Hi,
I have this problem: K candidates apply for a job. There are R referees
available to review their resumes and provide feedback. Suppose that we would
like M referees to review each candidate (M R). How would I assign
candidates to referees (or, conversely, referees to candidates)?
Hi Evan,
If you just need one font, you may try the showtext package. Here is a
piece of code that you can test:
library(showtext)
# If you have this font installed
font.add(gara, gara.ttf)
# Or you can install a similar one from Google Font
# font.add.google(EB Garamond, gara)
# Try some plots
On Apr 30, 2014, at 6:03 PM, Waichler, Scott R wrote:
Here is a working example with no random parts. Thanks for your patience and
if I'm still off the mark with my presentation I'll drop the matter.
v - c(NA, 1.5, NA, NA,
NA, 1.1, 0.5, NA,
NA, 1.3, 0.4, 0.9)
a1 -
I would ask you to look at this loop-free approach and ask if this is not
equally valid?
ans - matrix(NA, ncol=2, nrow=2)
ind.not.na - which(!is.na(a1))
ans[] - condition1*a1[,,ind.not.na[1]]+ m2 # two matrices of equal
dimensions, one logical.
ans
[,1] [,2]
[1,] NA 1.66
[2,]
On Apr 30, 2014, at 9:32 PM, Waichler, Scott R wrote:
I would ask you to look at this loop-free approach and ask if this is not
equally valid?
ans - matrix(NA, ncol=2, nrow=2)
ind.not.na - which(!is.na(a1))
ans[] - condition1*a1[,,ind.not.na[1]]+ m2 # two matrices of equal
dimensions,
Dear list-members,
Can someone explains me why the last command gives an error. Thanks a lot:
outer(0:1, 0:1, FUN=function(x, y) {x+y})
[,1] [,2]
[1,]01
[2,]12
outer(0:1, 0:1, FUN=function(x, y) {x})
[,1] [,2]
[1,]00
[2,]11
outer(0:1, 0:1,
Marc Girondot marc_grt at yahoo.fr writes:
outer(0:1, 0:1, FUN=function(x, y) {1})
Erreur dans outer(0:1, 0:1, FUN = function(x, y) { :
dims [produit 4] ne correspond pas à la longueur de l'objet [1]
Because whatever the dimensions of your 2 input vectors,
this function simply returns the
On 01-05-2014, at 08:44, Marc Girondot marc_...@yahoo.fr wrote:
Dear list-members,
Can someone explains me why the last command gives an error. Thanks a lot:
outer(0:1, 0:1, FUN=function(x, y) {x+y})
[,1] [,2]
[1,]01
[2,]12
outer(0:1, 0:1, FUN=function(x, y) {x})
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
On Behalf Of Ravi Varadhan
Sent: Wednesday, April 30, 2014 10:49 AM
To: r-help@r-project.org
Subject: [R] A combinatorial assignment problem
Hi,
I have this problem: K candidates apply
-Original Message-
From: r-help-boun...@r-project.org [mailto:r-help-boun...@r-project.org]
On Behalf Of Daniel Nordlund
Sent: Thursday, May 01, 2014 1:10 AM
To: r-help@r-project.org
Subject: Re: [R] A combinatorial assignment problem
-Original Message-
From:
This is not really a combinatorial problem, I'll use small letters
instead of caps.
Arrange the r referees in a circle.
start - 1
Replicate k times{
end - (start + m-1)%% r
output: c(start,end)
start - (end+1)%% r
}
Bert Gunter
Genentech Nonclinical Biostatistics
(650) 467-7374
Data is not
I had trouble with my email and it went before it should. Here's the
solution I meant to send:
Arrange the r referees in a circle.
start - 0
Replicate k times{
end - (start + m-1)%% r
output: c(start,end) +1
start - (end+1)%% r
}
The start and end pairs give the subsets of referees around the
Hi Phil
On 30 April 2014 23:06, phil quij...@gmx.net wrote:
I just started to work with R a couple of weeks ago. Right now I would like
to regress an independent variable on a couple of explanatory variables. The
dependent variable is left censored in the sense that all negative values
and
Hi,
You may try:
evaluate - function(arr, mat1, mat2) {
if (!all(dim(mat1) == dim(mat2))) {
stop(both matrices should have equal dimensions)
}
indx1 - as.matrix(do.call(expand.grid, lapply(dim(arr), sequence)))
indx2 - paste0(indx1[, 1], indx1[, 2])
condition1 -
Thank you John, I solved exploiting Anova call type 2 in your car package
:)
Il 25/apr/2014 14:57 John Fox j...@mcmaster.ca ha scritto:
Dear Sergio,
The Anova() function in the car package can perform MANOVA with a
multivariate linear model fit to unbalanced data by lm() -- see the
examples
Hello everybody
I need to approximate the amount of integral by using
legendre quadrature. I have written a program which doesn't give me a
logical answer; Can anybody help me and send the correct program? For
example the approximated amount of integral of ( x ^2) on (-1,1) based
on legendre
Hello everybody
I need to approximate the amount of integral by using
legendre quadrature. I have written a program which doesn't give me a
logical answer; Can anybody help me and send the correct program? For
example the approximated amount of integral of ( x ^2) on (-1,1) based
on legendre
you could use package distrEx:
library(distrEx)
GLIntegrate(function(x) x^2, lower = -1, upper = 1, order = 50)
hth
Matthias
On 01.05.2014 09:43, pari hesabi wrote:
Hello everybody
I need to approximate the amount of integral by using
legendre quadrature. I have written a program which
On Thu, 01 May 2014, pari hesabi statistic...@hotmail.com writes:
Hello everybody
I need to approximate the amount of integral by using
legendre quadrature. I have written a program which doesn't give me a
logical answer; Can anybody help me and send the correct program? For
example the
Does anyone know of package that implements a tobit model with L1 and L2 (lasso
and ridge) penalties aka elastic net.
I am interested in an elastic net implementation of tobit because my variables
are SNPs genotypes/dosage in Linkage disequilibrium and elastic net type models
to well for that.
Hi,
Sorry, a typo in the previous function:
-
if (condition1[i] !is.na(indx3)) {
arr[x1][indx3] + m2[i] ## should be mat2[i]
} else NA
---
Also, you can try:
library(plyr)
evaluateNew - function(arr, mat1, mat2){
if
Duncan,
Yes, I admit I haven't updated since 2.15.2 so I was behind. I am seeing the
same problem with reading from RODBC (sql server) tables. I write data to a
table and then read it back. In R 2.15 it would come in numeric. Under R 3.1
it comes in as a string.
Thanks,
Roger
Ravi:
You cannot simultaneously have balance and guarantee random mixing.
That is, you would need to specify precisely what you mean by balance
and random mixing in this context, as these terms are now subjective
and undefined.
You could, of course, randomize the initial assignment of referees
Sapply or mapply may work, I haven't used these much and will try to
learn better how to use them. Your use of sapply looks good; but I'm
trying to understand if and how I can bring in the operation on a1. This
doesn't work:
evaluate - function(idx) {
ind.not.na -
Thank you, A.K. I learned from both of your solutions. I find the one that
uses alply easier to follow and understand intuitively. I guess I'll want to
learn more about what plyr can do. I've been using R for years but hadn't
pushed vectorization far enough in my code. Now my computing
Ravi Varadhan ravi.varadhan at jhu.edu writes:
Hi,
I have this problem: K candidates apply for a job. There are R referees
available to review their resumes and
provide feedback. Suppose that we would like M referees to review each
candidate (M R). How would I assign
candidates to
Thank you, A.K. I learned from both of your solutions. I find the one that
uses alply easier to follow and understand intuitively.
Another approach is to only loop over the 3rd dimensional slices of
a1. Your original code, converted to a function so it is easier to
test and think about is
Thanks very much. I'll give it a try.
On 4/30/2014 9:33 PM, Yixuan Qiu wrote:
Hi Evan,
If you just need one font, you may try the showtext package. Here is a
piece of code that you can test:
library(showtext)
# If you have this font installed
font.add(gara, gara.ttf)
# Or you can install
Thanks, Bert.
I have written this simple code, which is crude, but seems to do a decent job.
It works perfectly when M is a factor of R. Otherwise, it gives decent balance
(of course, balance is not guaranteed). I guess it is possible to take the
results, that are somewhat unbalanced and
Hi Dear all,
I got an error when I try to do a MARS regression with the polymars argument
on the A matrix and the V vector here below.
I don't understand the error, I have nrow=22 for the response variable and for
the predictor matrix.
So if somebody could tell me what is going wrong, it would
Hi all,
I am trying to run a power analysis using simulated data to compare the power
of a glm versus a binomial proportion test to detect differences in
proportions. For example, suppose you have some proportion that decreases by
some amount over X number of time steps.
.4,.39,.38,.37 . . . .
Thank you, Dan and Bert.
Bert - Your approach provides a solution. However, it has the undesired
property of referees lumping together (I apologize that I did not state this as
a condition). In other words, it does not mix the referees in some random
fashion.
Dan - your approach attempts
While R is certainly used for statistical simulations as you showed,
this list is really for questions about R programming, not statistics.
While they certainly overlap and someone may respond here, I suggest
you post this to stats.stackexchange.com or other statistics site that
is specifically
Thanks for the information. I will pose the question on Stack Exchange.
Wade A. Wall
US Army ERDC-CERL
P.O. Box 9005
Champaign, IL 61826-9005
1-217-373-4420
wade.a.w...@usace.army.mil
-Original Message-
From: Bert Gunter [mailto:gunter.ber...@gene.com]
Sent: Thursday, May 01, 2014
Ravi Varadhan ravi.varadhan at jhu.edu writes:
Thanks, Bert.
I have written this simple code, which is crude, but seems to do a decent
job. It works perfectly when M is a
factor of R. Otherwise, it gives decent balance (of course, balance is not
guaranteed). I guess it is
possible to
On 05/01/2014 09:47 PM, varin sacha wrote:
Hi Dear all,
I got an error when I try to do a MARS regression with the polymars argument
on the A matrix and the V vector here below.
I don't understand the error, I have nrow=22 for the response variable and for
the predictor matrix.
So if somebody
On Apr 30, 2014, at 11:44 PM, Marc Girondot wrote:
Dear list-members,
Can someone explains me why the last command gives an error. Thanks a lot:
outer(0:1, 0:1, FUN=function(x, y) {x+y})
[,1] [,2]
[1,]01
[2,]12
outer(0:1, 0:1, FUN=function(x, y) {x})
[,1] [,2]
Hi R User,
I am wonedring how I can extract a part of objects from list.
For example
str(out1970)
List of 8
$ comm : num [1:16, 1:57] 1 1 1 1 1 1 1 1 1 1 ...
..- attr(*, dimnames)=List of 2
.. ..$ : chr [1:16] H_s5 H_s1 R_s2 H_s2 ...
.. ..$ : chr [1:57] Pimephales.promelas
Hi Kristi,
Try
out1970$smoot
HTH,
Jorge.-
On Fri, May 2, 2014 at 10:00 AM, Kristi Glover kristi.glo...@hotmail.comwrote:
Hi R User,
I am wonedring how I can extract a part of objects from list.
For example
str(out1970)
List of 8
$ comm : num [1:16, 1:57] 1 1 1 1 1 1 1 1 1 1 ...
Hello everyone,
I'm trying to construct bins for each row in a matrix. I'm using apply() in
combination with hist() to do this. Performing this binning for a 10K-by-50
matrix takes about 5 seconds, but only 0.5 seconds for a 1K-by-500 matrix. This
suggests the bottleneck is accessing rows in
Hi,
I am trying to create multiple orthogonal designs using the Conjoint
package. I have 4 factors with 5 levels in each.
library(conjoint)
experiment-expand.grid(
price-c(a1,a2,a3,a4,a5),
tag-c(b1,b2,b3,b4,b5),
smell-c(c1,c2,c3,c4,c5),
aroma-c(f1,f2,f3,f4,f5))
I'm trying to create a map of transmission lines in Alberta. In addition, I'm
very new to creating maps.
The data can be found at: http://geogratis.gc.ca/site/eng/download
http://ftp2.cits.rncan.gc.ca/pub/canvec/doc/CanVec_distribution_formats_en.pdf
Would someone be able to point me in the
The showtext package is really nice!
On Thu, May 1, 2014 at 9:33 AM, Yixuan Qiu yixuan@cos.name wrote:
Hi Evan,
If you just need one font, you may try the showtext package. Here is a
piece of code that you can test:
library(showtext)
# If you have this font installed
font.add(gara,
Hi Arne,
thanks a lot for your reply, it was really helpful!
Now, after having managed to apply the censReg to my data, I get the
following error message when I enter the command summary():
Error in printCoefmat(coef(x, logSigma = logSigma), digits = digits) :
'x' must be coefficient
Hi Arne,
it's me once again. I just tried the same regression with less predictors
since so far I have used 16 for 52 observations. Having used less
predictors, R showed me some output for the command summary(). Without
doubt, it was clear beforehand that this ratio between dependent and
Thanks for your answer and attention :) I will try to do it
Merve
*ArÅ.Gör.Merve ÅAHÄ°N*
*Abant Ä°zzet Baysal Ãniversitesi*
*EÄitim Bilimleri Bölümü*
*Ãlçme ve DeÄerlendirme A.B.D.*
2014-04-30 15:57 GMT+03:00 Lorenz, David lor...@usgs.gov:
Merve,
I'm not 100 percent sure I
Hi Jim,
Many thanks. Sorry for disturbing just for a parenthesis...
But I couldn't go ahead...
Le Jeudi 1 mai 2014 23h22, Jim Lemon j...@bitwrit.com.au a écrit :
On 05/01/2014 09:47 PM, varin sacha wrote:
Hi Dear all,
I got an error when I try to do a MARS regression with the polymars
Hey, I am trying to find some of the following functions in R packages:
MLEt
pt3
cormatrix2vector
ParameterEst
tCopula
riskBT
I have checked every package from this link:
http://cran.r-project.org/web/packages/available_packages_by_name.html but
is unable to find the above functions. These
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