Nope. Wrong address for an automated efforts at changing subscription
preferences, and it would not have worked anyway because you did not provide
your password. Most people who started using the Internet in the last 20 years
will need to use the web interface at the address in the message foote
Hi Brendon ,
Pls download and install the latest R version and try again.
> version
_
platform x86_64-w64-mingw32
arch x86_64
os mingw32
system x86_64, mingw32
status
major 3
minor 1.3
year 2015
month 03
day
See the help page for the "[" operator ...
?"["
... and use the drop parameter as in:
A[1,,drop=FALSE]
[,1] [,2] [,3] [,4]
a1147 10
B.
On Mar 21, 2015, at 8:10 AM, J Robertson-Burns
wrote:
> This is Circle 8.1.44 of 'The R Inferno'.
>
> http://www.burns-stat.com/documents
The posting guide warns you that this list is only for questions regarding the
current version of R. You probably need to be sure to use versions of packages
that were current as of the time that version of R was current... anything else
is a wild ride for you.
--
This is Circle 8.1.44 of 'The R Inferno'.
http://www.burns-stat.com/documents/books/the-r-inferno/
Pat
On 21/03/2015 11:04, jean.cour...@math.u-psud.fr wrote:
My question must be a trivial one.
There is automatic coercicion to vector when extracting only one line of a
matrix.
# example
A = ma
[[alternative HTML version deleted]]
__
R-help@r-project.org mailing list -- To UNSUBSCRIBE and more, see
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide comm
I'm trying to install RSQLite on the way to installing RQDA. I have
installed DBI, and RSQLite compiles but will not install.
Running install.packages("RSQLite") fails with the following messages:
...
** preparing package for lazy loading
Error in setClass("SQLiteConnection", contains = "DBIConn
Dear All,I'm using RSNNS package in R, for Elman Neural Network. Now I have
some question.s1- How can i set the weight range for the Elman Netwrok in RSNNS
Package? At the end my goal is to have activation value range between 0 and
1.2- How can i use Softmax activation function for the elman ne
... just for completeness - the more concise way: (no need to go through
names()).
boxplot(mydata[,order(apply(mydata,2,median))])
... or descending
boxplot(mydata[,order(-apply(mydata,2,median))])
B.
On Mar 21, 2015, at 7:04 PM, Boris Steipe wrote:
> There may be more concise ways to d
Greetings. I was reading through the vignette for "tidy-data" (from the
"tidyr" package) and came across something that puzzled me.
One of the examples in the vignette uses a data set related to tuberculosis,
originally from the World Health Organization, but also available at:
https://github.
There may be more concise ways to do this - but you are 99% there with your
approach:
try:
boxplot(mydata[,names(sort(apply(mydata,2,median)))])
B.
On Mar 21, 2015, at 6:49 PM, Antonio Silva wrote:
> Thanks Bill and David
>
> Here goes an example
>
> SP1<-c(9,6,7,8,5,8,7,5,9,7)
> SP2<-c(1,
Thanks Bill and David
Here goes an example
SP1<-c(9,6,7,8,5,8,7,5,9,7)
SP2<-c(1,3,4,2,4,2,5,3,2,1)
SP3<-c(4,6,7,5,7,8,7,6,5,4)
SP4<-c(5,4,3,5,2,3,4,3,4,2)
mydata<-data.frame(SP1,SP2,SP3,SP4)
rownames(mydata)<-c("ST1","ST2","ST3","ST4","ST5","ST6","ST7","ST8","ST9","ST10")
mydata
boxplot(mydata)
You can use the reorder() function to reorder the grouping vector's
factor levels according to a function of the data in each group. E.g.,
compare the following two plots:
d <- data.frame(Response=cos(1:15), Group=rep(c("A","B","C"),c(6,5,4)))
par(mfrow=c(1,2))
boxplot(Response ~ Group,
On Mar 20, 2015, at 2:20 PM, Antonio Silva wrote:
> Hello
>
> I'm using a dataframe (mydata) where row names are sampling points and
> column names are species in a multivariate analysis.
>
> If I write boxplot(mydata) I'll have boxplots for each species abundance in
> alphabetical order.
>
>
... or cleaner:
z1 <- with(f1,v4 + z -ave(z,v1,v2,FUN=mean))
Just for curiosity, was this homework? (in which case I should
probably have not provided you an answer -- that is, assuming that I
HAVE provided an answer).
Cheers,
Bert
Bert Gunter
Genentech Nonclinical Biostatistics
(650) 467-7374
z <- rnorm(nrow(f1)) ## or anything you want
z1 <- f1$v4 + z - with(f1,ave(z,v1,v2,FUN=mean))
aggregate(v4~v1,f1,sum)
aggregate(z1~v1,f1,sum)
aggregate(v4~v2,f1,sum)
aggregate(z1~v2,f1,sum)
aggregate(v4~v3,f1,sum)
aggregate(z1~v3,f1,sum)
Cheers,
Bert
Bert Gunter
Genentech Nonclinical Biostatis
On 21/03/2015 14:27, Johannes Radinger wrote:
Thanks for the fast response. The fitdistr() function works well for the
predefined density functions. However, what is the recommended approach
to optimize/fit a density function described by two superimposed normal
distributions? In my case it is N1
Thanks for the fast response. The fitdistr() function works well for the
predefined density functions. However, what is the recommended approach to
optimize/fit a density function described by two superimposed normal
distributions? In my case it is N1(mean=0,sd1)*p+N2(mean=0,sd2)*(1-p). With
fitdis
Hi Bert,
Thank you for your message. I am looking into ave() and tapply() as you
suggested but at the same time I have prepared a example of input and
output files, just in case you or someone else would like to make an
attempt to generate a code that goes from input to output.
Please see below o
One way using the standard R distribution:
library(MASS)
?fitdistr
No optimization is needed to fit a normal distribution, though.
On 21/03/2015 13:05, Johannes Radinger wrote:
Hi,
I am looking for a way to fit data (vector of values) to a density function
using an optimization (ordinary leas
Hi,
I am looking for a way to fit data (vector of values) to a density function
using an optimization (ordinary least squares or maximum likelihood fit).
For example if I have a vector of 100 values generated with rnorm:
rnorm(n=100,mean=500,sd=50)
How can I fit these data to a Gaussian density
1. Still not sure what you mean, but maybe look at ?ave and ?tapply,
for which ave() is a wrapper.
2. You still need to heed the rest of Jeff's advice.
Cheers,
Bert
Bert Gunter
Genentech Nonclinical Biostatistics
(650) 467-7374
"Data is not information. Information is not knowledge. And knowled
Hi Jeff & other R-experts,
Thank you for your note. I have tried myself to solve the issue without
success.
Following your suggestion, I am providing a sample of the dataset I am
using below (also downloadble in plain text from
https://www.dropbox.com/s/qhmpkkrejjkpbkx/sample_code.txt?dl=0):
#th
>From one Jean to another ... A[i, , drop=FALSE]
On Sat, Mar 21, 2015 at 6:04 AM, wrote:
> My question must be a trivial one.
>
> There is automatic coercicion to vector when extracting only one line of a
> matrix.
> # example
> A = matrix(1:12,3,4)
> rownames(A) = c('a1','a2','a3')
>
> i = 1:2
My question must be a trivial one.
There is automatic coercicion to vector when extracting only one line of a
matrix.
# example
A = matrix(1:12,3,4)
rownames(A) = c('a1','a2','a3')
i = 1:2
A[i,]
#[,1] [,2] [,3] [,4]
# a1147 10matrix
# a2258 11
i = 1
A[i,]
# [1
25 matches
Mail list logo