Looks like a job for aggregate()
-pd
On 13 Oct 2014, at 04:25 , dila radi dilarad...@gmail.com wrote:
Hi all,
Could someone help me on this? I have this kind of data set
structure(list(Year = c(1971L, 1971L, 1971L, 1971L, 1971L, 1971L,
1971L, 1971L, 1971L, 1971L, 1971L, 1971L, 1971L,
Back in 2009 I posted some code to this list, see:
http://tolstoy.newcastle.edu.au/R/e8/help/09/12/8784.html
I submitted the function 'inhull' to the geometry package maintainer,
but I don't think it was ever included.
HTH
Keith J
On 12/10/2014 21:24, Don McKenzie wrote:
Check the R-news
A basic approach is
x - rchisq(1000, 4)
qqplot(qchisq(ppoints(x), 4), x)
abline(0,1)
Substitute whatever distribution and parameters that might apply. Notice that
if you don't have a location-scale family of distributions, you need to compare
to the identity line, not just look for linearity.
I want to sum columns based on their names. As an exampel how could I
sum columns which contain 6574, 7584 and 85 as column names? In
addition, how could I sum those which contain 6574, 7584 and 85 in
ther names and have a prefix f. My data contains several variables
with
I want to sum columns
You can use grep with some basic regex, index your dataframe, and colSums
colSums(df[,grep(*6574*|*7584*|*85*, colnames(df))])
colSums(df[,grep(f6574*|f7584*|f85*, colnames(df))])
Regards,
Dr. Charles Determan
On Mon, Oct 13, 2014 at 7:57 AM, Kuma Raj pollar...@gmail.com wrote:
I want to sum
Learn regular expressions.. there are many websites and books that describe how
they work. R has a number of functions that use them...
?regexp
?grep
For example...
grep(^[^0-9]*(6574|85|7584)[^0-9]*$,names(dta))
where dta is your data frame. You can read that regular expression as zero or
Your regular expressions are invalid, Charles. You seem to be thinking of file
name globbing as at the command line.
---
Jeff NewmillerThe . . Go Live...
DCN:jdnew...@dcn.davis.ca.us
Hi Anna,
On Sun, Oct 12, 2014 at 3:24 AM, Anna Zakrisson Braeunlich
anna.zakris...@su.se wrote:
Hi,
I have a question how to split a factor name into different columns. I have
metabarcoding data and need to merge the FASTA-file with the taxonomy- and
counttable files (dataframes). To be
I tried this
fit-glm(Pred~Pressure+MissingStep, data = Test, family=binomial)
save(fit,file=pred.rda)
pred-load(pred.rda)
predict(pred,Testsamp,type=response)
Hi all,
I am envisioning the user logging into a shiny app, or RStudio
server, and then, based on that authentication, obtaining the
necessary credentials to access other remote systems.
Is there maybe any working solution for this kind of problem?
All the help would be greatly appreciated.
Kind
I'm not sure I understood your problem, maybe like this:
# split identifiers into columns
df1 - data.frame(cbind(X = 1:10, Y = rnorm(10)),
Z.identifierA.B1298712 = factor(rep(LETTERS[1:2], each = 5)))
id - names(df1)[3]
x - do.call(rbind, str_split(id, \\.))
y - sapply(x,
see help(load) and pay particular attention to what the function
returns: the names of the loaded objects, not the object(s)
themselves.
You have to use
predict(fit,Testsamp,type=response)
since the load() created a variable 'fit' (same name as the one saved).
HTH
Peter
On Mon, Oct 13,
Hi all,
I need help with a function. I'm trying to write a function to apply
to varying number of columns in a lot of files - hence the function...
but I'm getting stuck. Here it is:
gt- function(x) {
alleles - sapply(x, function(.) strsplit(as.character(.), /))
gt - apply(x,
Just an update to this:
gtal - function(d) {
alleles - sapply(d, function(.) strsplit(as.character(.), /))
gt - unlist(lapply(alleles, function(x)
ifelse(identical(x[[1]], vcf[,3]) identical(x[[2]], vcf[,3]), 'RR',
ifelse(identical(x[[1]], vcf[,4])
Hello
Any idea how to read a text file with fortran format, WITH MULTIPLE
RECORDS? My fortran format is as follows, and I do know I need to
change F7.4 to F7.0, and 2F2.0 to 2I2, etc.
I just have no idea how to handle the slash (/) which dictates a
jump to the next record in fortran. Thank you
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