Dear Craig,
It is better to ask questions about lme4 at r-sig-mixed-models (in cc).
Are you using a recent version of lme4? Try upgrading lme4 and see if you still
get the error.
Best regards,
Thierry
ir. Thierry Onkelinx
Instituut voor natuur- en bosonderzoek / Research Institute for Nature
Dear all,
in one of my packages I need to load some data from .Rdata files that
are to be used from
some functions (but not all off them). I would like to delay the
loading of this datasets
only when needed. In other cases I successfully used lazyLoad and
delayedAssign(),
but when I try to load a
Dear all
I try to fit a linear mixed model to my data. In short, my dependent variable
reflects changes of the bone level (Knmn, in mm), thus this variable is
continous and provides negative values. I have two different groups (factor
Group) that were measured 3 times each (thus repeated
Hello,
I want to subset a data.frame containing the variables Date in (%Y %m %d
) and N.
I want to print Date and N if N is less than or equal to 0.3 and if
N is also less than or equal to 0.3 on the day before the day where N
is less than or equal to 0.3.
This would be the case in line 3 and
Dear All,
Please, is there any package in R that has implemented ridge regression for
beta and gamma models?
If not, kindly help me to adjust my model below for the beta regression so as
to accommodate ridge
penalty. Thanks.
lbeta - function(par,y,X){
n -length(y)
k - ncol(X)
beta -
Thanks for your kind replies
Jorge's answer helps.
warm wishes
Xueming
xmliu1...@gmail.com
From: Jorge I Velez
Date: 2014-04-26 23:41
To: xmliu1...@gmail.com
CC: r-help
Subject: Re: [R] Faster way to transform vector [3 8 4 6 1 5] to [2 6 3 5 1 4]
Hi Xueming,
Try
Hi Christoph,
I'm not sure I understand your conditions. It is an AND or an OR,
i.e. must both conditions be met to subset or any one of them?
From your explanation, I would think you really mean AND, but then I
don't understand why you would select both lines 3 and 4.
I would just say:
Hi,
I noticed that if ?mean or ?median in fun1 is changed to other functions, for
e.g. ?sum, it will show error message.
##Using shortened version that runs
library(plyr)
fun1 - function(data, .group) {
f1 - function(x) c(x, mean(x, na.rm = TRUE), sum(x, na.rm = TRUE))
res - ddply(data,
Dear all
I am having trouble with subsetting an ffdf object, hopefully somebody can
help...
I have an index, which is a ff object of vmode logical:
index.SAS
ff (open) logical length=4977231 (4977231)
[1] [2] [3] [4] [5] [6] [7] [8]
Werner W pensterfuz...@yahoo.de
on Sun, 27 Apr 2014 17:48:23 +0100 writes:
Dear Martin, Arne, David,
Thanks for considering my problem. However, I have a bit of a problem in
making a small reproducible example. So far, I tried to drill down into the
code and to quick fix this
Dear Caroline,
Check the homogeneity of the variances. If they are inhomogeneous, you can add
a variance function to deal with it. However, you will need to switch to the
lme() from the nlme package.
Best regards,
Thierry
PS R-Sig-mixed-models is a better list for this kind of questions.
Hi,
The conditions are not very clear. Based on the rows you wanted to pick, may
be this helps,
#It is better to dput() the example.
dat - structure(list(Date = structure(c(14610, 14611, 14612, 14613,
14614, 14615, 14616, 14617, 14618, 14619, 14620, 14621, 14622,
14623, 14624, 14625,
Hi
Here is a very simple way.
mydat - read.table(text=
DateN
2010-01-010
2010-01-021.9
2010-01-030
2010-01-040
2010-01-051.6
2010-01-060
2010-01-070.3
2010-01-080
2010-01-091.1
2010-01-101.7
2010-01-112.6
2010-01-120
2010-01-130
2010-01-14
So Christoph now have 3 methods giving him three different results. Of course
it is not really clear what Christoph really wants ;-)
Yours sincerely / Med venlig hilsen
Frede Aakmann Tøgersen
Specialist, M.Sc., Ph.D.
Plant Performance Modeling
Technology Service Solutions
T +45 9730 5135
M
Dear R community, hello,
Hope everybody is doing great. I just downloaded R version 3.1.0, and,
whenever I try to load the forecast package, the following error message
appears:
Error in loadNamespace(i, c(lib.loc, .libPaths()), versionCheck = vI[[i]])
:
there is no package called âRcppâ
Dear Duncan,
This is what is happening when I try downloading the Rcpp package in R
version 3.1.0
Error in loadNamespace(i, c(lib.loc, .libPaths()), versionCheck = vI[[i]])
:
there is no package called âRcppâ
Error: package or namespace load failed for âforecastâ
2014-04-28 10:27
On 28/04/2014 11:22 AM, Paul Bernal wrote:
Dear R community, hello,
Hope everybody is doing great. I just downloaded R version 3.1.0, and,
whenever I try to load the forecast package, the following error message
appears:
Error in loadNamespace(i, c(lib.loc, .libPaths()), versionCheck =
Paul Bernal paulbernal07 at gmail.com writes:
This is what is happening when I try downloading the Rcpp package in R
version 3.1.0
Error in loadNamespace(i, c(lib.loc, .libPaths()), versionCheck = vI[[i]])
:
there is no package called âRcppâ
Error: package or namespace load failed
On Mon, 28 Apr 2014, Dirk Eddelbuettel wrote:
That is conflicting with the fact that the package page for Rcpp shows
you binaries for
three R versions (devel, release, old-release) on Windows
three R versions (devel, release, old-release) on OS X 'snow leopard'
one R version (release) on OS
Hello,
Or maybe better,
install.packages(forecast, dependencies = TRUE)
since package forecast depends on several other packages
Hope this helps,
Rui Barradas
Em 28-04-2014 17:04, Rich Shepard escreveu:
On Mon, 28 Apr 2014, Dirk Eddelbuettel wrote:
That is conflicting with the fact that
Roche Pharmaceuticals has openings for two nonclinical statisticians
at its Basel, Switzerland RD site. The positions' initial focus will
be working with process and formulation chemists. A solid background
in linear models, Design of Experiments, and English fluency are
minimal requirements.
On 28/04/2014 11:31 AM, Paul Bernal wrote:
Dear Duncan,
This is what is happening when I try downloading the Rcpp package in R
version 3.1.0
Error in loadNamespace(i, c(lib.loc, .libPaths()), versionCheck =
vI[[i]]) :
there is no package called ‘Rcpp’
Error: package or namespace load
Thanks Rolf. That took care of it. It should be lower=FALSE through right?
I want the upper tail because my values are right censored?
Regards,
Jake
On Fri, Apr 25, 2014 at 12:50 AM, Rolf Turner r.tur...@auckland.ac.nzwrote:
As usual I am too lazy to fight my way through the rather convoluted
Hi all,
I am a new comer in R . i am trying to figure out how to put in the
label of a plot the basic statistics values like mean=
no of data =
media =
chi-square =
in a box.
I tried a lot to search over the net but couldn't find one as
Thanks. I used the most current version of lme4 that is why I was a bit
concerned. My data seems appropriate and with lme4 working last week on a very
similar data set, I was left a bit confused. Since I only starting
implementing this technique, does anybody have some pointers on what I
Thank you all for your kind help.
On Sat, Apr 26, 2014 at 7:03 PM, Tal Galili tal.gal...@gmail.com wrote:
Thank you for mentioning the
dendextendhttp://cran.r-project.org/web/packages/dendextend/package
Gregory.
As I mention in the package, the dendextend package implements a similar
Dear list,
Reading a function I found this:
lm ( y ~ 1 )
I know that Y ~ -1 + A is a straight-line with no y-intercept; that is, a
fit forced through (0,0). But I never saw the first example. Any tip?
Thanks in advance!
C.
[[alternative HTML version deleted]]
Hi,
The princomp() function has a nice method to generate a pretty biplot of
the data. I have some data where the points are divided into a few
groups. My intention is to generate a biplot, using princomp, but color
the points based on group membership. The hope is that points will show
some
Hello,
That will compute a fit with coefficient equal to mean(y) and std
error equal to sd(y)/sqrt(length(y))
Hope this helps,
Rui Barradas
Em 28-04-2014 19:35, Alejo C.S. escreveu:
Dear list,
Reading a function I found this:
lm ( y ~ 1 )
I know that Y ~ -1 + A is a straight-line with
On Apr 28, 2014, at 10:47 AM, Ayan Mitra wrote:
Hi all,
I am a new comer in R . i am trying to figure out how to put in the
label of a plot the basic statistics values like mean=
no of data =
media =
chi-square =
In base graphics you
Hi,
I am trying to get the R package Cairo installed. I've been successfully in
building the latest version of Cairo library (1.12.16,
http://cairographics.org/) from source and installed into ~/usr/local using
./configure --prefix=/home/fong/usr/local
I set the my CAIRO_LIBS and CAIRO_CLAGS
You can also use the legend() function which will draw the box
and arrange the text in a single column (or three columns if you
want a single row). It also has shortcuts for positioning the
box such as topleft or bottomright.
?legend
for more details.
-
David
See also ?panel.text for lattice. This presumes that you know how to
use panel functions, however.
-- Bert
Bert Gunter
Genentech Nonclinical Biostatistics
(650) 467-7374
Data is not information. Information is not knowledge. And knowledge
is certainly not wisdom.
H. Gilbert Welch
On Mon,
Hi,
The princomp() function has a nice method to generate a pretty biplot of
the data. I have some data where the points are divided into a few
groups. My intention is to generate a biplot, using princomp, but color
the points based on group membership. The hope is that points will show
some
Hi,
I using the package vars to implement a SVEC model, however I have to
include a exogen vector that's not a dummy. I try to use the tsDyn package
but I don't see a solution for my problem.
So I need to know if any package allow me to do that.
thanks,
Denise
[[alternative HTML
Hi,
I will be very grateful if you can give a help on my problem. I am
really stuck on it now. The problem is that I need to construct a
classification tree model and prune tree in order to test the learning
dataset for getting its sensitivity and specificity. But my codes
seems wrong somewhere,
On Apr 28, 2014, at 2:41 PM, Noah Silverman wrote:
Hi,
The princomp() function has a nice method to generate a pretty biplot of
the data. I have some data where the points are divided into a few
groups. My intention is to generate a biplot, using princomp, but color
the points based on
On 04/29/2014 03:47 AM, Ayan Mitra wrote:
Hi all,
I am a new comer in R . i am trying to figure out how to put in the
label of a plot the basic statistics values like mean=
no of data =
media =
chi-square =
in a box.
I tried a lot to
Indeed it should be lower=FALSE. Du! Sorry 'bout that!
cheers,
Rolf
On 29/04/14 02:51, Jacob Warren (RIT Student) wrote:
Thanks Rolf. That took care of it. It should be lower=FALSE through
right? I want the upper tail because my values are right censored?
Regards,
Jake
On Fri, Apr
Probably not much help to you, but for what it's worth:
* on my system cairo.h is in /usr/include/cairo
Perhaps the CAIRO flags that you set are not adequately guiding the search.
* you need to have the *development* version of cairo installed; on my
system (Fedora 17) I do:
sudo
I have tried, but it doesn't help because when you use the load_all()
function of devtools,
the datasets are not lazyLoaded but fully evaluated..
Does LazyLoad:yes in yourPackage/DESCRIPTION work for you when you use
the command line 'R CMD INSTALL yourPackage?
I don't use devtools, but
Make sure you have cairo-devel installed, and remove the lines
export CAIRO_LIBS=${HOME}/usr/local/lib
export CAIRO_CFLAGS=${HOME}/usr/local/include
from your .bashrc file. If you have cairo-devel installed normally,
the headers should be found with default settings of all search paths.
The
Hi Peter,
Thanks for the reply. I don't have access to the package manager
unfortunately as I am working on a cluster where I don't have admin. So
everything has to installed into my ~/export CAIRO_LIBS=-L${HOME}/usr/local/
lib
export CAIRO_CFLAGS=-I${HOME}/usr/local/include
/local. I tried
At first I thought this is easy: use the same strategy you use for all of these
types of questions. Plot with type=n to suppress output of points, then use
points() or text() to get the colors and shapes and whatnot you need ...
Turns out biplot() does not use a type argument ...
... and you
Hi:
I have recently started working with creating maps in R. I have been able
to create cloropleth maps for Europe without a problem.
However, when I try doing the same for Japan, which shapefile is downloaded
from the website http://gadm.org/country , R stops working. The message
that pops up is
Thanks Peter. From the config.log file, the issue appears to occur here at
the */home/fong/Cairo/conftest.c:28: undefined reference to
`cairo_create'*
-
configure:3631: gcc -std=gnu99 -o conftest -g -O2
-I/home/fong/usr/local/include/cairo conftest.c -lz
-L/home/fong/usr/local/lib 5
Dear R-users,
I am trying to run kmeans on a set comprising of 100 observations. But R
somehow can not figure out the true underlying groups, although other
software such as Jmp, MINITAB are producing the desired result.
Following is a brief example of what I am doing.
library(stringdist)
Cassie,
I am sorry but do you even know what k-means does? That it is a locally
optimal algorithm. That different software implement the same algorithm
differently.
FYI, R uses the Hartigan-Wong (1979) algorithm by default, which is
probably the most efficient out there.
I suggest you first go
I **think** the linker is missing a directive to actually link in the
cairo library. Try adding -lcairo to the LIB flags, something like
export CAIRO_LIBS='-L${HOME}/usr/local/lib -lcairo'
or simply
export CAIRO_LIBS=-l${HOME}/usr/local/lib/libcairo.so
I am not 100% sure of the syntax, but
You are using the wrong algorithm. You want Partitioning around
Medoids (PAM, function pam), not k-means. PAM is also known as
k-medoids, which is where the confusion may come from.
use
library(cluster)
cl = pam(dis, 4)
and see if you get what you want.
HTH,
Peter
On Mon, Apr 28, 2014 at
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