Please read ?[ carefully -- or (re?)-read An Introduction to R.
The column name must be quoted:
temp.df[,month]-month
-- Bert
Bert Gunter
Genentech Nonclinical Biostatistics
(650) 467-7374
Data is not information. Information is not knowledge. And knowledge
is certainly not wisdom.
H.
Here is my current process:
x.sub- subset(Model.Update, Row 200 Row 0) # INITIAL SAMPLE
x.sub1-subset(Model.Update, Row 206 Row 200) # Subset into lots of 5
until current period - 5 period
...
Hi
I have a problem with linear regression. This is my codes:
acc1- lm(data$acc ~ dummy + data$Reqloanamount + data$Code + data$Code.1 +
data$EmpNetMonthlyPay + data$Customer_Age + data$RTI)
summary(acc1)
These attributes are all numerical except the acc(factors), so how can I
fix the problem R
Please provide some data from your variable data.
Show the output of dput( data) or an subset
of data which leads toe the specific error.
Regards
On Sun, Mar 30, 2014 at 02:23:09PM +0100, Si Qi L. wrote:
Hi
I have a problem with linear regression. This is my codes:
acc1- lm(data$acc ~
1. Post in plain text, not HTML.
2. Read ?lm and note the data argument. Use it in your lm call instead
of all the $data extractions.
3. Your problem is with the summary() call, so read ?summary.lm. Learn
about S3 methods if you do not know where the .lm part is coming
from by reading the
I suspect the problem may be with the structure of the data.
Si Qi L wrote:
[...]
acc1- lm(data$acc ~ dummy + data$Reqloanamount + data$Code +
data$Code.1 + data$EmpNetMonthlyPay + data$Customer_Age + data$RTI)
[...]
These attributes are all numerical except the acc(factors)
[...]
Ted:
Yes. You're probably right, and I'm probably wrong. I did not read
carefully enough. Impossible to know for sure with such an ill-posed
query, though.
Cheers,
Bert
Bert Gunter
Genentech Nonclinical Biostatistics
(650) 467-7374
Data is not information. Information is not knowledge. And
I am not able to find the criterion under which the best subset model for a
certain size is chosen for the function regsubsets (leaps package in R) . For
leaps function, we can determine the method ( cp,r2 or adj r2). For example,
x - predictors
y - response
g - regsubsets(x,y,nvmax=1,nbest=1)
Hi Atem,
Try this:
I created 3 folders (Precip, Tmax, Tmin) within the folder sample
#working directory: sample
list.files()
#[1] Imputation_Daily_Sim01.datImputation_Daily_Sim02.dat
#[3] Imputation_Daily_Sim03.datPrecip
#[5] Sim1971-2000_Daily_Sim001.dat
Mohammed:
I am sorry to burst your bubble, but the whole concept of finding a
best subset regression is now considered to be badly flawed. There
will typically be many essentially equivalent choices. Shrinkage of
varying kinds and ensemble fits are the sorts of things that are
done nowadays. I
Dear Sir,
I am not sure about the precision of the cov.wt function. It seems that it
provides different results when using frequency weights. This discrepancy only
occurs with the covariance matrix, not with the correlation matrix.
Do you know to how to solve this issue? Thank you
Best regards,
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