On 22 Nov 2014, at 08:12 , Aditya Singh aps...@yahoo.com wrote:
Dear Boris and R-Experts,
I have a variable my_state which is a 2-letter character string telling which
American state the user inputs. This I am do a if(identical(database
entry,my_state)) to check for occurrences in the
Dear all,
I use R 3.1.1 for Windows.
kindly how can I generate n number of random numbers with probability from [0,1]
and their sum must not be more than one
thanks in advance
Ragia
[[alternative HTML version deleted]]
Well, if their sum must be 1 they ain't random...
But anyway... given n
randnums - function(n)
{
Bert Gunter
Genentech Nonclinical Biostatistics
(650) 467-7374
Data is not information. Information is not knowledge. And knowledge
is certainly not wisdom.
Clifford Stoll
On Sat, Nov 22,
(Hit send key by accident before I was finished ...)
Bert Gunter
Genentech Nonclinical Biostatistics
(650) 467-7374
Data is not information. Information is not knowledge. And knowledge
is certainly not wisdom.
Clifford Stoll
On Sat, Nov 22, 2014 at 7:14 AM, Bert Gunter bgun...@gene.com
These are contradictory requirements: either you have n random numbers from the
interval [0,1), then you can't guarantee anything about their sum except that
it will be in [0,n). Or you constrain the sum, then your random numbers cannot
be random in [0,1). You could possibly scale the random
I don't understand this discussion at all.
n random numbers constrained to have sum =1 are still random. They are not all
independent.
That said, the original poster's question is ill=formed since there can be
multiple distributions these random numbers come from.
best wishes,
Ranjan
On
Of course they are random. But they can't all be randomly picked from [0,1).
By scaling them, one is effectively scaling the interval from which they are
picked.
B.
Nb: the scaling procedure will work for any probability distribution.
On Nov 22, 2014, at 10:54 AM, Ranjan Maitra
On 21 Nov 2014, at 19:18, David Winsemius dwinsem...@comcast.net wrote:
On Nov 21, 2014, at 6:52 AM, ivan wrote:
I am aware of the fact that bootstrapping produces different CIs with every
run. I still believe that there is a difference between both types of
procedures. My
Ok, thanks for the suggestions. I will look into that. And you are absolutely
right that I should have been more clear about what type of weighting I want.
So to clarify: I run time series regressions of returns of company i on two
different sets of explanatory variables. Then I extract the
Hi Boris/ David
Many thanks for the kind assistance. I will try following your codes.
Time has always been a slippery subject to me!
Cheers
On Sat, Nov 22, 2014 at 12:59 AM, David Winsemius
dwinsem...@comcast.net wrote:
On Nov 21, 2014, at 3:19 PM, David Winsemius wrote:
On Nov 21, 2014,
xx - as.factor(c(AL, AK, CA, FL))
xx
[1] AL AK CA FL
Levels: AK AL CA FL
as.character(xx)
[1] AL AK CA FL
I hope this helps.
Chel Hee Lee
On 14-11-22 01:12 AM, Aditya Singh wrote:
Dear Boris and R-Experts,
I have a variable my_state which is a 2-letter character string telling which
# fixed formula part:
f - dat ~ a0 * exp(-S*(x - 250)) + K
# convert to character
f - as.character(f)
# component:
C - (p0*exp(-0.5*((x-p1)/p2)^2))
# number of components (defined randomly):
n - sample(1:3, 1)
C - rep(C, n)
# collapse:
C - paste(C, collapse = +)
# combine
f - paste(f[2], f[1],
In the 2 and 3 vector case it is possible do define a fairly simple sampling
space where this is possible.
Consider the unit square where the sample space is the area where x+y 1.
It generalizes to 3 dimensions with no difficulty.
x= (0:100)/100
y= (0:100)/100
z=outer(x,y, function(x,y)
Estimados compañeros tengo un problema con la librería tm o con windows
8.1 o con algo que no controlo.
Hace tiempo con windows 7 y una versión anterior de R ejecutaba este código:
library(tm)
data(crude)
crude - tm_map(crude, tolower)
tdm-TermDocumentMatrix(crude)
y sin problemas me creaba
Hola, Juan:
Además de lo que te indica Carlos, ¿es posible que tengas un RStudio
sin actualizar a la última versión?
Si no recuerdo mal, el paquete tm daba problemas en alguna versión
reciente de RStudio y tenía algo que ver con algún cambio en R. Pero
lo solucionaron... Yo empezaría por ahí, si
Muchísimas gracias Carlos, como siempre tan rápido y eficaz.
Efectivamente funciona incluyendo esa función, que justo en versiones
anteriores no hacía falta.
Saludos,
Juan
El 22/11/2014 a las 22:23, Carlos Ortega escribió:
Hola Juan,
En la ayuda de la función tm_map() (versión 0.6 del
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