Thanks Jim, I see you are the author of staxlab.
In the second staxlab I have tried line=3.5 like in axis, and
top.line=3.5, separately, with no apparent effect.
We should have to select the second axis somehow.
Hurr
--
View this message in context:
Dear Sir/ Madam,
I have a problem with converting a matrix (247 rows, 16 columns) to an array in
R.
Would you please help me in this regard.
Thank you,
E. Habibi
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE
On Sun, 18 May 2014 11:12:21 PM Hurr wrote:
Thanks Jim, I see you are the author of staxlab.
In the second staxlab I have tried line=3.5 like in axis, and
top.line=3.5, separately, with no apparent effect.
We should have to select the second axis somehow.
Hurr
You are correct, as I didn't
On Sun, 18 May 2014 08:18:18 PM Effat Habibi wrote:
Dear Sir/ Madam,
I have a problem with converting a matrix (247 rows, 16 columns) to
an array
in R.
Would you please help me in this regard.
Hi Effat,
A two-dimensional array is the same thing as a matrix.
From the help page for
Hi David,
thanks for your reply.
On 16.05.2014 23:07, David Winsemius wrote:
On May 16, 2014, at 2:25 AM, Jannis wrote:
Hi R users,
I suspect this is due to yahoo recently changing its handling of DMARC policies.
Yes. It is due to ISP bounces coming back to the ETHZ server. You do not
On 18/05/2014 18:08, Prof Brian Ripley wrote:
On 14/05/2014 23:04, Andreas Leha wrote:
Hi all,
how do I find out about the filename, the currently open (let's say pdf)
device is writing to?
If I find 'dev.cur()' returning 'pdf 3' when I expect 'nulldevice 1' I
would like to know, which
hi,
I have got some data and draw a line graph with ggplot2 geom_line. The
output seems too sharp to me, is there any way to smooth it?
I mean smooth the line, NOT ADDING a smooth line. Or there is other
functions in ggplot2 can help me out with a smooth line?
Thank you.
--
Stand Alone Complex
Thanks to all for your ideas and inspirations
Il 18/05/2014 18.35, Joshua Ulrich ha scritto:
Using subset assignment with an array usually doesn't work well with
xts/zoo objects. Your case wouldn't even work with a matrix because
you have NA in your array.
In this case, you can achieve the
On 2014-05-18 20:43, peter dalgaard wrote:
On 18 May 2014, at 07:38 , Jeff Newmiller jdnew...@dcn.davis.ca.us wrote:
Then you had best not do it again if you don't like that result.
1) This is not the right mailing list for issues having to do with
bioconductor. Please go to the
We would like to announce the following stats course:
Course: Introduction to Generalized Additive Models and Generalized
Additive Mixed Effects Models with R
Where: Deakin University, Melbourne, Australia
When: 25 - 29 August, 2014
URL Flyer:
Thanks again Jim.
Sorry, again I'm enclosing incomplete not-runnable code.
Modified like this it works with the new staxlab function which
I inserted before the second staxlab call.
How long before I don't need to insert it?
I didn't see a way to select the specific axis, so
I used top.line=5.
Hi,
I have a list of 40 data.frames.
I would like to identify duplicated entries in the whole list, not only in
one specific data.frame, but in all 40.
Here is my list:
myList
[[1]]
XNAME MEM.SHIP
1 FBgn008 FBgn008 0.9304502
2 FBgn014 FBgn014 1.000
3
Dear R users,
Could anyone tell me if there is a way to obtain the residuals from a model
fitted by
qregspiv(y ~ x,wmat=wmat,inst=NULL,tau=.5,rhomat =
seq(-1,1,.01),printsariv=T,silent=F, nboot=300,data=)
in McSpatial, using the Chernozhukov and Hansen (2006) method.
Many thanks in
On Mon, 19 May 2014 05:23:20 AM Hurr wrote:
Thanks again Jim.
Sorry, again I'm enclosing incomplete not-runnable code.
Modified like this it works with the new staxlab function which
I inserted before the second staxlab call.
How long before I don't need to insert it?
I didn't see a way to
Hello togehter,
i have a litte problem to convert a data.frame. My data.frame looks like
this one
A
1 R5000
2 R4800
3 R4700
4 3500
5 3800
I need now a command, which outputs all the numbers, without the character
in front.
The solution look like this one:
A
1 5000
2 4800
Hello,
Take a look at
http://stats.stackexchange.com/questions/58772/brant-test-in-r
Hope this helps,
Rui Barradas
Em 19-05-2014 01:40, caoweina escreveu:
Dear Rose :
I saw your questions about the R function that performs brant test. Have
you worked out ? Please give some advice. I
Hello,
Try the following.
dat - read.table(text =
A
1 R5000
2 R4800
3 R4700
4 3500
5 3800
, header = TRUE)
dat
dat2 - dat
dat2[] - lapply(dat, function(x) sub(^[[:alpha:]]*(.*$), \\1, x))
dat2
Hope this helps,
Rui Barradas
Em 19-05-2014 14:00, Mat escreveu:
Hello togehter,
i have
Here is one way of doing it:
##
files - list(file1 = XNAME MEM.SHIP
+ 1 FBgn008 FBgn008 0.9304502
+ 2 FBgn014 FBgn014 1.000
+ 3 FBgn028 FBgn028 1.000
+ 4 FBgn109 FBgn109 1.000
+ 5 FBgn114 FBgn114
Hi Mat,
Try that:
gsub([A-Za-z], , df$A)
This is a regular expression that looks for all characters (A to Z and a
to z) and replaces it with nothing ()
You will need to convert the column to numeric after this operation.
HTH,
Ivan
--
Ivan Calandra
University of Franche-Comté
Laboratoire
Hi , I have some URL's like :-
2
facebook
http://www.facebook.com http://www.facebook.com/
http://twitter.com/facebook http://twitter.com/facebook
http://en.wikipedia.org/wiki/Facebook
Hi,
I have boxplots by factors for a dataset and trying to include a boxplot to
represent the entire dataset.
Any idea how this would be done?
Thanks
--
Shane
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list
On 05/19/2014 01:09 AM, Henric Winell wrote:
On 2014-05-18 20:43, peter dalgaard wrote:
On 18 May 2014, at 07:38 , Jeff Newmiller jdnew...@dcn.davis.ca.us wrote:
Then you had best not do it again if you don't like that result.
1) This is not the right mailing list for issues having to do
Read the posting guide, which tells you to provide a minimal reproducible
example [1] (there it's more than one way to accomplish what you have done
already) and post using plain text (so your R code comes through without being
corrupted).
[1]
Dear list,
I have this nls model and trying to calculate the confidence interval for
some parameter. I found if I use the default value level=0.95, confint can
calculate a value; when I change the level=0.9, then it return :Error in
prof$getProfile() : number of iterations exceeded maximum of
Hi Folks,
I have a set of x,y,z points in 3D space that defines the outline of a
tree crown (5 - 15 perimeter points + 1 top bottom point). I would
like to calculate the volume of the corresponding 3D polygon based on
those points. I have been able to use geometry::convhulln, but I think
I try to use NSGAII function in the mco but I am kind of confusing about the
numbers of input and output dimension in the argument. Could you explain a
little about this? Thank you.
--
View this message in context:
I am getting messages like:
Namespace prefix ccd on el-418bd009-f19a-4107-bc7b-2abb83748bbb is not defined
Namespace prefix mlhim244 on interval-type is not defined
when retrieving nodesets like this:
pct - getNodeSet(root, '//ccd:el-6acf3ae9-222c-4f71-8120-76375db84177',
nsDEF)
nsDEF is
I believe this has to do with numeric issues in nonlinear fitting and
interpolation, and is neither concerned with R programming nor trivial
to answer. I therefore suggest you post on the stats.stackexchange.com
for a fuller discussion of the issues.
Cheers,
Bert
Bert Gunter
Genentech
On 19/05/2014, 10:42 AM, Alexander Shenkin wrote:
Hi Folks,
I have a set of x,y,z points in 3D space that defines the outline of a
tree crown (5 - 15 perimeter points + 1 top bottom point). I would
like to calculate the volume of the corresponding 3D polygon based on
those points. I have been
Use defaul values initially, to see if you got reasonable results. See
here for the details of nsga2
http://dx.doi.org/10.1109/4235.996017
On 19 May 2014 16:42, Mingxuan Han han...@purdue.edu wrote:
I try to use NSGAII function in the mco but I am kind of confusing about the
numbers of input
Hi,
You may try:
myList - list(structure(list(X = c(FBgn008, FBgn014,
FBgn028,
FBgn109, FBgn114, FBgn120), NAME = c(FBgn008,
FBgn014, FBgn028, FBgn109, FBgn114, FBgn120
), MEM.SHIP = c(0.9304502, 1, 1, 1, 0.4839886, 1)), .Names = c(X,
NAME,
I have boxplots by factors for a dataset and trying to include a boxplot to
represent the entire dataset.
Have a look at last the example in ?boxplot which plots a second set of values
beside a first set. In your case, specifying xlim larger than needed by one and
then using boxplot(x,
tmp - data.frame(y=c(rnorm(20), rnorm(20), c=rnorm(20)),
g=rep(letters[1:3], each=20))
library(lattice)
library(latticeExtra)
A - bwplot(y ~ g, data=tmp)
B - bwplot(y ~ rep(Y,60), data=tmp, horizontal=FALSE)
resizePanels(c(Individual=A, All Together=B, layout=c(2,1)), w=c(3,1))
## for even
Thanks. Good suggestion. I completely forgot about the *apply() functions -- a
symptom of my R-neophyte status. ;-)
From: Peter Alspach peter.alsp...@plantandfood.co.nz
ct.org
Sent: Sunday, May 18, 2014 4:24 PM
Subject: RE: [R] Is there an easier way
Thanks. That's the answer I was looking for. It not only lists the function
names by also the arguments required.
I wonder why I was unable to find that command in all the searching I did (?).
- - Byron
To: r-help@r-project.org r-help@r-project.org
Hi,
Try:
dat - read.table(text=A
1 R5000
2 R4800
3 R4700
4 3500
5 3800,sep=,header=TRUE,stringsAsFactors=FALSE)
dat$A - as.numeric(gsub([[:alpha:]]+,,dat$A))
A.K.
On Monday, May 19, 2014 9:02 AM, Mat matthias.we...@fnt.de wrote:
Hello togehter,
i have a litte problem to convert a
Readers,
The function 'solve' states that it is applicable to a vector or matrix
object.
Please what is the syntax to solve a very simple equation like:
5x + 1 = 56
The books read so far give explanations for simultaneous linear
equations or differential equations, but there have not been
Hi,
If you meant to convert the matrix to a 3D array, check this link:
http://stackoverflow.com/questions/9572656/how-to-convert-matrix-into-array
A.K.
On Monday, May 19, 2014 2:18 AM, Effat Habibi habibi...@gmail.com wrote:
Dear Sir/ Madam,
I have a problem with converting a matrix (247
Hello everybody!!
I'm trying to plot a graphic with the title: INTERVALS λ.
But the special character λ can't be encoded using ISO8859-1.
Which another encoding I need to choose?
Att.
Alexsandro Cândido de Oliveira Silva
Great,
Thanks everyone :-)
On Monday, May 19, 2014, Richard M. Heiberger r...@temple.edu wrote:
tmp - data.frame(y=c(rnorm(20), rnorm(20), c=rnorm(20)),
g=rep(letters[1:3], each=20))
library(lattice)
library(latticeExtra)
A - bwplot(y ~ g, data=tmp)
B - bwplot(y ~ rep(Y,60), data=tmp,
Hello,
Try ?uniroot instead.
Your equation is equivalent to 5x - 55 = 0, so the instruction would be
uniroot(function(x) 5*x - 55, c(0, 20))
Hope this helps,
Rui Barradas
Em 19-05-2014 14:46, message escreveu:
Readers,
The function 'solve' states that it is applicable to a vector or matrix
Hi all, this is a reoccurring theme in my programming and I need some help
with it. When I use a built in function and need to use it on a subset of
my data frame, I always end up using the subset function first, but this
seems very clunky. For example, if I have years 2003:2013 with season a
Have you read An Introduction to R and sections on indexing (?[)
where this is discussed. Have you read about apply type functions
there like ?tapply. If not, don't you think you should. If so, read
again.
Cheers,
Bert
Bert Gunter
Genentech Nonclinical Biostatistics
(650) 467-7374
Data is not
It would have been nice if you at least supplied a subset of the data, but
here is a try at it:
myList - split(size, list(size$Year, size$Season))
result - lapply(myList, function(.sub){
smooth.spline(.sub$Size, spar = 0.25)
})
Jim Holtman
Data Munger Guru
What is the problem that you
Another method uses the core boxplot() function but replaces the usual
call to split() with a variant that puts all the data at the end of
the list of splits:
splitPlusAll - function(x, ...) c(split(x, ...), list(All=x))
boxplot(with(mtcars, splitPlusAll(wt, list(gear,am), drop=TRUE)))
hi,
I'v got some data attached as apx.csv. It shows the relationship about a
kind of enzyme and the temperature.
yhf and xbt are 2 kind of cowpea. apx is the kind of enzyme and low
means the lowest temperature intraday. date means 1 to 121 days.
What I want to show with it is how is apx changes
Hi
See ?plotmath.
Something like this:
plot(1, 1, main = expression(paste(INTERVALS , lambda)))
Yours sincerely / Med venlig hilsen
Frede Aakmann Tøgersen
Specialist, M.Sc., Ph.D.
Plant Performance Modeling
Technology Service Solutions
T +45 9730 5135
M +45 2547 6050
fr...@vestas.com
Check out the R Graph Gallery for ideas.
http://rgraphgallery.blogspot.com/
Cheers,
Bert
Bert Gunter
Genentech Nonclinical Biostatistics
(650) 467-7374
Data is not information. Information is not knowledge. And knowledge
is certainly not wisdom.
H. Gilbert Welch
On Mon, May 19, 2014 at
Hola Álvaro:
Hace años había más programas que relacionaban php y r (en uno u otro
sentido), pero acabo de buscar en el CRAN Task View: Web Technologies
and Services, y parece que no hay ninguno que haga referencia explícita
a php allí:
http://cran.r-project.org/web/views/WebTechnologies.html
De
Buen día a todos. Tengo un problema.Podría ayudarme diciendóme cómo se llama la
paquetería para encontrar el comando bs.data, lo he estado buscando para ver
como escribir el comando en R y no me aparece una paquetería para ver la
descripción. Saludos.
Hola,
Prueba con esta búsqueda y sÃrvete tu mismo
http://www.rseek.org/?cx=010923144343702598753%3Aboaz1reyxd4q=bs.datasa=Search+functions%2C+lists%2C+and+morecof=FORID%3A11siteurl=rseek.org%2Fref=ss=888j162752j7
Saludos,
Carlos Ortega
www.qualityexcellence.es
El 19 de mayo de 2014,
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