Don't use apply functions if you want to do what you describe. They don't work
that way. Use a while control structure.
---
Jeff NewmillerThe . . Go Live...
Hello,As an example for Exponential distribution the MLE is got by this
structure:t - rexp(100, 2)loglik - function(theta){ log(theta) - theta*t}a -
maxLik(loglik, start=1)print(a)Exponential distribution has a simple
loglikelihood function. But if a new pdf has a more complicated form
Is that mean while may be more effient than for in R? as i know, while and for
are all just functions in R.
Tks for your suggestion to not use apply that way, but i want to know, if
possible, is there any way to break it ?
Actually, there is a additional question:
x- c(3,4,5,6,9)
Dear All,
The following function gives me what I wanted.
The input of function is one value and this push me to use sapply function
to call it.
Is there a better way of doing this?
#
day - function(x){
if(x== 60) {
y =
Is it possible to break it? I already told you that... NO. Also your mention of
efficiency is not relevant. Keep in mind that apply functions are not
significantly faster than for loops or while loops. They are just compact ways
to express your intent. Usually people having speed problems with
Hi,
On 10/09/2014 11:12 PM, PO SU wrote:
Is that mean while may be more effient than for in R? as i know, while and for
are all just functions in R.
Tks for your suggestion to not use apply that way, but i want to know, if
possible, is there any way to break it ?
As Jeff said, you
Please help, it possible to make an r means barplot in R using base, where
there are more than 2 factors and not with lattice, Franklin.
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OK, it seems that i misunderstand something, i forget how and when i pick up
the monition in my mind that as possible as avoid using for loop.
TKS for all your suggestions!
But i still want the way to break sapply, if not exsits now, create it .
such as:
sapply-function(...){
out-FALSE
On Thu, 9 Oct 2014 11:18:43 PM Franklin Mairura wrote:
Please help, it possible to make an r means barplot in R using base,
where
there are more than 2 factors and not with lattice, Franklin.
Hi Franklin,
Have a look at the barNest function in the plotrix package.
Jim
Hi
But It is not doing what you wanted. It does not extend 365 days year to 366
days. Instead it will incorrectly rename all days after 28th February in non
leap years
format(strptime(59, format = %j), %d-%b)
[1] 28-II
format(strptime(60, format = %j), %d-%b)
[1] 01-III
format(strptime(61,
Hi R helpers,
I want to write a function which will
1. Count the number of fridays in the current month ( to extract month from
given date) and also the number of fridays in the preceeding month
2. Calculate the ratio of the number of fridays in current month to the
number of fridays in the
On 10/10/2014, 7:28 AM, Abhinaba Roy wrote:
Hi R helpers,
I want to write a function which will
1. Count the number of fridays in the current month ( to extract month from
given date) and also the number of fridays in the preceeding month
2. Calculate the ratio of the number of fridays
Doing as much as possible with vectors instead of loops of a good thing.
Fooling yourself that apply functions are vectorized is, well, not a good thing.
If you want to write a function to use instead of sapply, fine, but don't call
it *apply because those functions always give you one result
Hi Duncan,
I have converted the string to a POSIXIt object using
strptime('31-may-2014',format=%d-%b-%Y)
But could not figure out the way forward.
Could you please elaborate a bit?
On Fri, Oct 10, 2014 at 5:14 PM, Duncan Murdoch murdoch.dun...@gmail.com
wrote:
On 10/10/2014, 7:28 AM,
On 10/10/2014 8:10 AM, Abhinaba Roy wrote:
Hi Duncan,
I have converted the string to a POSIXIt object using
strptime('31-may-2014',format=%d-%b-%Y)
But could not figure out the way forward.
Could you please elaborate a bit?
Try this:
?POSIXlt
Duncan Murdoch
On Fri, Oct 10, 2014 at
Or try this:
fridays - function(the_day){
require(lubridate)
day(the_day) = 1
the_month = seq(the_day, the_day+months(1)-days(1),1)
sum(wday(the_month) == 6)
}
That returns the number of Fridays in the month of a Date object given as arg:
fridays(as.Date(2012-01-01))
[1] 4
On 10 October 2014 08:04, pari hesabi statistic...@hotmail.com wrote:
Hello,As an example for Exponential distribution the MLE is got by this
structure:t - rexp(100, 2)loglik - function(theta){ log(theta) - theta*t}a
- maxLik(loglik, start=1)print(a)Exponential distribution has a simple
I want to get rid of this thread. what to do?
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...
On 10 October 2014 16:16, Tasnuva Tabassum t.tasn...@gmail.com wrote:
I want to get rid of
On Fri, Oct 10, 2014 at 1:32 AM, Frederic Ntirenganya ntfr...@gmail.com wrote:
Please try to not post in HTML. It is one of the forum rules.
Dear All,
The following function gives me what I wanted.
The input of function is one value and this push me to use sapply function
to call it.
Is
maximum likelihood estimation
pari hesabi
6:04 AM
To: r-help@r-project.org
Hello,
As an example for Exponential distribution the MLE is got by this structure:
t - rexp(100, 2)
loglik - function(theta){ log(theta) - theta*t}
a - maxLik(loglik, start=1)
print(a)
Exponential distribution has a
Here is one way of doing it:
require(lubridate)
now - as.Date('2014-10-10') # some date
# get first of month
first_mon - now - day(now) + 1
# create sequence of days in the month so you can count Fridays
x - seq(first_mon, by = '1 day', length = days_in_month(first_mon))
first_fri -
On Fri, Oct 10, 2014 at 7:28 AM, Abhinaba Roy abhinabaro...@gmail.com wrote:
Hi R helpers,
I want to write a function which will
1. Count the number of fridays in the current month ( to extract month from
given date) and also the number of fridays in the preceeding month
2. Calculate the
Dear friends,
The addHeader function in the rtf package always generates two rows of texts
even if a subtitle was not specified. Is there any way to stop the function
from generating the second blank line?
FYI, I cannot use the other functions, such as the addParagram and the
addText, because
In my Impression, there seems exsits a function (let just call weekday) which
can return a POSIXlt format date 's weekday. That means, weekday( 31-may-2014
) may return the right weekday maybe 5, so a clumsy method is start to judge
from 1-may-2014 to 31-may-2014 , you get a vector x,
Dear all R users
I am trying to find the bayesian analysis using R2winBUGS but i have errors
in initial values with two groups.
the R-code
#Initial values for the MCMC in WinBUGS
init1-list(uby1=rep(0.0,10),lam1=c(0.0,0.0,0.0,0.0,0.0,0.0),
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