On 5 January 2015 at 21:08, Ben Bolker bbol...@gmail.com wrote:
Roger Coppock rcoppock at cox.net writes:
When will R implement the se.fit option to the
predict.nls() function? Is there some schedule?
I think this is unlikely to happen, ever (sorry). The exact method
for finding
Hi Dear Users,
I abonden ggplot2 adventure for the moment because of urgent results (i will of
course will do this with ggplot2 because I would like to use ggplot2 much more
than standart plots). But this time I came across with a different problem.
Problem is different graphical outputs from
Hi
I am not sure what do you want to achieve.
I would change your text function
{text(min(gecici$Tarih)+0.1,y,paste(z,sigma),cex=.85,pos=3)}
and instead of copy paste you can open and close appropriate device (pdf, jpg
or emf - from devEMF package)
Cheers
Petr
-Original Message-
On 05 Jan 2015, at 00:21 , Pete Brecknock peter.breckn...@bp.com wrote:
n - c(1,2,3,4,5)
lambda - c(0.1,0.8,1.2,2.2,4.2)
mapply(function(x,y) rpois(x,y), n, lambda)
Yes. I'd throw in a SIMPLIFY=FALSE to avoid getting results in a different
format if n is constant (then again, sapply()
Hi
cc to list, others can have further comments
substitute is superfluous
see results of
substitute(paste(z,sigma)
paste(z,sigma)
substitute(paste(z,sigma)
paste(z,sigma)
Cheers
Petr
-Original Message-
From: Levent TERLEMEZ [mailto:lterle...@anadolu.edu.tr]
Sent: Monday, January
Muchas gracias. Solucionado.
r-help-es-requ...@r-project.org escribió:
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Muchas gracias. Solucionado.
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O por correo
Dear R-help list,
I have a problem regarding text manipulation in R, where my basic knowledge
doesn't suffice anymore. It might be a bigger problem, but any help would be
greatly appreciated and acknowledged.
As input, I have a character string representing some Boolean function, such
as
You can create your own:
http://topepo.github.io/caret/custom_models.html
I put a prototype together. Source this file:
https://github.com/topepo/caret/blob/master/models/files/chaid.R
then try this:
library(CHAID)
### fit tree to subsample
set.seed(290875)
USvoteS -
On Jan 4, 2015, at 10:15 PM, കുഞ്ഞായി kunjaai wrote:
Dear all,
I am trying to control the font size of correlation axis and gamma label
(0.6, 0.4 , 0.2 labeling of attached plot) of Taylor diagram in R.
I am using **plotrix** package for making Taylor diagram.
Nothing attached in what
Dear all R members
I have a problem in the R when i wanted to call winbugs as following
#Input data set for WinBUGS
thd18 -read.table(C:/Users/hp/Desktop/thd18.txt)
#Input data set for WinBUGS
data-list(N1=2000,N2=2000,P=9,R=Ro,z1=yo1,z2=yo2,thd18)
#Call WinBUGS
model-bugs
On Jan 5, 2015, at 2:46 AM, PIKAL Petr wrote:
Hi
cc to list, others can have further comments
substitute is superfluous
see results of
substitute(paste(z,sigma)
paste(z,sigma)
substitute(paste(z,sigma)
paste(z,sigma)
Perhaps this would be more instructive (after adding back the
Hi All:
I have a data frame the first part of which is the following:
date lonlat mean chlcol missing
1 2003-04-23 203.899 19.664 0.0730 0.15176637 0
2 2003-04-24 204.151 19.821NaNNaN 1
3 2003-04-30 203.919 20.351 0.0740
Hello,
I am looking at a data set predicting number of plants (FERO) based on fixed
effects sowing method (Method) and sowing rate (Rate). I also have a slope
random effect for the site and intercept random effects for the nested
variables Block and Strip.ID (to account for experimental design).
Jinsong Zhao jszhao at yeah.net writes:
In the following code snippet,
#
a - strptime(121114 0510, %m%d%y %H%M)
b - data.frame(date = a, res = 1:5)
class(a)
class(b[1,1])
#
I am wondering why the class of a and b[1,1] are not the same.
How to make the class of a and b[1,1] to be same?
QUESTION: Can anyone give me advice on how to resolve an error message
regarding a non positive definite correlation matrix so that the computed
negative cross-variogram can be used to perform co-kriging?
I am performing co-kriging on negatively correlated parameters.
data = dtrd
x y
Perfect. Thanks.
-Roy
On Jan 5, 2015, at 5:20 PM, Ista Zahn istaz...@gmail.com wrote:
You were close, but a) if you want to map shape to something it needs
to be inside an aes() call, and b) shape 1 is also an open circle. I
think this does what you want:
ggplot(temp,aes(x=lon,y=lat)) +
Hi there,
In the following code snippet,
#
a - strptime(121114 0510, %m%d%y %H%M)
b - data.frame(date = a, res = 1:5)
class(a)
class(b[1,1])
#
I am wondering why the class of a and b[1,1] are not the same.
How to make the class of a and b[1,1] to be same?
I would really appreciate you for any
You were close, but a) if you want to map shape to something it needs
to be inside an aes() call, and b) shape 1 is also an open circle. I
think this does what you want:
ggplot(temp,aes(x=lon,y=lat)) +
geom_point(aes(colour=chlcol, shape=factor(missing)),size=3) +
On 2015/1/5 17:28, Ben Bolker wrote:
Jinsong Zhao jszhao at yeah.net writes:
In the following code snippet,
#
a - strptime(121114 0510, %m%d%y %H%M)
b - data.frame(date = a, res = 1:5)
class(a)
class(b[1,1])
#
I am wondering why the class of a and b[1,1] are not the same.
How to make the
On 2015/1/5 20:51, David Winsemius wrote:
On Jan 5, 2015, at 5:47 PM, Jinsong Zhao wrote:
On 2015/1/5 17:28, Ben Bolker wrote:
Jinsong Zhao jszhao at yeah.net writes:
In the following code snippet,
#
a - strptime(121114 0510, %m%d%y %H%M)
b - data.frame(date = a, res = 1:5)
class(a)
Because data.frame converts it. I don't know what rationale was originally used
to justify including that transformation automatically, but I think it is much
better this way than having POSIXlt in the data frame. POSIXlt is itself like a
little data frame, and having data frames inside of data
Saludo estimados compañeros y compañeras
Tengo una matriz de datos de 51 filas por 160 columnas, Cada columna es una
serie de tiempo.
Existe alguna libreria q me calcule la posicion de la fila donde se hallan
estos maximos y minimos o los eventos de estas curvas
Agradezco la atencion
CARLOS
On Jan 5, 2015, at 5:47 PM, Jinsong Zhao wrote:
On 2015/1/5 17:28, Ben Bolker wrote:
Jinsong Zhao jszhao at yeah.net writes:
In the following code snippet,
#
a - strptime(121114 0510, %m%d%y %H%M)
b - data.frame(date = a, res = 1:5)
class(a)
class(b[1,1])
#
I am wondering why the
Hello,
How can I export the sample data frame below -USvoteS with the associated
probabilities and rules for each row?
library(CHAID)
example(chaid, package = CHAID)
To be more specific, for each of 1000 rows of the USvoteS data frame I want to
see in which node is that row in (what are the
Roger Coppock rcoppock at cox.net writes:
When will R implement the se.fit option to the
predict.nls() function? Is there some schedule?
I think this is unlikely to happen, ever (sorry). The exact method
for finding confidence intervals on nonlinear fits would be
to compute
Hello,
Is there an option of cross validation for CHAID decision tree? An example of
CHAID is below:
library(CHAID)
example(chaid, package = CHAID)
How can I use a 10 fold cross-validation for CHAID?
I've read that caret package is to cross-validate on many times of models, but
model CHAID is
Hi, this is my function to find rstudent of model which will give me outlier
But I wonder if I could find out the exact no. of outlier in data set.
Like outlierTest() does from car package .
rm.outliers = function(dataset,model){
dataset$rstudent = rstudent(model)
for(i in
When will R implement the se.fit option to the predict.nls() function? Is
there some schedule?
__
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
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PLEASE do read the posting guide
Dear Pushpa Methekar,
You can use which.max(), as in
library(car)
mod - lm(prestige~ income + education, data=Duncan)
which.max(abs(rstudent(mod)))
minister
6
In fact, this is exactly what outlierTest() does, as you can see by looking at
car:::outlierTest.lm
Beyond that, I'd
Dear all,
I am trying to control the font size of correlation axis and gamma label
(0.6, 0.4 , 0.2 labeling of attached plot) of Taylor diagram in R.
I am using **plotrix** package for making Taylor diagram.
Thank you all in advance
--
DILEEPKUMAR. R
J R F, IIT DELHI
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