Hi
I looked in the help page which states
See Also
cor.test for confidence intervals (and tests).
cov.wt for weighted covariance computation.
Then I looked to cov.wt help page and it seems that it does what you want
cov.wt(data.frame(x,y), wt=c(.5,.25,.25), cor=T)
$cov
xy
x 1.1 4.1
Hi Fabio
Can you please reproduce your output? When I tried it curl are the
following issues I get:
download.file(
http://www.nseindia.com/content/historical/DERIVATIVES/2014/JUL/fo09JUL2014bhav.csv.zip;,
temp, method=curl)
Error in download.file(
At 17:49 16/07/2014, Megan Bartlett wrote:
Hi Michael,
Thank you! Just to clarify, in my question, I was thinking that in this
regression each study should be treated as one point, instead of each
species, so that each effect size x value has a unique climate y value. Is
that what the random=
Many thanks. I will try that.
On Thu, Jul 17, 2014 at 1:29 PM, Fábio Magalhães fmagalh...@gmail.com
wrote:
Hi Balaji,
Sorry, I forgot to tell that I'm running R on OSX. I don't know if
there's an easier way, but since you are running on Windows you could
try to install
Suppose I have the following dataframe:
L4 - LETTERS[1:4]
fac - sample(L4, 10, replace = TRUE)
(d - data.frame(x = 1, y = 1:10, fac = fac))
x y fac
1 1 1 B
2 1 2 B
3 1 3 D
4 1 4 A
5 1 5 C
6 1 6 D
7 1 7 C
8 1 8 B
9 1 9 B
10 1 10 B
I'd like to add
One way is to use a vector with names to do the mapping:
mapVector - c(A=8, B=11, C=3, D=2)
mapVector[as.character(d$fac)]
B B D A C D C B B B
11 11 2 8 3 2 3 11 11 11
# you may want to wrap this with unname()
d$mappedFac - mapVector[as.character(d$fac)]
d
x y fac mappedFac
What about:
d$var - c(8, 11, 3, 2)[d$fac]
Side note: it's much appreciated that you included data and a clear
problem statement. If you use
set.seed(123)
before your call to sample(), everyone who tries it will get the same
fac that you do. Otherwise we all get something different. Or just
Hi
depends if you want the new column as factor or numeric.
d$fac2-d$fac
I did not use var as it is R function.
levels(d$fac2)-c(8,11,3,2)
d$fac2
[1] 3 11 8 8 2 8 11 11 8 8
Levels: 8 11 3 2
You can change it to character or numeric if you wish.
as.character(d$fac2)
[1] 3 11 8 8 2
Hello,
I have a block of code that has two head calls at the end, but only the second
is shown on screen. If I manually execute the statement which is not showing,
it works. I thought that if statements are not functions. It is behaving as one.
if(1 2)
+ {
+ x-rnorm(100)
+ y - rpois(10,
I have found an interesting issue. I use R Studio for most of my
development and automate many tasks to run over night. I have a https
file scrape process that runs without issue from R Studio command line.
When I try to run from the R console, I get an error from download.file
stating
Hi Balaji,
Sorry, I forgot to tell that I'm running R on OSX. I don't know if
there's an easier way, but since you are running on Windows you could
try to install curl(http://curl.haxx.se/) binaries and try the curl
method again.
#! Fábio
On Thu, Jul 17, 2014 at 5:26 AM, Raghuraman Ramachandran
Hello everyone,
I am trying to define a PERT distribution by hand by transforming a classic
beta distribution - as I would like to understand where the shape parameter
(default value of 4) comes from in the mc2d package.
The help page says
The PERT distribution is a beta distribution extended
Hi,
I still seem to be getting errors from trying to run my altered R script, any
advice?
Thanks
Jess
Model1A = function(meth_matrix,exposure, X1, X2, X3, batch) {
+
+ mod = lm(methcol ~ exposure+X1+X2+X3+batch, data = meth_matrix)
+
+
+ res=coef(summary(mod))[2,]
+
+
+ }
##Run
Thanks a lot for the quick and elegant solutions, Sarah, Bill and
Petr! I really appreciate it, including the suggestion of setting a
random seed. Have a nice day!
Gang
On Thu, Jul 17, 2014 at 11:15 AM, Sarah Goslee sarah.gos...@gmail.com wrote:
What about:
d$var - c(8, 11, 3, 2)[d$fac]
Hi,
You can get the behaviour you want using the print() command:
if(1 2)
{
x-rnorm(100)
y - rpois(10, 5)
print(head(x))
print(head(y))
}
Sarah
On Thu, Jul 17, 2014 at 2:00 AM, Dario Strbenac
dstr7...@uni.sydney.edu.au wrote:
Hello,
I have a block of code that has two head calls
Hello,
i am working on a metagenomics, and analyzing a genome of different
sample using QIIME tools, will you tell me how can i use R Program for
metagenome analysis.
Regards.Shashank Gupta
[[alternative HTML version deleted]]
__
Hi Bill,
Modifying `f2` seems to solve the problem.
f2 - function (data)
{
library(dplyr)
data%%
group_by(id, value) %%
mutate(date=as.Date(date))%%
arrange(date) %%
filter(indx =any(c(abs(diff(date)),NA) 31) date==min(date)) %%
filter(row_number()==1)
}
You ask about generic methods for introducing alternate values for
factors, and some of the other responses address this quite efficiently.
However, a factor has meaning only within one vector at a time, since
another vector may have additional values or missing values relative to
the first
You should read the Posting Guide for the r-help list, and the list
control web page. One problem with your post is that the r-help-request
address is not for asking questions. Another problem is that cross-posting
to multiple lists would not have been polite anyway.
Your question is really
Hello,
Also, unlike what the op says, if statements are functions, explaining
the behavior he got.
Hope this helps,
Rui Barradas
Em 17-07-2014 16:53, Sarah Goslee escreveu:
Hi,
You can get the behaviour you want using the print() command:
if(1 2)
{
x-rnorm(100)
y - rpois(10, 5)
This question is related to FAQ 7.16, which you should look up.
In general, whenever you just type a variable or function directly at the
command line, R prints the result for you. Inside code blocks of any kind,
it does not do that, so you need to use the print function yourself.
On Thu, 17
Jeff,
Even though the solutions from the previous responders are good enough
for my current situation, the principle you just raised will be
definitely beneficial to your future work. Thanks a lot for sharing
the insights!
Gang
On Thu, Jul 17, 2014 at 12:06 PM, Jeff Newmiller
Dear Lorenzo,
I've just seen one post from you asking for hints to read SDMX data in R.
I don't know if you still need to read SDMX datasets in R. In case, you
can use the rsdmx package hosted here https://github.com/opensdmx/rsdmx
With the OECD sample you mention, you can do as follows:
Is there any equivalent to chartr for numeric values?
Meaning, something like:
numerictr(c(-1, 42, 666), 1:3, numeric.stuff)
that replaces in numeric.stuff (a vector, matrix, etc) all instances
of -1 for 1, 42 for 2 and 666 for 3?
Alberto Monteiro
Hi Michael,
I think you're right, it would be a good idea for me to get a better grip
on mixed effects modeling before I charge ahead with metafor. Thank you
very much for all of your help with this! Much appreciated!
Best,
Megan
On Thu, Jul 17, 2014 at 3:50 AM, Michael Dewey
Replying to self:
Is there any equivalent to chartr for numeric values?
Meaning, something like:
numerictr(c(-1, 42, 666), 1:3, numeric.stuff)
that replaces in numeric.stuff (a vector, matrix, etc) all instances
of -1 for 1, 42 for 2 and 666 for 3?
match does it. Sorry to ask.
Alberto
On Jul 17, 2014, at 9:27 AM, Rui Barradas wrote:
Hello,
Also, unlike what the op says, if statements are functions, explaining the
behavior he got.
I'm not sure that is correct. The help page says if() is a control-construct. I
think the function is actually {
{rnorm(10); rpois(10, 3)}
On 18/07/14 11:32, David Winsemius wrote:
On Jul 17, 2014, at 9:27 AM, Rui Barradas wrote:
Hello,
Also, unlike what the op says, if statements are functions, explaining the
behavior he got.
I'm not sure that is correct. The help page says if() is a control-construct. I think the
function
Rolf et.al
I have not followed this thread closely and so have nothing to say
about whose or what explanation is correct.
However, the following statement is misleading, if not wrong:
---
foo - function(){
x - 17
x
y - 42
y
}
If you type foo() you get
[1] 42
which is
The example in the question was not inside a user function.
__
R-help@r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal,
Buenas
tardes,
Tengo un
data frame denominado trabajadores, que cubre desde el 1 de
enero de 1997 hasta el 30 junio de 1999, con 3 columnas: Identificador (ID), la
fecha de entrada en la empresa (ENT) y la fecha de salida (SAL). Deseo localizar
aquellos trabajadores que, durante dicho
Simplificando (i.e., asumiendo que los días fin de año son los múltiplos de 10):
# datos simulados
dat - data.frame(id = letters[1:4],
ini = c(1, 15, 15, 11),
fin = c(11, 19, 25, 22))
fin.anno - 10 * 1:3
# resultado
dat[mapply(function(x,y) ! any(fin.anno
Me pilla un poco lejos de dónde trabajo. ;) Estaría interesado en que
fuera en Córdoba o Granada. Sé que en Granada hay unos cuantos eRReros
entre la uni y alguna que otra empresa, y en Málaga también hay unos
cuantos..
Saludos
El 17/07/14 23:03, Rubén Gómez Antolí escribió:
Hola:
El
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