Or, something to that effect. Following is an example of what I'm
working with basic ABO blood type ML estimation from observed type
(phenotypic) frequencies. First, I generate a log-likelihood function.
mu[1] - mu[2] are allele freqs for A and B alleles, respectively. Since
freq of O allele
David - the startup directory for Terminal.app shouldn't affect where R
looks for .Rprofile. If R is started from the command line, it should
look in whatever is the user's current directory (which will be ~/ if
Terminal was just launched), and then ~/ . It shouldn't be looking in
Thank you for considering my email and replying.
Well, I am working with TIMSS 2007 survey data ( Trends in
international mathematics and science study).
TIMSS is a stratified DATA, where the primary sampling unit is the
school
I want to test the effect of some independent variables
Thanks !
Just in case it could be of any help, this is what I have done for MS
Windows users :
library(RGtk2)
library(cairoDevice)
win = gtkWindow(show = FALSE)
win$setDefaultSize(500, 500)
hbox-gtkHBoxNew(homogeneous=FALSE, spacing=0)
if (Sys.info()[1]==Windows){
png(filename=temp.png,
Thank you for considering my email and replying.
Well, I am working with TIMSS 2007 survey data ( Trends in
international mathematics and science study).
TIMSS is a stratified DATA, where the primary sampling unit is the
school
I want to test the effect of some independent variables
Dear All,
my 3D PDF output package has got incompatible with recent rgl versions.
If someone needs a working version of rgl with 3D PDF export (sources
and Windows binaries) - send me a request.
Sincerely, Michail
__
R-help@r-project.org mailing
Hi
Thanks to all for the inputs. It will also be great to get inputs on the
procedure and the contact person for getting the commercial license on R
Rgds
Pasu
On 19-Sep-2014 2:13 AM, Duncan Murdoch murdoch.dun...@gmail.com wrote:
On 18/09/2014 2:35 PM, Marc Schwartz wrote:
On Sep 18, 2014,
There is no such person, because we don't do commercial licensing. This is
pretty much impossible because the R developers do not own every piece of
software that is used inside R.
There are however companies that sell commercial support for R, and they will
likely be able to help you about
Dear Subscribers,
I want to label a numeric variable 0=Bad /1=Good. I understand the only way
is to transform it into a factor variable.
Is there a way to check that the numeric values of the new factor variable are
0 and 1 and not 1 and 2?
Thank you very much.
Angel Rodriguez-Laso
Thiago,
This will not be simple using filled.contour, as this changes the layout from
the figure.
You might try the function image2D from plot3D:
require(plot3D)
par(mfrow = c(2, 1))
par(mar = c(0, 4, 4, 2))
plot(0, axes = FALSE, frame.plot = TRUE) # upper plot
par(mar = c(4, 4, 0, 2))
Col -
On Fri, 19 Sep 2014 12:53:16 PM Angel Rodriguez wrote:
Dear Subscribers,
I want to label a numeric variable 0=Bad /1=Good. I understand
the only
way is to transform it into a factor variable.
Is there a way to check that the numeric values of the new factor
variable
are 0 and 1 and not
On 19/09/2014, 6:53 AM, Angel Rodriguez wrote:
Dear Subscribers,
I want to label a numeric variable 0=Bad /1=Good. I understand the only
way is to transform it into a factor variable.
Is there a way to check that the numeric values of the new factor variable
are 0 and 1 and not 1 and
Thank you, Duncan. So isn't it possible to add labels to a variable with
numeric values 0/1? This kind of variable is very useful for logistic
regression, for example, but I'd rather have its categories labelled.
Angel
De: Duncan Murdoch
On 19/09/2014 8:12 AM, Angel Rodriguez wrote:
Re: [R] See the numeric codes of a factor
Thank you, Duncan. So isn't it possible to add labels to a variable
with numeric values 0/1? This kind of variable is very useful for
logistic regression, for example, but I'd rather have its
categories
Well, a variable with values 0/1 is useful for calculating observed
probabilities by groups. But it is not diffcult to have the same variable both
as numeric and as a factor in the dataframe and use each variation depending on
the analysis.
Angel
De: Duncan
Sounds like a factor to me. You are just inappropriately focused on the
underlying representation. Once you start using factors in regression you will
get it.
---
Jeff NewmillerThe .
Talk to a local statistician or study a book on regression. You do not
understand how regression works.
In R, see ?contrasts .
-- Bert
Bert Gunter
Genentech Nonclinical Biostatistics
(650) 467-7374
Data is not information. Information is not knowledge. And knowledge
is certainly not wisdom.
Hello all.
My system information:
R 2.14.1 x64
Windows 7
I'm attempting to access cores on other machines in my LAN. As setup, I can
ping all the machines successfully and it's a private office network where I
have access to all computers, so there really shouldn't be any problems arising
If it is possible, I think you will need to get the expression for
Puro.fun2 and then (essentially manually) put it into nls (or perhaps
better nlmrt or minpack.lm which have better numerics and allow bounds;
nlmrt even has masks or temporarily fixed parameters, but I need to
writa a vignette
One choice is to add a penalty to the objective to enforce the
constraint(s) along with bounds to keep the parameters from going wild.
This generally works reasonably well. Sometimes it helps to run just a
few iterations with a big penalty scale to force the parameters into a
feasible region,
While I hope someone with first hand experience or time to try it out pipes up,
I noticed something wrong in your description. The ssh command is executed on
the local machine, not the remote machine. That command must succeed on the
local machine in order to start Rscript on the remote
Thanks for your input Jeff, yes that was a misunderstanding on my part about
where the system command was actually run, and I think you're right on point,
that path to Rscript doesn't make any sense! Big oversight by me. Nicely
enough, there is a parameter for specifying the path to Rscript,
When working with datasets too large to fit in memory it is usually
best to use an actual database, read the data into the database, then
pull the records that you want into R. There are several packages for
working with databases, but 2 of the simplest are the RSQLite and
sqldf packages
After specifying the path to Rscript we're still hanging.
As for Jeff's comment on how the remote machine is receiving the ssh request, I
don't know. My assumption is that, given the ssh request going through, it's
attempting to make the command Rscript.exe parallel:::.slaveRSOCK(), which
Thanks for the help, Amos!
The only reason that *should* happen is if there's an .Rprofile in the
directory you're in when you start R.
There is only one .Rprofil, which is in my home directory ~/
Where *exactly* is the .Rprofile file you want loaded
The only one is in my home directory.
Good point. I see the behavior you describe.
Sent from my iPhone
On Sep 19, 2014, at 1:18 AM, Amos B. Elberg amos.elb...@gmail.com wrote:
David - the startup directory for Terminal.app shouldn't affect where R looks
for .Rprofile. If R is started from the command line, it should look in
An update to the Hmisc package is now on CRAN. Some recent changes:
* latex.summaryM: fixed bug in caption with test=TRUE. Thanks:
Yonghao Pua
* combined.levels: sensed all NA vector, now return non-factor
numeric instead
* dataframeReduce: handle all-NA factor variable
*
An update to the rms package is now on CRAN. Some recent changes:
* plot.summary.rms: allowed a vector for lwd, and passed lwd to
confbar. Thanks: Michael Friendly
* gendata: Starting in R 3.1.0, as.data.frame.labelled or
as.data.frame.list quit working when length vary; workaround
Thanks Henrick. Seems it fits my needs. One my question is the argument,
length.out=0.10*n, is it randomly taking out 10% ? I found it basically takes
every 10th row if I put length.out=0.1*n, and every 100th row if I put
length.out=0.01*n till the end. I couldn't find this information on
Hello
I have the two dataframes Df1 and Df2 which have the common variable
AgeSexeCadNCad
I would like to add the new variable Df2$Pourcent which correspond at
the value of Df1$AgeSexeCadNCad.
Thank you for your help.
Michel
Df1 - structure(list(AgeSexeCadNCad = structure(1:36, .Label =
Is merge() what you're looking for?
On Fri, Sep 19, 2014 at 1:15 PM, Arnaud Michel michel.arn...@cirad.fr wrote:
Hello
I have the two dataframes Df1 and Df2 which have the common variable
AgeSexeCadNCad
I would like to add the new variable Df2$Pourcent which correspond at the
value of
Hello,
Try ?merge:
Df3 - merge(Df2, Df1, by = AgeSexeCadNCad)
Hope this helps,
Rui Barradas
Em 19-09-2014 18:15, Arnaud Michel escreveu:
Hello
I have the two dataframes Df1 and Df2 which have the common variable
AgeSexeCadNCad
I would like to add the new variable Df2$Pourcent which
On Sep 19, 2014, at 12:15 PM, Arnaud Michel michel.arn...@cirad.fr wrote:
Hello
I have the two dataframes Df1 and Df2 which have the common variable
AgeSexeCadNCad
I would like to add the new variable Df2$Pourcent which correspond at the
value of Df1$AgeSexeCadNCad.
Thank you for your
You might also want to try argument all.x:
Df3 - merge(Df2, Df1, by = AgeSexeCadNCad, all.x = TRUE)
This is because there are 2 rows in Df2 without a corresponding
'AgeSexeCadNCad' in Df1.
Rui Barradas
Em 19-09-2014 18:39, Rui Barradas escreveu:
Hello,
Try ?merge:
Df3 - merge(Df2, Df1,
On Thu, 18 Sep 2014 10:28:42 -0400
davide.chi...@gmail.com davide.chi...@gmail.com wrote:
I tried with a different mirror, but nothing changed...
Any other idea?
Thanks anyway
-- Davide
What is the output of library()?
JWDougherty
__
On 18-09-2014, at 17:18, Gang Chen gangch...@gmail.com wrote:
When R starts in GUI (e.g.,/Library/Frameworks/R.framework/Resources/bin/R) on
my Mac OS X 10.7.5, the startup configuration in .Rprofile works fine.
However, when R starts on the terminal (e.g.,
Thank you to Marc Schwartz, Rui Barrada and Sarah Goslee
Michel
Le 19/09/2014 19:46, Marc Schwartz a écrit :
On Sep 19, 2014, at 12:15 PM, Arnaud Michel michel.arn...@cirad.fr wrote:
Hello
I have the two dataframes Df1 and Df2 which have the common variable
AgeSexeCadNCad
I would like to add
Dear fellow R users,
I am trying to run the random forest and Yaimpute packages in R to
impute a grid to project in a gis. However, after running the
imputation I keep getting an error in the rownames. This sounds simple
enough, but I cannot figure out what these rownames are reffering to.
Any
Dear R community,
For users interested in streaming classification or building classification
models with limited amounts of RAM on your whole data set, I would like to
announce the release of a new package called RMOA on CRAN (
http://cran.r-project.org/web/packages/RMOA).
MOA is the most
Dear listers,
I am using Jas Sekhon's Matching package to perform propensity score matching
and like it a lot so far.
Still though I wonder whether it is possible to impose restrictions on the
Matching. I've seen the restriction parameter, but I doubt this is what I want
(or I don't get how to
On 9/19/2014 11:32 AM, Prof J C Nash (U30A) wrote:
One choice is to add a penalty to the objective to enforce the
constraint(s) along with bounds to keep the parameters from going wild.
This generally works reasonably well. Sometimes it helps to run just a
few iterations with a big penalty
Hi,
kindly give me some guide on how to plot the following data in a single line
graph that is ( y1,y2,y3,y4 against x) including title and key
y1-c(0.84,1.03,0.96)
y2-c(1.30,1.46,1.48)
y3-c(1.32,1.47,1.5)
y4-c(0.07,0.07,0.07)
x-c(500,1000,2000)
Thanks
Ishaq
[[alternative HTML version
You could also use Rvmmin
that has bounds, or nmkb from dfoptim (though you cannot start on bounds).
One 'negative' for dfoptim is that is doesn't automatically generate the
Hessian (as far as I can tell). Rather nice to be able to do so for
other calculations that usual follow after the
I am trying to build R-3.1.0 on RHEL
But configure returns with an error due to X11/Intrinsic.h missing
Is there a workaround ?
Gaurav Chakravorty
Circulum Vite LLC | www.circulumvite.com
2500 PLAZA 5 . Harborside Financial Center, Jersey City, NJ 07311-4026
Tel: 201-377-2302 Fax:
On Sep 19, 2014, at 10:48 AM, IZHAK shabsogh ishaqb...@yahoo.com wrote:
Hi,
kindly give me some guide on how to plot the following data in a single line
graph that is ( y1,y2,y3,y4 against x) including title and key
y1-c(0.84,1.03,0.96)
y2-c(1.30,1.46,1.48)
y3-c(1.32,1.47,1.5)
On Sep 19, 2014, at 1:28 PM, Gaurav Chakravorty gc...@circulumvite.com wrote:
I am trying to build R-3.1.0 on RHEL
But configure returns with an error due to X11/Intrinsic.h missing
Is there a workaround ?
In most Linuxen, the header files are contained in *-dev[el] packages. For
RHEL,
On Sep 19, 2014, at 1:28 PM, Gaurav Chakravorty gc...@circulumvite.com wrote:
I am trying to build R-3.1.0 on RHEL
But configure returns with an error due to X11/Intrinsic.h missing
Is there a workaround ?
In most Linuxen, the header files are contained in *-dev[el] packages. For
RHEL,
On 19/09/2014 19:28, Gaurav Chakravorty wrote:
I am trying to build R-3.1.0 on RHEL
But configure returns with an error due to X11/Intrinsic.h missing
Is there a workaround ?
Yes, install it!
If you need more help, read the posting guide and note the appropriate
list from
plot(x=range(x),y=range(c(y1,y2,y3.y4),type='n')
lines(x=x,y=y1,lty=1)
lines(x=x,y=y2,lty=2)
lines(x=x,y=y3,lty=3)
lines(x=x,y=y4,lty=4)
legend('bottomright',c('Y1','Y2','Y3','Y4','Y5'),lty=1:4)
or something like that.
On Fri, 2014-09-19 at 14:11 -0500, Marc Schwartz wrote:
On Sep 19, 2014,
On Fri, Sep 19, 2014 at 1:28 PM, Gaurav Chakravorty
gc...@circulumvite.com wrote:
I am trying to build R-3.1.0 on RHEL
But configure returns with an error due to X11/Intrinsic.h missing
Is there a workaround ?
yum install libXt-devel
This from my Fedora 20 x86_64 installation.
--
There is
TERR (TIBCO Enterprise Runtime for R) is an independent implementation of an
R-compatible engine (based on our long history and expertise with S+). One
of the features of TERR is that it can be licensed for embedding and
redistribution, since it is not subject to the GPL license.
For more
Chris,
It's hard to troubleshoot without reproducible code. I suggest you post a
simple example of code that we can run. For example, use
dput(training[1:20, ])
to spit out the first 20 lines of the training data. Then simplify the
rest of the code as much as possible.
library(yaImpute)
Hi:
Appreciate if I could get some help.
I have two data frames.
I want to combine these two dfs bases on first column.
df1 :
SubjectG1 G2G3
A 10 1 0
B 20 220
df2:
Subject m1m2 m3
A 20 9 30
B
Dear all,
I have a data.frame xy which I am plotting like in the code below (provided is
a small data sample with dummy data that should work).
Is there a way how I could convert my xx and yy in the xy plot to a points
command so that I could set type='n' and add points afterwards in
Hello R friends,
I am trying to add label to each of my datapoints in an xyplot which
has two Y-axis. When I run my code with only 1 xyplot it labels the
datapoints just fine. However when I have two xyplots plotted
together,I am unable to label the data points. Any suggestion will be
See ?merge
Best,
Uwe Ligges
On 19.09.2014 22:58, Adrian Johnson wrote:
Hi:
Appreciate if I could get some help.
I have two data frames.
I want to combine these two dfs bases on first column.
df1 :
SubjectG1 G2G3
A 10 1 0
B 20 2
thanks it works I guess:
merge(b1,b2,by='Subject')
On Fri, Sep 19, 2014 at 5:03 PM, Uwe Ligges
lig...@statistik.tu-dortmund.de wrote:
See ?merge
Best,
Uwe Ligges
On 19.09.2014 22:58, Adrian Johnson wrote:
Hi:
Appreciate if I could get some help.
I have two data frames.
I want to
Dear all,
Good time.
Could anybody can help me with my below code on Windows 7 and R 3.1.0
when I run this code:
tidy_source (
ugly script.R,
file = beautiful script.R
)
I encounter this error message:
Error in parse(text = x, keep.source = TRUE) :
text:11:14: unexpected '=='
10:
11:
Looks like homework to me.
cheers,
Rolf
P. S. In any case, so some basic reading of introductory R material,
available from the R web page.
R.
On 20/09/14 03:48, IZHAK shabsogh wrote:
Hi,
kindly give me some guide on how to plot the following data in a single line
graph that is (
59 matches
Mail list logo
